Please help on the image below.

Answer:

0.19 mol H₂O

General Formulas and Concepts:

Chem

Explanation:

Step 1: Define

Given: 3.5 g H₂O from RxN

Step 2: Define conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

[tex]3.5 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} )[/tex] = 0.194229 mol H₂O

Step 4: Check

We are given 2 sig figs. Follow sig fig rules.

0.194229 mol H₂O ≈ 0.19 mol H₂O

Answer:

[tex]0.192\ \text{M}[/tex]

Explanation:

A = Absorbance of solution

E = Molar absorptivity

l = Length of cuvette = 1 cm

c = Concentration of solution

Beer's law is given by

[tex]A=Elc[/tex]

The equation of a straight line is given by

[tex]y=mx+c[/tex]

Comparing the above equations we get

Value on [tex]y[/tex] axis = A = Absorbance of solution = 0.23

[tex]m[/tex] = Slope of line = El = Molar absorptivity multiplied with length = [tex]1.2\times 1\ \text{M}^{-1}[/tex]

[tex]x[/tex] = Value of x axis = c = Concentration of solution

So we get

[tex]c=\dfrac{A}{El}\\\Rightarrow c=\dfrac{0.23}{1.2\times 1}\\\Rightarrow c=0.192\ \text{M}[/tex]

The molar concentration of the sample is [tex]0.192\ \text{M}[/tex]

Answer:

[tex]23.093\ \text{torr}[/tex]

Explanation:

[tex]M_g[/tex] = Molar mass of glucose = 180.2 g/mol

[tex]M_w[/tex] = Molar mass of water = 18 g/mol

[tex]m_g[/tex] = Mass of glucose = 76.6 g

[tex]m_w[/tex] = Mass of water = [tex]250\times 1\ \text{g/mL}=250\text{g}[/tex]

[tex]P_0[/tex] = Vapor pressure of pure water at 25°C = 23.8 torr

The mole fraction of glucose is

[tex]x_g=\dfrac{\dfrac{m_g}{M_g}}{\dfrac{m_g}{M_g}+\dfrac{m_w}{M_w}}=\dfrac{\dfrac{76.6}{180.2}}{\dfrac{76.6}{180.2}+\dfrac{250}{18}}\\\Rightarrow x_g=0.0297[/tex]

Mole fraction of the solute would be

[tex]\dfrac{P_0-P}{P_0}=x_g\\\Rightarrow 0.0297=\dfrac{23.8-P}{23.8}\\\Rightarrow P=23.8-0.0297\times23.8\\\Rightarrow P=23.093\ \text{torr}[/tex]

The vapor pressure of the solution is [tex]23.093\ \text{torr}[/tex].

Answer:

Explanation:

Ca₃( PO₄)₂ = 3 Ca⁺² + 2 PO₄⁻³

x                      3x            2 x

Let solubility be x mole per litre

solubility product = (3x )³ x ( 2x )²

= 108 x⁵ = 1.2 x 10⁻²⁹

x⁵ = .0111 x 10⁻²⁹ = .111 x 10⁻³⁰

x = .64 x 10⁻⁶ moles / litre

In a closed system, the total energy before an energy transformation is greater than the total energy after it.

A closed system is a natural physical system that does not permit the movement of matter into or out of the system, while energy transfer is permitted in some situations, such as those found in physics, chemistry, or engineering.

A closed system is one that only allows the flow of energy; it forbids the exchange of matter. The heat can transfer when we boil water with a closed cover, but the matter cannot.

In a closed system, the overall energy is constant. The universe's overall energy is always changing. Mass may be used to store energy. In a closed system, energy may be transformed from one form to another.

Thus, option D is correct.

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Answer:

A circle graph, or a pie chart, is used to visualize information and data. A circle graph is usually used to easily show the results of an investigation in a proportional manner. Bar graphs are used to compare things between different groups or to track changes over time. However, when trying to measure change over time, bar graphs are best when the changes are larger.

Explanation:

In short, bar graphs are better to keep track of data over long periods of time, and circle graphs are better when you are trying to visualize a specific set of data.

Circle graph can be also be called pie chart, which  is more widely used. It is usually made up of a circle, divided into parts or pies. In the divided parts, it is used to differentiate between different data.

Bar charts on the other hand are like graphs having both x and y axis. It is used to represent data with respect to the height of the graph. Each data is divided into different smaller parts on the graph.

Example of what they look like is attached below.

First one is bar chart while the second is a circle graph

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Answer:

0.16 L

Explanation:

From the question given above, the following data were obtained:

Mole = 0.0806 mole

Molarity = 0.490 M

Volume =?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the volume of the solution as illustrated below:

Mole = 0.0806 mole

Molarity = 0.490 M

Volume =?

Molarity = mole /Volume

0.490 = 0.0806/volume

Cross multiply

0.490 × volume = 0.0806

Divide both side by 0.490

Volume = 0.0806 / 0.490

Volume of solution = 0.16 L

Thus, the volume of the solution is 0.16 L.

A solution is a mixture of solute in the solvent. The volume of the solution is 0.16 L.

A solution is a mixture of solute in the solvent.

An example of a solution is a mixture of salt in water.

Given,

Moles = 0.0806 mol [tex]\rm CaCl_2[/tex]

Molarity = 0.490 M

To find: the volume of the solution

[tex]Molarity = \dfrac{n}{V}[/tex]

Putting the values

[tex]0.490 M = \dfrac{ 0.0806}{V}\\\\0.490 M \times V = 0.0806\\\\Divide\; both\;side\; with\; 0.490\\\\V= \dfrac{ 0.0806}{0.490}=0.16 L[/tex]

Thus, the volume so the solution is 0.16 l.

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Answer:

53.5%

Explanation:

Step 1: Given data

Step 2: Calculate the mass corresponding to 0.00875 moles of KClO₃

The molar mass of KClO₃ is 122.55 g/mol.

0.00875 mol × 122.55 g/mol. = 1.07 g

Step 3: Calculate the percent by mass of KClO₃ in the mixture

We will use the following expression.

%m/m = mass of KClO₃/mass of the sample × 100%

%m/m = 1.07 g/2.00 g × 100%

%m/m = 53.5%

The percent by mass of KClO3 in the original mixture is 53.5%.

Since

The mass of the sample should be 2.00 g

Moles of KClO₃: 0.00875 mol

The molar mass of KClO₃ is 122.55 g/mol.

Now the mass is

= 0.00875 mol × 122.55 g/mol.

= 1.07 g

Now the percentage should be

= mass of KClO₃/mass of the sample × 100%

= 1.07 g/2.00 g × 100%

= 53.5%

hence, The percent by mass of KClO3 in the original mixture is 53.5%.

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Option ( C ). Hydrolysis (/haɪˈdrɒlɪsɪs/; ancient Greek for "water" and "to dissolve") is a chemical reaction in which water molecules break one or more chemical bonds.)

What does the example of hydrolysis mean?

Hydrolysis is the process of breaking down compounds by adding water. Here is an example of hydrolysis:

Sodium acetate is a type of salt. When sodium acetate is mixed with water, the chemical bonds are broken and it breaks down into sodium ions and acetate ions.

What is function of hydrolysis?

Hydrolysis reactions break the bonds and release energy. Biopolymers are ingested and hydrolyzed in the gastrointestinal tract to form small molecules that can be absorbed by cells and further broken down to release energy.  

Where does the hydrolysis take place?

Hydrolysis is the process by which compounds are broken down into simpler compounds and involves the chemical uptake of water. Almost all tissues contain enzymes that catalyze hydrolysis, but the highest concentration is in the liver.

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Answers:

1. Chemistry

2. Cold

3. Heat

4. Protons and neutrons

5. Positive

6. Neutral

7. True

8. Nucleus

9. Protons

10. Nobel gasses

11. Dmitri Mendeleev

12. the bottom of the square

13. True

14. Helium

Answer:

Carbon

Explanation:

Answer:

[tex]$Cu_2+(SO_3)^2 \rightleftharpoons CuSO_3 \ (insoluble)$[/tex]

[tex]$Cu_2+2(SO_3)^2 \rightleftharpoons [Cu(SO_3)_2]_2 \ (soluble)$[/tex]

Explanation:

A ligand may be defined as a molecule or an ion or that binds to the central metal atom in order to form a more coordination complex. Sulfite is one such ligand and it behaves similarly as hydroxide as a ligand.

Now, according to the question, when we react copper with sulfite ion, it forms copper sulfite. The equation is

[tex]$Cu_2+(SO_3)^2 \rightleftharpoons CuSO_3 \ (insoluble)$[/tex]

Now when excess of the sulfite ion is used in the reaction, we get a complex formation, which is shown by

[tex]$Cu_2+2(SO_3)^2 \rightleftharpoons [Cu(SO_3)_2]_2 \ (soluble)$[/tex]

The way the sulfite reacts is quite similar to hydroxide ion where they form a complex ion when hydroxide ion in excess is used in the reaction with metal cation.

Answer:

i can only help with 2 :( atimic mass is: 35.453  and number of electrons is:17

Explanation:

Answer:

residue is whatever remains after something else has been removed while filtrate is the liquid or solution that has passed through a filter, and which has been separated from the filtride.

filtration id done by placing a filter paper on the beaker or container then pour the filtride then let it settle and it will pass through and you will have the fitrate and residue

Explanation:

Answer:

Its B

Explanation:

The enthalpy : 320.3 kJ/mol

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation  

The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)  

Based on the principle of Hess's Law,

the change in enthalpy of a reaction will be the same even though it is through several stages or ways  

Reaction

2Fe (s) + 3Cl₂ (g) → 2FeCl₃ (s) ∆H° = -800.0 kJ/mol  x 2

4Fe (s) + 6Cl₂ (g) → 4FeCl₃ (s) ∆H° = -1600.0 kJ/mol

Si(s) + 2 Cl₂ (g) → SiCl₄ (s) ∆H° = -640.1 kJ/mol

Reverse

SiCl₄ (s) → Si(s) + 2 Cl₂ (g) ∆H° = 640.1 kJ/mol x 3

3SiCl₄ (s) → 3Si(s) + 6Cl₂ (g) ∆H° = 1920.3 kJ/mol

------------------------------------------------------------------------ +

3 SiCl₄ (s) + 4 Fe (s) → 4 FeCl₃ (s) + 3 Si (s) ∆H° = 320.3 kJ/mol

The enthalpy for the formation of 4 moles of [tex]\rm FeCl_3[/tex] has been 320.3 kJ/mol.

The enthalpy of formation of 1 mole at standard temperature and pressure has been termed the standard enthalpy of formation.

The reaction enthalpy to be calculated has reactants of 3 moles of [tex]\rm SiCl_4[/tex], and 4 moles of Fe.

The enthalpy for the formation of [tex]\rm SiCl_4[/tex] has been -640.1 kJ/mol.

The enthalpy for the dissociation of [tex]\rm SiCl_4[/tex] has been the reverse of the formation reaction = +640.1 kJ/mol.

The enthalpy for the dissociation of 3 moles of [tex]\rm SiCl_4[/tex] has been = 3 [tex]\times[/tex] 640.1 kJ/mol.

The enthalpy for the dissociation of 3 moles of [tex]\rm SiCl_4[/tex] has been = 1920.3 kJ/mol.

The enthalpy for the formation of 2 moles of [tex]\rm FeCl_3[/tex] = -800 kJ/mol

The enthalpy for the formation of 4 moles of [tex]\rm FeCl_3[/tex] = -1600 kJ/mol.

The final reaction has 3 moles of  [tex]\rm SiCl_4[/tex], and 4 moles of [tex]\rm FeCl_3[/tex].

Thus, the final enthalpy of reaction will be: 1920 kJ/mol + (-1600 kJ/mol)

The final enthalpy of reaction will be = 320.3 kJ/mol.

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Answer:

A

Explanation:

I took the test

Answer:

In 1924, the French physicist, Louis de Broglie suggested that if light has electron, behaves both as a material particle and as a wave. According to this theory, small particles like electrons when in motion possess wave properties.

Explanation:

examples

This can be derived as follows according to Planck’s equation, E = hv = hc /λ ∴ v=c/λ(energy of the photon (on the basis of Einstein’s mass energy relationship) E = mc2    

( If Bohr’s theory is associated with de-Broglie’s equation then wave length of an electron can be determined in bohr’s orbit and relate it with circumference and multiply with a whole number 2πr = nλ or λ = (2πr/2π) From de-Broglie equation, λ = (h/mv).  

Answer:

Cultivated rice paddies

Drilling of natural deposits

Fossil fuel use

Burning of biomass

Landfills

Explanation:

The bulk of the methane released into the atmosphere are as a result of various human activities.

Answer:

0.56 mL

Explanation:

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of carbon tetrachloride would be produced by this reaction if 1.1 mL of chlorine were consumed.

Step 1: Write the balanced equation

CH₄(g) + 2 Cl₂(g) → CCl₄(g) + 4 HCl (g)

Step 2: Calculate the moles corresponding to 1.1 mL of Cl₂

At standard temperature and pressure, 1 mole of a gas has a volume of 22.4 L.

1.1 × 10⁻³ L × 1 mol/22.4 L = 4.9 × 10⁻⁵ mol

Step 3: Calculate the moles of CCl₄ formed from 4.9 × 10⁻⁵ moles of Cl₂

The molar ratio of Cl₂ to CCl₄ is 2:1. The moles of CCl₄ are 1/2 × 4.9 × 10⁻⁵ mol = 2.5 × 10⁻⁵ mol.

Step 4: Calculate the volume corresponding to 2.5 × 10⁻⁵ moles of CCl₄

At standard temperature and pressure, 1 mole of a gas has a volume of 22.4 L.

2.5 × 10⁻⁵ mol × 22.4 L/mol = 5.6 × 10⁻⁴ L = 0.56 mL

Answer:

Throughout the overview section following portion, the description and according to particular circumstance is defined.

Explanation:

As per the question,

⇒ [tex]NH_3(aq)+H_2O\leftrightarrow NH_4+(aq)+OH-(aq)[/tex]

⇒ [tex]NH_3+(aq) \leftrightarrow NH_3(aq)+H+(aq)[/tex]

However, it is also available in NH3 form throughout the aqueous solution much of the moment.

Answer:

I believe its 1,2, and 5

Explanation:

C D E

temperature of medium

type of wave

type of medium

Answer:

This means that a solution must be cooled to a lower temperature than the pure solvent in order for freezing to occur.

Explanation:

Answer:

Freezing Point Depression. The freezing point of a solution is less than the freezing point of the pure solvent. This means that a solution must be cooled to a lower temperature than the pure solvent in order for freezing to occur

Answer:

mass in gram = 642.6 g

Explanation:

Given data:

Density of aluminum = 2.70 g/mL

Volume of aluminum = 238 mL

Mass in gram = ?

Solution:

Density:

Density is equal to the mass of substance divided by its volume.  The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

d =m/v

d = density

m=mass

V=volume

Now we will put the values in formula.

2.70 g/mL = m/ 238 mL

m = 2.70 g/mL × 238 mL

m = 642.6 g

So when something is boiling it is moving faster meaning the molecules are more spread out and not condense like a solid

So the answer is the 2nd set

Answer:matter is anything has mass and take up space

Explanation: