Plz answer asap I need all of the answer

Answer:

[tex]F=2.84*10^{-26}N[/tex]  & -y direction

[tex]F=2.84*10^{-26}N[/tex] & +y direction

Explanation:

From the question we are told that:

Speed of electron [tex]V_e=3.83 * 10^5 m/s[/tex] +x direction

Earths magnetic field [tex]B_e=3.04 * 10^-^8[/tex] +z direction

a)

Generally the equation for magnetic force [tex]F_m[/tex] is mathematically given by

[tex]F=q(V_e*B_e)[/tex]

where

[tex]q=1.6*10^{-19}c\\\=i*\=z=-\=j[/tex]

[tex]F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)[/tex]

[tex]F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)[/tex]

[tex]F=-2.84*10^{-26}N \=j[/tex]

Magnitude & Direction

[tex]F=2.84*10^{-26}N[/tex]  -y direction

b)

Generally the equation for magnitude and direction of the magnetic force on an electron. is mathematically given by

[tex]\=F'=-1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)[/tex]

[tex]\=F'=-2.84*10^{-26}N \=j[/tex]

Magnitude & Direction

[tex]F=2.84*10^{-26}N[/tex] & +y direction

Answer:

636.6 W/m²

Explanation:

From the given information:

The area of the circular spot can be calculated as:

A = πr²

A = π(0.5 × 10⁻³ m)²

A = 7.85 × 10⁻⁷ m²

The intensity can be determined by using the formula:

[tex]I = \dfrac{P}{A}[/tex]

[tex]I = \Big ( \dfrac{0.500 \ mW}{\pi (0.5 \times 10^{-3} \ m )^2} \Big) \Big( \dfrac{10^{-3} \ W}{1\ mW} \Big)[/tex]

[tex]I = \dfrac{0.500 \times 10^{-3} }{\pi(0.25 \times 10^{-6} )}[/tex]

I = 636.6 W/m²

Answer:

A

Explanation:

if it was B it would say from one to another to another

Answer:

B) It appears to be SHM (simple harmonic motion) which is also the projection of an object moving in a circular path on either the x or y axes.

Answer:

The ratio of the average speed of the helium atoms to the average speed of the neon atoms is 5 to 1 C.

We have that for the Question, it can be said that the ratio of the average speed of the helium atoms to the average speed of the neon atoms is

5:1

Option B

From the question we are told

An empty container is filled with helium to a pressure P at a temperature T. Neon, which has atoms that are 5 times more massive than those of helium, is then added to the container until the new pressure in the container is 2P at the same temperature T. The ratio of the average speed of the helium atoms to the average speed of the neon atoms is:_________

a. 25 to 1

b. 5 to 1

c. 5to 1

d. 2to 1

e. 1 to 1

Generally the equation for the average speed of Molecules  is

mathematically given as

[tex]For Helium\\\\C_h=\frac{8P_hV_h}{\pim_h}\\\\Neon gas\\\\C_n=\frac{8P_nV_n}{\pim_n}\\\\Where\\\\Ph=P_n\\\\Vh=Vn\\\\[/tex]

[tex]\frac{C_h}{C_n}=\frac{\frac{8P_hV_h}{\pim_h}}{\frac{8P_nV_n}{\pim_n}}[/tex]

[tex]\frac{C_h}{C_n}=\sqrt{\frac{\frac{1}{5}}{{\frac{1}{5}}}[/tex]

[tex]\frac{C_h}{C_n}=\sqrt{\frac{5}{1}[/tex]

Therefore

The ratio of the average speed of the helium atoms to the average speed of the neon atoms is

5:1

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Answer: 0.1125A

Explanation:

We need to know the total resistance which will be:

R = R1+R2

where,

R1 = 20 ohm

R2 = 60 ohm

Therefore, R = 20 + 60 = 80 ohm

We should note that from Ohm's law

v = iR

i = v/R

where,

i = 9/80 = 0.1125 A

Therefore, the current that flows out of the battery is 0.1125A

Answer:

If we are upset, often our mind cannot think straight. we need to take deep breaths, and focus on reality. When we are upset we do things out of anger.

Explanation:

Hope this helps!

Answer:

hey iam bored pls join

ID: 724 645 3790

Password: 1111

The term change refers to an alteration of present conditions.

The term change refers to an alteration of present conditions. When a change occurs, things cease to be the way they were. As a student, the complexity of academic work increases with time. This is a change that has taken place.

As an employee, you are given real world tasks to accomplish rather than mere mental exercises like when you were a student, this is change that has taken place.

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Answer:

it's A subduction, deep water trench

Answer:

0.2 seconds

Explanation:

f=1/t

1/5=0.2

Answer:

Altitude is the height of landmass calculated from sea level. No it has no effect on weight.

Explanation:

The altitude at sea level is always assumed to be 0°, thus as you move away from altidude is calculated in increments while moving into the sea, the vice versa is true.

Answer:

the answer is 86400seconds.

Explanation:

1day= 24 hours

24hours to seconds =

24×60×60= 86400 seconds.

( 60 second = 1 minutes)

( 60 minutes = 1 hour)

Answer:

c. turn downward

Explanation:

From the information given:

To find the tendency of the sander;

We need to apply the right-hand rule torque; whereby we consider the direction of the flywheel, the direction at which the torque is acting, and the movement of the sander toward the right.

Since the flywheel of the sander is in counterclockwise movement, hence the torque direction will be outward placing on the wall. However, provided that the movement of the sander is toward the right, then there exists an opposite force that turns downward which showcases the tendency in the sander is downward.

Answer:

d

=

s

t

Explanation:

distance = speed * time

here, the distance is from the earthquake centre to the seismic station.

both the P and S waves travel from the earthquake centre before being detected by the seismic station, so the distance is the same for both.

the speeds are given as

8740

m

/

s

for the P wave and

4100

m

/

s

for the S wave.

we also know that the P wave arrives

47.4

seconds before the S wave.

we do not know the time that the P wave takes to travel, but we can denote it as

t

P

.

the time that the S wave takes to travel can be denoted as

t

P

+

47.4

, where time is in seconds.

for the S wave, speed * time is

4100

⋅

(

t

P

+

47.4

)

for the P wave, speed * time is

8740

⋅

t

P

.

since the distances that they travel are the same, the two expressions for speed * time are equal.

4100

⋅

(

t

P

+

47.4

)

=

8740

⋅

t

P

if you expand the brackets, you can find that

4100

t

P

+

194340

=

8740

t

P

then you can subtract

4100

t

P

:

4640

t

P

=

194340

and divide by

4640

to find

t

P

, which is the time that P takes to travel:

t

P

=

41.883

...

seconds

since distance = speed * time, the distance that the P wave travels is

t

P

⋅

the speed of P.

this is

41.883

s

⋅

8740

m

/

s

, which gives

366057.42

m

.

in kilometres, this is

366

k

m

to

3

significant figures.

Answer:

Weight = 8.162 Newton.

Explanation:

Given the following data;

Mass = 2.2 kg

Acceleration due to gravity = 3.71 N/kg

To find the weight of the textbook;

Weight = mass * acceleration due to gravity

Weight = 2.2 * 3.71

Weight = 8.162 N

Therefore, the weight of the science textbook in mars is 8.162 Newton.

Answer:

none no work cuz no motion

Explanation:

GOOD LUCK

Answer:

a. At the bottom of the first dip in the track when the car is moving the fastest.

Explanation:

P.S - The exact question is -

The correct option is - a. At the bottom of the first dip in the track when the car is moving the fastest.

Reason -

From the diagram , we can see that the total mechanical energy of the roller coaster car is greatest At the bottom of the first dip in the track when the car is moving the fastest.

Answer:

22Volts

Explanation:

The pd at the terminal is known as the emf

Since there are Ten 2.2V cells

Terminal voltage = number of cells * pd of one cell

Terminal voltage = 10 * 2.2

Terminal voltage = 22V

Hence the pd at the battery terminals​ is 22Volts

Answer:

V = 7.75 meters per seconds.

Explanation:

Given the following data;

Mass = 100000 Kilograms

Kinetic energy = 3 Megajoules = 3 * 10⁶ Joules

To find the velocity of the train;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

[tex] K.E = \frac{1}{2}MV^{2}[/tex]

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the formula, we have;

[tex] 3000000 = \frac{1}{2}*100000*V^{2}[/tex]

Cross-multiplying, we have;

[tex] 6000000 = 100000V^{2}[/tex]

[tex] V^{2} = \frac{6000000}{100000} [/tex]

[tex] V^{2} = 60 [/tex]

Taking the square root of both sides, we have;

[tex] V = \sqrt {60} [/tex]

V = 7.75 m/s

Answer:

(1.9756, -2.1951)

Explanation:

The center of mass equation is: [tex]x_{cm}[/tex] = [tex]\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex], where m represents the masses and x represents the position.

In order to find the coordinates of the center of mass, we need to use this equation for both the x-values and the y-values.

x-values:

[tex]x_{cm}[/tex] = [tex]\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex] = [tex]\frac{4(-1)+6(4)+7(-3)+10(5)+2(-2)+12(3)}{4+6+7+10+2+12}[/tex] = [tex]\frac{(-4)+(24)+(-21)+(50)+(-4)+(36)}{41}[/tex] = [tex]\frac{81}{41}[/tex] = 1.9756

y-values:

[tex]y_{cm}[/tex] = [tex]\frac{m_{1}y_{1} + m_{2}y_{2} + m_{3}y_{3} + m_{4}y_{4} + m_{5}y_{5} + m_{6}y_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex] = [tex]\frac{4(1)+6(2)+7(-2)+10(-4)+2(4)+12(-5)}{4+6+7+10+2+12}[/tex] = [tex]\frac{(4)+(12)+(-14)+(-40)+(8)+(-60)}{41}[/tex] = [tex]\frac{-90}{41}[/tex] = -2.1951

center of mass:

(1.9756, -2.1951)

Answer:

Refraction involves passing through a boundary (choice a) and changing speed (choice ... A ray of light in air is incident on an air-to-glass boundary at an angle of 30. ... If the index of refraction of the glass is 1.65, what is the angle of the refracted ray ... The critical angle is the angle of incidence (which is always in the more ...

Explanation:

Answer: 5.08 L.

Explation down below

Answer:

The two poles of the bar magnet change positions. The compass needle spins a half circle.

Explanation:

Answer:

The two poles of the bar magnet change positions. The compass needle spins a half circle.

Explanation:

edmentum answer

The first time after 3:00 that the angle between the two hands has decreased by half to 45.0 is 3:08:11.

The angular velocity of the hour hand for 12 hours time is calculated as follows;

[tex]\omega_h = \frac{2\pi}{12(3600 \ s)}[/tex]

The angular velocity of the minute hand for 12 hours time is calculated as follows;

[tex]\omega _m = \frac{2\pi}{3600}[/tex]

[tex]\Delta \omega = \frac{2\pi }{3600} - \frac{2\pi }{12(3600)} = \frac{11(2\pi)}{12(3600)} = \frac{22\pi}{12 (3600)}[/tex]

[tex]45^0 = \frac{45}{180} \pi= \frac{\pi}{4}[/tex]

The time after 3:00 is calculated as follows;

[tex]t =( \frac{\pi}{4}) /\frac{22\pi}{12(3600)} \\\\t = \frac{\pi }{4} \times \frac{12(3600)}{22\pi} \\\\t = 490.91 \ s\\\\t = 8 \min, \ 10.91 \ s[/tex]

[tex]t \approx 8\min, 11 \ s[/tex]

Thus, the first time after 3:00 that the angle between the two hands has decreased by half to 45.0 is 3:08:11.

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