Please someone help me

Answer:

x = 8

In all the boxes, you will first subtract 8 with 2, which will be 6. Then you will add them.

6 + 6 + 6 = 18

Answer:

3x + 6 < 21

subtract 6 on both sides

3x < 15

reduce by dividing with 3

x < 5

remember to handle inequalities just like equations

Answer:

9.9 inches

Step-by-step explanation:

The area of a triangle is given by

A = 1/2 bh  where b is the length of the base and h is the length of the height

49 = 1/2 x*x

Multiply each side by 2

2*49 = x^2

98 = x^2

Take the square root of each side

sqrt(98) = sqrt(x^2)

9.899494937 =x

Rounding to the nearest tenth

9.9 =x

Answer:

269.0

Step-by-step explanation:

Trigonmetric area formula: 0.5 * a* b* sin(C)

a = 46

b=19

c = 38 degrees

0.5 * 46 * 19 * sin(38)

Pulg it into a calculator and you get 269.0441

Then round to the nearest tenth to get 269.0

Answer:

3x

Step-by-step explanation:

3x^2 - 6x / x - 2

3x(x - 2) / x-2

cancels out

3x

Answer:

a)  67.4°

Step-by-step explanation:

since this is a right triangle you can use the sine trigonometric ratio of opposite/hypotenuse

sin⁻¹(Ф) = 12/13 which equals 67.4°

Answer:

Surface area of cone = 286.55 cm² (Approx.)

Volume of cone = 263.89 cm³ (Approx.)

Step-by-step explanation:

Given:

Height of cone = 7 cm

Diameter of cone = 12 cm

Find:

Surface area of cone

Volume of cone

Computation:

Radius of cone = 12 / 2 = 6 cm

Surface area of cone = πr(l +r)

Surface area of cone = (3.14)(6)[(√7² + 6²) + 6]

Surface area of cone = 18.84[15.21]

Surface area of cone = 286.55 cm² (Approx.)

Volume of cone = (1/3)(π)(r²)(h)

Volume of cone = (1/3)(3.14)(6²)(7)

Volume of cone = (1/3)(3.14)(36)(7)

Volume of cone = 263.89 cm³ (Approx.)

Answer:

area: 454.2 sq.cm

perimeter: 77.7 cm

Step-by-step explanation:

to find area, find the area of all the separate shapes and add them together:

semi-circle:

radius is 12 cm

area = [tex]\frac{\pi (12)^2\\}{2}[/tex] = 226.2 sq.cm

separate the trapezoid into two right triangles and a rectangle.

area for triangles:

[tex]\frac{1}{2}[/tex](5)(12) = 30

30 x 2 = 60 sq.cm (since there are two triangles)

area for rectangle:

12 x 14 = 168 sq.cm

area of whole shape: 226.2 + 60 + 168 = 454.2 sq.cm

for perimeter, just add the length of the exterior sides together.

we have some unknown sides, such as the semicircle and the sides of the trapezoid

we can find the hypotenuse of the triangles we used earlier to find the sides of the trapezoid with pythagorean theorem

[tex]5^2 + 12^2 = c^2[/tex]

[tex]25 + 144 = c^2[/tex]

[tex]169 = c^2[/tex]

[tex]\sqrt{169} =\sqrt{c^2}[/tex]

c = 13 cm

to find the outside perimeter of the semi-circle, solve as if you were finding the circumference of a normal circle and divide it in half

[tex]\frac{2\pi12}{2}[/tex] = 37.7 cm

now add it all up:

14 + 13 + 13 +37.7 = 77.7

Answer:

The slope is -7

Step-by-step explanation:

[tex]y = mx + c[/tex]

The [tex]m[/tex] indicates the slope/gradient of a graph

Answer:

m = -7

Step-by-step explanation:

y = -7x is a typical slope-intercept equation of a straight line.  Comparing it to

y = mx + b, we see that the slope, m, is -7 and the y-intercept, b, is 0.

Answer:

-7

Step-by-step explanation:

cause I took the test and got it right in my first try

Given:

The two numbers are [tex]-\dfrac{1}{2}[/tex] and [tex]-\dfrac{1}{3}[/tex].

To find:

The 4 rational numbers between the given numbers.

