The steeper the slope of a line, the _______ the object was moving
Answer:
"Faster" is most likely the answer, I'm not 100% sure though
How long is the flea in the air from the time it jumps to the time it hits the ground
Answer:
0.613 milliseconds
Explanation:
if you ran 3.1 miles in 0.5 hours. what was your speed
Answer:
speed= 6.2 m/hrExplanation:
distance= 3.1 mile
time=0.5 hours
s=d/t
s=3.1/0.5
speed= 6.2 m/hr
If you run for a distance of 3.1 miles in 0.5 hours, then the speed in miles per hour will be 6.2 m/hr.
What is Speed?A scalar quantity in kinematics and common usage, an object's speed is the size of the change in its position over time or the amount of change in its position per unit of time.
As the duration of the time interval approaches zero, the instantaneous speed is the maximum limit of the average speed. The distance traveled divided by the duration of the interval represents the average speed of an object over a period of time.
Given information,
Distance covered, d = 3.1 miles
Time taken, t = 0.5 hours
Speed = [tex]Distance/time[/tex]
Speed = 3.1/0.5
Speed = 6.2 m/hr
Therefore, the speed while running is 6.2 m/hr.
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25 POINTS!! ANSWER CORRECTLY FOR BRANLIEST!
Which of the following statements describes an interaction between the atmosphere and biosphere?
Water and its vapor move through air.
Earth's internal heat warms the layer of air around it.
Oceans provide an environment for sustaining marine life.
Life is possible on Earth due to layers of air that surround it.
Answer:
the answer is probably most likely D first and if thats incorrect than its B
♡ Hope it helps♡
27 miles per gallon into kilometers per liter.
Answer:
11.479 kilometres per litre
Explanation:
for an approximate result, divide the fuel economy value by 2.352
27 miles per gallon is equivalent to approximately 6.09 kilometers per liter.
What is Unit conversion?A statement of the connection between units that are used to alter the units of a measured quantity without affecting the value is called a conversion factor. A conversion ratio (or unit factor), if the numerator and denominator have the same value represented in various units, always equals one (1).
To convert 27 miles per gallon to kilometers per liter, we need to use conversion factors:
1 mile = 1.60934 kilometers
1 gallon = 3.78541 liters
So, first we convert miles to kilometers:
27 miles * 1.60934 km/mile = 43.45218 kilometers
Then we convert gallons to liters:
1 gallon = 3.78541 liters
27 miles per gallon = 27 miles / 1 gallon = 27 / 3.78541 liters/mile = 7.13888 liters/kilometer
Finally, we divide the distance traveled in kilometers by the amount of fuel used in liters:
43.45218 km / 7.13888 liters = 6.09023 kilometers per liter
Therefore, 27 miles per gallon is equivalent to approximately 6.09 kilometers per liter.
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suppose both the dog and the girl run at a speed of 2 m/s.Calculate both of there kinetic energies. kinetic energy of dog =
Answer:
78
Explanation:
Answer:
78
Explanation:
dakaylaRiley 12
an elastic material of length 3m is to be stretched to produce an extension three times it's original length. Calculate the force required to produce the extension if the force constant of the material is 982.3 Newton per metre
Answer:
F = 8840.7 N
Explanation:
The parameters given are:
Length L = 3 metres
Extension e = 3 × 3 = 9m
Force constant K = 982.3 Newton per metre
From Hook's law,
Provided the elastic limit is not extended, the extension is directly proportional to the force applied.
That is,
F = Ke
Substitute all the parameters into the formula
F = 982.3 × 9
F = 8840.7 N
a tungsten and coil has a resistance of 12 ohm at 15 degree celsius is the temperature coefficient of resistance of tungsten is 0.004 calculate the equal resistance at 80 degree Celsius
Answer:
The resistance of the tungsten coil at 80 degrees Celsius is 15.12 ohm
Explanation:
The given parameters are;
The resistance of the tungsten coil at 15 degrees Celsius = 12 ohm
The temperature coefficient of resistance of tungsten = 0.004/°C
The resistance of the tungsten coil at 80 degrees Celsius is found using the following relation;
R₂ = R₁·[1 + α·(t₂ - t₁)]
Where;
R₁ = The resistance at the initial temperature = 12 ohm
R₂ = The resistance of tungsten at the final temperature
t₁ = The initial temperature = 15 degrees Celsius
t₂ = The final temperature = 80 degrees Celsius
α = temperature coefficient of resistance of tungsten = 0.004/°C
Therefore, we have;
R₂ = 12×[1 + 0.004×(80 - 15)] = 15.12 ohm
The resistance of the tungsten coil at 80 degrees Celsius = 15.12 ohm.
An instrument is defective for all of the following conditions EXCEPT:_______
a. when an instrument is overdue.
b. when an instrument is dishonored.
c. when an instrument is presented.
d. when an instrument is irregular.
e. when an instrument is incomplete.
Answer:
I believe its C
How should you behave while performing laboratory experiments?
Explanation:
Always behave responsibly in the laboratory. Do not run around or play practical jokes. Always check the safety data of any chemicals you are going to use. Never smell, taste or touch chemicals unless instructed to do so.
