Please someone help me!
I need this done ASAP *URGENT*
I Need this done before Thursday or Friday because Friday is my last day of school so please finish this today!
Best answer gets BRAINLIEST
PLEASE HURRY AND ANSWER ALL QUESTIONS CORRECTLY
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What’s the difference worksheet
Atoms,molecules,elements and compounds
PLEASE PLEASE PLEASE PLEASE PLEASEEEEEEE ANSWER THIS I only have TWO days of school left! And I need this done quickly

Please Someone Help Me! I Need This Done ASAP *URGENT* I Need This Done Before Thursday Or Friday Because

Answers

Answer 1

Answer:

A molecule is the smallest particle of a substance that is made up of 2 or more atoms

An atom is the smallest particle of any pure element

An element is a substance that cannot be broken chemical and physical processes

A molecule is known as the building block of matter

A compound is a chemical substance that is made up of 2 more more different atoms bonded together


Related Questions

I need help with my chemistry

Answers

Answer:

Single displacement

Explanation:

single replacement.

Congratulations you have worked hard and now you are done with the year! I am so proud of you!

Answers

Answer:

lololol

Explanation:

what is the shape of the TeF5 anion ​

Answers

Answer:

There are four atoms and two lone pairs around the central atom, which corresponds to AX4E2 or square planar. The shape of XeF4 is square planar.

Explanation:

I hope it's help u


i. Complete the chemical reaction to show this. Make sure your equation is balanced. (2 points)
C6H12O6 + 02 →

Answers

C6H12O6 + O2 = CO2 + H2O
Balanced Equation:
1 = C6H12O6
6 = O2
6 = CO2
6 = H2O

This is the reaction of respiration. Hence, the complete reaction is:

C₆H₁₂O₆ + O₂ → 6CO₂ + 6H₂O

What is respiration?

Respiration is defined as a metabolic process wherein the living cells of an organism obtain energy (in the form of ATP) by taking in oxygen and releasing carbon dioxide from the oxidation of complex organic compounds. There are two forms of respiration: aerobic and anaerobic.

Aerobic respiration occurs in the presence of oxygen, while anaerobic respiration occurs in the absence of oxygen.

Because it generates the energy required for body function, respiration is significant. It gives the cells oxygen and releases harmful carbon dioxide. Hence, the reaction of cellular respiration is:

                           C₆H₁₂O₆ + O₂ → 6CO₂ + 6H₂O

Learn more about respiration, here:

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how many liters of hydrogen gas I needed to react with CS2 to produce 2.5 L of CH4 At STP

Answers

Answer:

9.8 L

Explanation:

The reaction that takes place is:

4H₂(g) + CS₂(g) → CH₄(g)+ 2H₂S(g)

At STP, 1 mol of any gas occupies 22.4 L.

We calculate how many moles are there in 2.5 L of CH₄ at STP:

2.5 L ÷ 22.4 L/mol = 0.11 mol CH₄

Then we convert CH₄ moles into H₂ moles, using the stoichiometric coefficients of the reaction:

0.11 mol CH₄ * [tex]\frac{4molH_2}{1molCH_4}[/tex] = 0.44 mol H₂

Finally we calculate the volume that 0.44 moles of H₂ would occupy at STP:

0.44 mol * 22.4 L/mol = 9.8 L

Brainiest and 10 points
Which has MORE energy?
A. Radio
B. Infrared

Answers

Answer:

B. infrared

hope this helps

have a good day :)

Explanation:

Calculate the volume of 0.07216 M AgNO3 needed to react exactly with 0.3572 g of pure Na2CO3 to produce solid Ag2CO3.

