Answers
Statement Problem: Select all values of x for which;
[tex]f(x)=g(x)[/tex]Solution:
The value of x for which the two functions are equal is the x-coordinate of their insections;
The coordinates of the intersections are;
[tex](0,-3)\text{ and }(4,5)[/tex]Thus, the values of x that is correct are;
[tex]x=0,x=4[/tex]Hence, CORRECT OPTIONS are;
[tex]A\text{ and D}[/tex]Related Questions
While solving an equation 2x^2+32=0 the answer calculated is x=+-4i I understand the +- means the answer can be positive or negative but what does the i mean
Answers
Answer:
Explanation:
Given:
[tex]\begin{gathered} 2x^2+32=0 \\ \text{The answer is x=}+-4i \end{gathered}[/tex]To fully understand how we get the given answer, we simplify the equation first:
[tex]\begin{gathered} 2x^2+32=0 \\ \text{Simplify and rearrange} \\ 2x^2=-32 \\ x^2=-\frac{32}{2} \\ x^2=-16 \\ \end{gathered}[/tex]Next, we apply the rule:
[tex]\begin{gathered} \text{For x}^2=f(a),\text{ the solutions are } \\ x=\sqrt[]{f(a)} \\ x=-\sqrt[]{f(a)} \end{gathered}[/tex]So,
[tex]\begin{gathered} x^2=-16 \\ x=\sqrt[]{-16},x=-\sqrt[]{-16} \end{gathered}[/tex]Then, we also apply the radical rule:
[tex]\begin{gathered} \sqrt[]{-a}=\sqrt[]{-1}\sqrt[]{a} \\ So, \\ x=\sqrt[]{-16} \\ =\sqrt[]{-1}\sqrt[]{16} \\ \text{Then, apply the imaginary number rule:} \\ \sqrt[]{-1}=i \\ \text{Hence,} \\ x=4i \end{gathered}[/tex]For
[tex]\begin{gathered} x=-\sqrt[]{-16} \\ Use\text{ the same steps} \\ x=-4i \end{gathered}[/tex]Therefore the x-values are: x=4i, x=-4i. The i on the answer means imaginary number. It is a number that, when squared, has a negative result.
after how many hours will the two trucks be 558 miles apart?
Answers
Given:
a.) A truck travels due west at an average speed of 48 miles per hour.
b.) The other truck travels due east at an average speed of 45 miles per hour.
Let's determine how many hours will the two trucks be 558 miles apart.
We will be using the following equation:
Let the two trucks be named Truck A and Truck B.
Let x = the time the two trucks will be 558 miles apart
[tex]\text{ (Speed of Truck A)(x) + (Speed of Truck B)(x) = 558 miles}[/tex]We get,
[tex]\text{ 48x + 45x = 558}[/tex]Let's find x,
[tex]\text{ 48x + 45x = 558}[/tex][tex]\text{ 93x = 558}[/tex][tex]\text{ }\frac{\text{93x}}{93}\text{ = }\frac{\text{558}}{93}[/tex][tex]\text{ x = }6[/tex]Therefore, the two trucks will be 558 miles apart after 6 hours.
A shop repairs 4 types of electronic devices. The number of repairs of each device last week is shown in the bar graph below. Use this bar graph to answer the questions.
Answers
Answer:
a) Telephone; 2 repairs
b) 3 more repairs
c) computer, radio , and television = 3 types
Explanation:
From the bar graph we see that the least amount of repairs done to the telephones. How many r
Evaluate. 5[83–(8-1)²]
Answers
5 [ 83- (8-1)²]
we will first work on the inner parenthesis
5 [ 83 - (7)²]
5[ 83 - 49]
5[34]
=170
What is the slope of a line that passes the points (-1,4 ) and ( 3,9 ) ?
Answers
Answer:
slope = 5/4
Step-by-step explanation:
What is the slope of a line that passes the points (-1,4 ) and ( 3,9 ) ?
slope = change in y ÷ change in x
slope = (9-4) ÷ (3 - (-1))
slope = 5/4
Graph the line that has an z-intercept of (-3,0) and a y-intercept of (0, - 5). What is the slope of this line?
