PLEASE HELP a current of 0.5 A flows with a resistance of 50 ohms what is the e.m.f applied NEED HELP ASAP AND BRAINLIEST​

Answer:

One possible explanation students can make: The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.

Answer:

0.24 A

Explanation:

Voltage is given by the equation :

V = I × R

Voltage = Current × Resistance

Rearrange to make Current/I the subject :

18 = I × 75

I = 18÷75

I = 0.24 A

Hope this helped and brainliest please

Answer:

[tex]\huge\boxed{\sf 1.6\ units = 14.4p}[/tex]

Explanation:

Since,

So,

1.6 kWh = 1.6 units

If,

1.6 units = 9p × 1.6

1.6 units = 14.4p

[tex]\rule[225]{225}{2}[/tex]

Answer:

metal, non, metal, metal, non, non, metal, non

Explanation:

knowledge

Time for which the wagon is pushed before it speed reaches 10m/s from rest.

The momentum is the product of mass of an object and its velocity.

Let the impact force is applied for time t. The impulse is equal to the change in momentum.

F.t = m(Vf -Vi)

where Vf =10 m/s, Vi =0 m/s, m =20kg and F =200N, then time for the force applied will be

200 x t = 20 x (10)

t =1s

Thus, the time for which the wagon is pushed before it speed reaches 10m/s from rest is 1s.

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Answer:

ma+mgsinh0​+f=F∴(25)(0.75)+(25)(10)sinh0​+μk​N=F∴18.75+(250)(0.6h)+μk​(mgcosh0​=F⟹18.75+150+μk​((25)(10)(0.76))=500∴168.75+μk​(190)=500⟹μk​(190)=331.25⟹μk​=1.74

Explanation:

Answer:

8.16m/s south

Explanation:

North is the negative direction.

60kg*(-5m/s)+79.5kg*v=(79.5kg+60kg)*(2.5m/s)

-300kgm/s+79.5kg*v=348.75kgm/s

79.5kg*v=648.75kgm/s

v=8.16m/s

The two pointy tapes repel. This shows they have the same type of charge.

The attraction of two charges occurs when the two charges have opposite charges.

The repulsion of two charges occurs when the two charges have similar charges.

Thus, since the two pointy tapes will have the same charge, we can conclude that they will repel each other when brought near each other.

The complete question is below:

How did the pointy tapes behave when brought near each other, and what does this demonstrate about their charges?

Two pointy tapes repel. This shows they have opposite types of charge.

Two pointy tapes attract. This shows they have opposite types of charge.    

Two pointy tapes repel. This shows they have the same type of charge.

Two pointy tapes attract. This shows they have the same type of charge.

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Hi! digital forensics is important because not only does digital forensics allow cyber security organisations to develop technologies that can prevent hackers from accessing devices, websites and networks but can lead businesses in the direction of understanding exactly what data is compromised.

Friction can only occur between solids, liquids and gas.

Friction can be defined as the force that a moving object encounters when sliding over a surface.

The various phases of matter include solid, liquid and gases and friction occurs in all the three phases of matter.

Therefore, Friction can only occur between solids, liquids and gas.

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Based on the calculations, it would take 7.5 seconds before the final velocity of this object would be equal to three times its initial velocity.

Given the following data:

Mathematically, acceleration can be calculated by using the first equation of motion:

v = u + at

Where:  

Making t the subject of formula, we have:

t = (v - u)/a

Substituting the given parameters into the formula, we have:

t = (45 - 15)/4

t = 30/4

t = 7.5 seconds.

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Answer:

Kinetic energy

Explanation:

You are working for a manufacturing company, which is mathematically given as

a)

Generally, the equation for the force of equilibrium is mathematically given as

F=2fcos\theta

Therefore

[tex]K(npq^2/a^2)=2\frac{kmpq^2}{a\sqrt{2}^2}0.5\\\\np=mP/ \sqrt{2}\\\\where n=3[/tex]

[tex]m=3\sqrt{2}[/tex]

b)

By force equilibrium

[tex]K(npq^2/(2a^2))=2*\frac{kmpq^2}{a\sqrt{5a}^2}* \frac{2a}{\sart{5a}}[/tex]

Therefore

[tex]n/4=2/5*m*2/\sqrt{5}\\\\m= \frac{5\sqrt{5}}{16}\\\\\\\\[/tex]

[tex]m=\frac{15\sqrt{5}}{16}[/tex]

c)

[tex]K(npq^2/x^2)=2\frac{kmpq^2}{a\sqrt{x^2+a^2}^2}0.5*x/\sqrt{x^2+a^2}[/tex]

x^2+a^2=(14/3)^{2/3}x^2

x=a/1.338

x=0.747a

d)

By force equilibrium

[tex]K(npq^2/x^2)=2\frac{kmpq^2n}{\sqrt{x^2+a^{3/2}}^2}\\\\n/x^2=\frac{2mx}{(x^2+a^2)^{3/2}}[/tex]

[tex]m/n=\frac{(x^2+a^2)3/2}{x^3}[/tex]

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Answer:

A 0.88

Explanation:

frequency=1/period

=1/1.13=0.88

The amount of force required to accelerate the given mass of the wagon is 129 Newtons.

A force is simply referred to as either a push or pull of an object resulting from the object's interaction with another object.

From Newton's Second Law, force is expressed as;

F = m × a

Where is mass of object and a is the acceleration.

Given the data in the question;

F = 8.6kg × 15m/s²

F = 129kgm/s²

F = 129N

Therefore the amount of force required to accelerate the given mass of the wagon is 129 Newtons.

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Answer:

D. Poison

Explanation:

Hi there!

We can use the following relationship between the Potential Difference and the Electric field:

[tex]V = E d[/tex]

V = Potential Difference (500V)
E = Electric Field (V/m)
d = separation between plates (0.2 m)

We can rearrange the equation to solve for the electric field:
[tex]E = \frac{V}{d}\\\\[/tex]

Plug in the given values.

[tex]E = \frac{500}{0.2} = \boxed{2500 \frac{V}{m}}[/tex]

Answer:

resolution

Explanation:

  That is the definition of resolution

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

A person taking the charge of the organization and leading a team under him is known as a leader.

"The complete question is"Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate _______________. An employee will display _______________ by adhering to professional standards of the workplace and encouraging co-workers to do the same."

Options:

First Blank: work ethic

First Blank: self-representation

First Blank: diversity awareness

Second Blank: leadership skills

Second Blank: nonverbal skills

Self-representation may be shown through dressing appropriately for diverse settings, speaking politely, and keeping up with personal cleanliness.

By upholding the workplace's ethical norms and encouraging others to do the same, an employee will demonstrate leadership qualities.

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate self-representation.

An employee will display leadership skills by adhering to the professional standards of the workplace and encouraging co-workers to do the same.

Hence, self-representation and leadership skills are the correct answer.

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The speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.

The speed of the car passing you is determined by applying relative velocity principle as shown below;

Vr = Va - Vb

Vr = 26 m/s - 32 m/s

Vr = -6 m/s

Thus, the speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.

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Answer:

Work done =3 joules

Explanation:

1 volt is the same as 1 Coulomb and 1 Joule

V=W/Q

1=W/3

W=3 x 1

W=3 Joules

An object of volume 2.0×10^4cm³ is underwater, the buoyant force of the water on the object  

Fb= 1.962 *10^7N

Generally, the equation for buoyant force   is mathematically given as

Fb = g * p * V

Therefore

Fb=9.81* 2.0*10^4 *1000

Fb= 1.962 *10^7N

In conclusion,  the buoyant force

Fb= 1.962 *10^7N

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Fluid Dynamics is an area of ​​research that started a long time ago, along with Calculus. It combines techniques of Mathematical Analysis and of Dynamical Systems, such as Bifurcation Theory, among others.

Surface Tension is a phenomenon that occurs in all liquids, it is characterized by the formation of a kind of elastic membrane at its ends.

Contact angles in powders can be measured using the sessile drop measurement in the compressed powder or using the force tensiometer with the Washburn method.

In fluid dynamics, the variables of surface tension, viscosity and contact angle are treated. When dealing with viscosity we have  fluid can be viscous or a real fluid. In general, fluids are viscous.

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Hi there!

To solve, we need to find the distance traveled by the proton at which the proton's velocity reaches 0 m/s. This indicates the point at which the repulsive force caused by the line of charge and its consequential acceleration causes the proton to stop for an instant and be repelled back in the opposite direction.

For this, we can use the work-energy theorem to solve.

Recall the following equations:
[tex]W = \Delta KE[/tex]

[tex]W = \int F \cdot dx\\\\KE = \frac{1}{2}mv^2[/tex]

We will integrate along the path from the point 19.0 cm (0.19 m) from the line up to a point 'z' at which the proton has no kinetic energy (v = 0 m/s). This means that the wire will be doing NEGATIVE work on the proton as it is decreasing the proton's kinetic energy.

The equation for a force acting on a charged particle is given as:
[tex]F_E = qE[/tex]

For an infinite line of charge, the electric field is given as:
[tex]E = \frac{2k\lambda}{r}\\\\F_E = \frac{2k\lambda q}{r}[/tex]

**λ = Linear charge density (C/m)

To set up our integral:
[tex]W = \Delta KE = \int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2[/tex]

Integrate using the following natural log rule:
[tex]\int {\frac{1}{r}} \, dr = ln(r) + C[/tex]

[tex]\int\limits^z_{0.19} {\frac{2k\lambda q}{r}} \, dr = -\frac{1}{2}mv^2\\\\2k\lambda q ln(r) \left \| {{z} \atop {0.19}} \right. = -\frac{1}{2}mv^2\\\\2k\lambda q (ln(z) - ln(0.19) = -\frac{1}{2}mv^2\\\\2k\lambda q ln(\frac{z}{0.19}) = -\frac{1}{2}mv^2[/tex]

Now, we can begin solving for 'a'.

Move coefficients to one side:
[tex]ln(\frac{z}{0.19}) = -\frac{mv^2}{4k\lambda q }[/tex]

Take the base 'e' of both sides:
[tex]e^{ln(\frac{z}{0.19})} = e^{-\frac{mv^2}{4k\lambda q }}\\\\\frac{z}{0.19} = e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{mv^2}{4k\lambda q }}\\\\z = (0.19)e^{-\frac{(1.67*10^{-27})(1200^2)}{4(8.99*10^9)(8.00*10^{-12}) (1.6*10^{-19}) }}\\\\\boxed{z = 0.1803 m= 18.03 cm}[/tex]

It will reach a distance 18.03 cm from the wire before it temporarily loses all of its kinetic energy (at rest) and begins to speed up in the opposite direction.

Answer: A heat engine uses temperature differences which cause pressure changes to exert force on a moving part. A Carnot Process is a theoretical explanation of a process involving pressure and temperature changes during ,amongst other things, phase changes.

Explanation:

Answer: The difference is a heat engine uses temperature differences which cause pressure changes to exert force on a moving part, A Carnot engine is only a theoretical explanation of a process involving pressure and temperature changes during or amongst other things.

Explanation:

T he role of oxygen in air supply is to keep all the ling beings live and healthy.

Oxygen is the most important gas required for the living of human beings, animals, birds and the whole ecosystem.

Oxygen is fundamental for breath on the grounds that the body utilizes it to 'consume' food atoms. Creatures take in oxygen while breathing in and radiate carbon dioxide while breathing out. Oxygen makes up practically 21% of the all out gases in air, with the majority of the excess gas being physiologically latent nitrogen.

Oxygen assumes a basic part in breath, the energy-delivering science that drives the digestion systems of most living things. We people, alongside numerous different animals, need oxygen in the air we inhale to remain alive. Oxygen is created during photosynthesis by plants and many sorts of organisms.

Thus, the air supply needs oxygen on the majority.

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Looking out from a vertex with angle θ, sin(θ) is the ratio of the opposite side to the hypotenuse , while cos(θ) is the ratio of the adjacent side to the hypotenuse . No matter the size of the triangle, the values of sin(θ) and cos(θ) are the same for a given θ, as illustrated below.

From Hooke's law, the force constant of the wire is 3.0 * 10^5 N/m while the Young Modulus is  6.4 * 10^7 .

According to Hooke's law, the force is directly proportional to the extension of the wire.

Given that;

F = Ke

F = 240N

e = 0.8 mm or 0.0008m

K = F/e

K = 240N/0.0008m

K = 3.0 * 10^5 N/m

Now;

Young Modulus = 240N/(3.14 * (1.5 * 10^-3)^2)/0.0008m/1.5 * 10^-3

= 6.4 * 10^7

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Answer:

The best reason for the increased risk of cardiovascular diseases in women after menopause is the significant decrease in the levels of Estrogen in the body.

Detailed answer: