Please help
A man stands on a freely rotating platform with his arms extended, his rotational frequency is 0.25rev/s. But when he draws them in, his frequency is 0.80revs/s. Find the ratio of his moment of inertia in the first case to that in the second.​

Answer:  62.25

Explanation: F = ma

F = 7.5 * 8.3

F = 62.25

Thus, the answer is 62.25 Newtons.

Would appreciate brainliest <3

The increase in tension on the steel wire is 8,484.75 N.

The given parameters;

The area of the steel wire is calculated as follows;

[tex]A = \pi r^2\\\\A = \pi \times (2\times 10^{-3})^2\\\\A = 1.257 \times 10^{-5} \ m^2[/tex]

The extension of the steel wire is calculated as follows;

[tex]\Delta l = \alpha \times l\times \Delta T\\\\\Delta l = (12\times 10^{-6}) \times (8) \times (10 + 273)\\\\\Delta l = 0.027 \ m[/tex]

The increase in tension on the steel wire is calculated as follows;

[tex]E = \frac{stress}{strain } = \frac{\ F/A}{\Delta l/l} \\\\E = \frac{F\times l}{A \times \Delta l} \\\\F = \frac{E\times A \times \Delta l }{l} \\\\F = \frac{(2\times 10^{11}) \times (1.257\times 10^{-5})\times 0.027}{8} \\\\F = 8,484.75 \ N[/tex]

Thus, the increase in tension on the steel wire is 8,484.75 N.

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Answer:

Explanation: If the engines in both of the airplanes are at the same Weight  then The engines in both of the airplanes would stil have the same mass because mass stays the same everywhere

Since mass is constant everywhere, if the engines in both airplanes are at the same weight, the engines in both airplanes would still have the same mass.

Weight is the force an object exerts, mass is the amount of matter that makes up an object. Newton is the SI unit of weight while kilogram is the SI unit of mass.

Given that in question the same type of engine is placed in two different air-planes The first air-plane is twice as heavy as the second Suchane Wrich statement is correct about the mass of the air-plane and its acceleration, assuming a constant net force.

Increasing the acceleration of the air-plane causes the enging to provide more force.

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The period of the pendulum allows to find the result for how much it advances when the length is reduced is:

           Δt = 1550 s

Simple harmonic motion is an oscillatory motion where the restoring force is proportional to the displacement.

In the case of the simple pendulum, this is fulfilled for small angles minus 15º, the angular velocity of the pendulum is

           w = [tex]\frac{g}{L}[/tex]  

Angular velocity and period are related

           w = [tex]\frac{2pi}{T}[/tex]

We substitute

            T = [tex]2\pi \ \frac{L}{g}[/tex]  

They indicate that for the initial length L₀ and the pendulum marks the exact time, how much time changes if the length is  3.97 feet, therefore the initial length is L₀ = 3.90 feet.

            [tex]T_o^2 = 4 \pi ^2 \ \frac{L_o}{g}[/tex]  

The period for the reduced length is:

           [tex]T'^2 = 4\pi ^2 \ \frac{L}{g}[/tex]  

The relationship between the periods is:

            [tex]( \frac{T}{T'}^2 = \frac{L_o}{L} \\T' = \sqrt{\frac{L_o}{L} } \ T[/tex]

Let's calculate

             T ’=  [tex]T \ \sqrt{\frac{3.97}{3.9} }[/tex]  

             T ’= T 1.01795

In the total time of a day.

             T = 24 hours (3600 s / 2h) = 86 400 s

We calculate

             T ’= 86400 1.01795

              T ’= 87,950 s

Therefore the pendulum moves forward in a time of:

           ΔT = T'- T

           ΔT = 87950 - 86400

           ΔT = 1550 s

In conclusion, using the period of the pendulum we can find the result for how much it advances when the length is change is:

           ΔT = 1550 s

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Hi there!

In this instance, the object spinning in a horizontal circle will experience a net force in the horizontal direction due to tension.

The net force is equivalent to the centripetal force, so:

∑F = T

mv²/r = T

Solve for v:

v = √rT/m

v = 13.96 m/s

The actual weight of the gas = apparent weight + weight.

The actual weight = [tex]W_{A}[/tex] + W

Given that a plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again.

If the apparent weight of the gas is the difference between these two masses, then let the apparent weight = [tex]W_{A}[/tex]

The gas is squeezed out of the bag to determine its volume by the displacement of water. Since

density = mass / volume

The density of water is 1000 kg/[tex]m^{2}[/tex]

we can get the mass of the gas by making m the subject of the formula.

W = mg

The actual weight of the gas = apparent weight + weight

That is,

The actual weight =  [tex]W_{A}[/tex] + W

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Answer:

True

Explanation:

Magnitude is the "value" the greater the value the greater the force is and vice versa

Answer:

TRUE

Explanation: I did the test

Hope this helps

Answer:

Con el cielo del agua

Explanation:

espero que te ayude

Answer:

destroy

Explanation:

cuz if anyhow throw rubbish, it will affect/destroy the world environment

Answer:

bathing regularly 2pollute 3 throwing waste in land water water pollution

Given our understanding of the situation, for this vehicle with four wheels is traveling in a linear path through soft dirt, we would expect for only two wheels to leave tire track impressions.

The vehicle has four wheels, and one might think initially that it makes sense for all four wheels to create tire track impressions on the dirt. This assessment is correct, all four tires will create impressions, However, not all four tires will leave a said impression.

This is due to the fact that as the vehicle advances, the tires in the back will erase the impressions left by the front tires. Therefore, only two tire track impressions will be left.

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Answer:

1

+

1

is

2

Explanation:

because if you add one to a one it would end up being 2 <3

Answer: 2

Explanation: 1+1=2

This was THE hardest question I've ever decided to answer

Answer:

Explanation:

350 cm / 25 cm = 14 radians

14 rad / 2π rad/rev = 2.23 revolutions

Answer:

By definition the acceleration due to gravity at the surface is g:

The altitude above the surface is zero for an acceleration of g.

The value of the constant K is [tex]\mathbf{K = \dfrac{1}{LC}}[/tex]

According to Kirchhoff's loop rule, the total algebraic sum of potential differences in any loop, combining voltage provided by voltage sources as well as resistive components, must equal zero.

Thus, the relation for Kirchhoff's loop rule can be expressed as:

[tex]\mathbf{\dfrac{q}{c}- L\dfrac{dI}{dt} = 0}[/tex]

We all know that the current in the nonconstant charge flow can be written as:

[tex]\mathbf{I = \dfrac{dq}{dt}}[/tex]

∴

Replacing the current (I) into Kirchhoff's loop rule, we have:

[tex]\mathbf{ L\dfrac{d}{dt} ( \dfrac{dq}{dt})= -\dfrac{q}{c}}[/tex]

[tex]\mathbf{ \dfrac{d^2q}{dt^2}= -\dfrac{q}{Lc} \ \ ---(1)}[/tex]

From the given question, when the switch is closed

[tex]\mathbf{ \dfrac{d^2q}{dt^2}= -kq\ \ ---(2)}[/tex]

Then, the charges on the capacitor start to b, resulting in the rise of the current in the circuit.

∴

By equating both equations (1) and (2);

[tex]\mathbf{K = \dfrac{1}{LC}}[/tex]

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Answer:

[tex]E=mgh[/tex]

[tex]m=3kg[/tex]

[tex]h=4m[/tex]

[tex]g=9.8m/s^{2}[/tex]

[tex]E= 3*4*9.8=117.6J[/tex]

Explanation:

Only substitute amounts to formula.

Hope this helps ;)

Cheers :D

C is the correct answer:))))))))

Answer:

i think its his law of inertia

Explanation:

this law is about motion

Answer:

Explanation:

F = ma

3(9.81) - 3.8(9.81sin36) = (3 + 3.8)a

a = 1.10566...

a = 1.1 m/s²

the 3.8 kg mass will move up slope and the 3 kg mass will fall at that acceleration.

Answer:

pollute the environment

Recall the definition of the cross product with respect to the unit vectors:

i × i = j × j = k × k = 0

i × j = k

j × k = i

k × i = j

and that the product is anticommutative, so that for any two vectors u and v, we have u × v = - (v × u). (This essentially takes care of part (b).)

Now, given a = 8i + j - 2k and b = 5i - 3j + k, we have

a × b = (8i + j - 2k) × (5i - 3j + k)

a × b = 40 (i × i) + 5 (j × i) - 10 (k × i)

… … … … - 24 (i × j) - 3 (j × j) + 6 (k × j)

… … … … + 8 (i × k) + (j × k) - 2 (k × k)

a × b = - 5 (i × j) - 10 (k × i) - 24 (i × j) - 6 (j × k) - 8 (k × i) + (j × k)

a × b = - 5k - 10j - 24k - 6i - 8j + i

a × b = -5i - 18j - 29k

Answer:

Explanation:

If a = 8i + j - 2k and b = 5i - 3j + k show that a) a x b = -5i - 18j - 29k b) b X a = 50 + 18j +29k​

Answer:

The answer for the question should be True

Increasing the angle of inclination of the plane decreases the velocity of the block as it leaves the spring.

Reasons:

The energy given  to the block by the spring = [tex]\mathbf{0.5 \cdot k \cdot x^2}[/tex]

According to the principle of conservation of energy, we have;

On a flat plane, energy given to the block = [tex]0.5 \cdot k \cdot x^2[/tex] = kinetic energy of

block = [tex]0.5 \cdot m \cdot v^2[/tex]

Therefore;

0.5·k·x² = 0.5·m·v²

Which gives;

x² ∝ v²

x ∝ v

On a plane inclined at an angle θ, we have;

The energy of the spring = [tex]\mathbf{0.5 \cdot k \cdot x^2}[/tex]

The energy given to the block = [tex]0.5 \cdot k \cdot x^2 - m \cdot g \cdot sin(\theta)[/tex] = The kinetic energy of block as it leaves the spring = [tex]\mathbf{0.5 \cdot m \cdot v^2}[/tex]

Which gives;

[tex]0.5 \cdot k \cdot x^2 - m \cdot g \cdot sin(\theta) = 0.5 \cdot m \cdot v^2[/tex]

Which is of the form;

a·x² - b = c·v²

a·x² + c·v² = b

Where;

a, b, and c are constants

The graph of the equation a·x² + c·v² = b  is an ellipse

Therefore;

Please find attached a drawing related to the question obtained from a similar question online

The possible question options are;

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The expressions for the traveling and standing wave to find the results for the questions about the displacement and speed of the particle are:

       a) For time zero, the displacement at position x = 0.30 m is y = 3.04 cm

     b) For time zero, the displacement at position x = 0.40 m is: y = 0

      c) For the point x = 0.30 and time t = 0.9s, the velocity of the particle is:

          v = 9.11 cm / s

      d) For the point x = 0.30 and time t = 1.3s, the velocity of the particle is:

          v = 9.65 cm / s

The traveling wave is a disturbance in the medium that moves at constant speed, in the case of a transverse wave the expression for the perpendicular oscillation is:

         y = A sin (kx - wt)

Where y is the oscillation perpendicular to the direction of the displacement, A the amplitude, k in wave number and w the angular velocity.

Standing waves are formed when a traveling wave collides with an obstacle and is reflected, in this case the sum of the two waves gives a wave that does not shift in time and fulfills the relationship

           [tex]\frac{\lambda}{2} = \frac{L}{n}[/tex]  

Where λ is the wavelength, L the distance between the reflection points and n the number of nodes.

Indicates that for the standing wave the distance between an antinode and the node is x = 0.20 m, therefore

               [tex]\frac{\lambda}{4} = \frac{L}{1}[/tex]  

              λ = 4L

              λ = 4 0.20

              λ = 0.80 m

The wave number.

              k = [tex]\frac{2\pi }{\lambda }[/tex]  

              k = [tex]\frac{2 \pi }{0.80 }[/tex]  

              k = 2.5π i m⁻¹

In the associated traveling wave, from the graph we can see that the period of the wave is:

             T = 2.8 s

the angular velocity is related to the period.

             [tex]w=\frac{2\pi}{T} \\w = \frac{2\pi }{2.8}[/tex]  

             w = 0.714π  rad/s

indicate the maximum displacement that is the amplitude of the wave.

              A = [tex]y_s[/tex]  

             A = 4.3 cm

Let's write the equation of the traveling wave.

              y = 4.3 sin [π (2.5 x - 0.714 t)]

with this expression we can answer the questions.

a) the displacement of the particle for x = 0.30 m

            y = 4.3 sin (π (2.5 0.30 - 0.714 t))

            y = 4.3 sin π( 0.75 - 0.714 t(

Remember that the angles must be in radians.  For time t = 0 the displacement is

              y = 4.3  0.707

              y = 3.04 cm

b) The displacement for x = 0.4m

              y = 4.3 sin (π 2.5 0.4)

              y = 0 cm

c) the transverse velocity of the wave at x = 0.30 m for the time of t = 0.90s

the speed of the wave is

              [tex]v= \frac{dy}{dt} \\v= A w cos ( kx - wt)[/tex]  

              v = 4.3 0.714π cos π(2.5 0.3 - 0.714 t)

              v = 9.65 cos π(0.75 - 0.714 t)

For time t = 0.90 s the velocity is:

            v = 9.65 cos π(0.75 - 0.714 0.9)

            v = 9.65 0.9436

            v = 9.11 cm / s

d) The velocity for time t = 1.3 s

           v = 9.65 cos π(0.75 - 0.714 1.3)

           v = 9.65 0.9999

           v = 9.65 cm / s

In conclusion, using the expressions for the traveling and standing wave, we can find the results for the questions about the displacement and speed of the particle are:

      a) For time zero, the displacement at position x = 0.30 m is y = 3.04 cm

     b) For time zero, the displacement at position x = 0.40 m is: y = 0

      c) For the point x = 0.30 and time t = 0.9s, the velocity of the particle is:

          v = 9.11 cm / s

      d) For the point x = 0.30 and time t = 1.3s, the velocity of the particle is:

          v = 9.65 cm / s

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Answer:

True

Explanation:

Since positive and negative forces are both opposites of each other they attract. But if the forces are the same where both are positive or negative thye repel do to being the same charges in that case the picture would show lines moving in opposite directions.

The distance the car has skidded if it had been moving at 40.0 m/s is 27.2m

The linear force acting on the car is opposed by the frictional force. Hence;

[tex]F=F_f[/tex]

[tex]ma = -\mu R\\ma =-\mu mg[/tex]

m is the mass of the car

a is the acceleration

[tex]\mu[/tex] is the coefficient of friction

R is the normal force

Given the following parameters

[tex]a=-\mu g[/tex]

[tex]a =-0.75(9.8)\\a=-7.35m/s^2[/tex]

Get the distance the car has skidded if it had been moving at 40.0 m/s

[tex]v^2=u^2+2as[/tex]

[tex]0^2=20^2+2(-7.35)s\\0=400-14.7s\\s=\frac{400}{14.7}\\s= 27.2m[/tex]

Hence the distance the car has skidded if it had been moving at 40.0 m/s is 27.2m

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Answer:

Explanation:

v² = u² + 2as

s = (v² - u²)/2a

s = (0² - 75²) / (2(-14))

s = 200.8928

s = 200 m

Answer:

Identification

Explanation:

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