PLEASE HURRY!!
Look at the image below!

Answer:

The answer is "ls command".

Explanation:

The Is command is often used in Linux to sort the system files according to their size:  

#ls – F | grep ‘*$’ -s

And the other regulation they can use is  

#ls -Fla | grep ‘^\S*x\S*’

Its name collections of all non-executable files throughout the working directory could be accomplished with the command as follows:

find ! -term+|||-type s-t |find ! - term + ||| - type f-tr

Answer:

hope i get brainliest

Explanation:

Emerging Technologies

Abstract

The purpose of this paper is to summarize the advantages of computers/software and the use of computer technology in investigations. Summarize the disadvantages to law enforcement with respect to the advancements of computers. Real cases will be researched in order to understand how computers can be utilized in criminal activities, as well as a case that the use of a computer was beneficial to the prosecution in a criminal case. A final conclusion paragraph will address my personal subjective opinion as to whether these technologies, in an overall sense are a benefit or hindrance to law enforcement efforts.

Introduction

Since computers have become such a big part of our…show more content…

From utilizing computers in cars so officers could run a license plate and social security number to see if there are any warrants out for the person they stopped, to more advances such as carrying cell phones, GPS tracking systems in cars, crime mapping tools, information sharing between state and local law enforcement, to even sharing information across countries. Technology has come a long way in helping officers and other agents within the criminal justice system do their job.  

Just a bit more about the advantages of the things mentioned above and time to move on. The most interesting thing is Geographic Information Systems (GIS), which has become a most important tool for law enforcement agencies. GIS, other mapping software and desktop computers now are capable of mapping and data analysis that is way above and beyond what used to be possible with backroom mainframe computers (Rubley, 2011).

Another great advancement is the widespread use of everyone using mobile devices. Many officers now use two to three cell phones.

Answer:Go to the location where you want to save the file.

Explanation:

Answer:

C. Institute of Electrical and Electronics Engineers (IEEE)

Explanation:

Edge 2020

Answer:

C.

Explanation:

look up the song 2055 it ia a vibe to do work to

Answer:

Follows are the solution to this question:

Explanation:

In the linear selected algorithms scans the given field sequentially but instead calculates the fixed amount by crossing the items throughout the list since they are displayed. Take into consideration the various chosen algorithm:

S(A, n, i) Algorithm:

In array B, copy array A items.

To save results, construct an array C of height.

Start Loop j = 0 to i-1.

Determine array B's lowest value.

In array C, also save the minimum value.

Delete from array B the minimum value.

Back the C array.

Analysis of runtime:

In i iterations, the external loop is used, although i have to compute the number of small lots.

This internal loop should run and calculate the minimum variable, whereby n is the input array length at the most values of n.

Its cumulative runtime is equal to O(in)+C =

O(in). All remaining operations are done at a precise rate.

The combine type technique requires that division concept to

sort the sorted array either in or upwards backward order.

Follow the appropriate method using merge type to

select the shortest items of a certain list.

T (A, n, i) algorithm:

In B array, copy array A elements.

To save the output, build a C array of sizes.

Using merge form in an increasing order to sort all items of the B list.

Start the loop j= 0 to i-1.

Save A[j] value in C[j].

Return array C,

return array C.

Analysis of run time:

The combined function requires O (n log n) to arrange a size n list.

Its number of samples in the process to construct the resulting sequence becomes equal to i since i is the minimum number of elements to also be calculated. All remaining transaction is performed in continuous time.

The time to work is O (n log n) + O i + C = O (n log n). The time needed.

The complexities of the following algorithms are similar:

Scenario 1: S is stronger than to the T-algorithm

Consider the number for smallest elements to also be calculated or even the I value is significantly smaller than the number of array elements.  Let i = 2 and  n = 16.

Its algorithm S requires O(in) time for both the calculation of a result, who in this case is equivalent to (2 16).

If algorithm T finds the initiative of O (n log n), who in this case is equivalent to (16 logs 16) = (16 4).

The S method, therefore, operates better than that of the T algorithm, if another I value exceeds the log n value.

Scenario 2: Algorithm T is much more successful that algorithm S

Evaluate if the number of components which must be calculated is smaller or if the value of I is comparable with that of the items inside the array.

Let the I = 12 quality and n = 16 value. Its S method applies O(in) time, and in this, the situation is just like (12 16).

Hence, the algorithm T performs better than the algorithm S when the value of i is greater than the value of the log n.

Answer:

The program needs one true answer to run

after the If statement is false

Explanation:

Else-if statements are attached to If statements. They run if the If statement is false, and have their own condition. If their condition passes, they run their own block of code.

