please answer right please

Please Answer Right Please

Answers

Answer 1

Answer:

i think its A

Explanation:

I hope this helps :)


Related Questions

using the methos of dimensions derive an expression for the centripetal force f acting on a particle of mass m mivingv with velocity v in a circle of radius r? ​

Answers

Answer:

According to the Question:

[tex]\footnotesize\implies F \propto [m]^x [v]^y [r]^z[/tex]

[tex]\footnotesize\implies F =k [m]^x [v]^y [r]^z \:...(i)[/tex]

K = Dimensionless Constant

Now, substituting Dimensions of each physical quantity in equation (I):

[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M^1L^0T^0]^x [M^0L^1T^{-1}]^y [M^0L^1T^0]^z[/tex]

[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M]^x [L]^{y + z} [T]^{ - y}[/tex]

On comparing the powers of LHS and RHS:

[tex]\implies \bf x = 1[/tex]

[tex]\implies - y = - 2[/tex]

[tex] \implies \bf y = 2[/tex]

[tex]\implies y + z = 1[/tex]

[tex]\implies z = 1 - 2[/tex]

[tex]\implies \bf z = - 1[/tex]

[tex]\footnotesize\implies F = [m]^x [v]^y [r]^z[/tex]

[tex]\footnotesize\implies F = [m]^1 [v]^2 [r]^{ - 1}[/tex]

[tex]\implies\footnotesize \underline{ \boxed{ \bf \red{ F = \frac{m {v}^{2} }{r} }}}[/tex]

An escalator in a busy shopping centre lifts people up from one floor to another. This takes 1.2 MJ every minute. What is the power output of the escalator motor? Give your answer in kW.

Answers

An escalator that takes 1.2 MJ every minute has a power output of 1200 kW.

An escalator used to lift people up from one floor to another, exerts a work (w) of 1.2 MJ in 1 minute (t).

In physics, power (P) is the amount of energy (w) transferred or converted per unit time (t).

[tex]P = \frac{w}{t} = \frac{1.2 \times 10^{6} J }{1min} = 1.2 \times 10^{6} W[/tex]

We can convert 1.2 × 10⁶ W to kW using the conversion factor 1 kW = 1000 W.

[tex]1.2 \times 10^{6} W \times \frac{1kW}{1000W} = 1200kW[/tex]

An escalator that takes 1.2 MJ every minute has a power output of 1200 kW.

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State a hypothesis about your estimated daily water use.

Answers

Answer

Estimates vary, but, on average, each person uses about 80-100 gallons of water per day, for indoor home uses.

Explanation:

NO LINKS! What are the definitions of initial horizontal velocity and initial vertical velocity? Please help! This like is my 10th time asking this question because many people have been scamming me...

Answers

Answer:

Additionally, the initial horizontal velocity may be calculated by measuring the diameter d of the ball and dividing the result by the amount of time t required for the ball to pass across the photogate. Vo = d/t is the formula.

Initial vertical velocity is the vertical component of the initial velocity: v 0 y = sin 0 sin 0 = (30.0 m/s) sin 45° = 21.2 m/s

Explanation:

Hope it helps:)

In fish BB-blue, BW-blue with white stripes, WW-white. Cross a white fish with a fish with blue and white stripes. What is the probability of having white fish offspring?

Answers

Answer: Juvenile fish go through various stages between birth and adulthood. When they have developed to the point where they are capable of feeding themselves, the fish are called fry. When, in addition, they have developed scales and working fins, the transition to a juvenile fish is complete and it is called a fingerling.

An object weighs 15 N in air and 13 N when submerged in mineral spirits, which has a density of 788 kg/m3. Determine the density of the object

Answers

The density of the object is 5911.94 kg/m³

An object's buoyancy is the upward force produced by a fluid in opposition to the weight of a partly or totally submerged object.

The buoyancy = weight of the object - weight in water

= 15 N - 13N

= 2 N

The buoyancy force can also be determined by using the expressed:

[tex]\mathbf{F_B = Volume (V) \times density ( \rho) \times g}[/tex]

[tex]\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }[/tex]

[tex]\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}[/tex]

volume (v) = 2.589 × 10⁻⁴m³

Recall that:

The mass of an object can be estimated by using the formula:

Weight = mass × gravity

mass = Weight / gravity

mass = 15/9.8

mass = 1.5306 kg

The density of the object can now be calculated using the relation

Density = mass/volume

Density = 1.5306 kg / 2.589 × 10⁻⁴m³

Density = 5911.94 kg/m³

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A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Answers

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

[tex]dl'=3.621*10^{-4}m[/tex]

From the question we are told

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Generally the equation for copper cylinder   is mathematically given as

[tex]dl=\frac{Flo}{yA}[/tex]

[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=1.19064778*10^-^4[/tex]

Generally the equation for brass cylinder   is mathematically given as

[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=2.43*10^{-4}[/tex]

Therefore Total change in length

[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]

[tex]dl'=3.621*10^{-4}m[/tex]

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The rate at which work is done is called

a. efficiency

b. effort time

c.

force

d. power

Please select the best answer from the choices provided

Ο Α

ОВ

ОС

Answers

Answer:

The rate at which work is done is power

A girl pushes her little brother on his sled with a force of 300 N for 750 m.

