please help for 21! will mark brainliest

Please Help For 21! Will Mark Brainliest

Answers

Answer 1

The answer for this question is D


Related Questions

A parallel plate vacuum capacitor has 8.40 J of energy stored. The separation between plates is 2.30 mm. If the separation is decreased to 1.15 mm what is the energy stored if (a) the charge Q on the plates is held constant, and (b) the voltage V across the plates is held constant

Answers

Answer:

(a) 4.20 J

(b) 16.74 J

Explanation:

For a parallel plate vacuum capacitor with area A and whose plates are separated by by a distance of d, its capacitance C is given by;

C = A∈₀ / d              --------------------(i)

Where;

∈₀ = constant called permittivity of vacuum.

The energy U stored in such capacitor is given by;

U = [tex]\frac{1}{2}[/tex]CV²             ----------------------(ii)

or

U =  [tex]\frac{1}{2}[/tex](Q²/C)        -------------------(**)

Where;

V = potential difference or voltage across the plates.

Q = charge on the plates.

(a) If the charge is held constant

Combine equations (i) and (**) to give;

U =  [tex]\frac{1}{2}[/tex]Q² / (A∈₀ / d)     -----------------------(iii)

From the question;

The parallel plate capacitor has 8.40J energy stored and distance between plates is 2.30mm i.e

U = 8.40J

d = 2.30mm = 0.023m

Substitute these values into equation (iii)

8.40 =  [tex]\frac{1}{2}[/tex]Q² / (A∈₀ / 0.023)

8.40 =  [tex]\frac{1}{2}[/tex]Q² x (0.023 / A∈₀)

Multiply through by 2

2 x 8.40 = Q² x (0.023 / A∈₀)

16.80 = Q² x (0.023 / A∈₀)

Divide through by 0.023

16.80 / 0.023 = Q² x (0.023 / A∈₀) / 0.023

730.4 = Q² / (A∈₀)

Make Q² subject of the formula

Q² = 730.4(A∈₀)

Now, if the separation distance is decreased to 1.15mm and the voltage is held constant i.e

d = 1.15mm = 0.0115m

Q = constant [this means that Q² still remains 730.4(A∈₀) ]

The energy stored is found by substituting these values of d and Q² into equation (iii) as follows;

U =   [tex]\frac{1}{2}[/tex]Q² / (A∈₀ / d)

U = [tex]\frac{1}{2}[/tex](730.4(A∈₀)) / (A∈₀ / 0.0115)

U = [tex]\frac{1}{2}[/tex](730.4(A∈₀))(0.0115 / A∈₀)

U = [tex]\frac{1}{2}[/tex](730.4)(0.0115)

U = 4.20J

Therefore, the energy stored if the charge Q on the plates is held constant is 4.20 J

(b) If the voltage is held constant

Combine equations (i) and (ii) to give;

U =  [tex]\frac{1}{2}[/tex](A∈₀ / d)V²     -----------------------(iv)

From the question;

The parallel plate capacitor has 8.40J energy stored and distance between plates is 2.30mm i.e

U = 8.40J

d = 2.30mm = 0.023m

Substitute these values into equation (iv)

8.40 =  [tex]\frac{1}{2}[/tex](A∈₀ / 0.023)V²

Multiply through by 2 x 0.023

2 x 0.023 x 8.40 = (A∈₀)V²

2 x 0.023 x 8.40 = (A∈₀)V²

0.385 = (A∈₀)V²

Make V² subject of the formula

V² = 0.385/(A∈₀)

Now, if the separation distance is decreased to 1.15mm and the voltage is held constant i.e

d = 1.15mm = 0.0115m

V = constant [this means that V² still remains 0.385/(A∈₀) ]

The energy stored is found by substituting these values of d and V² into equation (iv) as follows;

U =  [tex]\frac{1}{2}[/tex](A∈₀ / 0.0115)[0.385/(A∈₀)]  

U = [tex]\frac{1}{2}[/tex](0.385/0.0115)

U = 16.74

Therefore, the energy stored if the voltage V across the plates is held constant is 16.74 J

Who is a socio-economically disadvantaged child? Explain any four ways forhelping such a child

Answers

Explanation:

A socio-economically disadvantaged child is the one who is disadvantaged in terms of social position and economic position. Such children have limited resources in terms of education, money and future options. Four ways of helping such children are as follows:

1) Help them in education - You can help such children by giving them free tuition. If you belong to a well off family, you can get them admitted in schools as well. Provide them with books and uniform.

