napthalene combustion can be used to calibrate the heat capacity of a bomb calorimeter The heat of combustion of naphthalene is -40.1kj/g. When .8210g of naphthalene was burned in a calorimeter containing 1,000g of water, a temperature rise of 4.21C was observed. What is the heat capacity?

Answers

Answer 1

A bomb calorimeter with a heat capacity of 3.63 kJ/°C experiences a temperature rise of 4.21 °C when .8210 g of naphthalene is burned.

The combustion of naphthalene is used to calibrate the heat capacity of a bomb calorimeter.

What is a bomb calorimeter?

It is a device used to measure the change in the internal energy of a reaction.

To determine the heat capacity of the calorimeter (C), we need to follow a series of steps.

Step 1: Calculate the heat released by the combustion.

The heat of combustion of naphthalene is -40.1kJ/g and .8210g were burned.

Qcomb = -40.1kJ/g × .8210g = -32.9 kJ

Step 2: Determine the heat absorbed by the bomb calorimeter.

According to the law of conservation of energy, the sum of the heat released by the combustion and the heat absorbed by the bomb calorimeter is zero.

Qcomb + Qbomb = 0

Qbomb = -Qcomb = 32.9 kJ

Step 3: Calculate the heat capacity of the bomb calorimeter.

32.9 kJ were absorbed, part by the calorimeter itself and part by the 1,000 g (m) of water, whose specific heat capacity (c) is 4.18 J/g°C.

A temperature rise (ΔT) of 4.21 °C is observed. We can determine the heat capacity of the bomb calorimeter (C) using the following expression.

Qbomb = Qcal + Qwater

32.9 kJ = C × ΔT + c × m × ΔT

32.9 kJ = C × 4.21 °C + (4.18 × 10⁻³ kJ/g.°C) × 1,000 g × 4.21 °C

C = 3.63 kJ/°C

A bomb calorimeter with a heat capacity of 3.63 kJ/°C experiences a temperature rise of 4.21 °C when .8210 g of naphthalene is burned.

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B. 3.68 teaspoons
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Answers

Answer:it's b hope that help

The molar mass of water is 18 g. Given that there are 0.23 teaspoon for every 1 g. Thus , for 18 g there would be 4.14 teaspoons.

What is one mole?

Any substance that contains  6.022 × 10²³ number of atoms is called one mole of that substance. The mass of a compound or molecule containing these much atoms is called its molar mass.

Molar mass of water is 18 g. Thus, it means that one mole of water weighs 18 g. Given that for every 1 g of water there are 0.23 teaspoon. Thus, number of teaspoons for one mole or 18 g of water is:

number of teaspoons = 18 g × 0.23  /1 g

                                    = 4.14 teaspoons.

Therefore, 4.14 teaspoons are required for one mole of water.

To find more on molar mass, refer here:

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Which of these objects will most likely float?

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Answer:

plastic,palstic bottle,balloon,cap of water bottle,plastic slippers and plastic comb.

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hope it helps :D

Which charge does iron (Fe) have in iron sulfate (FeSO4)?
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D)+2

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I’m not sure but I think the answer is B

The charge on iron (Fe) in iron sulfate (FeSO₄) is equal to +2. Therefore, option (D) is correct.

What are the ionic charges?

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In the modern periodic table, the elements placed on the left side are electropositive and act as metals because they can donate one or more electrons. The elements placed on the right side are electronegative as they can accept one or more electrons and get a negative charge on their ions.

Considering that the charge on the iron is x, We know that charge on the sulfate ion is -2.

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Therefore, the charge on iron (Fe) in iron sulfate (FeSO₄) is +2.

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4. The new element Plainsmenium (Pe) was discovered in 2005 by Monte E. Rey
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three isotopes: Pe-184 (24.60%), Pe-185 (11.20%), and Pe-188 (64.20%).
What is its average atomic mass?

Answers

This is my answer

Explanation:

p=m/v

where:. p=density

m=mass

v=volume

p=F/A = Lim F / A

1 ATM=14.7 psi

= 1.013x10 d/cm²

1 bar=10 d/cm²

=10 N/m2

Hope it helps to you goodluck

I'm not sure but that's the answer of my notebook like my answer please

2.
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Group of answer choices

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C. top

D. trough

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Answer:

B. crest

Explanation:

The highest part of a wavelength is called the crest, meanwhile, the lowest part is the trough.

Answer:

b

Explanation:

it's highest because it have the most higher wave

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Answer:

huh

Explanation:

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Electrolysis is a technique that separates natural elements. It is commercially used to obtain important materials (e.g., pure metals) for construction.

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Answer: Electrolysis is a technique that separates natural elements. It is commercially used to obtain important materials (e.g., pure metals) for construction.

Electrolysis refers to the use of an electric current to trigger non-spontaneous chemical reactions.

This technology (electrolysis) is commercially important in industry, construction and therefore also in architecture in order to extract metals and minerals from the ground.

Electrolysis uses particular electrolytic cells in order to extract highly pure metals from ores.

Learn more about electrolysis here:

brainly.com/question/12054569

Consider the gas phase reaction 4HCl + O2 → 2Cl2 + 2H2O. What volume of chlorine gas at STP can be prepared from the reaction of 600. mL of gaseous HCl, measured at STP, with excess oxygen?
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Answer:

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Answer:

nm, dm, km, m

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Answers

Answer:

6.022 × 1023

Explanation:

1 mole of H:

The definition of Avogadro's number of 6.022 × 1023/mole is the number of atoms or molecules per one gram atomic weight. For one gram atomic weight of hydrogen with an atomic weight of one gram, one mole of hydrogen contains 6.022 × 1023 hydrogen atoms. 1.45⋅6.02⋅1023≈8.73⋅1023 hydrogen atoms.

1 mole:

The value of the mole is equal to the number of atoms in exactly 12 grams of pure carbon-12. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).

in an H:

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1.00 mole:

One mole is equal to 6.02214179×1023 atoms, or other elementary units such as molecules.

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1. How does the figure below illustrate Hund's rule?

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Answer:

it indicates that the lower orbitals are filled first and they have the maximum number of electrons compared to the higher orbitals

Which element is shown below? How do you know?

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It’s Neon (Ne). You know because there are 10 protons and the number of protons is equal to the atomic number of an element. (Neon is #10 on the periodic table)

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[tex] \rule{999pt}{66646pt}[/tex]

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Conduction
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Convection

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Group of answer choices


180°


90°


120°


60°


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Answers

Answer:

109.5°

Explanation:

Pls Cross Check It, If It Correct

109.5° and it’s a Tetrahedral shape - a Carbon atom has 4 valence electrons and can share each electron with each of the 2 H atoms and 2 of the F atoms in order for them to form a full valence shell. This forms a 109.5° bond angle between F-C-F and all other atoms as the molecule experiences repulsion (atoms are trying to be as far apart as possible).

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Answers

Answer:

2.00n2g

Explanation:

hope its attachments

Gaseous methane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water. If 0.809g of carbon dioxide is produced from the reaction of 0.80g of methane and 2.1g of oxygen gas, calculate the percent yield of carbon dioxide.

Be sure your answer has the correct number of significant digits in it.

Answers

Answer:

About 58%.

Explanation:

We first need to write the balanced chemical equation:

[tex]\displaystyle \text{CH$_4$(g)} + 2\text{O$_2$(g)} \longrightarrow \text{CO$_2$(g)} + 2\text{H$_2$O(g)}[/tex]

We are given that 0.809 g of carbon dioxide was produced from the reaction of 0.80 g of methane and 2.1 g of oxygen gas. We want to calculate the percent yield of carbon dioxide.

First, determine the limiting reagent. We can convert each initial mass to the mass of carbon dioxide using stoichiometry. The molar mass of methane is 16.05 g/mol and the molar mass of carbon dioxie is 44.01 g/mol. From the equation, every one mole of carbon dioxide is produced from every one mole of methane and every two moles of oxygen gas.

0.80 g of methane will (theoretically) produce:

[tex]\displaystyle \begin{aligned} 0.80 \text{ g CH$_4$} &\cdot \frac{1 \text{ mol CH$_4$}}{16.05 \text{ g CH$_4$}} \cdot \frac{1 \text{ mol CO$_2$}}{1 \text{ mol CH$_4$}} \cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} \\ \\ & = 2.2 \text{ g CO$_2$}\end{aligned}[/tex]

2.1 g of oxygen gas will (theoretically) produce:

[tex]\displaystyle \begin{aligned} 2.1 \text{ g O$_2$} & \cdot \frac{ 1 \text{ mol O$_2$}}{32.00 \text{ g O$_2$}} \cdot \frac{1 \text{ mol CO$_2$}}{2 \text{ mol O$_2$}}\cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} \\ \\ & = 1.4 \text{ g CO$_2$} \end{aligned}[/tex]

Hence, oxygen gas is the limiting reagent. A maximum of 1.4 g of carbon dioxide can be produced.

To calculate the percent yield, we divide the actual yield by the theoretical yield. The actual yield was 0.809 g and the theoretical yield is 1.4 g. Hence:

[tex]\displaystyle \begin{aligned} \%\text{Yield} & = \frac{\text{Actual}}{\text{Theoretical}} \times 100\% \\ \\ & = \frac{(0.809\text{ g CO$_2$})}{(1.4\text{ g CO$_2$})} \times 100\% \\ \\ & = 58\%\end{aligned}[/tex]

In conclusion, the percent yield of carbon dioxide is about 58%.

please help
write the correct IUPAC name for these componds

Answers

Answer:

A. 4,6-dimethyloct-1,4,6-yne

B. deconic acid

C. 3-ethyl-4-methyl-7-bromocyclohexene

D. 2,2,3-trimethyl-4-butyl-heptane

E. 3-methylhexane

F. ethyl hexanoate

G. butanal

H. propyne

J. 2,4-dimethyl-pent-2-ene

Explanation:

sorry i didn't have time to do I

calculate the number of molecules in 4.48dm3 of hydrogen at STP​

Answers

Answer: 1 more of hydrogen =22.4dm3

X moles of hydrogen =4.48dm3

22.4dm3x = 4.48dm3

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Explanation: 1 volume of hydrogen at STP is 22.4dm3

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Answer:

5-3. Ice water 0 "C. A steel tank contains carbon dioxide at 27 "C and a pressure of 12.0 atm.

Explanation:

what is the mass in g of 7.009 x 10^21 molecules of Pl3?

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I have completed the problem

The covalent compounds are soluble in:

a) All acids

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Answer:

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Explanation:

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