Answers

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

A car weighs 14500 N. What is its mass?

Answers

Answer:

w = mg

14500 = m ×10 [g=10m/s2]

m =14500/10

m=1450kg

weight of 1 kg becomes 1/6 on moon. If radius of moon is 1.76×10^6 m, then the mass of moon will be​

Answers

Answer:

7.65 x 10^22kg

sorry if im wrong!

What is the centripetal force acting on a 1.5 kg mass moving in a circular path with a centripetal
acceleration of 18 m/s2

Answers

The centripetal force acting on a 1.5 kg mass moving in a circular path is 27N

A centripetal force is a net force acting on an object in order to maintain the object's movement in a circular motion.

According  to Newton's first law, it states an object will continue to proceed its movement in a straight line unless acted upon by an external force.

The centripetal force is the external force at work here and  It's the net force that propels the object in a circular motion.

Using the formula for calculating centripetal force:

[tex]\mathbf{F_c = mass (m) \times acceleration (a)}[/tex]

[tex]\mathbf{F_c = 1.5 \ kg \times18 \ m/s^2}[/tex]

[tex]\mathbf{F_c = 27 \ N}[/tex]

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If force F, volume V and density D are taken as fundamental quantities, then the representation of pressure P will be​

Answers

Using the principle of dimensional analysis, the representation of Pressure would be [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

Pressure is related to Force, Volume and Density thus :

[tex] Pressure, P = F^{a}V^{b}D^{c}[/tex]

Using dimensional analysis :

Pressure, P = ML¯¹T¯²

Substituting the dimension into the relation :

[tex] ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} [/tex]

[tex] ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} [/tex]

Equating the power ;

a + c = 1 - - - (1)

a + 3b - 3c = - 1 - - - (2)

-2a = - 2

a = - 2/-2

a = 1

From (1)

1 + c = 1

c = 1 - 1 = 0

c = 0

From (2) :

1 + 3b - 3(0) = - 1

1 + 3b = - 1

3b = - 2

b = - 2/3

Hence, [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

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The representation of pressure is:

[tex]P=FV^{-\frac{2}{3} }[/tex]

Given that:

Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:

[tex]P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}[/tex]

Hence:-

2 = -2a

a = 1

a + c = 1

1 + c = 1

c = 0

a + 3b - 3c = -1

1 + 3b - 3(0) = -1

3b = -2b = -2/3

Hence the representation of pressure is:

[tex]P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }[/tex]

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In a car race, the average speed of the car was 90 km/hr where the total
covered distance was 450 km.
1. Calculate the average speed of the car in SI unit.

Answers

Explanation:

The speedometer of a motor car showed the following speeds in km per hour at the ends of successive intervals of 3 secs. 38.9, 52.8, 64.4. 73.6, 80.9, 86.1, 90.0, 92.5 Plot the velocity – time graph in convenient units and find from the graph, (a) The distance covered while the speed increased from 80

If 40 N force is exerted by a box covering 2 metre square area, calculate pressure.

Answers

Force=40NArea=2m^2

[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]

[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]

[tex] \sf \huge \red {\dag} Given[/tex]

[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]

[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]

We know that the formula of Pressure is

[tex]\sf \longmapsto \: Force/Area[/tex]

Let's start.

Put the values

[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]

[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]

[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]

Please help :[ Hold a flat piece of paper horizontally. Lift it high in front of you, and drop it. Then crumple a piece of paper into a tight ball, hold it high in front of you, and drop it from the same height. Compare the motion of the two pieces of paper.

Answers

The one you lifted in front of you ( the flat piece of paper being holded horizontally ) goes down so slow. While the one being crumpled into a ball goes down fast. Subscribe to DreamfanBG for support.

Answer:

Answer below

Explanation:

The flat piece of paper just gently glided to the ground, as if it were a feather. It didn’t go down in a straight line, it swayed from side to side. The crumpled piece of paper seemed like it had more weight to it (although I know that it didn’t), and it fell way quicker than the flat piece of paper.

_____________________________________________________

(Hope this helps can I pls have brainlist (crown)☺️)

b. Ron bicycles forward with an acceleration of 2.1 m/s2. If he is applying a forward force of 195 N, what is his mass?

Answers

Answer:

92.86 kg

Explanation:

lThe mass of an object given only it's force and acceleration can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question

f = 195 N

a = 2.1 m/s

We have

[tex]m = \frac{195}{2.1 } = 92.857142... \\ [/tex]

We have the final answer as

92.86 kg

Hope this helps you

Wire coils spinning between two magnets will produce …?



A: cold
B : electricity
C: chemicals
D: Steam

Answers

Answer:

B

Explanation:

I don't know but its b

The answer is B.

Magnetic fields can be used to make electricity
Moving a magnet around a coil of wire, or moving a coil of wire around a magnet, pushes the electrons in the wire and creates an electrical current. Electricity generators essentially convert kinetic energy (the energy of motion) into electrical energy.

In a hydraulic press a force of 200N is applied to a master piston of area 25Cm2.if the press produces 500N determine the area of the piston.​

Answers

Answer:

625                                      GIVE ME BRAINLIEST ANSWER PLEASE

Explanation:

This question is based on pascal's Law.

So By Pascal's Law

=

therefore  =force on input piston =200N

                 = Force on output piston = 5000N

therefore after putting the values we get,

a)  = (25x 5000)/200

    = 625

b) area of the salve piston =  = 625

so  = 625/3.14 = 199

so     r =    = 14.10 cm

Two 4 kg blocks hang from a rope that passes over two frictionless pulleys . What is the tension in the horizontal portion of the rope if the blocks are not moving and the rope and the two pulleys have negligible mass?

Answers

The tension in the horizontal portion of the rope provided the blocks are not moving and the rope has negligible mass is 40 N

The tension in the rope is a pulling force that acts on the rope when the mass of 4kg is placed on each side of the two frictionless pulley.

According to Newton's second Law;

Force = (Tension) = mass × acceleration due to gravity

We can say:

Tension = 4kg × 9.81 m/s²

Tension = 39.24 N

Tension = 40 N (to the nearest whole number)

Therefore, we can conclude that the tension in the horizontal portion of the rope is 40 N

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Guys plz i need those answers as soon as possible

Answers

9) a) formula = h(ρ)g by default g=9.8m/s²

Pressure = 2×1000×9.8 = 19600Pa

b)

Dark matter is inferred to exist because it explains the abundance of helium in the universe today. we can observe its gravitational influence on visible matter. it explains how the expansion of the universe can be accelerating. we see lots of dark patches in the sky

Answers

we can observe its gravitational influence on visible matter.

Dark matter is a term used in astrophysics to refer to matter that corresponds to approximately 80% of the matter in the universe.

Dark matter is related to the motion of galaxies because visible matter makes up only a small part of the cluster and the galaxies show signs of being composed mainly of a halo of dark matter concentrated in their center.

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What is the difference between a low tide and a high tide

Answers

A high tide means when the water has risen and is higher up(closer to high up land). Low tide is when it’s receded

Answer:

High water level during a tide is called High tide.

Low water level during a tide is called Low tide.

Of the Three elements listed, which element is NOT present in the mixture?

Element D
Element A
Element Z

Answers

Answer:

element ammmkkkv was a very good

A state government wants to increase the taxes on cigarettes to increase tax revenue. Because cigarettes are addictive, we would expect its demand to be: ______________

a. Elastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
b. Elastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
c. Inelastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
d. Inelastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.

Answers

The demand of cigarette is elastic so the government's cigarette-tax revenues would rise with a tax increase.

The demand of cigarette is elastic because of the addiction the people can buy the cigarette even at high prices and the government's cigarette-tax revenues would rise.

The demand for cigarettes is unitary elastic (−1.06) means that a 1% increase in the price of cigarette would reduce its consumption by 1.06% so we can conclude that the demand of the cigarette is elastic and the government revenues increases.

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A mass of 5.00 kg in a gravitational field of 7.00 n/kg. What force acts on the mass?

Answers

Answer:

35N

Explanation:

force=mass×gravity

the mass is 5 and the gravity is 7 therefore:

force=7×5

=35N

I hope this helps

What is thermal energy.

Answers

Explanation:

thermal energy refers to the energy contained within a system that is responsible for its temperature. Heat the flow of thermal energy

The term 'thermal energy' is used differently, and often loosely, in different contexts. It refers to several distinct physical concepts, such as the internal energy, or as the enthalpy, of a body of matter and radiation; or as heat, defined as a type of energy transfer (as is thermodynamic work); or as the characteristic energy of a degree of freedom,
k
B
T
{\displaystyle k_{\mathrm {B} }T}, in a system that is described in terms of its microscopic particulate constituents, where
T
T denotes temperature and
k
B
k_{\mathrm{B}} denotes the Boltzmann constant.

I learned this last week in my Sci-tech class!

A 30 kg boy stands on rough horizontal ground. The coefficient of
static friction,
us is 0.8. The present static friction between the boy and the ground is
?

Answers

Answer:

0n

Explanation:

given. force of 88N and an acceleration of 4 m/s 2 what is the mass?

Answers

Mass, m=22 kg
It is given that Force, F = 88N
Acceleration, a=4 m/s 2

If the acceleration of an object increases, what effect does this have on the Force and Mass?
A Force Increases, Mass Increases
B Force Decreases, Mass Decreases
C Force increases, Mass remains the same
D Force Decreases, Mass remains the same​

Answers

Answer:

Force Increases and Mass remains the same.

Explanation:

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