Answers
Answer:
D is correct
Explanation:
Related Questions
There is a ball at rest on a flat floor. What kind of equilibrium is it in? *
Stable Equilibrium
Unstable Equilibrium
Neutral Equlibirum
Not in Equilibrium
Answers
ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements.
In working this problem, assume the value of "g" to be 9.8 m/s2 with two (2) significant digits unless otherwise stated.
Given that a lever has a mechanical advantage of 6.0 and is 100% efficient, if the resistance is to be lifted 2.0 inches, then how far must the effort move?
De = _____ in.
12
8.0
4.0
3.0
NEXT
Answers
The effort must move 8•0
QUICKK I NEED HELP!!
How is a mineral different from an element rock
Answers
Answer:here you goo
Explanation:
A mineral is a naturally occurring inorganic element or compound having an orderly internal structure and characteristic chemical composition, crystal form, and physical properties. ... A rock is an aggregate of one or more minerals, or a body of undifferentiated mineral matter.
Answer:
Minerals are naturally occuring solid while rocks are naturally occuring substances consist of aggregate minerals clumped together with other materials
if you walk at an avaerage speed of 5 km/h for 30 min how far will you walk
Answers
Answer:
2.5 km/30min
Explanation:
Divide 5 by 2 because 30 min is half of 1 hour. when you do that you get 2.5
An object O is acted upon by a 6 N force and a 5 N force. The angle between these two forces is 60°. Draw a scale diagram showing the forces acting on object O and determine the resultant force.
Answers
Answer:
Resultant force = [tex]\sqrt{91}[/tex]N
Explanation:
Rf = [tex]\sqrt{f1²+f2²+2.f1.f2.cos60}[/tex]
Rf = [tex]\sqrt{6²+5²+2.6.5.1/2}[/tex]
Rf = [tex]\sqrt{36+25+30}[/tex]
Rf = [tex]\sqrt{91}[/tex]
doesn't look right though...
The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Given parameters:
Two forces are 6 N and 5N.
Angle between them is 60 degree.
So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N = = 9.54 N.
Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°) } = 33⁰.
Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
To find more about force, refer the link:
https://brainly.com/question/13191643
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can u plz help
Define: Medium
Answers
Answer:
Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral. (I'm sorry if that wasn't helpful)
Explanation:
Un gas ideal ocupa un volumen de 4.00 m3 a una presión absoluta de 200 kPa. ¿Cuál será la nueva presión si el gas es comprimido lentamente hasta 2.00 m3 a temperatura constante?
Answers
Given :
Initial pressure, [tex]P_i=200\ kPa[/tex].
Initial volume, [tex]V_i= 4\ m^3[/tex].
Final volume, [tex]V_f = 2 \ m^3[/tex].
To Find :
Final pressure, [tex]P_f[/tex].
Solution :
We know, at constant temperature :
[tex]P_iV_i=P_fV_f\\\\P_f=\dfrac{P_iV_i}{V_f}\\\\P_f=\dfrac{200\times 4}{2}\\\\P_f=400\ kPa[/tex]
Therefore, new pressure is 400 kPa.
Hence, this is the required solution.
a man climbs a ladder.which quamtities can be used to calculatethe useful power of the man
Answers
Explanation:
Power is the rate at which work is done. It is expressed as:
Power = [tex]\frac{work done}{time taken}[/tex]
To find the power of the man climbing the ladder, we must know the work he is doing and the duration of the work done.
Work done = force x distance
Since he climbs,
Force = weight = mg (mass x acceleration due to gravity)
distance = height = h
Power = [tex]\frac{mgh}{t}[/tex]
t is the time
If we know these parameters, we can find the power.
If the velocity of an object is zero, then that object cannot be accelerating. | True or False
Answers
Answer: False
Explanation:
A cannon sitting on the edge of a cliff 500 meters above the ground shoots a cannon ball with a horizontal velocity of 100m/s. At some point the cannon hits the ground. How far away from the point it was launched will the cannon ball land?
Answers
Answer:
1010 m
Explanation:
The following data were obtained from the question:
Height (h) of cliff = 500 m
Horizontal velocity (u) = 100 m/s
Horizontal distance (s) =?
Next we shall determine the time taken for the cannon ball to hit the ground. This can be obtained as follow:
Height (h) of cliff = 500 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
500 = ½ × 9.8 × t²
500 = 4.9 × t²
Divide both side by 4.9
t² = 500/4.9
Take the square root of both side
t = √(500/4.9)
t = 10.1 s
Finally, we shall determine the horizontal distance travelled by the cannon ball.
This can be obtained by using the following formula (s = ut) as illustrated below:
Horizontal velocity (u) = 100 m/s
Time (t) = 10.1 s
Horizontal distance (s) =?
s = ut
s = 100 × 10.1
s = 1010 m
Thus, the cannon ball was launched 1010 m away from the cliff.
Which of the following is a FALSE statement? (A) Heat moves through solids by conduction (B) Molecules move faster in warmer substances (C) Warm water is denser than cold water (D) Heat moves through liquids and gases by convection
Answers
Answer:
C.
Explanation:
A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a distance of 0.5 m
before the 1.56-kg target launched. What is the target's velocity as it leaves the spring?
Please help.
(A) 10m/s
(B) 20m/s
(C) 40m/s
(D) 30m/s
Answers
Answer:
(C) 40m/s
Explanation:
Given;
spring constant of the catapult, k = 10,000 N/m
compression of the spring, x = 0.5 m
mass of the launched object, m = 1.56 kg
Apply the principle of conservation of energy;
Elastic potential energy of the catapult = kinetic energy of the target launched.
¹/₂kx² = ¹/₂mv²
where;
v is the target's velocity as it leaves the catapult
kx² = mv²
v² = kx² / m
v² = (10000 x 0.5²) / (1.56)
v² = 1602.56
v = √1602.56
v = 40.03 m/s
v ≅ 40 m/s
Therefore, the target's velocity as it leaves the spring is 40 m/s
HELP ASAP!!!
A force of 50N acts in an easterly direction on an object at the same time as a force of 80N pushes on it in the direction of N 45 degrees E. Determine the magnitude and direction of resultant force
Answers
Write each force in component form:
v ₁ : 50 N due east → (50 N) i
v ₂ : 80 N at N 45° E → (80 N) (cos(45°) i + sin(45°) j ) ≈ (56.5 N) (i + j )
The resultant force is the sum of these two vectors:
r = v ₁ + v ₂ ≈ (106.5 N) i + (56.5 N) j
Its magnitude is
|| r || = √[(106.5 N)² + (56.5 N)²] ≈ 121 N
and has direction θ such that
tan(θ) = (56.5 N) / (106.5 N) → θ ≈ 28.0°
i.e. a direction of about E 28.0° N. (Just to clear up any confusion, I mean 28.0° north of east, or 28.0° relative to the positive x-axis.)
A rocket has a mass of 142 kg. If you want to give it an acceleration of 7 m/s2 how much force does the engine need to apply
Answers
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 142 × 7
We have the final answer as
994 NHace this helps you
A car travels 19 km in 30 minutes. What was its speed in km/hour?
HURRY WILL MARK BRAINLIST
Answers
19km in 30mins
1 hour is twice of 30 mins.
Twice the time means twice the distance.
therefore 2(19km) in 2(30 mins)
19km in 30mins = 38km/hour
Can you give
an
example of a physical quantity
which cannot be measured?
Answers
Answer:
Feeling's.
Explanation:
Nobody can measure the feeling of a person or love , etc
A linebacker strikes a fullback with full force in a football game.The reaction force to the force of the linebacker striking the fullback is ____.
a. the fullback falls backwards to the ground
b. the force of the fullback colliding with the ground
c. the fullback fumbles
d. the fullback applies a force to the linebacker
e. the linebacker applies a force to himself.
f. the fullback applies a force to himself
g. the sound of the pads colliding
h. there is a 3-yard loss and the linebacker is applauded
Answers
shelly srarts from rest on her bicycle at the top of hill.after 6.0s she has reached final veocity of 14m/s. what is shelly's acceleration
Answers
V0=0
So v=at.
And v=14m/s, t=6.0s.
So a=v/t, a=14/6m/s^2
a=2.333333m/s^2
A rocket is launched from the origin with an acceleration of 20.0 m/s2 in a straight line at an angle of 30.0 degrees above the horizontal. The launch acceleration lasts for 2.00 seconds at which time the fuel is exhausted. The rocket then falls with an acceleration of 9.80 m/s2 downward. What is the time it takes to reach maximum height?
Answers
Answer:
4.04 seconds
Explanation:
Context before solving:In order to solve this problem, we must keep in mind that the initial 2.00 seconds at which the fuel is exhausted does not signal when the rocket reaches its maximum height.
From this moment on, the rocket has a downward acceleration of 9.8 m/s² but it still has an upwards velocity, which we will calculate. This upwards velocity keeps the rocket moving up for a certain period of time, which we will also calculate.
For this problem, let's set the upwards direction to be positive and the downwards direction to be negative.
To find the time that the rocket takes to reach its maximum height, we are going to use the initial 2.00 seconds and find the additional seconds it takes to reach a final vertical velocity of 0 m/s. This represents the time at which the rocket stops moving and heads in the downwards direction, which takes place after the rocket has reached its maximum height.
Solving for initial velocity:The time in the air of an object in projectile motion can be found using this equation, derived from one of the constant acceleration kinematic equations.
Time in the air (projectile motion):
[tex]$t=\frac{2v_isin\theta}{g}[/tex] where g = gravitation acceleration = 9.8 m/s²Solve for [tex]v_i[/tex] by plugging in 2.00 seconds for t, 30 degrees for theta, and 20.0 m/s² for acceleration, since this is not a constant acceleration problem.
[tex]$2.00=\frac{2v_isin(30)}{20.0}[/tex]Multiply sin(30) and 2 together.
[tex]$2=\frac{v_i}{20}[/tex]Multiply 20 to both sides of the equation.
[tex]$40=v_i[/tex] [tex]v_i=40[/tex]Finding the vertical component:Now we know that the initial velocity of the rocket is 40 m/s. We need to solve for the vertical component of the rocket's velocity in order to solve for the additional time it took after the 2.00 seconds to reach its maximum height.
Vertical component:
[tex](v_i)_y=v_i \times sin\theta[/tex] [tex](v_i)_y=(40) \times sin(30)[/tex][tex](v_i)_y=20[/tex]The vertical component of the velocity vector is 20 m/s.
Finding additional seconds after 2.00 s:Now, in order to solve for the additional seconds that the rocket took to reach its maximum height, let's use one of the kinematic constant acceleration equations that uses the variables [tex]v_f[/tex], [tex]v_i[/tex], [tex]a[/tex], and [tex]t[/tex].
[tex]v_f=v_i + at[/tex]Since we are trying to solve for time, we need to use this equation in terms of the vertical direction, aka the y-direction. Time is the same in either case.
[tex](v_f)_y=(v_i)_y+a_yt[/tex]The final vertical velocity of this rocket is 0 m/s at the top, or its maximum height. We found that the vertical component, aka the rocket's initial vertical velocity, is 20 m/s. The acceleration is given to us: -9.8 m/s² (since it's falling downwards, the acceleration must be negative because we already established this in the beginning).
We are trying to solve for time t. Substitute the known values into the equation.
[tex]0=(20)+(-9.8)t[/tex]Subtract 20 from both sides of the equation.
[tex]-20=-9.8t[/tex]Divide both sides of the equation by -9.8.
[tex]2.040816327=t[/tex] [tex]t=2.04\ \text{seconds}[/tex] Finding total time to reach max height:Now we can take this time and add it to the initial 2.00 seconds of the rocket. This time we just solved for is the time after these initial seconds that the rocket kept going upwards, since its initial vertical velocity was not 0 m/s yet.
[tex]2.00+2.04=4.04 \ \text{seconds}[/tex]The time that the rocket takes to reach its maximum height is 4.04 seconds.
Answer:
4.04 second is your answer hope it help you........
Convert 100°c into Faherenite and kelvin in steps.
Answers
Answer:
100°c = 373.15 K
100°C=212°F
Explanation:
Given the 100°CTo convert Celsius to Kelvin, we need the following equation.
°C + 273.15 = K
100°C + 273.15 = K
373.15 = K
Therefore, 100°c = 373.15 K
Celsius To Fahrenhite:F = 9/5C + 32
=9/5(100)+32
= (180) + 32
= 212°
Therefore,
100°C=212°F
A ball thrown vertically upward is caught by the thrower after 2.93 s. Find the initial velocity of the ball. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s.
Answers
Answer:
The initial velocity of the ball is 28.714 m/s
Explanation:
Given;
time of flight of the ball, t = 2.93 s
acceleration due to gravity, g = 9.8 m/s²
initial velocity of the ball, u = ?
The initial velocity of the ball is given by;
v = u + (-g)t
where;
v is the final speed of the ball at the given time, = 0
g is negative because of upward motion
0 = u -gt
u = gt
u = (9.8 x 2.93)
u = 28.714 m/s
Therefore, the initial velocity of the ball is 28.714 m/s
What is an electron?
Answers
Answer:
A stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.
Explanation:
In more simple terms, an electron is a negatively charged subatomic particle.
Hope that helps :)
Answer:
An electron is a particle with negative charge that can be found in the atom, along with neutrons and protons
What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100 g of the substance increases in temperature from 10 degrees Celsius to 70 degrees Celsius?
Answers
Answer:
I'm sorry to inform that I couldn't find an answer to this question. Socratic can help! This learning app, powered by Google AI, helps you understand your school work at a high school and university level. Ask Socratic a question and the app will find the best online resources for you to learn the concepts.
Explanation:
4. A box of books weighing 325 N moves at a constant velocity across the floor when the box is pushed with a force of 425 N exerted downward at an angle of 35.2° below the horizontal. Find mk between the box and the floor.
Answers
Answer:
0.61°
Explanation:
Since the box move at constant velocity, it means there is no acceleration then we can say it has a balanced force system.
Pulling force= resistance force
From the formula for pulling force,
F(x)= Fcos(θ)
= 425×cos(35.2)
=347N
The force exerted downward at an angle of 35.2° below the horizontal= Fsin(θ)= 425sin(35.2)
=425×0.567=245N
Resistance force= (325N+ 245N) (α)= 570N(α)
We can now equates the pulling force to resistance force
570 (α)= 347N
(α)= 347/570
= 0.61
based on your reading "take a closer look" what can you say about the image that forms on the retina of your eye?
Answers
Answer:
it is an upside-down image but the brain realizes it and corrects it in its orientation so we see it in right direction.
Answer:
The lens of the eye is a convex lens. The image that it forms on the retina is upside down.
Explanation:
The eye makes an image, but it is upside down, the brain corrects the image and turns it right side up
Reena has rolled down her toy car through a ramp. When she increases the height of the ramp (10 cm ) the car has travelled 5 metres and she increases the height of the ramp (13 cm) the car has travelled 6 metres . What happened when she raises the height of the ramp?
Answers
Answer:
As she raises the height of the ramp, the speed of the toy car decreases.
Explanation:
Speed is the ratio of the distance traveled by an object to the time taken.
i.e speed = [tex]\frac{distance}{time}[/tex]
From the given question, it would be observed that:
i. when the height of the ramp was 10 cm, the car traveled 5 meters.
ii. when the height of the ramp was increased to 13 cm, the car traveled 6 meters.
Therefore, an increase in the height of the ramp causes a decrease in the speed of the toy car so that the distance traveled per unit time increases. Showing that there is an inverse relationship between the height of the ramp and the speed of the toy car.
In which scenario will the two objects have the least gravitational force between them?
Answers
Answer:
A
Explanation:
In scenario A the two objects have the least gravitational force between them.
What is gravitational force?Gravitational force is defined as the force which one mass exert on the other mass separated by finite distance. Mathematically gravitational force is directly proportional to product of mass and inversely proportional to square of distance between them.
Force between two mass,
F = Gmm/r²
Given question, to find when have the least gravitational force between two masses so from option A we see there separation distance is maximum 1.5 m and mass product is less than option B.
So least gravitational force when masses are 12 kg and separation distance is 1.5 meter.
To learn more about gravitational force refer to the link:
brainly.com/question/12528243
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who songs are better jason derulo or Dababy , roddy ricch
Answers
Answer:
roddy i guess?
Explanation:
Answer:
Dababy and Roddy Ricch. Jason's songs use to be fire years back but now....not so much.
Explanation:
If it takes 100 N to move a box 5 meters, what is the work done on the box?
A. 20 J
B. 5,000 J
C. 5 J
D. 500 J
Answers
Answer: D. 500 J
=========================================================
Explanation:
To find the amount of work done, we multiply the force by displacement
work = force*displacement
work = (100 N)*(5 m)
work = (100*5) Nm
work = 500 J
In this case, "Nm" refers to "Newton meters" and not "nanometers"
1 newton meter is equal to 1 joule
Which of the following is not a true statement about atomic bonds?
Answers
Answer:
Havent seen this one before but the explanation should help you out :)
Explanation:
There are only three atomic bonds.
Ionic bonding.
Covalent bonding.
Metallic bonding.