PLEASE HELP DUE TODAY

Answer:

44

Step-by-step explanation:

Answer:

just count how many shapes like the front triangle is one face

Answer:

2 triangle faces, 3 rectangle faces. Thank me later

Answer:

-1.52

-0.990 radians

No

2.15 radians

Step-by-step explanation:

The slope is equal to the y-coordinate/x-coordinate = -32/21 = -1.52

Then, tan^-1(m)=tan^-1(-32/21)=-0.990 radians

This does not give the correct value of theta, however.

The correct value of theta is tan^-1(-32/21)+pi=2.15 radians

Answer:

(x−2)^2+(y+1)^2=26

Step-by-step explanation:

https://socratic.org/answers/456712

Answer:

Step-by-step explanation:

For the lateral area we have to find the perimeter:

p = 2 x 8 x π

p = 16 π

now we can find it

LA = p x height

LA = 16 π x 3 = 48 π

for find the the surface area we have to find the base area

Base area = radius^2 π

base area = 8^2 π = 64 π

now can we find it

SA = 2 x base area + LA

SA =  2 x 64π + 48π = 128π + 48π = 176π

V = base area x height

V = 64π x 3 = 192 π

Answer:

b. 25

Step-by-step explanation:

The square root cancels out

and you divide only 100 and 4

Answer:

5 or 25

Step-by-step explanation:

I first got the 25 but when I tried a different formula to make sure it's correct I got 5.

Answer:

a) 341

b) 7243

c) 11018

d) 33000

Answer:

8 CM

Step-by-step explanation:

(Hypotenuse)²=(Base)²+(Height)²

10²=X+6².

100=X+36

100-36=X ( by transposition method )

√64=X

8=X

Answer:

80-foot pounds

Step-by-step explanation:

As per the given data, the work needed to move the 40 pound box a distance of 2 feet is 79.86 foot-pounds.

In physics, work is defined as the product of force and displacement, where force is the applied force and displacement is the distance moved by the object in the direction of the applied force.

To calculate the work needed to move a 40 pound box a distance of 2 feet, we need to use the formula:

Work = Force x Distance x Cos(theta)

where Force is the amount of force applied to move the box, Distance is the distance moved, and Cos(theta) is the cosine of the angle between the force vector and the direction of motion.

Assuming that the force is applied in the same direction as the motion, the angle between the force vector and the direction of motion is 0, and thus Cos(0) = 1. Therefore, the formula simplifies to:

Work = Force x Distance

We are given that the box has a weight of 40 pounds. Since weight is a type of force, we can use the formula:

Force = Mass x Acceleration due to gravity

where Mass is the mass of the box and Acceleration due to gravity is the gravitational acceleration constant, which is approximately 32.2 feet per second squared.

Converting the weight of the box from pounds to slugs (the unit of mass in the English system of units) gives:

Mass = Weight / Acceleration due to gravity = 40 pounds / 32.2 feet per second squared = 1.24 slugs

Therefore, the force required to move the box is:

Force = Mass x Acceleration due to gravity = 1.24 slugs x 32.2 feet per second squared = 39.93 pounds-force

Finally, we can calculate the work needed to move the box a distance of 2 feet as:

Work = Force x Distance = 39.93 pounds-force x 2 feet = 79.86 foot-pounds

Therefore, the work needed to move the 40 pound box a distance of 2 feet is 79.86 foot-pounds.

For more details regarding work done, visit:

https://brainly.com/question/13662169

#SPJ3

Answer:

3

Step-by-step explanation:

Define the range of a list of numbers.

I'm not %100 percent certain because I learned that a long time ago.

Answer: 3

Step-by-step explanation:

The range is the difference between the largest and smallest numbers. The midrange is the average of the largest and smallest number.- source

SOO the first thing we have to do is find the smallest and largest numbers : 5 (smallest), 8 (largest).

Then we have to substract5 from 8 (8-5= 3)

The range is 3!

If you need extra help you can go to the site khanacademy as they give educational videos and practice on how to do the standards. Ever since I started using it I have become an A students.

I hope this helps and may God bless you! Have a nice day, bye!

Answer: 11,921,360

Step-by-step explanation:

Answer:

Gay?

Step-by-step explanation:

Answer:

120km

Step-by-step explanation:

1hr 12 min is double 36 minutes

so just double 60

Answer:

Step-by-step explanation:

On the Navajo Reservation, a random sample of 218 permanent dwellings in the Fort Defiance region showed that 60 were traditional Navajo hogans. In the Indian Wells region, a random sample of 139 permanent dwellings showed that 19 were traditional hogans. Let p1 be the population proportion of all traditional hogans in the Fort Defiance region, and let p2 be the population proportion of all traditional hogans in the Indian Wells region.

(a) Find a 95% confidence interval for p1 – p2. (Use 3 decimal places.)

lower limit

upper limit

(b) Examine the confidence interval and comment on its meaning. Does it include numbers that are all positive? all negative? mixed? What if it is hypothesized that Navajo who follow the traditional culture of their people tend to occupy hogans? Comment on the confidence interval for p1 – p2 in this context.

Because the interval contains only positive numbers, we can say that there is a higher proportion of hogans in the Fort Defiance region.Because the interval contains both positive and negative numbers, we can not say that there is a higher proportion of hogans in the Fort Defiance region. We can not make any conclusions using this confidence interval.Because the interval contains only negative numbers, we can say that there is a higher proportion of hogans in the Indian Wells region.

Answer:

-15

Step-by-step explanation:

Answer:

12p=48

Step-by-step explanation:

Answer:

17

Step-by-step explanation:

Answer:

17

Step-by-step explanation:

You would use pemdas to solve this so since there is no parentheses, exponents, or multiplication you would do the division first and then the subtractions then addition because the subtraction comes first in this equation. 6 divided by 3 is 2 then 8 - 2 = 6 and then 6 + 11 = 17

Hello!

This is a question relating trigonometric ratios and a missing angle.

Here, since we are given all three sides of the triangle, we can use any of the three trigonometric ratios, sine, cosine, or tangent to solve this problem.

I'll be using the sine ratio for this problem.

The sine of an angle is the ratio between the triangle's opposite side and its hypotenuse.

Meaning the following equation could be set up.

[tex]sin(\theta)=\frac{45}{75}[/tex]

Now, we can just solve for theta.

[tex]\theta=sin^{-1}(\frac{45}{75})[/tex]

Make sure you're in degrees when you're solving this problem.

[tex]\theta=36.870[/tex]

Hope this helps!

Answer:

The answer is "Option B".

Step-by-step explanation:

The null hypothesis relates to either the initial reality in which no significant statistically meaningful evidence stays; else the equal variances which would be the reverse of the zero become preferred rather than the zero. From the above case, that scientist claimed that 'the proportion of main coon cats' community in region A surpassed these in region B.' The alternate theory is Ha: PA - PB > = 0 whereas the Null is from the idea that Polydactyl cats were the same as in areas A and B.

Answer:

36 .......................

Answer:

1/2

Step-by-step explanation:

Answer:

27

Step-by-step explanation:

Here's the complete question:

Write the word sentence as an equation. Then solve the equation. A number k increased by 7 is 34.

An increase in k simply means that there's an addition. This will be:

k + 7 = 34

k = 34 - 7

k = 27

Therefore, the value of k is 27

Step-by-step explanation:

Answer:

k = 34 - 7

k = 27

Step-by-step explanation:

increased by 7 = 34 which is means,

this number was 27

The solution is Equation: k = 34 - 7

Solution: k = 27

Answer:

Prism A:

[tex]Area = 288cm^2[/tex]

Prism B:

[tex]Area =250cm^2[/tex]

Step-by-step explanation:

Given

See attachment for prisms

[tex]Height(h) = 10cm[/tex]

Required

Determine the surface area of both prisms

Prism A is triangular and as such, the surface area is:

[tex]Area = 2 * A_b + (a + b + c) * h[/tex]

Where

[tex]A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}[/tex]

and

[tex]s = \frac{a + b + c}{2}[/tex]

Such that a, b and c are the lengths of the triangular sides of the prism.

From the attachment;

[tex]a = 8; b =6; c =10[/tex]

So, we have:

[tex]s = \frac{a + b + c}{2}[/tex]

[tex]s = \frac{8 + 6 + 10}{2}[/tex]

[tex]s = \frac{24}{2}[/tex]

[tex]s = 12[/tex]

Also:

[tex]A_b = \sqrt{s * (s - a) * (s -b) * (s - c)}[/tex]

[tex]A_b = \sqrt{12 * (12 - 8) * (12 - 6) * (12 - 10)}[/tex]

[tex]A_b = \sqrt{576}[/tex]

[tex]A_b = 24[/tex]

So:

[tex]Area = 2 * A_b + (a + b + c) * h[/tex]

[tex]Area = 2 * 24 + (8 + 6 + 10) * 10[/tex]

[tex]Area = 288cm^2[/tex]

Prism B is a rectangular prism. So, the area is calculated as:

[tex]Area = 2 * (ab + bh + ah)[/tex]

From the attachment

[tex]a = b = 5[/tex]

[tex]h =10[/tex]

So:

[tex]Area =2 * (5 * 5 + 5 * 10 + 5 * 10)[/tex]

[tex]Area =250cm^2[/tex]

Answer:

a. Jacques will be 46.4m below the surface and his assistant will be 78.1m below the surface.

b. 10 minutes

c. 6 minutes

Step-by-step explanation:

Let the equation for Justin's motion be J(x)=-13.9-7.5x (where J(x) is his distance from the surface in metres and x is time in minutes), because he starts off 13.9m below the surface and descends 7.5m every minutes.

Let the equation for the assistant be a(x)=-97.3=+6.4x (where a(x) is his distance from the surface in metres and x is time in minutes), because he starts off 97.3m below the surface and ascends 6.4m every minutes.

a.

J(x)=-13.9-7.5x

J(3)=-13.9-7.5(3)=-13.9-22.5=-36.4

a(x)=-97.3=+6.4x

a(3)=-97.3+6.4(3)=-97.3+19.2=-78.1

b.

a(x)=-97.3=+6.4x

-33.3=-97.3=+6.4x

64=6.4x

x=10

c.

when divers are at the same depth, J(x)=a(x)

J(x)=a(x)

-13.9-7.5x=-97.3=+6.4x

83.4=13.9x

x=6

Answer: H

Step-by-step explanation: H. Its H

9514 1404 393

Answer:

Step-by-step explanation:

Yes, it is very important. The idea here is that the decimal point in division problems like these can be moved the same number of places in the same direction in each number without changing the result.

__

1. Without a calculator, this is about 8/5, which you know to be more than 1 and less than 4. The only suitable answer choice is the correct one:

  B  1.645 ft.

__

2. Moving the decimal point 1 place to the left in both numbers, we have ...

  (892×10) ÷ (8×10) = 8290 ÷ 80 . . . . matches A

Moving the decimal point 3 places to the left in both numbers, we have ...

  (892×0.001) ÷ (8×0.001) = 0.892 ÷ 0.008 . . . . matches E

The other choices did something other than move the decimal point the same number of places. (Your calculator can verify this.)

__

3. Moving the decimal point 3 places to the right, we have ...

  (4367×1000) ÷ (0.004×1000) = 4,367,000 ÷ 4 ≈ 1,000,000

_____

Additional comment

For numbers like the ones in problem 3 that differ substantially in magnitude, it can work well to adjust the decimal points in both numbers so the divisor is between 1 and 10. This lets you easily estimate the position of the decimal point in the quotient.

Of course, if you're doing long division by hand, you always adjust the decimal points so the divisor is an integer (possibly with no trailing zeros).

Answer:

Y = - x + 4

Step-by-step explanation:

Answer:

4.8

Step-by-step explanation:

Since the scale is 2 feet and the real is 70 to find the cale factor you do 70/2. Since the answer to that is 35 the scale factor is 35. SO to find tha drawing scale factor in feet you do 168/35 to get 4.8,

Answer:

[tex]K \approx 51.2^\circ[/tex]

[tex]K \approx 128.8^\circ[/tex]

Step-by-step explanation:

Given

[tex]k = 480[/tex]

[tex]j = 420[/tex]

[tex]\angle J = 43^\circ[/tex]

Required

Find the measure of K

The value of K ranges from: [tex]0^\circ \le K \le 180^\circ[/tex]

To do this, we apply sine rule;

[tex]\frac{j}{\sin J} = \frac{k}{\sin K}[/tex]

So, we have:

[tex]\frac{420}{\sin 43} = \frac{480}{\sin K}[/tex]

Cross multiply

[tex]\sin K * 420 = \sin 43 * 480[/tex]

Make sin K the subject

[tex]\sin K= \frac{\sin 43 * 480}{420}[/tex]

[tex]\sin K= \frac{0.6820 * 480}{420}[/tex]

[tex]\sin K= 0.7794[/tex]

Take arc sin of both sides

[tex]K = sin^{-1}(0.7794)[/tex]

[tex]K \approx 51.2^\circ[/tex]

Recall that: [tex]0^\circ \le K \le 180^\circ[/tex]

The other possible value of K is:

[tex]K \approx 180 - 51.2[/tex]

[tex]K \approx 128.8^\circ[/tex]