pls help What are the benefits and limitations of scientific experiments and investigations?

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Answer 1
The benefits and limitations of scientific experiments and investigations is the knowledge allows us to develop new technologies

Related Questions

Given a mass of 14 g and a volume of 28 ml, calculate the density. g/ml (note: insert the numerical answer in standard form with the correct number of significant figures.)

Answers

Given a mass of 14 g and a volume of 28 ml, the density in g/ml is

0.5 grams per cubic centimeter.

What is density in g/ml?

Density is the mass of a substance in relation to its volume. Despite the fact that the Latin letter ρ can also be used, the symbol for density that is utilized the most frequently is. The size of how tightly a cloth is packed together is called density. it's far characterized as the mass predictable with unit amount.

ρ = m/V, where m denotes the item's mass, V denotes its quantity, and m denotes its density.

According to the given question:

A material substance's density is defined as its mass per unit volume. D is density, M is mass, and V is volume, therefore the formula for density is d = M/V.

d = M/V :

- 14/28= 1/2 = 0.5 grams per cubic centimeter.

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From the following pairs of coordination complexes, identify which are pairs of coordination isomers. Select all that apply.
Group of answer choices Na2[NiCl2Br2] and Na2[NiBr2Cl2]
[Ni(NH3)3Br]Cl and [Ni(NH3)3Cl]Br
[Ni(NH3)3(H2O)]SO4 and [Ni(NH3)2(H2O)2]SO4

Answers

The pair of coordination isomers is [Ni(NH3)3Br]Cl and [Ni(NH3)3Cl]Br.

A coordination complex is made up of a central atom or ion, which is usually metallic and is known as the coordination centre, and a ring of bound molecules or ions, which are known as ligands or complexing agents. Coordination complexes are found in many metal-containing compounds, particularly those containing transition metals.

The coordination sphere is made up of the central atom or ion and all ligands. The first coordination sphere is made up of the central atoms or ions and the donor atoms. The coordination number is the number of donor atoms attached to the central atom or ion. The most common coordination numbers are 2, 4, and 6, in particular.

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Explain how the ionic bond is formed in Lithium Fluoride.

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( I underlined the important part the rest is extra info that can help you understand)

Answer

Lithium is a metal (Alkali metal) it will donate one of its electrons to fluoride so then it becomes positively charged (cation).

(atoms are neutral because protons (p+) and electrons (e-) are equal taking one electron from an atom will make it positive)

Flouride is a nonmetal so it will accept the electron from lithium so then it becomes negatively charged (anion)

lithium is in group 1 so its charge is +1
Flouride is in group 17 so its charge is -1

both cancel each other so there are no subscripts

ased on the data above, what can be concluded regarding the strength of the C-H, N-H, and O-H bonds in the molecules shown? (A) The C-H bond is the strongest. (B) The N-H bond is the strongest. (C) The O-H bond is the strongest. (D) Nothing can be concluded without knowing the strength of the H-CI bond.

Answers

The O-H bond is the strongest due to high electronegativity difference.

Bond energy, also known as mean bond enthalpy or average bond enthalpy in chemistry, is a measure of bond strength in a chemical bond. Bond energy is defined by the International Union of Pure and Applied Chemistry as the average value of the gas-phase bond-dissociation energy for all bonds of the same type within the same chemical species. The greater the difference in electronegativity, the greater the bond polarity and thus bond strength.

As the difference in the electronegativities of the bonded atoms grows, so does the bond dissociation energy. The electronegativity of the atoms in a compound influences the ionic bonds. More electronegative elements have a higher proclivity to form ionic character bonds with other elements.

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Please, help me with this question !! Thank you so much.
Translation in the picture:
Among the 6 electronic structures, there is only one that is correct, in 5 that remain, each one has one fault, then directly to the figure, make a round around each fault (I've circled it, but I don't know how to explain it simply most), and give a simple explanation of what is the fault. (Answer in English)

Answers

Answer:

Explanation:

In this figure, the six electronic structures represent the electron configurations of six different elements: Li, Be, B, C, N, and O. The correct electron configurations are shown in green, and the incorrect ones are shown in red.

In the electron configuration for Li (top left), the fault is that the 2s orbital is not completely filled. The correct electron configuration for Li should have two electrons in the 1s orbital and one electron in the 2s orbital.

In the electron configuration for Be (top center), the fault is that the 2s orbital is not completely filled. The correct electron configuration for Be should have two electrons in the 1s orbital and two electrons in the 2s orbital.

In the electron configuration for B (top right), the fault is that the 2s orbital is not completely filled. The correct electron configuration for B should have two electrons in the 1s orbital, two electrons in the 2s orbital, and three electrons in the 2p orbital.

In the electron configuration for C (bottom left), the fault is that the 2p orbital is not completely filled. The correct electron configuration for C should have two electrons in the 1s orbital, two electrons in the 2s orbital, and four electrons in the 2p orbital.

In the electron configuration for N (bottom center), the fault is that the 2p orbital is not completely filled. The correct electron configuration for N should have two electrons in the 1s orbital, two electrons in the 2s orbital, and five electrons in the 2p orbital.

In the electron configuration for O (bottom right), the fault is that the 2p orbital is not completely filled. The correct electron configuration for O should have two electrons in the 1s orbital, two electrons in the 2s orbital, and six electrons in the 2p orbital.

I hope this helps! Let me know if you have any questions or need further clarification.


Which of the following electron configurations represents the most chemically stable atom?
a. 1s²2s²2p³
c. 1s22s22p 3s²3p64s²3d5
d. 1s²2s²2p 3s23p6
b. 1s²2s²2p 3s²3p5

Answers

Answer:

D. 1s²2s²2p 3s²3p6

Explanation:

The most chemically stable electron configuration is typically the one that has a full valence shell, which means that the outermost electron shell is completely filled with electrons. In this case, the electron configuration with a full valence shell is 1s²2s²2p 3s²3p6. This configuration is often called the "noble gas" configuration, because it is similar to the electron configuration of a noble gas, such as neon or argon, which are extremely stable and unreactive.

Complete and balance the given precipitation reactions, including the physical states of the products as predicted by the solubility rules.
Ba(NO3)2 (aq)+ CuSO4(aq)-------->
K3 PO4 (aq)+ MgCl2 (aq)----------->

Answers

BaSO4 (s) + Cu(NO3)2 (aq)  and KCl (s) + Mg3(PO4)2 (s) is the product of given precipitation reactions.

What is precipitation reactions ?Precipitation is the process of changing a dissolved substance from a super-saturated solution to an insoluble solid in an aqueous solution. Precipitate refers to the produced solid.The Ba2+ ions from the barium nitrate solution would react with the SO42- ions from the copper sulfate solution to form BaSO4, a white solid precipitate. The Cu2+ ions from the copper sulfate solution would react with the NO3- ions from the barium nitrate solution to form Cu(NO3)2, a blue solution

Ba(NO3)2 (aq) + CuSO4 (aq) → BaSO4 (s) + Cu(NO3)2 (aq)

The K+ ions from the potassium phosphate solution would react with the Cl- ions from the magnesium chloride solution to form KCl, a white solid precipitate. At the same time, the Mg2+ ions from the magnesium chloride solution would react with the PO43- ions from the potassium phosphate solution to form Mg3(PO4)2

 K3 PO4 (aq) + MgCl2 (aq) → KCl (s) + Mg3(PO4)2 (s)

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An organic compound (CaHbNcOdCle) was synthesized and a sample of it was analyzed and found to contain only C, H, N, O, and Cl. It was observed that when a 0.150-g sample of the compound was burned, it produced 0.138 g CO2 and 0.0566 g H2O. All the nitrogen in a different 0.200-g sample of the compound was converted to NH3, which found to weigh 0.0238 g. Finally, the chlorine in a 0.125-g sample of the compound was converted to Cl- and by reacting it with AgNO3, all the chlorine was recovered as AgCl. The AgCl, when dried, was found to weigh 0.251 g. Calculate the weight percent of each element in the compound.

Answers

The mass percent of each element is:

mass percent of C is 24%

mass percent of H is 4%

mass percent of Cl is 50%

mass percent of N is 9.8%

Mass percent of oxygen is 12.2%

What is the mass of each of the constituent elements in a sample of the compound?

