The change in the Gibb's free energy per mole (G) is 1.96 J.
The given parameters:
Density of the ice, ρ = 917 kg/m³Initial pressure, P₁ = 1.0 barFinal pressure, P₂ = 2.0 barTemperature, T = - 10 CMass of water = 18 gThe change in the Gibb's free energy per mole (G) is calculated as follows;
[tex]\Delta G = V(P_2-P_1) \\\\[/tex]
where;
V is the volume of the ice
[tex]Density = \frac{Mass}{Volume} \\\\Volume = \frac{Mass}{Density} \\\\Volume = \frac{18 \times 10^{-3} \ kg}{917 \ m^3} \\\\Volume = 1.96 \times 10^{-5} \ m^3\\\\Volume = 1.96 \times 10^{-5} \ m^3 \times \frac{1000 \ L}{m^3} \\\\Volume = 0.0196 \ L[/tex]
Change in pressure;
[tex]P_2 - P_1 = 2.0 \ bar \ - \ 1.0 \ bar = 1.0 \ bar = 0.987 \ atm[/tex]
The change in the Gibb's free energy per mole (G);
[tex]\Delta G= V(P_2-P_1)\\\\\Delta G = 0.0196\ L \times 0.987\ atm \\\\\Delta G = 0.0193 \ L.atm\\\\1 \ L.atm = 101.325 \ J\\\\\Delta G = 0.0193 \ L.atm \times \frac{101.325 \ J}{1 \ L.atm} \\\\\Delta G = 1.96 \ J[/tex]
Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.
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HELP PLEASE WILL MARK BRAINLIEST
Outside wooden steps may get slippery when they are wet. How could you make them less slippery?
There are many ways you can get wooden steps to be less slippery even when they are wet. Some ways are:
*You can put a carpet on the steps. The fibers in a carpet usually have some friction which will give you a grip as you climb up and/or down and prevent you from falling.
*You can apply anti-slip coatings like a paint on the steps. If you add some sand to the paint to add traction and lessen the slippery nature. Alternatively, If the wood has been waxed, you may consider using a wax remover.
*You can fix a hand railing so that you can hold on to it when you go up and down the steps.
when a student comned his dry hair for a long time, his hair began to stand up. Which of these has MOST LIKELY happened
His hair got charged due to continuous friction causing them to get attracted to other objects and thus standing up.
Answer:The comb and hair have become charged with opposite charges.
Explanation:When a comb is run through your hair charges pass between your hair and the comb, so the comb becomes charged either positively or negatively, and the hair oppositely charged. When the comb is brought close to paper an opposite charge is induced in the paper, and the opposite charges attract.
a rectangular block has the density of 350g/cm3 the dimensions are 3.5 6.cm 2.5
cm calculate the mass of the bock
Answer:
18375g
Explanation:
[tex]\boxed{density = \frac{mass}{volume} }[/tex]
[tex]∴ mass = density \times volume[/tex]
Let's find the volume of the rectangular block.
Volume
= length ×breadth ×height
= 3.5 ×6 ×2.5
= 52.5cm³
Mass of the block
= 350(52.5)
= 18375g
A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position �� as a function of time . What are the oscillation’s: a. period; b. frequency; c. angular frequency; d. amplitude; and e. What is the force constant of the spring?
(a) The period of the oscillation is 0.8 s.
(b) The frequency of the oscillation is 1.25 Hz.
(c) The angular frequency of the oscillation is 7.885 rad/s.
(d) The amplitude of the oscillation is 3 cm.
(e) The force constant of the spring is 148.1 N/m.
The given parameters:
Mass of the ball, m = 2.4 kgFrom the given graph, we can determine the missing parameters.
The amplitude of the wave is the maximum displacement, A = 3 cm
The period of the oscillation is the time taken to make one complete cycle.
T = 0.8 s
The frequency of the oscillation is calculated as follows;
[tex]f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz[/tex]
The angular frequency of the oscillation is calculated as follows;
[tex]\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s[/tex]
The force constant of the spring is calculated as follows;
[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m[/tex]
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Need help asap
A scientist has invented a robot to work on the seabed. According to his calculation, the armour of the robot can withstand a maximum pressure of 10⁵ Pa exerted by the sea water. If the density of the sea water is 1025 kg/m3, what is the maximum depth of the seabed that this robot can work? [Given g = 9.81 m/s2 and rho water = 1000 kg/m3]
Answer:
Explanation:
Well which is it ? ρ = 1000 kg/m³ or ρ = 1025 kg/m³?
Obviously the sea is salt water so we can ignore ρ = 1000 kg/m³
1025 kg/m³(d m)(9.81 N/kg) = 1 x 10⁵ N/m² = Pa
d = 9.9450535...
d = 10 meters
That's if we only account for the pressure due to the water. On top of that pressure would be atmospheric pressure which is about 101000 Pa
so the robot would be a hair above its pressure limit before it even got in the water.
20 PTS!
If an object is moving at a constant velocity, which must be true?
Its acceleration is zero.
Its acceleration in decreasing.
Its acceleration is increasing,
Its acceleration is a non-zero constant.
[tex]\huge \bf༆ Answer ༄[/tex]
The Correct choice is ~ A
[tex] \textsf{its \: acceleration \: is \: zero}[/tex]If an object moves at a constant velocity, then the change in velocity over the time is 0, Acceleration is defined as rate of change in velocity but since there is no change in velocity, the value of Acceleration is equal to Zero.
How much work is done on a 30 kg object when 20 Newton’s of force is exerted for a distance of 5 meters
Answer:
Work = force * displacement
= 50 N * 20 Meter
=1000 Newton meter = 1000 joule .
Explanation:
A jet is flying at a speed of 700 kilometers per hour. The pilot encounters turbulence due to a 50-kilometer- per-hour wind blowing at an angle of 47°. Find the resultant force on the plane.
Answer:
F = 0 N
Explanation:
The problem does not talk about any acceleration. We can just assume it always moves at a constant speed so the resultant force will be 0 newtons. Of course you could say that it accelerates for a certain amount of time, as the wind blows, but the problem doesn't tell us when to calculate the resultant force (if during the acceleration or after) + we don't have the mass of the jet.
3 materials that are denser than water and 3 that arent denser than water
Answer:
denser than water:
1. clay
2. coins
3. rock
aren't denser than water
1. wood
2. sponge
3. apple
the conduction of heat from hot body to cold body is an example of what thermodynamics process?
Answer:
Heat flow
Explanation:
Ben (55kg) is standing on very slippery ice when Junior (25kg) bumps into him. Junior was moving at a speed of 8m/s before the collision. Find the speed of ben and junior as they move across the ice after the collision. Give the answer in m/s. Describe the work you did to get the answer
Answer:
2.5m/s
Explanation:
m1=55kg
m2=25kg
Ben's velocity before collision=0m/s
Junior's velocity before collision= 8m/s
P1=m1v1+m2v2
P1=55kg(0m/s)+25kg(8m/s)
P1=200kg(m/s)
Know that the momentum before the collision = momentum after the collision
P2=(55kg+25kg)V
200kg(m/s)=(75kg)V
200kg(m/s)/75kg=V
V=2.5m/s.
It makes sense bc after they collide, their speed would slow down, and it wouldn't make sense if the momentum would be greater or less after they collide.
f. Protons and neutrons
2. TRUE or FALSE: An object that is positively charged contains all protons and no electrons
3. TRUE or FALSE: An object that is negatively charged could contain only electrons with me
accompanying protons
4. TRUE or FALSE: An object that is electrically neutral contains only neutrons.
An object which has more electron than proton is negatively charged, otherwise positively charged. Every statement is false
What is atom?Atom is the smallest unit of the matter consist of the positive charged nucleus and the electrons which moves around it. The atom can not be divided further.
The atom of a matter is made by three elements-
1) Neutron-Neutron is the element of atom, which has zero charge.2) Proton-Proton is the element of atom, which has positive charge.3) Electron-Electron is the element of atom, which has negative charge.For the Protons and neutrons, lets check all the statement wheather they are true or false.
2. An object that is positively charged contains all protons and no electrons- An object which is positively charged, has more number of proton than electron. This is a false statement.3. An object that is negatively charged could contain only electrons with me accompanying protons- An object, which is negatively charged, has more number of electron than proton. This is a false statement.4. An object that is electrically neutral contains only neutrons-The number of electron and proton is equal in an electrically neutral object. This is a false statement.Thus, every statement is false as a object which has more electron than proton is negatively charged, otherwise positively charged.
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Velocity v (m/s)
11/A stone is dropped from the top of a 45 m high building, How
fast will it be moving when it reaches the ground? And what
lits velocity be?
Explanation:
given solution
h=45m v^2=u^2+2gh
g=10m/s^2 v^2=0^2+2×10m/s^2×45m
vi=0 v^2=900m^2/s^2
v=30A block of wood
wood, with mass 1.34 kg rests stationary
on horizontal ground.
The coefficient of Kinetic
friction between the block and the ground is 0.966.
A bullet, with mass 0.250kg, moving horizontally
hits and sticks into the block of wood. We find
that the speed of the block of wood, with the
ballet embedded in it, just after collision is 11.9 m/s.
A) calculate the speed of the bullet before hitting the block of wood.
it, just after the collision
is 11-9mis.
as calculate the speed of the bullet before
s
hitting the block of wood.
Answer:
Explanation:
conservation of momentum
m(u) + M(0) = (m + M)v
u = (m + M)v/m
u = (0.250 + 1.35)(11.9) / 0.250
u = 76.16
u = 76.2 m/s
That's a fairly massive, and slow, bullet.
Two rods of mass m, length L are stuck together to form an X shape and spun around the center. What is the rotational inertia
Would it be possible to predict the speeds that a coaster will reach before it’s ever placed on the track?
Yes, it's possible to predict the speeds that a coaster will reach before it’s
ever placed on the track.
This is usually calculated with the potential energy which is
Potential energy = m g h
where m is mass, g is acceleration due to gravity and h is height.
The given formula above is used in predicting the speeds that a coaster will
reach before it’s ever placed on the track.
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what forces would a person inside an elevator feel when it is going up?
How do you measure a English saddle to fit your horses?
Answer:
measure the area in which the rider will sit on, then take those measurements to a person who crafts saddles, tell them the exact measurements. then you wait a while until he/she is done then put the saddle on the horse.
Explanation:
Answer:
Explanation:
The shape of the horse's withers is also a determining factor in choosing a saddle. An adjustable hoop saddle allows you to choose with finesse the opening of the tree at the height of the withers, in order to best adapt to each horse. It is the size of the arch that determines the opening of the saddle.
English saddles are the main riding saddles used in equestrian disciplines around the world: Show jumping, endurance, require specific designs to meet specific needs. For example, dressage saddles are designed to bring the rider closer to the horse, allowing him to communicate very precisely with his horse.
A student connects a 21.0 V battery to a capacitor of unknown capacitance. The result is that 52.8 µC of charge is stored on the capacitor. How much energy (in J) is stored in the capacitor?
Answer:
1.108 × [tex]10^{-3}[/tex]J
Explanation:
v=21.0v
Q=52.8× [tex]10^{-6}[/tex]
E=?
V=E/Q
E=v ×Q
=21 ×52.8 ×[tex]10^{-6}[/tex]
=1108.8 ×[tex]10^{-6}[/tex]
E= 1.108 × [tex]10^{-3}[/tex]J
In a collision, a 30 kg ball moving at 3 m/s transfers all of its momentum to a 5kg ball. what is the velocity of the 3kg ball after the collision?
Answer:
Explanation:
Is it a 30 kg ball or a 3 kg ball?
Does not matter as we don't have to do actual calculations
If all of the momentum is transferred out of a mass, the velocity remaining must be ZERO
A textbook weighs 34 N on the surface of the Earth. What is the book’s mass on Earth’s surface?
Answer:
About 3.47kg
Explanation:
Recall that weight is equal to mass times acceleration.
In this case, our acceleration is due to gravity which on earth is about 9.8m/s/s
So we have 34N=9.8 *mass, divide both sides by 9.8 we get mass is equal to about 3.47kg.