The speed needed to escape the pull of Earth's gravity is 11.3 km/s. What is this speed in mi/h? (1 mile = 1609 m)
Answer:
11.3 km/sec * 1000 m/km / 1609 m/mi = 7.02 mi / sec
7.02 mi/sec * 3600 sec / hr = 25,300 mph
The value of the speed needed to escape the pull of Earth's gravity in miles per hour (mi/h) is 25282.8.
Given the following data;
Speed = 11.3 km/s1 mile = 1609 mIn this exercise, you're required to convert the value of the speed needed to escape the pull of Earth's gravity in kilometer per seconds (km/s) to miles per hour (mi/h).
Conversion:
1 mile = 1.609 kilometer
X mile = 11.3 kilometer
Cross-multiplying, we have;
[tex]1.609[/tex] × X = [tex]11.3[/tex]
[tex]X = \frac{11.3}{1.609}[/tex]
X = 7.0230 miles
Since we know that one (1) hour is equal to 3600 seconds, we would multiply the value of X by 3600 in order to convert it to miles per hour (mi/h).
X = 7.0230 × 3600
X = 25282.8 mi/h
Therefore, the value of the speed needed to escape the pull of Earth's gravity in miles per hour (mi/h) is 25282.8.
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what does a spring balance measure
The spring balance provides a mass measurement
Answer:
mass
Explanation:
The mass is hung on the end of a spring, and the deflection of the spring due to the downwards gravitational force on the mass is measured against a scale.
Calculate the change in momentum of a 45 kg runner who starts out at 1 m/s and speeds up to 3 m/s. Which anser choice is correct 90 kg⋅m/s 45 kg⋅m/s 135 kg⋅m/s 0 kg⋅m/s
momentum can also be defined in terms of newton second
that is P=F.V
now v =vf-vi
v=3 m/s-1m/s=2 m/s
now F=W=45 kg
therefore
change in momentum=F.v
P=45*2=90 kg.m/s
What statement most accurately classifies this cell?
Choose 1 answer:
(Choice A) A It is a plant cell.
(Choice B) B It is a fungal cell.
(Choice C) C It is a bacterial cell.
(Choice D) D It is an animal cell.
Answer:
D It is an animal cell.
Explanation:
3. Briefly explain why measured data
must have units.
Answer:
because it helps data to be meaningful
Explanation:
I took a test and and got 100%
what volume will a sample of copper 98.2 g occupy? the density of copper is 8.96 g/mL
Answer:
Density=mass/volume.
8.96=98.2/volume.
volume=98.2/8.96=10.95982143 ~ 11cm^3.
The volume of a sample of copper of 98.2 g would be 10.95 ml if the density of copper is 8.96 g/mL.
What is density?It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
Due to their superior electrical and thermal conductivities, remarkable resistance to corrosion, and simplicity of production, copper alloys are frequently employed. In general, copper alloys are not magnetic. Electrical wire, cable, contacts, and other components.
As given in the problem the density of copper is 8.96 g/mL, and we have to find the volume occupied by the sample of copper.
mass = density×volume
98.2 g = 8.96 g/mL×volume
volume =98.2/8.96
=10.95 ml
Thus, the volume of a 98.2 g sample of copper would be 10.95 ml.
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Record your hypothesis here: Record the results from step one of the experiment (dropping the objects in the air): First trial: Second trial: Third trial:
Answer:
First trial (Big Ball vs. Feather):The big ball hit the ground first.
Second trial (Small Ball vs. Feather):The small ball hit the ground first.
Third trial (Big Ball vs. Small Ball):They hit the ground at the same time
Explanation:
HOPE IT HELP :)Let G be the garvitational constant and R be the radius of earth. If the radius of the earth becomes half, the new value of gravitational constant will be
Answer:
G = 1.670 × [tex]10^{-11}[/tex] [tex]m^{3}kg^{-1}s^{-2}[/tex]
Explanation:
From Newton's law of universal gravitation,
F = [tex]\frac{GMm}{R^{2} }[/tex]
Where F is the force of attraction, G is the gravitational constant, M is the mass of the earth, R is the radius of the earth.
From Newton's second law of motion,
F = mg
mg = [tex]\frac{GMm}{R^{2} }[/tex]
g = [tex]\frac{GM}{R^{2} }[/tex]
⇒ G = [tex]\frac{gR^{2} }{M}[/tex]
If the radius of the earth becomes half,
R = [tex]\frac{R}{2}[/tex], then;
G = [tex]\frac{gR^{2} }{4M}[/tex]
Given that: g = 9.8 m/[tex]s^{2}[/tex], radius of the earth is 6371000 m, mass of the earth is 5.972 × [tex]10^{24}[/tex]kg, then;
G = [tex]\frac{9.8*(6371000)^{2} }{4*5.972*10^{24} }[/tex]
= 1.670 × [tex]10^{-11}[/tex] [tex]m^{3}kg^{-1}s^{-2}[/tex]
what do you mean by 100W is written on an electric bulb?