The mass of each of the constituent elements in a sample of the compound is determined as follows:

mass of C:

1 mole of C is present in 1 mole of CO₂

The mass of C in 0.138 g of CO₂ will be:

0.138 g / 44 g * 12 g = 0.0368 g

mass of H:

2 moles of H are present in 1 mole of H₂O

The mass of H present in 0.0566 g H₂O will be:

0.0566 g / 18 * 2 * 1 = 0.00628 g

mass of Cl;

1 mole of Cl is present in 1 mole of AgCl

The mass of Cl in 0.251 g of AgCl will be:

0.251 g / 143.5 g * 35.5 g = 0.0621 g

mass of N:

1 mole of N is present in 1 mole of NH₃

The mass of N in 0.251 g of NH₃ will be:

0.0238g / 17.0 g * 14 g = 0.0196 g

Mass percent of each element will be:

mass percent of C:

mass percent = 0.0368/0.15 * 100

mass percent = 24%

mass percent of H:

mass percent = 0.00628 / 0.15 * 100%

mass percent = 4%

mass percent of Cl;

mass percent of Cl:

mass percent = 0.0621 / 0.125 * 100%

mass percent = 50%

mass percent of N:

mass percent = 0.0196 / 0.2 * 100%

mass percent = 9.8%

Mass percent of oxygen = 100 - (24 + 4 + 50 + 9.8)

Mass percent of oxygen = 12.2%

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In a second experiment, which is performed at a much higher temperature, a sample of ethanol gas and a
copper catalyst are placed in a rigid, empty 1.0 L flask. The temperature of the flask is held constant, and the
initial concentration of the ethanol gas is 0.0100 M. The ethanol begins to decompose according to the
chemical reaction represented below. CH3CH2OH(g) æCuæà CH3CHO(g) + H2(g)
The concentration of ethanol gas over time is used to create the three graphs below.
(c) Given that the reaction order is zero, one, or two, use the information in the graphs to respond to the
following
(i) Determine the order of the reaction with respect to ethanol. Justify your answer.
The order of the reaction is zero. The plot on the left is a straight 1 point is earned for the correct
line, indicating that the rate of decrease in [ethanol] is constant as choice with a valid justification. [ethanol] changes. Therefore the rate of reaction does not depend
on [ethanol].
(ii) Write the rate law for the reaction
(iii) Determine the rate constant for the reaction, including units
(d) The pressure in the flask at the beginning of the experiment is 0.40 atm. If the ethanol completely
decomposes, what is the final pressure in the flask?

Answers

Answer:

Hope this help you i try my best :)

The Order of the reaction is zero. The rate law for the reaction is rate = k[CH₃CH₂OH]⁰.  The rate constant for the reaction is 4.0 x 10⁻⁶ Ms⁻¹. the final presure is 0.8 atm.

The order of the reaction is zero. The plot on tye left is a straight line, indicating that the rate is decreasing in[ ethanol] is constant as [ ethanol ] changes. Therefore the rate of the reaction does not depend on the[ethanol] because of the order of the reaction is zero the rate law for the reaction became  rate = k[CH₃CH₂OH]⁰.

The rate constant can be calculate as follows:

rate = k = - Δ [ethanol] = - (0.0020-0.0100) mol/L

                      Δt                        2000s

rate = 4.0 x 10⁻⁶ Ms⁻¹

The final pressure is 0.080 its twice the original pressure because the product represent twice as many moles of gas as reactant

your question is incomplete but most probably your full question attached below

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The first the principal quantum number consider what property of an electrons?
a) direction of spin
b) orientation in space
c) distance from the nucleus

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Answer:

Orientation in space.

Explanation:

I had a similar question.

What would the answer be?

Answers

the first choice is correct

FILL IN THE BLANK Collision frequency provides an upper limit on how fast a reaction can take place. The laws of probability tell us that the number of collisions depends on the _____ of the number of reactant particles, not their _____.

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that the number of collisions depends on the energy, of the number of reactant particles, not their orientation.

How is energy defined?

Energy is referred to by scientists as the capacity for work.People have figured out how to transform energy from one type to the other and use it to accomplish tasks, making modern civilization possible.

What function does orientation serve?

boosts employee confidence and enables new hires to settle in more quickly; results in a more efficient and successful staff; increases employee retention; andencourages dialogue between the new employee and the supervisor.

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Suppose that a certain fortunate person has a net worth of $77.0 billion ($ 7.70×1010 ). If her stock has a good year and gains $3.20 billion ( 3.20×109 ) in value, what is her new net worth?
Express your answer to three digits.

Answers

her new network is $80.20 billion

Three blocks of equal volume are completely submerged into water. The blocks made of different materials: aluminum, iron and lead. Which of the following is the correct statement about the buoyant force on each block? (Paluminum = 2700 kg/m', Pion = 7800 kg/m, Plead = 11300 - kg/m) (A) Faluminum > Fire > Fland (B) Faluminum < Firon Flead (D) Faluminum = Fire = Fiend (E) Faluminum > Fire

Answers

Faluminum & gt and plead = 11300

Which one of the following options give the correct procedure to calculate the mass of a substance if number of moles are given? A moles / molar mass B. molar mass /mole C none of them D. moles x molar mass

Answers

The answer is D. moles x molar mass.

How do we determine a substance's mass?

Number of moles divided by molecular weight equals the substance's mass.Since the question states that glucose has a molecular weight of 180.16, plugging in our calculations shows that we require 180.16 x 1.5 = 270.24 g of sugar.

What are the three methods for determining mass?

There are numerous instruments available for determining mass in various settings.The utilization the gravitational interaction between things is one of them, along with balances and scales, measuring transducers, vibrating tubes sensors, Newtonian weight measurement devices, and balances and scales.

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How many electrons are needed when the following half-equation is balanced using the lowest possible whole numbers? no3 (aq) h (aq) - -> no(g)

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The no. of electrons needed are 3 for the following half-equation is balanced using the lowest possible whole numbers is NO three− +4H + +e − →2H 2 O+NO.

The oxidation numbers for nitrogen has been assigned.

+5N O three− +4H + +e → 2H 2 O+ +2N O

This is a discount 1/2 of equation. All atoms are balanced.

We stability prices via way of means of including the proper quantity of electrons.

NO three− +4H + +3e − →2H 2 O+NO

This is a balanced discount 1/2 of-reaction.

Thus, the quantity of electrons required to stability the equation is three.

Hence, the best choice is 3 .

The balancing steps are proven below:Some nitrogen in nitrate anion is oxidized from +three to +five in nitrate anion.Oxidation 1/2 of-reaction: NO−2(aq)→NO−three(aq)+2e−2OH−(aq)+NO−2(aq)→NO−three(aq)+2e−2OH−(aq)+NO−2(aq)→NO−three(aq)+2e−+H2O(l).

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what is the concentration of solution if absorbance is 0.02 explain​

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1 : 5 000

100 : 0,02 = 5 000 1 : 5 000

How many mL of 0.500 M Nal would be required to make a 0.0410 M
solution of Nal when diluted to 275.0 mL with water?

Answers

V1 M1 = V2M2
(V1 ml)(0.500 M) = (275 ml)(0.0350 M)
V1 = (275 ml)(0.0350 M) / 0.500 M
V1 = 19.25 mls = 19.3 mls (3 sif. figs.) would be required

What is a stem cell?

Answers

stem cell rizzler big cousin stem cell is when

The active ingredient in one does of antacid A is 0.50g Al(OH)3. the active ingredient in one does of antacid B is 0.50g CaCO3. Would one does of antacid A or B neutralize more stomach acid? Explain your choice, and show a calculation to support your answer.

Answers

One dose of antiacid A will neutralize more stomach acid (0.019 mol) than one dose of antacid B (0.01 mol).

Stoichiometric problem

Stomach acid is HCl. The reaction of HCl with each of the active ingredients of the antiacids is expressed in the following equations:

[tex]3HCl + Al(OH)_3 --- > AlCl_3 + 3H_2O[/tex].......................Eqn 1

[tex]2HCl +CaCO_3 --- > CaCl_2 + H_2O + CO_2[/tex]...................Eqn 2

In equation 1, the mole ratio of stomach acid to [tex]Al(OH)_3[/tex] is 3:1.

Mole of 0.50 g  [tex]Al(OH)_3[/tex] = 0.5/78 = 0.0064 mol

The equivalent amount of stomach acid to be neutralized = 0.0064 x 3 = 0.0192  mol

In equation 2, the mole ratio of stomach acid to [tex]CaCO_3[/tex] is 2:1.

Mole of 0.50 g  [tex]CaCO_3[/tex] = 0.5/100 = 0.005

The equivalent amount of stomach acid to be neutralized = 0.005 x 2 = 0.01 mol.

Thus, one dose of antiacid A will neutralize more stomach acid (0.019 mol) than one dose of antacid B (0.01 mol).

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An organic compound (CaHbNcOdCle) was synthesized and a sample of it was analyzed and found to contain only C, H, N, O, and Cl. It was observed that when a 0.150-g sample of the compound was burned, it produced 0.138 g CO2 and 0.0566 g H2O. All the nitrogen in a different 0.200-g sample of the compound was converted to NH3, which found to weigh 0.0238 g. Finally, the chlorine in a 0.125-g sample of the compound was converted to Cl- and by reacting it with AgNO3, all the chlorine was recovered as AgCl. The AgCl, when dried, was found to weigh 0.251 g. Calculate
the weight percent of each element in the compound.

Answers

The weight percent of each element in the compound. is given below.

The mass percent of C = 24%

The mass percent of H = 4%

The mass percent of Cl = 50%

The mass percent of N = 9.8%

The Mass percent of oxygen = 12.2%

The weight percent of the element in the compound?

The following formula is used to calculate the mass of each component element in a sample of the compound:

The weight of C:

In 1 mole of CO2, there is 1 mole of carbon.

In 0.138 g of CO2, there will be:

0.138 g / 44 g * 12 g = 0.0368 g

H's mass:

1 mole of H2O contains 2 moles of hydrogen.

0.0566 g of H2O will contain the following quantity of H:

0.0566 g / 18 * 2 * 1 = 0.00628 g

volume of Cl;

In 1 mole of AgCl, there is 1 mole of Cl.

In 0.251 g of AgCl, the mass of Cl will be:

0.251 g / 143.5 g * 35.5 g = 0.0621 g

N's mass:

In 1 mole of NH3, there is 1 mole of N.

In 0.251 g of NH3, the mass of N will be:

0.0238g / 17.0 g * 14 g = 0.0196 g

Each element's mass percentage will be:

Mass proportion of C:

mass percent is equal to 0.0368/0.15 * 100.

24% mass percent

Mass proportion of H:

mass percent is equal to 0.00628/0.15 * 100%.

4% mass percent

Cl mass percentage;

Mass proportion of Cl:

mass percent is equal to 0.0621/0.125 * 100%.

50% mass percentage

N mass percentage:

Mass percent is equal to 0.0196/0.2*100%.

9.8% mass percent

Oxygen mass percentage equals 100 minus (24 + 4 + 50 + 9.8)

oxygen mass percentage: 12.2%

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Which of the following compounds would have the largest enthalpy of formation? The bond energies are given in parentheses. a. H-H (436 kJ/mol) b. H-Cl (431 kJ/mol) c. H-F (567 kJ/mol) d. H-I (299 kJ/mol) e. H-Br (366 kJ/mol)

Answers

To solve this, we must be knowing each and every concept related to bond enery and enthalpy o formation. Therefore, the correct option is option C among all the given options.

What is Enthalpy?

Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances. Internal energy is the sum of all kinds of energy that the particles of a matter can possess, for example translational energy. Rotational energy.

Bond energy is directly proportional to the bond strength. since the bond enthalpy of H-F is the highest among all the given bond energy. H-F has the largest enthalpy of formation.

Therefore, the correct option is option C.

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electrolysis can be used to resolve hydrogenation pathways at palladium surfaces in a membrane reactor. t/f

Answers

True. Electrolysis can be used to resolve hydrogenation pathways at palladium surfaces in a membrane reactor. It uses electro catalytic palladium membrane reactor.

Palladium surface membrane reactors use electricity to hydrogenate organic molecules at ambient temperature and pressure. These reaction conditions position ePMRs as a sustainable alternative to thermochemical hydrogenation which requires high-temperature and high-pressure reaction conditions. The electro catalytic palladium membrane reactor uses electrolysis and a hydrogen-selective palladium membrane to deliver reactive hydrogen to a catalyst surface in an adjacent compartment for reaction with an organic substrate. This process forms the requisite metal-hydride surface for hydrogenation chemistry but at ambient temperature and pressure and without a H2 source.

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aluminum metal reacts with oxygen gas. assuming the reactants are ordered as written, the coefficients when this reaction is completed and balanced are

Answers

As a result, aluminum interacts with oxygen gas to form aluminum oxide, which results in the chemical reaction 4Al+3O22Al2O3. oxygen gas.

O2, or just O, is oxygen gas?

At room temperature, oxygen is a gas that lacks all other flavors, smells, and colors. Molecular oxygen can be found in nature. To create dioxygen, often known as O2, two oxygen atoms form a covalent double bond. As a molecule, oxygen is typically present.

Is the gas oxygen (O2)?

The reactive gas oxygen (O2) has no color or smell. A little under 21% of the oxygen is made up of it, which is the most common feature in the earth's crust and is primarily found in oxides, silica, and carbonates.

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Sixty milliliters of a particular liquid has a mass of 350g. What is its density?

Answers

Answer:

Once a density has been calculated the tool will also display two conversion scales for a range of mass and volume values

Explanation:

The density of this particular liquid is [tex]5833 kg/ m^3[/tex].

What is Density?

Density is defined as mass per unit volume. It is a standard mechanical quantity. The most frequently used symbol for density is ρ (rho), D can also be used which is a Latin letter.

It can be expressed as

[tex]\rho ={\frac {m}{V}}\\\\\rho = density \\m = mass\\V = volume[/tex]

Density is expressed in [tex]kg/m^3[/tex] , mass in kg and volume in [tex]m^3[/tex]

For above given information,

Mass= 350 g= 0.350kg

Volume= 60ml = 0.00006 [tex]m^3[/tex] ([tex]1ml= 1/10^6 m^3[/tex])

So, Density= 0.350/0.00006 = [tex]5833 kg/m^3[/tex]

Thus, the density of this particular liquid is [tex]5833 kg/ m^3[/tex].

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In a galvanic cell, positively charged ions migrate from the salt bridge to the ______ compartment, while negatively charged ions migrate from the salt bridge to the ______ compartment.

Answers

Positively charged ions move from a salt bridge to the anode compartment in a galvanic cell, whereas negatively charged ions move from a salt bridge to a cathode compartment.

A Galvanic Cell is what?

Galvanic or voltaic cells are two types of electrochemical devices that use chemical energy from spontaneous redox reactions to produce electricity. Convectional cell An electrochemical device known as a voltaic cell uses chemical reactions to produce electricity.

A galvanic cell's mechanism of operation

The electrical energy generated by the transfer of electrons during a redox reaction is used by galvanic cells to carry out practical electrical operations. Separating the oxidation / reduction half-reactions and connecting them with a wire makes it possible to collect the electron flow since the electrons must pass through the wire in order to move between the two half-reactions.

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HIGH SCHOOL CHEMISTRY #8-15
PLEASE HELP!!

Answers

One mole of diatomic oxygen weighs 32 grams and it contains 6.02 × 10²³ oxygen molecules. Similarly 55 grams of Fe contains 6.02 × 10²³  Fe atoms.

One mole or 27 g of Al contains 6.02 × 10²³ molecules. Hence, 3 molecules of Al weighs 1.34 × 10⁻²² g. Similarly 4 molecules of Fe weighs 1.26  × 10⁻²² g.

What is Avogadro number?

One mole of  every substance contains 6.02 × 10²³  atoms or molecules. This number is called Avogadro number. Hence the mass of an element or molecule containing Avogadro number of atoms is called its molar mass or atomic mass of element.

The molar mass of O₂ = 32 g/mol

Hence, number of molecules in 32 g of oxygen gas =  6.02 × 10²³

The atomic mass of Fe = 55 g

Hence, the number of molecules  =  6.02 × 10²³

One mole or 27 g of Al contains  6.02 × 10²³  molecules. Hence,  mass of 3 molecules =  (27 × 3 )/ 6.02 × 10²³  = 1.34 × 10⁻²² g

One mole or 19 g of F contains 6.02 × 10²³  molecules. Thus, mass of 4 molecules of F = (19 × 4)/ 6.02 × 10²³   = 1.26  × 10⁻²² g.

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The positive ions carries a number of positive charges………..the number of given electrons

Answers

Answer:

less the number of electrons

Explanation:

electrons have a negative charge

Which of these energies are most suited for study of the NaCl crystal structure? (Select all that apply.)
20.0eV
200eV
2.00keV
20.0keV
0.200MeV
2.00MeV
None of these

Answers

The NaCl crystalline nature can be studied best at energies between 20.0 and 200 eV.

What is an example of a structure?

Examples of huge pile structures include bridges, anthills, skeletons, buildings, airplanes, beaver dams, and salt domes. The infrastructure of a human civilization is composed of the outcomes of construction, which are classified as buildings and non-building structures.

What class of words are structures?

Structure is a noun or a verb, as was said before. I'm working on better time management so I won't be running behind schedule. I set up the agreement to keep our potential losses to a minimum. Use of the noun: The birds had created an impressive building out of sticks and other abandoned materials.

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Convert 6.75 CM toMM

Answers

Answer:

.675

Explanation:

when going down on the chart you move the decimal point to the left however many times you go down

Other Questions
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