Solution:

We have,

[tex]-\dfrac{1}{2}[/tex] and [tex]-\dfrac{1}{3}[/tex]

First we need to make common denominators. So multiply and divide the first fraction by 3 and second fraction by 2.

[tex]-\dfrac{1\times 3}{2\times 3}=-\dfrac{3}{6}[/tex]

[tex]-\dfrac{1\times 2}{3\times 2}=-\dfrac{2}{6}[/tex]

We need to find 4 rational numbers between the given numbers. So, multiply and divide both fractions by five, (4+1=5).

[tex]-\dfrac{3\times 5}{6\times 5}=-\dfrac{15}{30}[/tex]

[tex]-\dfrac{2\times 5}{6\times 5}=-\dfrac{10}{30}[/tex]

Now, the four numbers between -15 to -10 are -14, -13, -12, -11.

[tex]-15<-14<-13<-12<-11<-10[/tex]

[tex]-\dfrac{15}{30}<-\dfrac{14}{30}<-\dfrac{13}{30}<-\dfrac{12}{30}<-\dfrac{11}{30}<-\dfrac{10}{30}[/tex]

[tex]-\dfrac{1}{2}<-\dfrac{14}{30}<-\dfrac{13}{30}<-\dfrac{12}{30}<-\dfrac{11}{30}<-\dfrac{1}{3}[/tex]

Therefore, the 4 rational number between the given numbers are [tex]-\dfrac{14}{30},\ -\dfrac{13}{30},\ -\dfrac{12}{30}\ -\dfrac{11}{30}[/tex].

For all the angles, you will have to solve for x

A: 162 = 3x

162/3 = x

54 = x

M: 120 + 2x = 180

2x = 180 - 120

2x = 60

x = 60/2

x = 30

W: 150 = 30x

150/30 = x

5 = x

S: 20 + 2x = 90

2x = 90 - 20

x = 70/2

x = 35

Q : 45 + 5x = 90

5x = 90 - 45

x = 45/5

x = 9

P: not too sure if its 150,

150 + (x+5) = 180

x+5 = 180- 150

x = 30 - 5

x = 25

now you will put all the x values in order. ( i think thats what you supposed to do)

it will be: 5, 9, 25, 30, 35, 54

hope this helps♡♡♡

Answer:

$405

Step-by-step explanation:

SI=PTR/100

=9*1*750/100

=$ 67.50

In 6 yrs= 67.50*6

=$405

Answer:

The answer is $1087.50

I got it wrong because someoneeeeeee didnt give the right answer (2 people to be exact)

Answer:

[tex]11.2[/tex]

Step-by-step explanation:

We can use the distance formula to solve this problem.

This distance formula states that the distance between two points [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] is equal to [tex]\sqrt{(\Delta x)^2+(\Delta y)^2}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex].

School is at coordinate point (9,6) and the closest point to school on Cherry St. is (4,-4).

Thus, the distance between school and Cherry Street is [tex]\sqrt{(9-4)^2+(6-(-4))^2}=\sqrt{5^2+10^2}=\sqrt{125}=5\sqrt{5}\approx \boxed{11.2}[/tex]

Answer:

to blury

Step-by-step explanation:

Answer:

(-7,-1)

Step-by-step explanation:

bcoz coordinates of a is (-6,-2) and x=-6 we use the x-1 to find the new x which is

-6-1=-7

and to find y you should use y-3 and replace y with 2 which will be

2-3=-1

and y =-1

so the new coordinates are -7 for x-axis and -1for y-axis

Answer:

12

Step-by-step explanation:

[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]

in this case its

[tex]5^{2}[/tex] + [tex]b^{2}[/tex] = [tex]13^{2}[/tex]

25 + [tex]b^{2}[/tex] = 169 subtract 25 from both sides

[tex]b^{2}[/tex] = 144 take square root of each side

b = 12

Answer:

[tex]12[/tex]

Step-by-step explanation:

----------------------------------------

In order to find the missing side of the triangle, we would need to use the Pythagorean theorem: [tex]a^2+b^2=c^2[/tex]

So,

[tex]5^2+b^2=13^2[/tex]

[tex]25+b^2=169[/tex]

[tex]b^2=144[/tex]

[tex]b=12[/tex]

--------------------

Hope this helps.

Thanks! But what is it for??

Answer:

Thanks I got my free thing from this code that points out where to redeem it

Step-by-step explanation:

Answer:

[tex]\text{C. }g(x)=(x-5)^2[/tex]

Step-by-step explanation:

The function [tex]y=(x-c)^2[/tex] has a phase shift of [tex]c[/tex] to the parent function [tex]y=x^2[/tex]. Since [tex]g(x)[/tex] has moved to the right 5 units from the parent function [tex]f(x)=x^2[/tex], we're looking for a value of [tex]c=5[/tex].

Therefore, we have:

[tex]g(x)=\boxed{(x-5)^2}[/tex]

Answer:

a/e

~~~~~~~~~~

[tex]\frac{(18) ab (20)cd}{ (15) bc (24) de}[/tex]

[tex]\frac{(3) ab (4)cd}{ (3) bc (4) de}\\[/tex]

[tex]\frac{ ab cd}{ bc de}\\[/tex]

[tex]\frac{ a }{ e}\\[/tex]

Step-by-step explanation:

Answer and also explanation:

Use the drawing tool(s) to form the correct answer on the provided plot.

In order to construct a dot plot representing the number of correct problems on each student's quiz, first find the range of the data.

The maximum number of correct problems is 10. The minimum number of correct problems is 2. Therefore, the number of correct problems ranges from 2 to 10.

Next, determine how many students had each number of correct problems in the range.

No. of Correct Problems

0 1 2 3 4 5 6 7 8 9 10

No. of Students 0 0 1 1 2 0 3 2 2 2 2

The number of correct problems, from 0 to 10, will be the values on the number line. The number of students will be the number of dots above each value on the number line.

The dot plot showing the correct number of math problems for Ms. Mackey's students is shown on your question.

Answer:

El pasajero recorrió 15 kilómetros.

Step-by-step explanation:

Dado que se sabe que el precio a pagar por un viaje en taxi incluye una parte fija, que se denomina bajada de bandera, y una parte variable, que es función de la distancia recorrida, si el precio de la bajada de bandera es de R $ 4,60 y el kilómetro recorrido es de R $ 0,96, para determinar cuál es la distancia recorrida por un pasajero que pagó R $ 19,00 se debe realizar el siguiente cálculo:

Costo total = (0.96 x cantidad de km recorridos) + 4.60

19 = 0.96X + 4.60

19 - 4.60 = 0.96X

14.4 = 0.96X

14.4 / 0.96 = X

15 = X

Por lo tanto, el pasajero recorrió 15 kilómetros.

Step-by-step explanation:

-1×5 1×3

------ -----

3×5 -5×3

=

-5/15 -3/15

-5/15×4/4 ;

-3/15×4/4

=

-20/60 ;

-12/60

you can write any 8 rational no. between them

please mark as brainliest answer as it will also give you 3 pts

Answer:

37.6 cm

Step-by-step explanation:

5.6m = 560cm

3.8m = 380cm

560/50 = 11.2 cm

380/50 = 7.6 cm

11.2 + 11.2 + 7.6 + 7.6 = 37.6 cm

Answer:

paki sagot naman po para my isagot ako sa module ko

Answer:

it should be 37°

Step-by-step explanation:

cos=adj/hypo

cis-1(12/15)

=36.8

=37

Answer:

[tex]9^{3/2}-3\times 5^0-(\dfrac{1}{81})^{-1/2}=15[/tex]

Step-by-step explanation:

The given expression is :

[tex]9^{3/2}-3\times 5^0-(\dfrac{1}{81})^{-1/2}=15[/tex]

We need to prove that LHS is equal to RHS.

Taking LHS,

[tex]=9^{3/2}-3\times 5^0-(\dfrac{1}{81})^{-1/2}[/tex]

[tex]=(3)^{2\times\dfrac{3}{2}}-3-(\dfrac{1}{9})^{2\times \dfrac{-1}{2}}\\\\=27-3-9\\\\=15\\\\=RHS[/tex]

Hence, LHS = RHS.

Answer:

T=-13

Step-by-step explanation:

substitute T=3*5+4*(-7)

the product:T=15-28

the sum:T=-13

Answer:

A

Step-by-step explanation:

For a number to be written in scientific notation, you need to have it in the form:

a x 10^n

Where a is between 1 and 10(not including 10), and n is an integer. We can notice that in option A, 0.1(a) is not between one and ten, so it is not in scientific notation.