2) Encourage them to do well in school and pursue their passions.

3) Provide them with meals, if they do not have access to regular meals.

4) encourage them to go school regularly.

Answer:

sorry i dont know the answer bit mark me as BRAINLIST

how can you prove that acceleration is a derived unit​

Answers

a = (dx / dt)²

Explanation:  Unit of distance is m (metres) and unit of time is s (seconds) speed v is  first derivative of distance x versus time:

  v = dx / dt, unit is m/s.    Acceleration is second derivative of

 speed versus time  a = (dx / dt)² = (dv/dt) , unit is m/s²

Answer:

Explanation:

Acceleration is derived unit because it has two fundamental units involved i.e. meter and second square.

If a car's velocity is 30 m/s and it drives at this velocity for 4 seconds, how far did it go?

Answers

Answer:

120 m

General Formulas and Concepts:

Kinematics

VelocityDisplacementDistanceTime

Explanation:

Step 1: Define

Identify

[Given] v = 30 m/s

[Given] t = 4 s

Step 2: Solve

Multiply [Cancel out units]:                                                                            30 m/s · 4 s = 120 m

Answer:

[tex]\boxed {\boxed {\sf 120 \ meters}}[/tex]

Explanation:

Distance, or how far an object travels, is the product of velocity and time.

[tex]d= v*t[/tex]

The velocity is 30 meters per second and the time is 4 seconds.

v= 30 m/s t=4 s

Substitute the values into the formula.

[tex]d= 30 \ m/s * 4 \ s[/tex]

Multiply. The units of seconds (s) cancel.

[tex]d= 30 \ m * 4[/tex]

[tex]d=120 \ m[/tex]

The car travels a distance of 120 meters in 4 seconds at a velocity of 30 meters per second.

C.
A palm fruit dropped to the ground from the top of
a tree 45m tall. How long does it take to reach the
ground? A. 9s B. 4.5s C. 6 D. 7.5s E. 35
(g = 10ms2).​

Answers

Answer:

b 4.5

Explanation:

time=distance/speed

what happened in my room

Answers

Answer:

A GHOST CAME! Booooo!!!!!!

Hah lol

Convert 15000kg/m cube
into gm/cm cube
please write the process also​

Answers

Answer:

15000 Kilograms/Cubic Meters (kg/m3) = 15 Grams/Cubic Centimeters (g/cm3)

Explanation:

1 g/cm3 is equal to 1000 kilogram/cubic meter. To convert 100 gram into kg then divide it by 1000 i.e. 100/1000 = 0.1 kg. To convert any value of gm/cm3 into kg/m3 then multiply it by 1000.

15000 kg / m^3 =

15000 × 10^3 g / m^3 =

15000 × 10^3 × 10^3 mg / m^3 =

15 × 10^9 mg / m^3 =

15 × 10^9 × 10^(-3) mg / dm^3 =

15 × 10^9 × 10^(-3) × 10^(-3) mg / cm^3 =

15 × 10^9 × 10^(-6) mg / cm^3 =

15 × 10^( 9 - 6 ) mg / cm^3 =

15 × 10^3 mg / cm^3 =

15000 mg / cm^3 =

Look : We found the exact thing we had ...

WoW ...

We got a point ;

Remember from now on :

kg / m^3 = mg / cm^3

Terminal velocity. A rider on a bike with the combined mass of 100kg attains a terminal speed of 15m/s on a 12% slope. Assuming that the only forces affecting the speed are the weight and the drag, calculate the drag coefficient. The frontal area is 0.9m2 .