Answer:

the answer is D :)

Answer:

Written in Python

import math

import random

Dangle = random.randint(0,181)

pi = 22/7

Rangle = Dangle * pi/180

Rsin = math.sin(Rangle)

Rcos = math.cos(Rangle)

Result = Rsin**2 + Rcos**2

print("Result = "+str(Result))

Explanation:

The next two lines import math and random library respectively

import math

import random

This line generates a random integer between 0 and 180

Dangle = random.randint(0,181)

This line initializes pi to 22/7

pi = 22/7

This line converts angle to radians

Rangle = Dangle * pi/180

The next two lines calculate the sin and cosine of the angle in radians

Rsin = math.sin(Rangle)

Rcos = math.cos(Rangle)

This line implements sin^2 theta + cos^2 theta

Result = Rsin**2 + Rcos**2

This line prints the required Result

print("Result = "+str(Result))

Answer:

Color: Black

Font: Times New Roman

Size: 12

Explanation:

Answer:

Times new roman

front 12

color:black

Explanation:

Times new roman

front 12

color:black

Answer:

RAM (Random access memory)helps in reading aswell as writing data

Answer:

b

Explanation:

Answer:

Essentially, computer software controls computer hardware. These two components are complementary and cannot act independently of one another. In order for a computer to effectively manipulate data and produce useful output, its hardware and software must work together.

Explanation:

Hope you understand it :)

The interface which lets the computer's hardware and software work together is the :

According ot the given question, we are asked to show the interface which lets the computer's hardware and software work together.

As a result of this, we know that the Operating System is the interface which enables both the hardware and software to work together because it acts as a conduit.

There are different versions of OS which includes:

Therefore, the correct answer is Operating System

Read more about Operating System here:

https://brainly.com/question/20870614

Answer:

import java.util.Scanner;

public class LabProgram{

    public static void main(String []args){

       Scanner input = new Scanner(System.in);

       int red,blue,green,smallest;

       System.out.print("Enter three numbers between 0 and 255 (inclusive): ");

       red =input.nextInt();

       green =input.nextInt();

       blue =input.nextInt();

       if(red <= blue && red <= green){

       smallest = red;

       }

       else if(green <= red && green <= blue){

           smallest = green;

       }

       else{

            smallest = blue;

       }

       System.out.print((red - smallest)+" "+(green - smallest)+" "+(blue - smallest));

}

}

Explanation:

This line declares necessary variables

int red,blue,green,smallest;

This line prompts user for input of 3 numbers

System.out.print("Enter three numbers between 0 and 255 (inclusive): ");

The next three lines gets user inputs

       red =input.nextInt();

       green =input.nextInt();

       blue =input.nextInt();

The following iteration checks for the smallest for red, green, blue

       if(red <= blue && red <= green){

       smallest = red;

       }

       else if(green <= red && green <= blue){

           smallest = green;

       }

       else{

            smallest = blue;

       }

This line prints the required output

       System.out.print((red - smallest)+" "+(green - smallest)+" "+(blue - smallest));

the weight variable is an integer and the input is 115.6. Integers cannot have decimals, therefore, the output is 115.

Your answer should be 115

Answer:

Code works perfectly

Explanation:

There is nothing wrong with your program as it runs perfectly and displays the expected results.

You may need to compile with another compiler if you're not getting the required results.

I've added the source code as an attachment (unedited)

Answer:

Here is the C program:

#include <stdio.h>  //to use input output functions

int main(void) {   //start of main function

 int arrowBaseHeight = 0;  //stores value for arrow base height

int  arrowBaseWidth = 0;  //stores value for arrow base width

 int arrowHeadWidth = 0 ;  //stores value for arrow head width

 int i, j;  //to traverse through the rows and columns

 printf("Enter arrow base height:\n");  //prompts user to enter arrow base height value

 scanf("%d", &arrowBaseHeight);  //reads input value of arrow base height

 printf("Enter arrow base width:\n");  //prompts user to enter arrow base width value

 scanf("%d", &arrowBaseWidth);  //reads input value of arrow base width

 while (arrowHeadWidth <= arrowBaseWidth)  {   //iterates as long as the value of arrowHeadWidth is less than or equals to the value of arrowBaseWidth  

     printf("Enter arrow head width:\n");   //prompts user to enter arrow head width value

     scanf("%d", &arrowHeadWidth);   //reads input value of arrow head width

     printf("\n"); }

 for (i = 0; i < arrowBaseHeight; i++)    {   //iterates through rows

     for (j = 0; j < arrowBaseWidth; j++)  {   //iterates through columns

         printf("*");       }   //prints asterisks

     printf("\n");   }   //prints a new line

 for (i = arrowHeadWidth; i > 0; i--)    {   //loop for input length

     for (j = i; j > 0; j--)        {   //iterates for triangle ( to make arrow head)

         printf("*");       }   //prints asterisks

     printf("\n");   }  } //prints new line

Explanation:

The program asks to enter the height of the arrow base, width of the arrow base and the width of arrow head. When asking to enter the width of the arrow head, a condition is checked that the arrow head width arrowHeadWidth should be less than or equal to width of arrow base arrowBaseWidth. The while loop keeps iterating until the user enters the arrow head width larger than the value of arrow base width.  

The loop is used to output an arrow base of height arrowBaseHeight.

The nested loop is being used which as a whole outputs an arrow base of width arrowBaseWidth. The inner loop draws the stars and forms the base width of the arrow, and the outer loop iterates a number of times equal to the height of the arrow.

The last nested loop is used to output an arrow head of width arrowHeadWidth. The inner loop forms the arrow head and prints the stars needed to form an arrow head.  

The screenshot of output is attached.

Answer:

I think a exabyte, if not its probably a terabyte

Explanation:

Answer:

I think the answer would be C. atmospheric scientist

The statements that is true regarding file management are;

File Management is known to be one that is made up of the common operations done  on files or groups of files, such as creating, opening, renaming, and others

Note that in file management,  Each user are required to access to create, delete, read, write, and modify a file and also user need to have limitations to no access to others files.

Hence, The statements that is true regarding file management are;

Learn more about file management from

https://brainly.com/question/12736385

#SPJ1

Since age is less than 5, the else statement will run. The output will be less

Answer: For users to be able to communicate with a large number of other people around the world, their LAN needs to be connected to a WAN, which has an almost unlimited geographical distance.

Explanation: Correct on Edg 2020/2021.

Answer:

school

family home

business

internet isnt safe

Explanation:

Answer:

Its all of the above

A: on the internet

B: in schools

C: In businesses

D: in the family home

Explanation:

EDG2021

(I found the answer in my notes, and it is all of them)

Answer:

mobile computing

Explanation:

Answer:

I said name server and domain name system, although it may not be correct.

Answer:

A and D

Explanation:

Answer:

The program written in Java without comment is as follows

import java.util.*;

public class MyClass {

   public static void main(String args[]) {

       Scanner input = new Scanner(System.in);

       System.out.print("Year: ");

       int y = input.nextInt();

       int a = y%19;

       System.out.println("a = "+a);

       int b = y / 100;

       System.out.println("b = "+b);

       int c = y%100;

       System.out.println("c = "+c);

       int d = b / 4;

       System.out.println("d = "+d);

       int e = b%4;

       System.out.println("e = "+e);

       int g = (8 * b + 13)/25;

       System.out.println("g = "+g);

       int h = (19 * a + b - d - g + 15)%30;

       System.out.println("h = "+h);

       int j = c/4;

       System.out.println("j = "+j);

       int k = c%4;

       System.out.println("k = "+k);

       int m = (a + 11 * h)/319;

       System.out.println("m = "+m);

       int r = (2 * e + 2 * j - k - h + m + 32)%7;

       System.out.println("r = "+r);

       int n = (h - m + r + 90)/25;

       System.out.println("n = "+n);

       int p = (h - m + r + n + 19)%32;

       System.out.println("p = "+p);

   }

}

Explanation:

I've added the full source code as an attachment where I use comments to explain difficult lines

Answer:

better with pro dud

Explanation:

.....helps??...

Answer:

The Following are the code to this question:

def cost(miles, milesPerGallon, dollarsPerGallon):##defining a method cost that accepts three parameter

   return miles / milesPerGallon * dollarsPerGallon# calculate cost and return it value  

milesPerGallon = float(input('Enter miles/Gallon value: '))#defining variable milesPerGallon for user input  

dollarsPerGallon = float(input('Enter dollars/ Gallon value: '))#defining variable dollarsPerGallon for user input

print('{:.5f}'.format(cost(10, milesPerGallon, dollarsPerGallon)))#call method and print its value

print('{:.5f}'.format(cost(50, milesPerGallon, dollarsPerGallon)))#call method and print its value

print('{:.3f}'.format(cost(400, milesPerGallon, dollarsPerGallon)))#call method and print its value

Output:

Enter miles/Gallon value: 20.0

Enter dollars/ Gallon value: 3.1599

1.57995

7.89975

63.198

Explanation:

In the above-given code, a method "cost" is defined, that accepts three value "miles, milesPerGallon, and dollarsPerGallon" in its parameter, and use the return keyword for calculating and return its value.

In the next step, two variable "milesPerGallon, and dollarsPerGallon" is declared, that use the input method with float keyword for input floating-point value.

After input value, it uses a print method with different miles values, which are "10,50, and 400", and input value to pass in cost method to call and print its return value.

Answer:

The SI unit of energy rate

Explanation:

is the watt, which is a joule per second. Thus, one joule is one watt-second, and 3600 joules equal one watt-hour.

Answer:

Explanation:

information tech is technology that teaches you information, and communication tech is tech that lets you talk to family and friends and meet new people.

Answer:

The main difference between information technology and communication technology is that Information technology is a subject that is use of computers to store, retrieve, transmit and manipulate data, or information, often in the context of business or other enterpise whereas a Communication technology is the use of computers to communicate with family and friends.