An airplane accelerates from rest down a runway at 9.50 m/s2 for 29.3 seconds when it
takes off. What is the distance traveled while taking off?
Answer:
Explanation:
s = ½at²
s = ½(9.50)(29.3²) = 4,077.8275
s = 4080 m
when rounded to the three significant digits of the question numerals.
Please help me answer the following image!
A baseball is hit with a speed of 27.0 m/s at an angle of 47.0 ∘ . It lands on the flat roof of a 10.0 m -tall nearby building. Part A If the ball was hit when it was 1.3 m above the ground, what horizontal distance does it travel before it lands on the building?
Answer:
H = Vy t - 1,2 g t^2 formula for height of ball after t sec
H = 10 - 1.3 = 8.7 m
Vy = 27 sin 47 = 19.7 m/s vertical speed of ball
8.7 = 19.7 t - 9.8/2 t^2 height of ball after t sec
4.9 t^2 - 19.7 + 8.7 = 0 rearranging
[19.7 ± (388 - 170)^1/2] / 2 *4.9 = [19.7 ± 14.7] / 9.8 = .51 ,3.5 sec
.51 sec would be on the way up and 3.5 sec on the way down
Sx = 27 * cos 47 * 3.5 = 64.4 m around 200 ft seems reasonable
A 70 kg man is running up the stairs which is 3m high in 2s.(a)How much work is done by the man?(b)What is the power exerted by the man? (Use g = 10ms 2)
Explanation:
m = 70 kg
s = 3m
t =2s
g = 10 m/s²
(a)How much work is done by the man?
W = Fs
= mg X s
= 70 x 3 x 10
= 210 x 10
= 2100 Joule
(b)What is the power exerted by the man?
P = W/t
= 2100/2
P = 1050 Watt
How can whales descend quickly and face no problems
Answer:
Whales face an increasing number of threats including: For hundreds of years people hunted whales for their oil to fuel lamps and candles, to lubricate machinery and to make margarine, lipsticks and other products. They also used baleen whales to make tennis racquets and corsets!
Explanation:
Help on 9 and 10!!!!!! I’ll give 5 starts
Answer: part a is e
part b a
Explanation:
I HOPE THIS HELPS
1. 1. are the charged parts of an atom.
a. Only electrons
b. Only protons
c. Neutrons only
d. Electrons and neutrons
e. Electrons and protons
f. Protons and neutrons
Answer:
e. Electrons and protons
Explanation:
Two satellites are in orbit around a planet. Satellite 1 has a mass of mm and an orbital radius of 2r2r. Satellite has a mass of 2m2m and an orbital radius of rr. If the magnitude of the gravitational force the planet exerts on Satellite 1 is FF, the magnitude of the gravitational force the planet exerts on Satellite 2 is
a) F
b) 1/2F
c) 2F
d) 1/4F
The magnitude of the gravitational force the planet exerts on Satellite 2 is 1/2F.
We recall that from Newton's law of universal gravitation, the gravitational force is given by;
F =G m1m2/r^2
m1 and m2 are the respective masses
r is the distance of separation.
Let the mass of the planet be M and the mass of the satellite be m. The distance of separation is r.
For satellite 1;
F = GmM/(2r)^2
F = GmM/4r^2
For satellite 2;
F2= G2mM/r^2
Hence, the magnitude of the gravitational force the planet exerts on Satellite 2 is 1/2F.
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. Boa constrictor snakes have tiny pelvic girdles and leg bones within their bodies. Since these structures are not functional, they are called *
a. vestigial
b. analogous
c. maladaptive
d. homologous
Those organic structures that do not seem to play any important biological function in the organism that possesses them are known as vestigial structures.
What is a vestigial structure?A vestigial structure is one that has atrophied or lost its original function throughout the course of evolution.
It generally refers to those organic structures that were useful at some point, but are now practically or totally useless.These structures are preserved as an inheritance of the evolutionary process, because at some point an ancestor of the current species had that structure, which was functional, but it ceased to be important and would end up atrophy.Therefore, we can conclude that vestigial structures are structures that some organisms still conserve as an inheritance from their ancestors but that, for some reason or another, are no longer useful for the functioning of the same.
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