Please help 23 also 29 the answer choices are reflection or refraction your fraction absorption

Answer:

zhvshshisvdiscdoscd if vdidg

Answer:

50000 μT

Explanation:

From the given information:

the diameter of the loop = 1.0 mm = 0.001 m

no of turns (N) = 200

current (I) = 0.199 A

radius = d/2 = 0.001/2

= 5 × 10⁻⁴ m

Recall that;

the magnetic field at the centre of circular wire is:

[tex]= \dfrac{\mu I N}{2R}[/tex]

[tex]= \dfrac{4 \pi \times 10^{-7} \times 200 \times0.199}{2\times 5\times 10^{-4}}[/tex]

= 0.05 T

= 50000 μT

Since the centre of the earth's magnetic field is given to be equal to the magnetic field produced by the wire, then:

the earth's magnetic field = 50000 μT

I

think

Answer:

is.......

it has several other objects in its original, though few are as massive as itself........

Answer:

my teachers have always taught me that a dwarf planet cannot have other objects in its orbit seeing that the gravitational force will make it collide with the planet or push it out of the orbit. hope it helps xx

Answer:

     cos to = $ 24

Explanation:

When replacing the bulb only 25% of the energy is used, therefore

          W = 0.25 100

          W = 25 W

Let's look for the energy in the life of the bulb

          E = 25 10⁻³ 12000

          E = 300 Kwh

now we can calculate the cost using a direct proportion rule.

          Cost = 0.08 300

          cos to = $ 24

Answer:

a)speed of light.

a)speed of light×time=distance.

Explanation:

light has a constant speed of 299,792,458m/s

This distance is analyzed quantitatively by LIDAR (Light Detection And Ranging) stations, which bounce laser pulses off the retroreflecting mirrors installed on the Moon by the Apollo astronauts.

Lidar is a method of determining ranges that involves using a laser to target an object or a surface and measuring the time it takes for the reflected light to return to the receiver.

LiDAR is a type of remote sensing technology. LiDAR technology collects measurements by using a laser pulse. These are employed in the production of 3D models and maps of objects and environments.

Lidar, which stands for light detection and ranging, has been around for quite some time. It employs lasers to ping off objects and return to the laser source, measuring distance by timing the travel, or flight, of a light pulse.

LIDAR (Light Detection And Ranging) stations analyze this distance quantitatively by bouncing laser pulses off the retroreflecting mirrors installed on the Moon by the Apollo astronauts.

Thus, this way, the distance can be calculated.

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Answer:

Prototype

Explanation:

It's correct on Edge

The first version of a product, which is built and tested during the third stage of technological design, is called a​ prototype

There are mainly five stages of the technological design

Identifying the issue that needs to be solved is the first step in every problem-solving process.

The second stage is to imagine; during this phase, a designer would generate several concepts and conduct research on potential creations. They must pick a handful of their greatest concepts and then narrow it down to the best.

The third stage plans the imaging stage's selected product. In this process, the product is designed and drawn in order to be made into a model or prototype while taking into account the limitations that must be overcome.

The fourth step entails assessing, testing, and revising the final product. By creating a model or prototype of their product, the designer may decide what they like and what they could modify. This is found through product testing. If changes are necessary, the designer will go through the process again until they are happy with the outcome.

The fifth step is to share your solution. You present your solution to get feedback, exchange ideas with others, and improve your product. After you've gone through the design process a few times, you might decide to reveal your response to a larger audience in later phases. Similar modifications are made to homework by World of Inquiry students before they deliver it during an excursion.

Thus,a prototype is the initial iteration of a product that is constructed and tested during the third stage of technological design.

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Answer:

please give me brainlist and follow

Explanation:

Infrared radiation

The infrared part of the electromagnetic spectrum covers the range from roughly 300 GHz to 400 THz (1 mm – 750 nm). It can be divided into three parts: Far-infrared, from 300 GHz to 30 THz (1 mm – 10 μm). The lower part of this range may also be called microwaves or terahertz waves.

Answer:

a. f < M < T

Explanation:

Let us take the right direction as positive.

Since Ted exerts a force T to the right his force is +T, Mario exerts a force M to the left, his force is -M. It is also given that Mario's force is half of Ted's force, so M = T/2. Finally, the frictional force , f is to the left, so it is -f. Let the net force be F and it is to the right since the box moves to the right.

So, +T - M - f = +F

Substituting M = T/2, we have

+ T -T/2 - f = F

+ T/2 - f = F

+T/2 = F + f

So, T = 2(F + f) and

M = T/2 = F + f

Since T = 2(F +f) = 2M, It follows that T > M

Also, since M = F + f, it follows that M > f

So, T > M > f ⇒ f < M < T

So, the answer is a.

Answer:

[tex]N_a=1.8*10^{-6}kg/sm^2[/tex]

Explanation:

From the question we are told that:

Thickness of plastic membrane [tex]L_t=0.3mm[/tex]

The temperature of hydrogen [tex]T_h=25 \textdegree C[/tex]

Diffusion coefficient of hydrogen in the plastic [tex]25 \textdegree C \mu=9*10-8m2/s[/tex]

The solubility of hydrogen in the plastic membrane [tex]\+x=1.5*10{-3} kmol/m3[/tex]

Generally the equation for molar conc is mathematically given by

[tex]CA_1=x*bar[/tex]

3bars

[tex]CA_1=1.5*10^{-3}*3[/tex]

[tex]CA_1=4.5*10^{-3}kmol/m^3[/tex]

1bar

[tex]CA_1=1.5*10^{-3}*1[/tex]

[tex]CA_1=1.5*10^{-3}kmol/m^3[/tex]

Generally the equation for molar diffusion flux of Hydrogen N_a is mathematically given by

[tex]N_a=\frac{D{AB}}{\L}(CA_1-CA_2)[/tex]

[tex]N_a=\frac{9*10^{-8}}{0.3*10^-^3} (4.5*10^{-3}-1.5*10^{-3})kmoi/m^-3[/tex]

[tex]N_a=9.*10^{-7}kmol/sm^2*2kh/kmole[/tex]

[tex]N_a=1.8*10^{-6}kg/sm^2[/tex]

Answer:

Streptococcus Pyogenes

Explanation:

Strep throat!

Answer:

I think it would be V=g/t

Answer:

The frequency increases by a factor of 3.

Explanation:

The relation between speed, wavelength and frequency of a wave is given by :

[tex]v=f\lambda[/tex]

or

[tex]f\propto \dfrac{1}{\lambda}[/tex]

A wave travels at a constant speed. If the wavelength is reduced by a factor of 3, it would mean that the frequency increases by a factor of 3 because there is an inverse relationship between wavelength and frequency.

Answer:

1) 0.01(1500) = 0.05F

F = 300 N

2) 2000/125 = 16

3) 100(800/2400) = 33.3%

4) 2000/15 = 133 N

Explanation:

Answer:

The answer "[tex]E_{red1} < E_{blue1}[/tex] can include that is  [tex]L_{red} > L_{blue}[/tex]".

Explanation:

In this scenario, when we take the expression [tex]E_n =\frac{1}{2m}(\frac{hn}{2L})^2[/tex]  that is the energy of the inversely  proportional to the length of the box. because[tex]E_{red1} < E_{blue1}[/tex] it could be include  that is [tex]E_{red1} < E_{blue1}[/tex]  because [tex]E_{red1} < E_{blue1}[/tex] which can include [tex]E_{red1} < E_{blue1}[/tex].

Explanation:

Net force on the car= mass of the car × acceleration

F=1×10^3×4.5

=4.5×10^3 N

Answer:

Answer:

the  wavelength of the interfering waves for this mode is 2.4168

Explanation:

The computation of the wavelength of the interfering waves for this mode is shown below:

Given that

The length is 7.25m

And, the number of nodes is 6

So, the wavelength should be

= 2 × 7.25m ÷ 6

= 2.4168 m

Hence, the  wavelength of the interfering waves for this mode is 2.4168

The same would be considered

Answer:

The maximum height above its initial position is:

[tex]h_{max}=1.53\: m[/tex]

Explanation:

Using momentum conservation:

[tex]m_{b}v_{ib}=m_{B}v_{fB}+m_{b}v_{fb}[/tex] (1)

Where:

Let's find v(fb) using equation (1)

[tex]m_{b}(v_{ib}-v_{fb})=m_{B}v_{fB}[/tex]

[tex]v_{fB}=\frac{m_{b}(v_{ib}-v_{fb})}{m_{B}}[/tex]

[tex]v_{fB}=\frac{0.1(900-300)}{2}[/tex]

[tex]v_{fB}=30\: m/s[/tex]

We need to find the maximum height, it means that all kinetic energy converts into gravitational potential energy.

[tex]\frac{1}{2}m_{B}v_{fB}=m_{B}gh_{max}[/tex]

[tex]h_{max}=\frac{1}{2g}v_{fB}[/tex]

[tex]h_{max}=\frac{1}{2(9.81)}30[/tex]

[tex]h_{max}=1.53\: m[/tex]

I hope it helps you!

The maximum height above its initial position is:  [tex]h_{max}[/tex]=1.53m

Simple harmonic motion is the periodic motion or back and forth motion of any object with respect to its equilibrium or mean position. The restoring force is always acting on the object which try to bring it to the equilibrium.

Using momentum conservation:

[tex]m_bv_{1b}=m_Bv_{fB}+m_bv_{fb}[/tex]

Where:

m(b) is the mass of the bullet

m(B) is the mass of the block

v(ib) is the initial velocity of the bullet

v(fb) is the final velocity of the bullet

v(fB) is the final velocity of the block

Now for finding the value of final velocity VfB

[tex]m_b(v_{1b}-v_{fb})=m_Bv_{fB}[/tex]

[tex]v_{fB}=\dfrac{m_b(v_{1b}-v_{fb})}{m_B}[/tex]

[tex]v_{fB}=\dfrac{0.1(900-{300})}{2}[/tex]

[tex]v_{fB}=30\ \frac{m}{s}[/tex]

We need to find the maximum height, it means that all kinetic energy converts into gravitational potential energy.

[tex]\dfrac{1}{2}m_Bv_{fB}=m_Bv_{fB}[/tex]

[tex]h_{max}=\dfrac{v_{fB}}{2g}[/tex]

[tex]h_{max}=\dfrac{30}{2\times 9.81}[/tex]

[tex]h_{max}=1.53\ m[/tex]

Thus the maximum height above its initial position is:  [tex]h_{max}[/tex]=1.53m

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Answer:

The correct answer is:

(a) [tex]3.31\times 10^{10} \ \omega/m^2[/tex]

(b) [tex]5\times 10^6 \ N/C[/tex]

Explanation:

The given values are:

Power of Laser beam,

= 10 mW

on converting it, we get

= [tex]10\times 10^{-3} \ \omega[/tex]

= [tex]10^{-2} \ \omega[/tex]

Spot's diameter,

= 0.62 μm

= [tex]0.62\times 10^{-6} \ m[/tex]

Now,

(a)

The intensity of light will be:

⇒ [tex]I=\frac{P}{\pi r^2}[/tex]

or,

⇒    [tex]=\frac{4P}{\pi d^2}[/tex]

On substituting the values, we get

⇒    [tex]=\frac{4\times 10^{-2}}{\pi(0.62)^2\times 10^{-12}}[/tex]

⇒    [tex]=3.31\times 10^{10} \ \omega/m^2[/tex]

(b)

The amplitude of electric field will be:

⇒ [tex]I=\frac{1}{2}\epsilon_0E_0.C[/tex]

or,

⇒ [tex]E_0=\sqrt{\frac{2I}{CE_0} }[/tex]

On substituting the values, we get

⇒       [tex]=\sqrt{\frac{3.31\times 10^{10}\times 2}{3\times 10^8\times 8.85\times 10^{-12}} }[/tex]

⇒       [tex]=5\times 10^6 \ V/m[/tex]

Answer:

The loss in rotational kinetic energy due to the collision is 36.585 J.

Explanation:

Given;

mass of the disk, m₁ = 1.64 kg

radius of the disk, r = 0. 61 m

angular velocity of the disk, ω₁ = 17.6 rad/s

mass of the rod, m₂ = 1.51 kg

length of the rod, L = 1.79 m

angular velocity of the rod, ω₂ =  5.12 rad/s (clock-wise)

let the counter-clockwise be the positive direction

let the clock-wise be the negative direction

The common final velocity of the two systems after the collision is calculated by applying principle of conservation of angular momentum ;

m₁ω₁  + m₂ω₂ = ωf(m₁ + m₂)

where;

ωf is the common final angular velocity

1.64 x 17.6    + 1.51(-5.12) = ωf(1.64 + 1.51)

21.1328 = ωf(3.15)

ωf = 21.1328 / 3.15

ωf = 6.709 rad/s

The moment of inertia of the disk is calculated as follows;

[tex]I_{disk} = \frac{1}{2} mr^2\\\\I_{disk} = \frac{1}{2} (1.64)(0.61)^2\\\\I_{disk} = 0.305 \ kgm^2[/tex]

The moment of inertia of the rod about its center is calculated as follows;

[tex]I_{rod} = \frac{1}{12} mL^2\\\\I_{rod} = \frac{1}{12} \times 1.51 \times 1.79^2\\\\I _{rod }= 0.4032\ kgm^2[/tex]

The initial rotational kinetic energy of the disk and rod;

[tex]K.E_i = \frac{1}{2} I_{disk}\omega _1 ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _2 ^2 \\\\K.E_i= \frac{1}{2} (0.305)(17.6) ^2 \ \ + \ \ \frac{1}{2} (0.4032)(-5.12) ^2\\\\K.E_i = 52.523 \ J[/tex]

The final rotational kinetic energy of the disk-rod system is calculated as follows;

[tex]K.E_f = \frac{1}{2} I_{disk}\omega _f ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _f ^2\\\\K.E_f = \frac{1}{2} \omega _f ^2(I_{disk} + I_{rod})\\\\K.E_f = \frac{1}{2} (6.709) ^2(0.305+ 0.4032)\\\\K.E_f = 15.938 \ J[/tex]

The loss in rotational kinetic energy due to the collision is calculated as follows;

[tex]\Delta K.E = K.E_f \ - \ K.E_i\\\\\Delta K.E = 15.938 J \ - \ 52.523 J\\\\\Delta K.E = - 36.585 \ J[/tex]

Therefore, the loss in rotational kinetic energy due to the collision is 36.585 J.

Answer:

1. k

2. t

3. k

4. k

5. k

6. k

7. k

8. k

9. k

10. k

I'm not sure but hope it helps:)

Answer:

C

D

Explanation:

Explanation:

F = ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

...

Answer:

Protons have positive charge

Electrons have negative charge

Neutrons have no charge

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weight is vector vary from place to place

Answer:

The difference between mass and weight is that mass is the amount of matter in a material, while weight is a measure of how the force of gravity acts upon that mass.

Explanation:

Mass is the measure of the amount of matter in a body. Mass is denoted using m or M. ... Weight is mass multiplied by the acceleration of gravity (g).

Answer: I am pretty sure it is (b) what is the value of mass suspended at the end of the spring.

Explanation:

Answer:

principal stresses :б1 = 32.62mPa  б2 = 31.38mPa

Max Shear stress : 16.31 mPa

Orientation of max principle plane = 44.43°

Orientation of minimum principal plane = 134.43°

Explanation:

Given data:

Torque = 50 N-m

weight = 80 kgs

half of weight is subjected to each leg

radius of bone = 10 mm = 0.010 m

a) Determine the principal stresses and shear stress

first calculate the max shear stress ( this will occur in the outermost element

= 16T / π*d^3   where : T = 50 , d = 0.020 m

hence max shear stress = 32 mPa

next determine compressive stress

= ( 40*g)  / π/4*d^2 . where : d = 0.020 m , g = 9.81

hence compressive stress = 1.24 mPa

draw and calculate the radius of Mohr's circle

radius of Mohr's circle = 32.0060

Hence principal stresses = 32.0060 ± 0.62

б1 = 32.62mPa  

б2 = 31.38mPa

attached below is the remaining part of the solution