Answers

Answer:

93.4 mL

Explanation:

Let's state the reaction:

2AgNO₃ +  Na₂CO₃  →   Ag₂CO₃  +  2NaNO₃

We determine the moles of sodium carbonate:

0.3572 g . 1mol / 105.98g = 3.37×10⁻³ moles

Ratio is 1:2. We say:

1 mol of sodium carbonate react to 2 moles of silver nitrate

Then, our 3.37×10⁻³ moles of carbonate may react to: 3.37×10⁻³ . 2

= 6.74×10⁻³ moles

If we convert to mmoles → 6.74×10⁻³ mol . 1000 mmol / mol = 6.74 mmol

Molarity is mol/L but we can use mmol /mL

6.74 mol / volume in mL = 0.07216 M

6.74 mol / 0.07216 M = volume in mL → 93.4 mL

4. Are there any solutions that have the measure of -3
? Briefly explain why.

Answers

yes for example : 1 x -3

Which of these is an ion with a charge of 1+?

Answers

The answer is going to be 1 because sodium atom has one electron in its outer shell

What is the relationship between the magnitude of Δ (crystal-field splitting energy for an octahedral crystal field) and the energy of the d-d transition for a d1 complex?
a. The energy of the d-d transition is four times as big as Δ.
b. Δ is twice as big as the energy of the d-d transition.
c. Δ is four times as big as the energy of the d-d transition.
d. Δ is equal to the energy of the d-d transition.
e. The energy of the d-d transition is twice as big as Δ.

Answers

Answer:

B

Explanation:

10. What is the molarity of a solution containing 20 moles of NaCl dissolved in 10 liters of water?
0.5 mol/L
2 mol/L
5 mol/L
10 mol/L

Answers

Answer:

2 mol/L

Explanation:

M=Mol of solute/L. of solution

M=20mol/10L of H2O= 2mol/L

Answer:

2mol/L

Explanation:

got it correct on my quiz

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CH
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C C
C001
CH H
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C C
1
NO ,
2
BY​

Answers

Answer:

hakdog

Explanation:

pangitag lainbbbsjsbshsisbsjsbshxx

what does this mean man

The electrolysis of molten AlCl3 for 2.50 hr with an electrical current of 15.0 A produces ________ g of aluminum metal. Group of answer choices

Answers

Answer:

The correct answer is 12.58 grams.

Explanation:

Based on the given information, the electrolysis equation will be,

Al³⁺ + 3e⁻ ⇔ Al

1 mol of Al needs 3 moles of electron, and the value for 1 mole of electron is 96485 C.

Thus, 1 mole of Al needs 3 × 96485 C = 289455 C

Now the amount of charge passed is,

T = 2.5 hours

= 2.5 × 3600 s = 9 × 10³ s

Q = Current × Time

= 15A × 9 × 10³ s

= 13.5 × 10⁴ C

The moles of Al plated will be,

= 13.5 × 10⁴ / 289455

= 0.4664 mol

The molecular mass of Al is 26.98 grams per mole

Now the mass of Al will be,

= Number of moles × Molecular mass

= 0.4664 × 26.98

= 12.58 grams

A 0.200 M solution of a week acid, HA, is 9.4% ionized. The molar concentration of H+ is 0.0188 M. the Acid-dissociation constant, Ka, for HA is...?​

Answers

We are given:

Initial concentration of HA: 0.200 Molar

The acid is 9.4% ionized

Dissociation constant (α) = (Percent Ionized) / 100 = 0.094

Molar concentration of H+ = 0.0188

Let's Chill! (making the ICE box):

Reaction:       HA         ⇄       H⁺      +      A⁻

Initial:           0.200M               -                -

Equilibrium: 0.200(1-α)      0.200α       0.200α

while we're here, let's confirm the given equilibrium concentration of H⁺ ions

from the table here, we can see that the equilibrium concentration of H⁺ ions is 0.200α, we know that α = 0.094

[H⁺] = 0.200α = 0.200 * 0.094 = 0.0188 M

which means that we're on the right track

We're basically scientists at this point (finding the dissociation constant):

Acid dissociation is nothing but the equilibrium constant, but for the dissociation of Acids

From the reaction above, we can write the equation of the acid dissociation constant:

Ka = [H⁺][A⁻] / [HA]

now, let's take the values from the 'equilibrium' row of the ice box the plug those in this equation

Ka = (0.200α)(0.200α) / [0.200(1-α)]

Ka = (0.200α)²/[0.200(1-α)]

plugging the value of α

Ka = (0.200*0.094)² / [0.200(0.906)]

Ka = (0.0188)² / 0.1812

Ka = 1.95 * 10⁻³

55
Tam pours salt water into one beaker and then pours acid into another beaker.
Tam realises that the liquids are not labelled.
What should Tam do?
A
Smell each liquid in order to identify them.
В.
Guess which beaker contains each liquid.
С
Mix the liquids together to find out what they are.
D
Safely throw away the liquids and get new ones.
3
PM
2021​

Answers

Answer:

correct answer i C i think so

Answer:

Safely throw away the liquids and get new ones.

Explanation:

Not A  because

you shouldn't smell them cause it could be toxic and hurt you

Not B

you should never guess which chemical are which cause if your not correct and use the wrong one you could have a chemical reaction

Not C

you cant mix random liquids it could make a chemical reaction to exploded ore worse create a hurtful gas

Which atom has the smallest atomic radius between cesium, potassium, rubidium, and francium?

Answers

Ur answer is going to be francium

Why do vinyl raincoats become brittle as they get old, even if they are not exposed to air or to any pollutants

Answers

Answer:

The substances made from polyvinyls are generally brittle and hard. This property prevails because the polymer strands present in the polyvinyls form a very regular and well-organized packing composition in the solid-state. The Van der Waals associations between the strands make the substance brittle. To make the substance soft and suitable to use as a raincoat, the incorporation of small molecules is done within the molten polymer before the hardening of the plastic.

These polymer strands act as plasticizers and prevent the strands of polymer from forming a hard and brittle conformation.

Which of these half-reactions represents reduction?
I. Fe2+ → Fe3+
II. Cr2O72- → Cr3+
III. MnO4- → Mn2+

Answers

Answer: The half-reactions represents reduction are as follows.

[tex]Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}[/tex][tex]MnO^{-}_{4} \rightarrow Mn^{2+}[/tex]

Explanation:

A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element  takes place is called reduction-half reaction.

For example, the oxidation state of Cr in [tex]Cr_{2}O^{2-}_{7}[/tex] is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.

[tex]Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}[/tex]

Similarly, oxidation state of Mn in [tex]MnO^{-}_{4}[/tex] is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.

[tex]MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}[/tex]

Thus, we can conclude that half-reactions represents reduction are as follows.

[tex]Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}[/tex][tex]MnO^{-}_{4} \rightarrow Mn^{2+}[/tex]

If the specific heat capacity of copper is 387 J/kg/°C, then how much energy is needed to raise the temperature of 400 g of copper from 30°C to 55°C?

Answers

Answer:

Explanation:

mass = 400 grams * [1 kg/1000 grams] = 0.400 kg

c = 387 Joules / (oC * kg)

Δt = 55 - 30 = 25 oC

E = m*c * Δt

E = 0.4 * 387 * 25

E = 3870 Joules

Calculate the pOH in a solution with [H+] =9.8 • 10-3 M

Answers

The pOH of the solution containing 9.8×10⁻³ M of hydrogen ion concentration, [H⁺] is 11.99

How do i determine the pOH of the solution?

First, we shall determine the hydroxide ion concentration [OH⁻] in the solution. Details below:

hydrogen ion concentration, [H⁺] = 9.8×10⁻³ MHydroxide ion concentration [OH⁻] =?

[H⁺] × [OH⁻] = 10¯¹⁴

9.8×10⁻³ × [OH⁻] = 10¯¹⁴

Divide both side by 9.8×10⁻³

[OH⁻] = 10¯¹⁴ / 9.8×10⁻³

[OH⁻] = 1.02×10⁻¹² M

Finally, we shall determine the pOH of the solution. Details below:

Hydroxide ion concentration [OH⁻] = 1.02×10⁻¹² MpOH of solution =?

pOH = -Log [OH⁻]

pOH = -Log 1.02×10⁻¹²

pOH = 11.99

Thus, from the above calculation, we can conclude that the pOH of the solution is 11.99

Learn more about pOH:

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PLEASE HELP ME!!!!

TRUE or FALSE: When sperm and egg cells combine in fertilization, the
offspring ends up with the same number of chromosomes as their
parents.

Answers

Answer: False

Explanation:

Hope this help

Answer:

True.

Explanation:

Every child will contain the same number of chromosomes as the parents (otherwise they wouldn't be considered the same species). Additionally, animals can only mate with a species containing the same number of chromosomes as themselves. This means if the offspring of the parents had a different number fo chromosomes the offspring would be unable to mate with animals of it's own species.

compare and contrast the three types oflevers.

Answers

Answer:

The difference between the three classes depends on where the force is, where the fulcrum is and where the load is. In a first class lever, the fulcrum is located between the input force and output force. In a second class lever, the output force is between the fulcrum and the input force. write the class of lever.

Explanation:

Determine the molarity and mole fraction of a 1.09 m solution of acetone (CH3COCH3) dissolved in ethanol (C2H5OH). (Density of acetone

Answers

Answer:

Molarity = 0.809 M

mole fraction = 0.047

Explanation:

The complete question is

Calculate the molarity and mole fraction of acetone in a 1.09-molal solution of acetone (CH3COCH3) in ethanol (C2H5OH). (Density of acetone = 0.788 g/cm3; density of ethanol = 0.789 g/cm3.) Assume that the volumes of acetone and ethanol add.

Solution -

Solution for molarity:

1.09-molal means 1.09 moles of acetone in 1.00 kilogram of ethanol.

1)  

Mass of 1.09 mole of acetone

= 1.09  mol x 58.0794 g/mol = 63.306 g

Density of acetone = 0.788 g/cm3  

Thus, volume of 1.09 moles of acetone = 63.306 g/0.788 g/cm3 = 80.34 cm3

For ethanol

1000 g divided by 0.789 g/cm3 = 1267.427 cm3

Total volume of the solution = Volume of acetone + Volume of ethanol = 80.34 cm3 + 1267.427 cm3 = 1347.765 cm3  = 1.347 L

a) Molarity:

1.09 mol / 1.347 L = 0.809 M

Mole Fraction  

a) moles of ethanol:

1000 g / 46.0684 g/mol = 21.71 mol

b) moles of acetone:

1.09 / (1.09 + 21.71) = 0.047

Correct order of the levels of classification in the ecosystem

Answers

Numa máquina térmica uma parte da energia térmica fornecida ao sistema(Q1) é transformada em trabalho mecânico (τ) e o restante (Q2) é dissipado, perdido para o ambiente.



sendo:

τ: trabalho realizado (J) [Joule]
Q1: energia fornecida (J)
Q2: energia dissipada (J)


temos: τ = Q1 - Q2

O rendimento (η) é a razão do trabalho realizado pela energia fornecida:

η= τ/Q1

Exercícior resolvido:
Uma máquina térmica cíclica recebe 5000 J de calor de uma fonte quente e realiza trabalho de 3500 J. Calcule o rendimento dessa máquina térmica.

solução:

τ=3500 J
Q1=5000J

η= τ/Q1
η= 3500/5000
η= 0,7 ou seja 70%

Energia dissipada será:



τ = Q1 - Q2
Q2 = Q1- τ

Q2=5000-3500
Q2= 1500 J

Exercicio: Qual seria o rendimento se a máquina do exercicio anterior realizasse 4000J de trabalho com a mesma quantidade de calor fornecida ? Quanta energia seria dissipada agora?



obs: Entregar foto da resolução ou o cálculo passo a passo na mensagem

What is the mass of 25.5 L of water assuming it is at 4 degrees Celsius?

Answers

Answer:

25.5kg or about 56.2lbs

Explanation:

At 4°C pure water has a mass of about 1 kg/​liter.

So, if there was 25.5 L of water it would be 25.5kg or about 56.2lbs.

What is Hall-Heroult process?​

Answers

Answer:

... Sorry I don't know the answer

A potted plant is placed under a grow lamp, which provides 6,400 J of energy to the plant and the soil over the course of an hour. The specific heat capacity of the soil is about 0.840 J/g°C and the temperature goes up by 9.25°C of soil. How many grams of soil are there?

Answers

Answer:

823.7g

Explanation:

Using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

Using the information given in this question as follows:

Q = 6,400 J

m = ?

c of soil = 0.840 J/g°C

∆T = 9.25°C

Using Q = mc∆T

m = Q ÷ c∆T

m = 6,400 ÷ (0.840 × 9.25)

m = 6400 ÷ 7.77

m = 823.7g

Answer:

There are 823.68 grams.

Explanation:

Calorimetry is responsible for measuring the amount of heat generated or lost in certain physical or chemical processes.

Between heat and temperature there is a relationship of direct proportionality. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body. In summary, the amount of heat Q that receives or transmits a mass m of a substance with specific heat C to raise its temperature from T1 to T2 is given by the formula:

Q= C*m* (T2- T1) = C*m* ΔT

In this case:

Q= 6400 JC= 0.840 [tex]\frac{J}{g*C}[/tex]m= ?ΔT= 9.25 C

Replacing:

6400J= 0.840 [tex]\frac{J}{g*C}[/tex] *m* 9.25 C

Solving:

[tex]m=\frac{6400 J}{0.840 \frac{J}{g*C} *9.25 C}[/tex]

m=823.68 grams

There are 823.68 grams.

Please type out all of your calculations for this dilution equation: In your vitamin C experiment, it calls for a 5% concentration of iodine. However, your 7 fluid oz. tincture of iodine contains 70% iodine. How would you dilute this

Answers

Answer:

The original7 fluid oz. 70% tincture of iodine is diluted to 98 fluid oz. to obtain a 5% solution.

Explanation:

Dilution is a technique employed in experimental sciences such as chemistry and biochemistry as well as in medicine to obtain a less concentrated solution from a more concentrated one.

The dilution formula is the most important formula required in dilution. The dilution formula is given as: C1V1 = C2V2

Where C1 is the initial concentration of the stock solution;

V1 is the volume of the stock solution required;

C2 is the final concentration of the diluted solution to be prepared;

V2 is the final volume of the diluted solution.

Using the dilution formula to determine the answer to the above question:

C1 = 70% = 0.7; V1 = 7 fluid oz.; C2 = 5% = 0.05; V2 = ?

To determine V2, it is made subject of the dilution formula:

V2 = C1V1/C2

V2 = (0.7 × 7) / 0.05

V2 = 98 fluid oz.

Therefore, the original7 fluid oz. 70% tincture of iodine is diluted to 98 fluid oz. to obtain a 5% solution.

Bryce and his lab partner come up with an idea they think will save time: We just used the fast titrations. You can stop the video when the solution turns pink. We know that when the solution turns pink, the titration is complete, so we just read the volume from the burette as soon as it turns pink. This is faster than going through all the shorter videos and works just as well. Do you agree with Bryce

Answers

Answer:

Yes.

Explanation:

Yes, I agree with Bryce and his lab partner because titration is completed when the solution changes its colour. Add chemical from the burette until the solution change its colour so then calculate the amount of chemical is used from the burette and the time at which the titration is completed. Always be careful for calculating the titration in order to get accurate data of the solution.

If the copper ion just GAINED electrons,
which process did it go through?
Reduction or
Oxidation

Answers

Reduction I had this question befor
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