question is included in the picture!!! PUT REAL ANSWERS OR I WILL REPORT YOU​

Question Is Included In The Picture!!! PUT REAL ANSWERS OR I WILL REPORT YOU

Answers

Answer 1

Answer:

Explanation:

this is like rubbing a balloon on your head to make your hair stand up.  Do that to the can.    The balloon is filled , ofc,  and then just rub the balloon on the can.  This will charge the can with static electricity.   :P


Related Questions

32. Assume the helium-neon lasers commonly used in student physics laboratories have power outputs of 0.500 mW. (a) If such a laser beam is projected onto a circular spot 1.00 mm in diameter, what is its intensity

Answers

Answer:

636.6 W/m²

Explanation:

From the given information:

The area of the circular spot can be calculated as:

A = πr²

A = π(0.5 × 10⁻³ m)²

A = 7.85 × 10⁻⁷ m²

The intensity can be determined by using the formula:

[tex]I = \dfrac{P}{A}[/tex]

[tex]I = \Big ( \dfrac{0.500 \ mW}{\pi (0.5 \times 10^{-3} \ m )^2} \Big) \Big( \dfrac{10^{-3} \ W}{1\ mW} \Big)[/tex]

[tex]I = \dfrac{0.500 \times 10^{-3} }{\pi(0.25 \times 10^{-6} )}[/tex]

I = 636.6 W/m²

scholastic science world
CHECK FOR UNDERSTANDING: VIDEO GAME TYCOONS

Answers

I dont see it ;-; REEEEEEEE

ian pushed a piano across the room with the correct amount of force. Which of newton’s laws is this?
Newton’s 1st, 2nd, 3rd, or 1st and 2nd law?

Answers

Answer:

1st and 2nd

Explanation:

Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. Suppose the mass of a certain spherical neutron star is twice the mass of the Sun and its radius is 13.0 km. Determine the greatest possible angular speed the neutron star can have so that the matter at its surface on the equator is just held in orbit by the gravitational force. (The mass of the Sun is 1.99 1030 kg.)

Answers

Answer:

The required angular speed the neutron star is 10992.32 rad/s

Explanation:

Given the data in the question;

mass of the sun M[tex]_S[/tex] = 1.99 × 10³⁰ kg

Mass of the neutron star

M[tex]_N[/tex] = 2( M[tex]_S[/tex] )

M[tex]_N[/tex] = 2( 1.99 × 10³⁰ kg )

M[tex]_N[/tex] = ( 3.98 × 10³⁰ kg )

Radius of neutron star R[tex]_N[/tex] = 13.0 km = 13 × 10³ m

Now, let mass of a small object on the neutron star be m

angular speed be ω[tex]_N[/tex].

During rotational motion, the gravitational force on the object supplies the necessary centripetal force.

GmM[tex]_N[/tex] = / R[tex]_N[/tex]² = mR[tex]_N[/tex]ω[tex]_N[/tex]²

ω[tex]_N[/tex]² = GM[tex]_N[/tex] = / R[tex]_N[/tex]³

ω[tex]_N[/tex] = √(GM[tex]_N[/tex] = / R[tex]_N[/tex]³)

we know that gravitational G = 6.67 × 10⁻¹¹ Nm²/kg²

we substitute

ω[tex]_N[/tex] = √( (  6.67 × 10⁻¹¹ )( 3.98 × 10³⁰ ) ) / (13 × 10³ )³)

ω[tex]_N[/tex] = √( 2.65466 × 10²⁰ / 2.197 × 10¹²

ω[tex]_N[/tex] = √ 120831133.3636777

ω[tex]_N[/tex] = 10992.32 rad/s

Therefore, The required angular speed the neutron star is 10992.32 rad/s

Two vectors are given as A⃗ = 2i^ + 3j^ − 3k^ and B⃗ = -1i^ + 5j^ + 3k^. Find A⃗ ⋅ B⃗

Answers

Answer:

A·B = 4

Explanation:

Given that,

Vector A = 2i+3j-3k

Vector B = -i+5j+3k

We need to find the value of A·B.

We know that,

i·i=j·j=k·k = 1 and i·j=j·k=k·i=0

So,

[tex]A\cdot B=(2i+3j-3k)\cdot (-i+5j+3k)\\\\=-2+5(3)+(-3)(3)\\\\=-3+15-9\\\\=4[/tex]

So, the value of A·B is equal to 4.

Which waves can travel through space?
a. Electromagnetic waves only
b. Mechanical waves only
c. Electromagnetic and mechanical waves
d. Longitudinal and electromagnetic waves

Answers

Answer:

electromagnetic waves only

Explanation:

I just took the test, Hope it helps!

Answer:

A: Electromagnetic waves only

Explanation:

Plz help, will Mark brainliest. A 20.0 Ohm and 60.0 Ohm resistor are connected in series to a 9.00 V battery. How much current flows out of the battery?
(Unit = A)

Answers

Answer: 0.1125A

Explanation:

We need to know the total resistance which will be:

R = R1+R2

where,

R1 = 20 ohm

R2 = 60 ohm

Therefore, R = 20 + 60 = 80 ohm

We should note that from Ohm's law

v = iR

i = v/R

where,

i = 9/80 = 0.1125 A

Therefore, the current that flows out of the battery is 0.1125A

what is an axis in social​

Answers

Answer:

An axis is an invisible line around which an object rotates, or spins. The points where an axis intersects with an object's surface are the object's North and South Poles.

I need help please only way to put my grade up !!!!!! Would appreciate it !!! Someone who’s good at this

Answers

Answer:

Total energy = 1000J

KE = 500J

PE = 500J

Explanation:

As you may know, the equation for gravitational potential energy is mgh (weight x height)

If the skateboard is halfway down, that means it is at half the height. As the skateboard speeds up (as it goes downward), the potential energy becomes kinetic energy. Since it has 500J of kinetic energy at half way down, it means it had double that amount of Potential energy at the top (1000J). Since half of that became kinetic energy, there is only 500J of PE left.

Total energy = KE + PE = 1000J

KE = 500J

PE = 500J

3) 4 electrons are placed - one electron per corner - at the corners of a square of side 1 meter. One fixed proton is placed in the middle of the square.The 4 electrons are held in place by some mechanism. The 4 electrons are released by the mechanism at the same time. They move and reach the corners of a square of side 0.8 meters, and keep on moving . Find the velocity of each electron at the corners of the square of side 0.8 meters.

Answers

Explanation:

3

i believe that they are all going at 3.2 meters each, I did 4 times 0.8

The velocity of each electron at the corners of the square is 15.92 m/s.

The given parameters;

charge of electron, q = 1.6 x 10⁻¹⁹ Clength of the square, L = 0.8 m

The diagonal length of the square is calculated as;

[tex]d^2 = 0.8^2 + 0.8^2\\\\d = \sqrt{0.8^2 + 0.8^2} \\\\d = 1.13 \ m[/tex]

The distance of each corner charge and the middle charge is calculated as;

[tex]r = \frac{1.13}{2} \\\\r = 0.565 \ m[/tex]

The force between each corner charge and the middle charge is calculated as;

[tex]F= \frac{kq^2}{r^2}[/tex]

The centripetal force on each charge moving around the square is calculated as;

[tex]F = \frac{mv^2}{r}[/tex]

solve the forces together;

[tex]\frac{mv^2}{r} = \frac{kq^2}{r} \\\\v^2 = \frac{kq^2}{m} \\\\v = \sqrt{ \frac{kq^2}{m} } \\\\v = \sqrt{ \frac{(9\times 10^9) \times (1.602\times 10^{-19})^2}{9.11 \times 10^{-31}} } \\\\v = 15.92 \ m/s[/tex]

Thus, the velocity of each electron at the corners of the square is 15.92 m/s.

Learn more here:https://brainly.com/question/13219544

What my fav food for 20 points if you know it!?

Answers

Answer:

pizza

Explanation:

Answer:

sea food???

Explanation:

Which diagram best represents the gravitational forces, F, be-
tween a satellite, S, and Earth?

Answers

Answer:

Diagram (3).

Explanation:

N3L states that if object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A ([tex]F_{A} = -F_{B}[/tex]).

The diagram which best represents the gravitational forces, F, between a satellite, S, and Earth is; Choice (3).

The Newton's law of gravitation states that the Force of attraction between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

The law clearly states a Force of attraction; the two objects come towards each other.