Answers
Answer:
the slope is -5/3
Step-by-step explanation:
it is that because to find slope u do y2-y1/x2-x1
The total cost, in dollars of a membership in a fitness center is given by the function c(m) = 40m +10, where m is the number of months a person is a member. In dollars, how much is the cost of a membership for 1 year?
Answers
The cost of a membership for 1 year is 490
How to determine the cost of a membership for 1 year?The equation of the membership is given as
c(m) = 40m + 10
From the question, we understand that:
m represents the number of months
For the cost of a membership for 1 year, the number of months is 12
i.e. m = 12
Substitute the known values in the above equation
So, we have
c(12) = 40 * 12 + 10
Evaluate
c(12) = 490
Hence, the cost is 490
Read more about linear equation at
https://brainly.com/question/4074386
#SPJ1
while digging in his garden , will pushes a shovel into the ground at an 80 degree angle with 585 newtons of force . show the resolution of the force into its retangular components
Answers
Solution
Part a
Part b
For this case we can do this:
Fx= 585 N* cos 80= 101.58 N
Fy= 585N * sin 80= 576.11 N
Then the best answer is:
B. (102, 576) N
i need help with this problem
Answers
Answer:
whats the problme?
Step-by-step explanation:
26 is 50% of what number?
Answers
What is the scale factor of Figure B to Figure A?48.6B2510A1021.5A. O 6.25B.O 2.5C.0.16D. 0.4
Answers
As per given by the question,
There are given that two traingle, figure A and figure B.
Now,
The ratio of a dimension on figure B to the corresponding dimension on figure A is,
[tex]4\colon10=8.6\colon21.5=10\colon25[/tex]So,
The scale factor is,
[tex]\begin{gathered} k=\frac{10}{4}=\frac{25}{10}=\frac{21.5}{8.6}=2.5 \\ \end{gathered}[/tex]The scale factor of figure B on the figure A is 2.5.
Hence, the option B is correct.
Cuantas veses cabe el 13 en 47
Answers
Hay 3 veces 13 en 47.
La respuesta la divides 47 por 13 lo que te daría 3.6153846153846.
8. Find the slope between (-5, 4) & (0,3). * O m = 1/5 O O m = -5 m = 5 O m = -1/5
Answers
We can determine the slope using the following expression:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Now, using the two points given, we have:
[tex]m=\frac{3-4}{0-(-5)}\Rightarrow m=-\frac{1}{5}[/tex]From this, we have that the slope(m) equals -1/5.
What’s the correct answer answer asap for brainlist
Answers
Answer:
A. a chorus
Step-by-step explanation:
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Match the following scenarios with the correct inequality.
A phone company charges $15 per
month, and $2.50 for each gigabyte
of data used. Jaime cannot spend
more than $30 a month.
arrowBoth
A chess club has only $50 to make
t-shirts. It costs $15 for the design
and $3 per t-shirt.
arrowBoth
Sarah has $40 in a piggy bank. She
wants to keep at least $20 in the
piggy bank, and takes out half of
a dollar each week for a soda.