Answers

Answer:

0.9378

Explanation:

Weight (W) of the rider = 100 kg;

since 1 kg = 9.8067 N

100 kg will be = 980.67 N

W = 980.67 N

At the slope of 12%, the angle θ is calculated as:

[tex]tan \ \theta = \dfrac{12}{100} \\ \\ tan \ \theta = 0.12 \\ \\ \theta = tan^{-1}(0.12) \\\\ \theta = 6.84^0[/tex]

The drag force D = Wsinθ

[tex]\dfrac{1}{2}C_v \rho AV^2 = W sin \theta[/tex]

where;

[tex]\rho = 1.23 \ kg/m^3[/tex]

A = 0.9 m²

V = 15 m/s

Drag coefficient [tex]C_D = \dfrac{2 *W*sin \theta}{\rho *A *V^2}[/tex]

[tex]C_D =\dfrac{2 *980.67*sin 6.84}{1.23 *0.9 *15^2}[/tex]

[tex]C_D =0.9378[/tex]

A sound wave moving with a speed of 1500 m/s is sent from a submarine to the ocean floor. It reflects off the
ocean floor and is received 15s later. What is the distance between the submarine and the ocean floor?

Answers

Answer:

the distance between the submarine and the ocean floor is 11,250 m

Explanation:

Given;

speed of the wave, v = 1500 m/s

time of motion of the wave, t = 15 s

The time taken to receive the echo is calculated as;

[tex]time \ of \ motion \ (t) = \frac{total \ distance }{speed \ of \ wave} = \frac{2d}{v} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{1500 \times 15}{2} \\\\d = 11,250 \ m[/tex]

Therefore, the distance between the submarine and the ocean floor is 11,250 m

A 50 kg child sits on the left side of the bathtub. A small toy boat of 0.5 kg is on the right side of the bathtub. Which part of the bathtub has the greatest pressure

Answers

Answer:

Option 2

Explanation:

The complete question is

A 50 kg child sits on the left side of the bathtub. A small toy boat of 0.5 kg is on the right side of the bathtub. Which part of the bathtub has the greatest pressure

TopBottomLeftRight

Solution

It is the bottom of the bucket that will high pressure because of the additional weight of 50 Kg boy along with the weight of the water and the tub itself.

Pressure acts in the down ward direction and is equal to the force/weight divided by the area.

Hence, option 2 is correct

Give an example of a vertical motion with a positive velocity and a negative acceleration. Give an example of a vertical motion with a negative velocity and a negative acceleration.

Answers

Answer:

An example of positive velocity is throwing a ball upwards

An example of downward vertical velocity is when an object is dropped, for example a ball dropped from a height

Explanation:

In a vertical movement the acceleration is always downwards, therefore negative since it is created by the attraction of the Earth on the body.

An example of positive velocity is throwing a ball upwards

An example of downward vertical velocity is when an object is dropped, for example a ball dropped from a height

A 3.0-A current is maintained in a simple circuit that consists of a resistor between the terminals of an ideal battery. If the battery supplies energy at a rate of 25 W, how large is the resistance

Answers

Answer:

[tex]R=2.78\ \Omega[/tex]

Explanation:

Given that,

The current flowing in the circuit, I = 3 A

The power of the battery, P = 25 W

We need to find the resistance of the battery. We know that the power of the battery is given by the formula as follows :

[tex]P=I^2R[/tex]

Put all the values to find R.

[tex]R=\dfrac{P}{I^2}\\\\R=\dfrac{25}{(3)^2}\\\\R=2.78\ \Omega[/tex]

So, the resistance is equal to [tex]2.78\ \Omega[/tex].

what is the meaning of friend ?​

Answers

Answer:

person that you know and like (not a member of your family), and who likes you

Fill in the blanks. Power station produce electricity at __________.​

Answers

Answer:

heat

Explanation:

heat is the answer hdhhdhdhdhdhdhdhdhdhd

A large, metallic, spherical shell has no net charge. It is supported on an insulating stand and has a small hole at the top. A small tack with charge Q is lowered on a silk thread through the hole into the interior of the shell.

Required:
a. What is the charge on the inner surface of the shell?
b. What is the charge on the outer surface of the shell?

Answers

Answer:

(a) Negative Q

(b) Positive Q

Explanation:

Charge is the inherent property of matter due to the transference of electrons.