Consequently, Choice (3) best represents the gravitational forces, F, between a satellite, S, and Earth.

Read more:

https://brainly.com/question/11460810

PHYSICS HELP
PLEASE HELP ITS ABOUT ATWOOD MACHINES

Answers

Answer:

7.23407 [tex]\frac{m}{s^2}[/tex]

Explanation:

(I will not include units in calculations)

I'm assuming FBD's are already drawn, so I will work from there.

Let the 2.2kg block equal [tex]m_2[/tex], and the 20kg block equal [tex]m_1[/tex].

Summation equation for [tex]m_2[/tex]: [tex]\sum F_x=F_t_2-(F_f+F_g_x)=m_2a[/tex], [tex]\sum F_y=F_n-F_g_y=0[/tex]

Summation equation for [tex]m_1[/tex]: [tex]\sum F_y=F_g-F_t_1=m_1a[/tex]

Torque Summation Equation: [tex]\sum\tau=F_t_1*r-F_t_2*r=I\alpha[/tex]

Do some plugging in with the values given: [tex]\sum\tau=F_t_1*r-F_t_2*r=.5Mr^2\alpha[/tex]

Replace [tex]\alpha[/tex] with [tex]\frac{a}{r}[/tex], and cancel out the r's.

[tex]\sum\tau=F_t_1-F_t_2=.5Ma[/tex]

This step is important: Rearrange the force summation equation to solve for each tension force.

[tex]F_t_2=m_2a+F_f+F_g_x\\F_t_1=m_1g=m_1a[/tex]

Perform Substitution: [tex]\sum\tau=m_1g-m_1a-(m_2a+F_f+F_g_x)=.5Ma[/tex]

Now, we need to find the friction force and the horizontal component of the force of gravity.

Note that [tex]F_f=[/tex]μ[tex]F_n[/tex]

And based on our earlier summation equation: [tex]F_n=F_g_y[/tex]

First, break [tex]F_g[/tex] into x and y components. [tex]F_g_y=F_g\cos(\theta)[/tex], [tex]F_g_x=F_g\sin(\theta)[/tex]

Perform substitution with this and the fact that [tex]F_g=mg[/tex].

[tex]\sum\tau=m_1g-m_1a-(m_2a+\mu*m_2g\cos(\theta)+m_2g\sin(\theta))=.5Ma[/tex]

Solving for a, plugging in numbers yields an answer of 7.23407 [tex]\frac{m}{s^2}[/tex]

Answer:

7.23407

Explanation:

easy

A 3 kg block collides with a massless spring of spring constant 98 N/m attached to a wall. The speed of the block was observed to be 1.5 m/s at the moment of collision. The acceleration of gravity is 9.8 m/s 2 . How far does the spring compress if the surface on which the mass moves is frictionless

Answers

Answer: 0.83 m

Explanation:

Given

mass of the block is m=3 kg

spring constant k=98 N/m

The Speed at the time of collision is v=1.5 m/s

Here, the kinetic energy of the block is converted into Elastic potential energy

[tex]\Rightarrow \dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2 \\\\\Rightarrow 3\times 1.5^2=98\times x^2\\\\\Rightarrow x^2=0.6887\\\\\Rightarrow x=0.829\approx 0.83\ m[/tex]

A sphere with the same mass and radius as the original cylinder, but a smaller rotational inertia, is released from rest from the top of the ramp. KS and KC are the sphere's and cylinder's total kinetic energy at the bottom of the ramp, respectively. How do KS and KC compare, and why

Answers

Answer:

The Kinetic energy of Sphere is higher than the cylinder.

( KS > KC )

Explanation:

Given - A sphere with the same mass and radius as the original cylinder, but a smaller rotational inertia, is released from rest from the top of the ramp. KS and KC are the sphere's and cylinder's total kinetic energy at the bottom of the ramp, respectively.

To find - How do KS and KC compare, and why ?

Proof -

We know that,

The total energy of an object =  Potential energy +  linear kinetic energy + rotational kinetic energy.

⇒E = mgh + [tex]\frac{1}{2} mv^{2}[/tex] + [tex]\frac{1}{2} l\omega^{2}[/tex]  

Now,

Mass of sphere = m

Radius of sphere = r

So,

The moment of inertia of a uniform solid sphere = [tex]\frac{2}{5} mr^{2}[/tex]

Also,

Mass of cylinder = m

Radius of cylinder = r

So,

The moment of inertia of a uniform solid cylinder = [tex]\frac{1}{2} mr^{2}[/tex]

Now,

Total energy for the sphere , Es = mgh + [tex]\frac{7}{10} mv^{2}[/tex]

Total energy for the cylinder, Ec =  mgh + [tex]\frac{3}{4} mv^{2}[/tex]

As they always have the same total energy,

So, for height h of the sphere's velocity has to be higher.

Therefore,

The Kinetic energy of Sphere is higher than the cylinder.

Answer:

KS < KC

Explanation:

PLEASE HELP! I'LL GIVE BRAINLEST​

Answers

Neil is right as you don’t lose mass on the moon. The gravity is just stronger in earth so you weigh more on earth.

If a wave has a frequency of 5 hertz, the period for one wave cycle will be

Answers

Answer:

0.2 seconds

Explanation:

f=1/t

1/5=0.2

convert 1 day into seconds.(you will need to show your work to receive credit.) please help thank you​

Answers

Answer:

the answer is 86400seconds.

Explanation:

1day= 24 hours

24hours to seconds =

24×60×60= 86400 seconds.

( 60 second = 1 minutes)

( 60 minutes = 1 hour)

You are trying to catch the mutated mouse and you have a rope
that both you and the mouse are pulling with a force of 500 Newtons,
but the rope does not move.
How much work is done?


PLS ANSWER ASAP! WILL MARK AS BRAINLYIST!!!!!
time left (5:00)!!

Answers

Answer:

none no work cuz no motion

Explanation:

GOOD LUCK


PLEASE HELP !!!!!!!!!!

Answers

Answer:

1

Explanation:

If a 5-L balloon at 25 degrees celsius were gently heated to 30 degrees celsius, what new volume would the balloon have? Show all work for credi

Answers

Answer: 5.08 L.

Explation down below

Brian Lara is a cricketer playing in the field on the second day of a cricket test-match. He exerts a forward force on the 0.145kg cricket ball, as he catches it, to bring it to rest from a speed of 38.2m/s. During the process, his hand recoils a distance of 0.135m. Determine the acceleration of the ball and the force which is applied to it by Brian Lara.

Answers

Answer:

a = -3984.6 m/s²

F = 577.76 N

Explanation:

The acceleration of the ball can be calculated by using the third equation of motion:

[tex]2as = v_f^2 - v_i^2\\[/tex]

where,

a = acceleration of ball = ?

s = distance covered = recoil distance = 0.135 m

vf = final speed = 0 m/s

vi = initial speed = 38.2 m/s

Therefore,

[tex]2(0.135\ m)a = (0\ m/s)^2-(38.2\ m/s)^2\\[/tex]

a = -3984.6 m/s²

here negative sign shows deceleration.

Now, for the force applied by Brian Lara will be equal in magnitude but opposite in direction of the force required to stop the ball:

[tex]F = -ma\\F = -(0.145\ kg)(-3984.6\ m/s^2)\\[/tex]

F = 577.76 N


can someone please help me !!!!

Answers

Answer:

it's A subduction, deep water trench


A fisherman sitting on the end of a pier notices that 6 wave crests pass him in 3 seconds. What is the frequency of the waves?
9.0 Hz
18.0 Hz.
20 Hz
4.5 Hz

Answers

Do you know the muffin man?

The frequency of the waves will be 18 Hz. Then the correct option is B.

What is the frequency?

The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. One event occurs per second when measuring frequency in hertz.

Frequency is the number that represents the number of oscillations or intervals each second. The hertz is the SI unit for frequency (Hz). One cycle per second equals one hertz.

The number of finished waves produced each second is considered the wave frequency.

Six wave crests pass a fisherman sitting at the end of a pier in the span of three seconds.

The frequency of the waves is given as,

f = 6 x 3

f = 18 Hz

The waves will have a frequency of 18 Hz. Then, choice B is the best one.

More about the frequency link is given below.

https://brainly.com/question/29739263

#SPJ6

Niobium metal becomes a superconductor when cooled below 9K. Itssuperconductivity is destroyed when the surface magnetic fieldexceeds 0.100 T. Determine the maximum current a 2.00-mm-diameterniobium wire can carry and remain superconducting, in the absenceof any external magnetic field.

Answers

Answer:

the maximum current is 500 A

Explanation:

Given the data in the question;

the B field magnitude on the surface of the wire is;

B = μ₀i / 2πr

we are to determine the maximum current so we rearrange to find i

B2πr = μ₀i

i = B2πr / μ₀

given that;

diameter d = 2 mm = 0.002 m

radius = 0.002 / 2 = 0.001 m

B = 0.100 T

we know that permeability; μ₀ = 4π × 10⁻⁷ Tm/A

so we substitute

i = (0.100)(2π×0.001 ) / 4π × 10⁻⁷

i = 500 A

Therefore, the maximum current is 500 A

The wireless system is operating at 2GHz. A base station and a mobile unit are separated by 16km. The maximum gain of the transmitting antenna at the base station is 20dB. The input power to the transmitter is 100W, and the power received by the antenna is 5nW. The antennas are aligned, and there are no re ections or loses. What will be the received power if the distance between the mobile unit and the base station increases to 20km?

Answers

If everything else remains constant, then the received signal power is simply an inverse-square function of its distance from the transmitter.

That is, down 6dB when distance is doubled etc.

If distance increases from 16 to 20, then received power decreases by the factor of (16/20)^2.

That's (0.8)^2 = 0.64

New receive power is 5x0.64 = 3.2 nW

=. ===== ==========

Here's how I do it at my job:

Initial RSL = 5nW ~ - 53 dBm

loss = 20log(20/16)= 20log(1.25)~1.94dB

New RSL = - 54.94 dBm or ~ 3.2 nW .

A wheel has an angular speed of 32 rev/s when it experiences a constant angular acceleration of 65 rev/s2 which causes it to spin FASTER. During this time the wheel completes 92 rev. Determine how long the wheel was experiencing this angular acceleration and how fast the wheel was spinning at the end of this period. Assume that the wheel doesn't change the direction of its spin.

Answers

Answer:

ωf = 113.95 rev/s

t = 1.26 s

Explanation:

We can use the third equation of motion to find out the final spinning speed of the wheel:

[tex]2\alpha \theta = \omega_f^2 -\omega_i^2\\[/tex]

where,

α = angular acceleration = 65 rev/s²

θ = No. of revolutions completed = 92 rev

ωf = final angular speed = ?

ωi = initial angular speed = 32 rev/s

Therefore,

[tex](2)(65\ rev/s^2)(92\ rev) = \omega_f^2 - (32\ rev/s)^2\\\omega_f^2 = 11960\ rev^2/s^2 + 1024\ rev^2/s^2\\\omega_f = \sqrt{12984\ rev^2/s^2}[/tex]

ωf = 113.95 rev/s

Now, for the time we can use the first equation of motion:

[tex]\omega_f = \omega_i +\alpha t\\113.95\ rev/s - 32\ rev/s = (65\ rev/s^2)t\\t = \frac{81.95\ rev/s}{65\ rev/s^2}\\\\[/tex]

t = 1.26 s

PLEASE HELP! I'LL GIVE BRAINLEST​

Answers

Answer:

Weight = 8.162 Newton.

Explanation:

Given the following data;

Mass = 2.2 kg

Acceleration due to gravity = 3.71 N/kg

To find the weight of the textbook;

Weight = mass * acceleration due to gravity

Weight = 2.2 * 3.71

Weight = 8.162 N

Therefore, the weight of the science textbook in mars is 8.162 Newton.

The unit J/Pa is equivalent to

(a) m³

(b) cm³

(c) dm³

(d) None of these​

Answers

Answer:

(a) m³

Explanation:

Joule is the unit of work and Pascal is unit of pressure.

J/Pa = work/pressure = Nm/Nm⁻² =

Thus, The unit J/Pa is equivalent to

-TheUnknownScientist

Energy associated with moving objects or that could move later is?