arrowBoth
Answers
The linear inequalities in this problem are given as follows:
Jaime/phone company: 15 + 2.5x ≤ 30.Chess club/t-shirt: 15 + 3x ≤ 50.Sarah/bank: 40 - 0.5x ≥ 20. What is a linear function?A linear function, in slope-intercept format, is modeled according to the rule presented as follows:
y = mx + b
In which the parameters of the function are described as follows:
The coefficient m is the slope of the function, representing the rate of change of the function, that is, the change in y divided by the change in x.The coefficient b is the y-intercept of the function, which is the value of y when the function crosses the y-axis(x = 0).For cost/monetary functions, the slope and the intercept are given as follows:
Slope: variable amount, such as cost per item.Intercept: fixed amount = one-time amount, such as flat fees.Then the inequalities are given as follows:
Jaime/phone company: 15 + 2.5x ≤ 30. (slope of 2.5 and intercept of 15).Chess club/t-shirt: 15 + 3x ≤ 50. (slope of 3 and intercept of 15).Sarah/bank: 40 - 0.5x ≥ 20. (slope of -0.5, negative as the amount is removed from the bank account, and intercept of 40).More can be learned about linear functions at https://brainly.com/question/24808124
#SPJ1
The tables of ordered pairs represent some points on the graphs of lines q and v. Line 9 Line v Х -9 -3 2. Х 0 10 у 0 18 33 у 10 8 3 Which system of equations is represented by lines q and v? F 21x - y = 9 5x + 6y = 40 G 3x - y = -27 x + 2y = 16 H 21x - y = 9 5x - 6y = 20 3 9x - y = -27 x + 2y = 8
Answers
One of the forms we can write the equation of a line is like this:
y - y1 = m(x - x1)
Where (x1, y1) is a point where the line passes through, and the value of m, the slope of a line is given by the following formula:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]Then, for the first line (line q), we can take the points (-9, 0) and (-3, 18), then we get:
[tex]mq=\frac{18-0}{-3-(-9)}=\frac{18}{-3+9}=\frac{18}{6}=3[/tex]By replacing the value of the slope and the coordinates of the point (-9, 0), we get:
y - 0 = 3(x - (-9))
y = 3(x + 9)
y = 3x + 27
y - y = 3x + 27 - y
0 = 3x + 27 - y
-27 = 3x + 27 - 27 - y
-27 = 3x - y
For line v, we can take the points (-4, 10) and (0, 8), then we get:
[tex]mv=\frac{8-10}{0-(-4)}=\frac{-2}{4}=-\frac{1}{2}[/tex]By taking -1/2 for the slope and the coordinates of the point (0,8), we gat:
y - 0 = -1/2(x - 8)
y = -1/2x + 4, multiplying both sides by 2:
2y = -x + 16
2y + x = -x + x + 16
2y + x = 16
Then, the system represented by the lines q and v is option G
1)EF=JHFEG = HJGXProve FEG = HJGStatement1) EF = JHReason1) given2)2) given3) Vertical angles are conguent3)4)4)Theorem
Answers
2.
[tex]\angle FEG\cong\angle HJG[/tex]3.
[tex]\angle HGJ\cong\angle EGF[/tex]What is the value of (–3 + 3i) + (–2 + 3i)?
Answers
Answer: -5+6i
Step-by-step explanation:
Select the correct answer. What is the solution to the equation? (x - 2)^1/2 + 4 = x A. -3 and -6 B. 3 and 6 C. -3 D. 6
Answers
Answer:
D. x = 6
Step-by-step explanation:
Given equation:
[tex](x-2)^{\frac{1}{2}}+4=x[/tex]
Subtract 4 from both sides:
[tex]\implies (x-2)^{\frac{1}{2}}+4-4=x-4[/tex]
[tex]\implies (x-2)^{\frac{1}{2}}=x-4[/tex]
Square both sides:
[tex]\implies \left( (x-2)^{\frac{1}{2}}\right)^2=(x-4)^2[/tex]
[tex]\implies x-2=(x-4)^2[/tex]
Expand the brackets on the right side:
[tex]\implies x-2=(x-4)(x-4)[/tex]
[tex]\implies x-2=x^2-8x+16[/tex]
Subtract x from both sides:
[tex]\implies x-2-x=x^2-8x+16-x[/tex]
[tex]\implies -2=x^2-9x+16[/tex]
Add 2 to both sides:
[tex]\implies -2+2=x^2-9x+16+2[/tex]
[tex]\implies 0=x^2-9x+18[/tex]
[tex]\implies x^2-9x+18=0[/tex]
Factor the left side of the equation:
[tex]\implies x^2-6x-3x+18=0[/tex]
[tex]\implies x(x-6)-3(x-6)=0[/tex]
[tex]\implies (x-3)(x-6)=0[/tex]
Apply the zero-product property:
[tex]\implies x-3=0 \implies x=3[/tex]
[tex]\implies x-6=0\implies x=6[/tex]
Therefore, the solutions of the quadratic equation are:
[tex]x=3, \quad x=6[/tex]
Input both solutions into the original equation to check their validity:
[tex]\begin{aligned}x=3 \implies (3-2)^{\frac{1}{2}}+4&=3\\(1)^{\frac{1}{2}}+4&=3\\1+4&=3\\5&=3\end{aligned}[/tex]
[tex]\begin{aligned}x=6 \implies (6-2)^{\frac{1}{2}}+4&=6\\(4)^{\frac{1}{2}}+4&=6\\2+4&=6\\6&=6\end{aligned}[/tex]
Therefore, the only valid solution to the given equation is x = 6.
Answer:
The answer is D. 6
Step-by-step explanation:
Add both sides:
(x - 2)^1/2 + 4 + (-4) = x + (-4)
(x - 2)^1/2 = -4
Solve exponent:
(x - 2)^1/2 = x - 4
((x - 2)^1/2)^2 = (x - 4)^2
x − 2 = x^2 − 8x + 16
x − 2 − (x^2 − 8x + 16) = x^2 − 8x + 16 − (x^2 − 8x + 16)
−x^2 + 9x − 18 = 0
(−x + 3)(x − 6) = 0
−x + 3 = 0 or x − 6 = 0
x = 3 or x = 6
Check the answers: (Plug them in to see what will work.)
x = 3 (won't work)
x = 6 (does work)
Therefore,
x = 6
Use the ALEKS calculator to write as a percentage.
31
32
Round your answer to the nearest tenth of a percent.
0%
X 5
?
Answers
Divide 31 into 32 and then multiply the result by 100 to get the percent:
[tex]\begin{gathered} \frac{31}{32}=0.96875 \\ \\ 0.96875*100=96.875 \end{gathered}[/tex]Then, to the nearest tenth of a percent the given fraction is 96.9%The figure shows a quarter circle and an equilateral triangle. What is thearea of the shaded part? Give your answer to 3 significant figures. (Take it= 3.14.)7 cm
Answers
Since the triangle is equilateral, all of its interior angles have a measure of 60º.
Substract the area of the triangle from the area of a circular sector with radius 7cm enclosed by an angle of 60º to find the area of the shaded region.
The area of an equilateral triangle with side length L is:
[tex]A=\frac{\sqrt[]{3}}{4}L^2[/tex]The area of a circular sector of radius r enclosed by an angle of θ degrees is:
[tex]A=\frac{\theta}{360}\times\pi r^2[/tex]Replace θ=60 and r=7cm to find the area of the circular sector:
[tex]A_c=\frac{60}{360}\times3.14\times(7\operatorname{cm})^2=25.643\ldots cm^2[/tex]Replace L=7cm to find the area of the triangle:
[tex]A_T=\frac{\sqrt[]{3}}{4}\times(7\operatorname{cm})^2=21.2176\ldots cm^2[/tex]Then, the area of the shaded region is:
[tex]\begin{gathered} A_C-A_T=25.6433\ldots cm^2-21.2176\ldots cm^2 \\ =4.4257\ldots cm^2 \\ \approx4.43\operatorname{cm}^2 \end{gathered}[/tex]Therefore, the area of the shaded region to 3 significant figures, is:
[tex]4.43\operatorname{cm}^2[/tex]can somebody please help me with this question
Answers
Answer:
I don't really understand this but I think will be a great way to solve this so 123.00
Step-by-step explanation:
.
What is Qualitative Data and what is the discreate and Continuous in qualitative data?
Answers
Answer:
Qualitative data is the data that is not represented by numbers, for example, favorite food or country.
On the other hand, the quantitative data is represented by numbers and it is classified as discrete and continuous. The discrete data is the data that only can take specific values, for example, the number of people is always a whole number, there can't be 5.5 people. The continuous data is the data that can take decimal values, for example, the mass of an object can be 4.06 kg.
Six friends went out for dinner. The total cost of their dinner was $92,82. If they divide the bill equally, how much should
each friend pay?
Provide your answer below:
Answers
Answer:$15.47 per person
Step-by-step explanation:
The total cost of the bill, divided into 6 groups:
92.82/6=15.47
4x-7 (2-x)=3x+2/ need help
Answers
First, apply distributive property to solve the parenthesis:
[tex]4x-7(2)-7(-x)=3x+2[/tex][tex]4x-14+7x=3x+2[/tex]Combine like terms:
[tex]-14+11x=3x+2[/tex][tex]11x-3x=2+14[/tex][tex]8x=16[/tex]Divide both sides by 8:
[tex]\frac{8x}{8}=\frac{16}{8}[/tex][tex]x=\text{ 2}[/tex]I'll send a picture! please answer fast!
Answers
Given data:
The given expression for the points is,
[tex]10w-3t+5[/tex]Thus, the expression or
Pre calculus 6a. Consider the equation x^5 - 3x^4 + mx^3 + nx^2+ ox + q = 0, where m, n, P, q € R.The equation has three distinct real roots which can be written as log2a, log2b and log2C.The equation also has two imaginary roots, one of which is di where dE R.Show that abc = 8.6b. The values a, b, and C are consecutive terms in a geometric sequence. Show that one of the real roots is equal to 1.6c. Given that q = 8d^2, find the other two real roots.
Answers
We have a fifth degree polynomial:
[tex]x^5-3x^4+mx^3+nx^2+px+q=0[/tex]This polinomial has 3 real roots, that can be expressed as: log2(a), log2(b) and log2(c).
Also, it has two imaginary roots, one of which is di (they have to be conjugate, so the other imginary root is -di).
We have to show that abc = 8.
If we consider the information given, we have some information about all the roots.
We can rewrite the polynomial in factorized form as:
[tex]\begin{gathered} (x-\log _2a)(x-\log _2b)(x-\log _2c)(x-di)(x+di)=0 \\ (x-\log _2a)(x-\log _2b)(x-\log _2c)(x^2+d^2)=0 \end{gathered}[/tex]As the polynomial is defined for real numbers, we can write a polynomial with only the real roots as:
[tex](x-\log _2a)(x-\log _2b)(x-\log _2c)=0[/tex]Then, we can relate the roots as:
[tex]\begin{gathered} 2^{(x-\log _2a)(x-\log _2b)(x-\log _2c)}=2^0 \\ 2^{(x-\log _2a)}\cdot2^{(x-\log _2b)}\cdot2^{(x-\log _2c)}=1 \\ \frac{2^x}{2^{\log_2a}}\cdot\frac{2^x}{2^{\log_2a}}\cdot\frac{2^x}{2^{\log_2a}}=1 \\ \frac{2^{3x}}{a\cdot b\cdot c}^{}=1 \\ abc=2^{3x} \\ abc=2^3\cdot2^x \\ abc=8\cdot2^x \end{gathered}[/tex]Jamar finds some nickels and quarters in his change purse. How much money (in cents) does he have if he has 4 nickels and 11 quarters? How much money (in cents) does he have if he has n nickels and q quarters?
Answers
1 nickel is worth 5 cents and 1 quarter is worth 25 cents.
So, if he has 4 nickels, this is worth 4 times 5 cents and if he has 11 quarters, this is worth 11 times 25 cents.
Both are worth the sum of these, so:
[tex]4\cdot5+11\cdot25=20+275=295[/tex]So, he has 295 cents.
If he has n nickels and q quarters, he has 5 times n plus 25 times q worth, so he has:
[tex]5n+25q[/tex]use the two given points and calculate the slope.(6,4),(4,-1)
Answers
EXPLANATION:
Given;
We are given two points which are shown below;
[tex]\begin{gathered} (6,4) \\ (4,-1) \end{gathered}[/tex]Required;
We are required to calculate the slope.
Step-by-step solution;
To calculate the slope given two points, we shall use the following formula;
[tex]\begin{gathered} Slope: \\ m=\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]Where the variables are;
[tex]\begin{gathered} (x_1,y_1)=(6,4) \\ (x_2,y_2)=(4,-1) \end{gathered}[/tex]We can now substitute these values and solve;
[tex]m=\frac{-1-4}{4-6}[/tex][tex]m=\frac{-5}{-2}[/tex][tex]m=\frac{5}{2}[/tex]Therefore.
ANSWER:
[tex]m=\frac{5}{2}[/tex]For each relation, decide whether or not it is a function.
Answers
Relation 1: Yes, each input corresponds to only one output.
Relation 2: No, the input of -1 corresponds to two outputs: sun and moon.
Relation 3: Yes, each input corresponds to only one output.
Relation 4: Yes, each input corresponds to only one output.