There are three methods of charging a body.

(i) Charging by friction: When two uncharged bodies rubbed together, then one body gets positive charged and the other is negatively charges it is due to the transference of electrons form one body to another.  

(ii) Conduction: when a charged body comes in contact with the another uncharged body, the uncharged body gets the same charge and the charge is distributed equally.

(iii) Induction: When a uncharged body keep near the charged body, the uncharged body gets the same amount of charge but opposite in sign.  

(a) When a small tack of charge Q is lowered into the hole, then due to the process of induction, the charge on the inner surface of the shell is - Q.

(b) Due to the process of conduction, the charge on the outer surface of the shell is Q.

The charge on the inner surface of the shell is negative whereas the charge on the outer surface of the shell is positive.

Reasons for change of charge on a body

Due to the process of induction the inner surface of the shell creates negative charge because when a uncharged body bring near to the charged body, the uncharged body gets the same amount of charge but opposite in sign.

While on the other hand, there is no charge interaction with the outer surface so it remains positively charge so we can conclude that the charge on the inner surface of the shell is negative whereas the charge on the outer surface of the shell is positive.

Learn more about charge here: https://brainly.com/question/18102056

a. Green light shines through a 100mm-diameter hole and is observed on a screen. If the hole diameter is increased by 20%, does the circular spot of light on the screen decrease in diameter, increase in diameter, or stay the same? Explain.
b. Green light shines through a 100-μ m-diameter hole and is observed on a screen. If the hole diameter is increased by 20%, does the circular spot of light on the screen decrease in diameter, increase in diameter, or stay the same? Explain.

Answers

Answer:

a) size of the bright spot is proportional to the hollow size

b) as the size of the hole increases, the circular point decreases.

Explanation:

a) In this case the diameter of the hole is much greater than the wavelength, as the size of the hole is many orders greater than the wavelength we are in the part of geometric optics,

Consequently the size of the bright spot is proportional to the hollow size.

Consequently the size increases

b) in this case the hole diameter d = 100 10⁻⁶m and the wavelength that for the green color is lam = 500 nm  = 5 10⁻⁷ m

We see that angles are very small so the wavelength of the office is greater than the wavelength, but you can observe the effects of diffraction

          d sin θ = 1.22 m λ

the numerical constant appears by solving the equation in polar coorθdinates, because the hole is circular

           

the first zero occurs for m = 1

        sin θ = 1.22 λ / d

In these experiments the angles are small

        sin θ = θ

we substitute

       θ = 1.22 λ/ d

       θ = 1.22 500 10⁻⁹ / 100 10⁻⁶

       θ = 6.1 10⁻³

without the hole diameter increases by 20%            

       d’ = 1.2 d

we substitute

    θ'= 1.22 λ / d'

    θ’ = 1.22 λ /1.2 d

    θ‘= 1.22 λ /d  [tex]\frac{1}{1.22}[/tex]

    θ ’=  θ  0.83

    θ ’= 6.1 10⁻³ 0.83

    θ' = 5 10⁻³ rad

Therefore, the answer is that as the size of the hole increases, the circular point decreases.

A 20-g bullet is shot vertically into an 2.8-kg block. The block lifts upward 9 mm. The bullet penetrates the block and comes to rest in it in a time interval of 5 ms. Assume the force on the bullet is constant during penetration and that air resistance is negligible. What is the speed of the bullet just before the impact

Answers

Answer:

The speed of the bullet just before the impact is 701 m/s

Explanation:

Given;

mass of the bullet, m₁ = 20 g = 0.02 kg

mass of the block, m₂ = 2.8 kg

displacement of the block, d = 9 mm = 9 x 10⁻³ m

duration of motion of the bullet, t = 5 ms = 5 x 10⁻³ s

Apply the principle of conservation of energy;

The final kinetic energy of the bullet = maximum potential energy of the block

[tex]\frac{1}{2} m_1v^2 = m_2gh\\\\v^2 = \frac{2m_2gh}{m_1} \\\\v= \sqrt{\frac{2m_2gh}{m_1} } \\\\v = \sqrt{\frac{2 \times 2.8 \times 9.8 \times (9\times 10^{-3})}{0.02} } \\\\v = 4.97 \ m/s[/tex]