Answers

Answer: Mechanical Energy

Explanation: Mechanical energy can be either kinetic energy (energy of motion) or potential energy (stored energy of position)

Hope this helped! :)
Other Questions
Ana planted a garden with equal of roses daffodils and tulips. if she randomly selects a flower what is the probability that it is a lilly True or false PLEASE EXPLAIN WHY ITS TRUE OR FALSE. Only European countries were practicing imperialism in order to build their empires. Explain social welfare and how each side views it. A printer makes more than 3 copies of a book every hour. How many books can the printer make in 4 hours? Which of the following was a major concern for Farmers out in the west during the 1890sA) the water shortage from the great droughtB) I need to get their products sold back in the eastC) the lack of protection from attacks of the FrenchD) it's over productive of wheat from the Great Plains ******WORTH 85 POINTS******WILL MARK BRAINLIEST*****PLEASE ANSWER ALL QUESTIONS****A catering company is setting up tables for a big event that will host 360 people. When they set up the tables they need 2 forks for eachchild and 5 forks for each adult. The company ordered a total of 1470 forks. Set up a system of equations involving the number of adults,a, and the number of children, c, and solve to find out how many of each attended the event.A) Create an equation to represent the breakdown of people attending this event (children and adults).B) Create an equation to model the number of forks used at this event.C) Solve the system you created and write down the number of Children and Adults that attended. 2) If there was a discount of 20%, what is the final deconstructedpercent? *A.0.8%B.120%C.20%D.80% 3.4 What is the importance of the "rule of law" Which of the following effects were caused by the Compromise of 1877? Union troops were to be removed from former rebellious southern states.the US government would supply subsidies to the textile industry to assist in rapidIndustrialization.Democrats were able to return to positions of power and take back control of theSouth.The US government would supply subsidies to the South Railroads to help theirgrowth.The US government would continue to fund the Freedman's Bureau for an additional 20 years.The US government would support appropriations for rebuilding levees along theMississippi River The passage below is from the U.S. Supreme Court decision Plessy Ferguson:We consider the underlying follacy of the plaintiff's argument to consist in the assumption that the enforced separation of the two races stamps thecolored race with a badge of inferiority. If this be so, it is not by reason of anything found in the act, but, solely because the colored race chooses to purthat construction upon it. If the civil and political rights of both races by equal, one cannot be inferior to the other civilly or politically. If one roce beinferior to the other socially, the constitution of the United States cannot put them upon the same plane.What was the impact of the reasoning in Plessy v Ferguson?A. Racial segregation remained in place in the South for another half century.B. Southern state governments were forced to end their practice of racial segregation.C. States government had to not provide equal facilities to members of different races.D. States government had to ensure economic social equality 15 chocolate were distributed between raju and sanju in the ratio 2:3 . How many chocolates did raju receive? NO LINKS OR WILL PLE REPORTED!! WILL GIVE BRAINIEST!! In the given figure, can you conclude r || s?A. The lines are parallel because the given angles are same-side interior angles and their sum is 180.B. The lines are parallel because the given angels are alternate interior and they are supplementary.C. The lines are not parallel because the given angles are corresponding angles and they do not have equal angle measures.D. There is not enough information. what is the value of d? 135 is 90% of what number A torque of 36.5 N m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result of a directed force combined with a friction force. As a result of the applied torque the angular speed of the wheel increases from 0 to 10.3 rad/s. After 6.10 s the directed force is removed, and the wheel comes to rest 60.6 s later. (a) What is the wheel's moment of inertia (in kg m2)? kg m (b) What is the magnitude of the torque caused by friction (in N m)? N m (c) From the time the directed force is initially applied, how many revolutions does the wheel go through? ______ revolutions Which of the following is meant to be taken literally?Select one: NO LINKS PLZThe bowl of popcorn was bottomless.I had detention for a week.She was dying for a glass of water.I was so hungry I could have eaten a horse. Please answer at least 5 at the most its really important and I need help.! (18 points) (tap on the picture) Karolyn puts 4,500 into a life insurance policy that pays 7.5% annual interest. If no additional investment is made into the policy how much accumulated interest should Karolyn expect at the end of 10 years? Bounty paper towels cost $8.49 for 8 rolls. Brawny paper towels cost $13.99 for 12 rolls. Which is the better buy? A total of 255 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student tickets sold was two times the number of adult tickets sold. How many adult tickets were sold? answer ASAP will give brainliest!!!