Answer:
100 watt
Watt is a unit of power, for the light bulb its produces or consumes 100 watts of power
Answer:
100w means the power consumed by the electric bulb
How much does Earth weight?
Answer:
About 13, 000,000,000,000,000,000,000,000 pounds.
Explanation:
Answer:
6,000,000,000, 000,000,000,000,000 kilograms (6 x 1024 kilograms, or 1.3 x 1025 pounds).
What is the length of the line to the correct degree of precision?
92 mm
9.2 mm
9.2 cm
9.23 cm
Answer:
9.2 cm
Explanation:
on a ruler you can only measure in cm
and the precision is of one decimal point
Suppose you receive $5.00 at the beginning of a week and spend $1.00 each day for
lunch. You prepare a graph of the amount you have left at the end of each day for one
6.
week.
A)
Would the slope of this graph be positive, negative, or zero?
B)
Why?
What is non-science? Philosophy or art.
Answer:
both
Explanation:
because science is not included in both of them
Two students both kick a soccer ball. Havanna's ball travels three times as fast as Mitzi's ball. How does the kinetic energy of the two soccer balls compare? A. Both soccer balls have the same amount of kinetic energy, because they have the same mass. B. Mitzi's soccer ball has 3 times as much kinetic energy, because it travels a third of the speed. C. Havanna's soccer ball has 9 times the kinetic energy, because it travels at 3 times the speed. D. Havanna's soccer ball has 3 times because it travels at 3 times the speed.
Answer:
the answer is c. Havanna's soccer ball has 9 times the kinetic energy, because it travels at 3 times the speed
Explanation:
A rock is thrown vertically upward at an initial velocity of 70 m/s. What is the approximate acceleration of the rock when it reaches its maximum height (assume upward is the positive y direction)?
Answer:
Zero.
Explanation:
Given that a rock is thrown vertically upward at an initial velocity of 70 m/s. What is the approximate acceleration of the rock when it reaches its maximum height
(assume upward is the positive y direction)?
Since the reached the maximum height, the final velocity V will be equal to zero.
Using the first equation of motion to find the time.
And since it is a vertical direction, and not horizontal, the acceleration a will be equal to zero.
A spherical balloon is being inflated and the radius of theballoon is increasing at a rate of 2 cm/s.(A) Express the radius (r) of the balloon as a function of thetime (t).(B) If V is the volume of the balloon as a function of theradius, find Vor and interpret it.
Answer:
A.) r = 2t
B.) V = 33.5t^3
Explanation:
Given that a spherical balloon is being inflated and the radius of the balloon is increasing at a rate of 2 cm/s
A) Express the radius (r) of the balloon as a function of the time (t).
Since the rate = 2 cm/s that is,
Rate = radius/ time
Therefore,
2 = r/t
Make r the subject of formula
r = 2t
(B) If V is the volume of the balloon as a function of the radius, find V or and interpret it.
Let assume that the balloon is spherical. Volume of a sphere is;
V = 4/3πr^3
Substitute r = 2t into the formula
V = 4/3π(2t)^3
V = 4/3π × 8t^3
V = 32/3 × πt^3
V = 33.5t^3
Graphs are ____ of relationships.
Answer:
Diagrammatic representation
How can shoe and tire marks be preserved in mud?
es )
A)
casting
B)
dusting
fluorescence
D)
printing
In her dissertation research, a graduate student finds a correlation of +0.95 between two of the variables being studied. How should she interpret this correlation coefficient
Answer:
Explanation:
A correlation of +0.95 between two variables signifies a strong positive relationship between the two measured variables (the dependent and independent). The value is usylay called the correlation Coefficient (r) as it measures the level or degree of relationship or correlation between two measured linear variables. The value ranges between - 1 and +1 with + signifying a positive relationship (increase or decrease in one variable leads to corresponding increase or decrease in the other) while a negative correlation means (a decrease in A leads to increase in B and vice versa). A correlation Coefficient of 0 means no relationship and the strength of the relationship increases as the value approaches - 1 or +1.
9. Carlos jumps out of a hovering helicopter. After he opens his parachute, his acceleration due to gravity decreases
to zero. This is because
A The force of air resistance becomes equal in magnitude to his weight.
B. The force of gravity has become zero.
C. Air resistance must be zero
D. He must have struck the ground,
Answer:
A The force of air resistance becomes equal in magnitude to his weight.
Explanation:
When Carlos jumped out of the helicopter, he fell with a downward force which is proportional to his weight.
His weight is the product of his mass and acceleration due to gravity.
When the parachute is deployed, air resistance between the air molecules and the surface area of the parachute generates a drag force, which acts upwards.
If the drag forces exceeds his weight, then his net force will be directed upwards.
If his weight exceeds the drag forces, then the net force on his body will be downwards.
In the case that his drag force, and his weight are equal, there will be a zero net force on him, and he will experience no acceleration.
So, if after he opens his parachute, his acceleration due to gravity decreases to zero, then we can say that this is because the force of air resistance (drag) becomes equal in magnitude to his weight.