Apply the principle of conservation of linear momentum, to determine the initial velocity of the bullet before the impact.

m₁u₁  +  m₂u₂  =  v(m₁  +  m₂)

where;

u₁ is the initial velocity of the bullet

u₂ is the initial velocity of the block = 0

m₁u₁  +  0  = v(m₁  +  m₂)

m₁u₁  =  v(m₁  +  m₂)

0.02u₁ = 4.97(2.8 + 0.02)

0.02u₁ = 14.02

u₁ = 14.02 / 0.02

u₁ = 701 m/s

Therefore, the speed of the bullet just before the impact is 701 m/s

John is going to use a rope to pull his sister Laura across the ground in a sled through the snow. The rope makes an angle of 25 with the ground He is pulling horizontally with a constant force of 400 N. John and manages to get the sled going from 0 to 4 m/s in 5 s. The force due to friction on the sled is 310 N. What is the mass of Laura and the sled combined

Answers

the mass of Laura and the sled combined is 887.5 kg

A single-story retail store wishes to supply all its lighting requirement with batteries charged by photovoltaic cells. The PV cells will be mounted on the horizontal rooftop. The time-averaged lighting requirement is 10 W/m2 , the annual average solar irradiance is 150 W/m2 , the PV efficiency is 10%, and the battery charging/discharging efficiency is 80%. What percentage of the roof area will the PV cells occupy

Answers

Answer:

83.33% of the roof area will be occupied by the PV cells

Explanation:

Given the data in the question;

time-averaged lighting requirement [tex]P_{lighting[/tex] = 10 W/m²

the annual average solar irradiance [tex]q_{solar[/tex] = 150 W/m²

the PV efficiency η[tex]_{pv[/tex] = 10% = 0.1

battery charging/discharging efficiency η[tex]_{battery[/tex] = 80% = 0.8

we know that; Annual average power to the light = [tex]P_{lighting[/tex] × A[tex]_{roof[/tex]

Now, the electrical power delivered by the solar cell battery system will be;

⇒  [tex]q_{solar[/tex] × A[tex]_{pv[/tex] × η[tex]_{pv[/tex] × η[tex]_{battery[/tex]

[tex]P_{lighting[/tex]A[tex]_{roof[/tex] = [tex]q_{solar[/tex] × A[tex]_{pv[/tex] × η[tex]_{pv[/tex] × η[tex]_{battery[/tex]

Such that;

A[tex]_{pv[/tex] = [tex]P_{lighting[/tex]A[tex]_{roof[/tex] / [tex]q_{solar[/tex] × A[tex]_{pv[/tex] × η[tex]_{pv[/tex] × η[tex]_{battery[/tex]

A[tex]_{pv[/tex] / A[tex]_{roof[/tex] = [tex]P_{lighting[/tex] /  [tex]q_{solar[/tex] × η[tex]_{pv[/tex] × η[tex]_{battery[/tex]

so we substitute

A[tex]_{pv[/tex] / A[tex]_{roof[/tex] = 10 W/m² / [ 150 W/m² × 0.1 × 0.8 ]

A[tex]_{pv[/tex] / A[tex]_{roof[/tex] = 10 W/m² / 12 W/m²

A[tex]_{pv[/tex] / A[tex]_{roof[/tex] = 0.8333

A[tex]_{pv[/tex] / A[tex]_{roof[/tex] = (0.8333 × 100)%

A[tex]_{pv[/tex] / A[tex]_{roof[/tex] = 83.33%

Therefore, 83.33% of the roof area will be occupied by the PV cells.

Many adventures like to go rafting on the Colorado River through Grand Canyon National Park. There are many locations where the river becomes more narrow, both the distance between the canyon walls as well as the depth changes due to debris like boulders on the bottom of the river; this leads to changes in the water speed. In the park, the Colorado River has an average width of 100m and an average depth of 8m, and an average speed of 3 m/s. At the Lava Falls Rapids, the river has an average width of about 25m and an average depth of about 15m. What is the approximate speed of the water in this location

Answers

Answer:

6.4 m/s

Explanation:

Given that :

The average width of the Colorado river = 100 m

Average depth of the river is = 8 m

Therefore, area = [tex]$A_1= 100 \ m \times 8 \ m$[/tex]

Speed of the river, [tex]$v_1 = 3 \ m/s$[/tex]

After the lava falls on the river,

Width of the river becomes = 25 m

Depth of the river became = 15 m

Therefore, area = [tex]$A_2= 25 \ m \times 15 \ m$[/tex]

Now, since the volume flow rate of the Colorado river is same, then from the Continuity equation,

[tex]$Q_1=Q_2$[/tex]

[tex]$A_1v_1=A_2v_2$[/tex]

∴ [tex]$100 \times 8 \times3 = 25 \times 15 \times v_2$[/tex]

[tex]$v_2=\frac{100 \times 8 \times 3}{25 \times 15}$[/tex]

    = 6.4 m/s

Therefore, the speed of the river in this location is 6.4 m/s

which of the following is not a good working habit in doing an embroidery

Answers

Answer:

Where is following ??

Post proper Ques

You drop a ball from a height of 10 meters. Each time the ball bounces, it
reaches a lower height. Why does the ball lose height after each time it hits
the ground?

Answers

C ,because kinetic energy is stored and there is energy needed for the ball to keep bouncing

How do a parachutes work??4-5 sentences plsss help rn

Answers

Answer:

Explanation:

A parachute works by forcing air into the front of it and creating a structured 'wing' under which the canopy pilot can fly. Parachutes are controlled by pulling down on steering lines that change the shape of the wing, cause it to turn. The main forces acting on a parachute are gravity and drag. When you first release the parachute, the force of gravity pulls it downward, and the parachute speeds toward the ground. The faster the parachute falls, though, the more drag it creates.

Visible matter belonging to the Milky Way Galaxy can be traced out to about 50,000 light years from the center.

a. True
b. False

Answers

Answer:

b. False

Explanation:

The visible matter that belongs to the Milky way Galaxy are traced out to be about 50 kpc distance from the center.

Kpc stands for kiloparsec. It is the unit of measurement of distance.

A parsec is[tex]$\text{ used to measure large distances}$[/tex] of the astronomical objects that lies [tex]$\text{outside the solar system}$[/tex], mainly where galaxies are involved.

1 kiloparsec is 1000 parsec and is equal to 3260 light years.

So the visible matter is about 163,078 light years away.

Hence the answer is FALSE.

Two trains are moving at 50 m/s in opposite directions on the same track. The engineers see simultaneously that they are on a collision course and apply the brakes when they are 1,100 m apart. Assuming both trains have the same acceleration, what must this acceleration be (in m/s2) if the trains are to stop just short of colliding

Answers

Answer:

Acceleration is 2.5 m/s^2

Explanation:

Let train 1 travel x meters and train 2 travels 1000-x meters

As per the las of acceleration

[tex]v^2 = u^2 + 2ax[/tex]

Substituting the given values, we get -

[tex]0 = 50^2 + 2ax\\ax = -1250\\[/tex]---Eq (1)

Similarly

[tex]0 = 50^2 + 2a(1000-x)\\a(1000-x) = 1250[/tex]-- Eq (2)

Substituting the value of ax from eq (1) into Eq(2), we get -

1000*a  - 1250 = 1250

a = 2500/1000 = 2.5 m/s^2

magnetism/ magnetic field ana magnetic forces

Answers

Answer:

Magnetism is a physical phenomenon that manifests itself in a force acting between magnets or other magnetized or magnetisable objects, and a force acting on moving electric charges, such as in current-carrying cables. The force action takes place by means of a magnetic field, which is generated by the objects themselves or otherwise. There are natural and artificial magnets. All magnets have two poles called the north pole and the south pole. The north pole of one magnet repels the north pole of another magnet and attracts the south pole of another magnet; the same with south poles.  

allung d Uall, Wily
In which condition is mirage seen ? Why is light dispersed ?​

Answers

Answer:

Mirage is a phenomenon which can be seen when the surface air gets heated up and it becomes lighter. Lighter air moves up in the atmoshphere.

Explanation:

When the lighter air from cooler areas to warmer areas are refracted and they bent upwards.and it dispers

,

Before the 1970's, energy prices were A. relatively low B. extremely burdensome C. incredibly high D. very problematic​

Answers

Answer:

C

Explanation:

correct me if I'm wrong.

Answer:

A

Explanation:

i got it right on acellus

the boiling point of F2 much lower than the boiling point of NH3​

Answers

Answer:yeah it A

Explanation:

PLEASE HELP!!!!
A person pushes attempts to push a couch with a 25 N force. The couch, however, doesn't move. What is the static friction force acting on the couch? *
A. 25 N
B. 0 N
C. 50 N
D. There is no static friction the ONLY force acting on the couch is the push

Answers

Static friction cancels out the force of the push, so it also has a magnitude of 25 N.

Other Questions
what is Geography? pliz help what is the resolution is the text "marigolds" Find an article regarding full disclosure or the treatment of accounting changes. In 250-300 words, summarize the article that you found and post that summary in the discussion forum. Post the article name in the subject line and do not post on an article that another classmate has already posted. Participate in follow-up discussion by choosing one of the articles that your classmates' posted on and providing additional comments about the findings of that article. Your initial post should be 250-500 words, and should demonstrate solid academic writing skills. Please include proper citations in your discussion post. Points will be deducted if proper citations are not used. The large amounts of whatled to regulations by the Texas Railroad Commission, to ensure to much of this was not available in the market.a. Cattle b. Oilc. Cottond. Tobacco Marking brainliest Please help Which quotation from the passage most clearly shows that the author thinks Mount Shasta is very impressive?1. "is the single cone of an immense, extinct volcano"2. "occupies the country east of Scott's Mountain"3. "they are utterly inconspicuous under the shadow of the great peak"4. "a grandeur equaled by hardly any American mountain" Can anyone explain step by step how to get this answer?Will mark branliest!! X = mb + y Is this written out in slope intercept form? Names for following compounds.a)COb)NaCIc)SCId)NaF If a business had a capacity of $10,000,000 of sales, actual sales of $6,000,000, break-even sales of $4,500,000, fixed costs of $1,800,000, and variable costs of 60% of sales, what is the margin of safety expressed as a percentage of sales Please help ASAP I need helppppo An investigation is conducted into how the mass of magnesium metal reacting with hydrochloric acid affects the amount of hydrogen gas produced. Masses of 0.10g, 0.20g, 0.30g and 0.40g of powdered Mg metal are reacted with hydrochloric acid(HCl). The conical flask containing the reaction mixture of Mg and HCl is connected to another conical flask with a hose. The hydrogen gas produced by the reaction is collected in this conical flask. The greater the amount of hydrogen gas produced by the reaction the greater the pressure of the gas in the flask. Answer:A) what is the independent variable: B) what is the dependent variable:C) write a hypothesis for this investigation:D) give 2 variables that should have been controlled for this investigation: 45-45-90 Right Triangles! Can somebody please help me? ASAP!! Hurry Asap Need Help I Will Give Brainliest!! Nine chips numbered 1 through 9 are placed in a box and mixed. Margie selected one chip from the box. What is the probability that Margie selected a chip that is a multiple of three? Factor 2x^2 c^2 + 3xc^2- 35c^2 if four times the sum of a number and three is six less than twice the number what is the number hellllllllllp now in my questionDiscussion of Activity 1You just learned the importance of research in daily life. Answer the following questions briefly but intelligently on the blanks provided.Was there an instance in your life when you did an inquiry or research? Share and describe your experiences. What are your challenges and difficulties?________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________As a learner in senior high school, how important is research in your daily life? What are the solutions to the following quadratic equation? *1 pointCaptionless Imagex = 8 and x = 7x = 7 and x = 8x = 7 and x = 1 What type of decay changes the atomic number of the atom?B. TranslocationC. TranslationD. TransuraniumA. Transmutation