Simplify. -4(x+1)-6.

Answer: They need to complete 21 more jumps all together .

Step-by-step explanation: So 14+13=J

14+13=27

27=j

World record: 48; 48-27=21

They will have to jump 21 more times in a row .

(a) If a person who identifies as a man is 6 feet 3 inches tall, his z-score will be 2.96.

(b) If a person who identifies as a woman is 5 feet 11 inches tall, her z-score will be 2.17.

(a) To find the z-score, if a person who identifies as a man is 6 feet 3 inches tall.

Explanation: First, convert 6 feet 3 inches to inches.

6 feet 3 inches = (6 x 12) + 3 inches

= 72 + 3 inches

= 75 inches

The formula for calculating the z-score is: z = (x - μ) / σ, where x is the given value, μ is the mean, and σ is the standard deviation.

Substitute the given values in the above formula.

z = (75 - 69.2) / 2.63

= 2.21 / 2.63

= 0.8382

≈ 2.96 (to two decimal places)

(b) To find the z-score, if a person who identifies as a woman is 5 feet 11 inches tall..

Explanation: First, convert 5 feet 11 inches to inches.

5 feet 11 inches = (5 x 12) + 11 inches

= 60 + 11 inches

= 71 inches

The formula for calculating the z-score is: z = (x - μ) / σ, where x is the given value, μ is the mean, and σ is the standard deviation.

Substitute the given values in the above formula.

z = (71 - 64.6) / 2.53

= 6.4 / 2.53

= 2.5336

≈ 2.17 (to two decimal places)

Therefore, the z-score for the given heights of men and women in the US are 2.96 and 2.17 respectively.

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Given:

Base dimensions of a rectangular prism = 15 cm × x cm

The height of the prism = 8 cm

Volume of the prism = 600 cm.

To find:

The value of x.

Solution:

Base area of the prism is:

[tex]B=length\times width[/tex]

[tex]B=15\times x[/tex]

[tex]B=15x[/tex]

Volume of the prism is:

[tex]V=Bh[/tex]

Where, B is the base area and h is the height of the prism.

Putting [tex]V=600,B=15x,h=8[/tex], we get

[tex]600=15x\times 8[/tex]

[tex]600=(8)(15)x[/tex]

[tex]\dfrac{600}{(8)(15)}=x[/tex]

Therefore, the correct option is C.

Answer:

The value of g is  144 when h is 2 and j is 3 .

Step-by-step explanation:

If g varies jointly with h and j.

g = khj

Where k is the constant of proportionality.

Put value in the above

k = 4 × 6

k = 24

As when  h = 2 , j = 3 and k = 24 .

Put in the above

g = 2 × 3 × 24

g = 144

Therefore the value of g is 144 when h is 2 and j is 3 .

Answer:

true

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

60-44

The inequality is $40 + 4x < $60 and she has to spend 5 gigabytes to stay within her budget

Note that:  

> means greater than

< means less than

≥ means greater than or equal to  

≤ less than or equal to  

The total amount Lily has to spend has to be less than $60

The total amount she can spend can be represented with this equation

Flat cost + variable cost < $60

Flat cost = $40

Variable cost = cost per gigabyte x gigabyte

$4 × x = $4x

$40 + 4x < $60

To solve for x, combine similar terms

$4x < $60 - $40

$4x < $20

x < 5

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Answer:

Cost of 7 pound potato = $3.15

Step-by-step explanation:

Given:

Cost of 5 pound potato = $2.25

Find:

Cost of 7 pound potato

Computation:

Cost of 1 pound potato = 2.25 / 5

Cost of 1 pound potato = $0.45

Cost of 7 pound potato = 7 x Cost of 1 pound potato

Cost of 7 pound potato = 7 x 0.45

Cost of 7 pound potato = $3.15

The proposition that is a tautology is d. (p ^ q) → p. In a tautology, the truth value of the proposition is always true, regardless of the truth values of its individual components.

To determine if a proposition is a tautology, we can construct a truth table and evaluate all possible combinations of truth values for its variables.

For option d, (p ^ q) → p, we have the following truth table:

p q (p ^ q) (p ^ q) → p

T T T T

T F F T

F T F T

F F F T

The proposition that is a tautology is d. (p ^ q) → p.

In a tautology, the truth value of the proposition is always true, regardless of the truth values of its individual components. To determine if a proposition is a tautology, we can construct a truth table and evaluate all possible combinations of truth values for its variables.

For option d, (p ^ q) → p, we have the following truth table:

p q (p ^ q) (p ^ q) → p

T T T T

T F F T

F T F T

F F F T

As we can see, regardless of the truth values of p and q, the proposition (p ^ q) → p always evaluates to true. Therefore, option d is a tautology.

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To generate a figure containing the curves y = 1.5*sin(x) and y = x in MATLAB using the linspace and plot commands, you can follow the steps below:

matlab

% Set the range of x values

x = linspace(0, 2.5, 100);

% Calculate y values for each curve

y1 = 1.5*sin(x);

y2 = x;

% Plot the curves

plot(x, y1, 'b', x, y2, 'r')

% Add labels and title

xlabel('x')

ylabel('y')

title('Curves: y = 1.5*sin(x) and y = x')

% Add a legend

legend('y = 1.5*sin(x)', 'y = x')

% Display the grid

grid on

In this code, we use linspace to create a range of x values from 0 to 2.5 with 100 points. Then, we calculate the corresponding y values for each curve using the equations y1 = 1.5*sin(x) and y2 = x. We use the plot command to plot the curves, with 'b' and 'r' specifying the colors of the curves. Next, we add labels, title, and a legend to the graph. Finally, we display the grid.

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a) The required conditions are i. g(p) = p for p ∈ [a, b].ii. | g'(p) | < 1 for p ∈ (a, b).

b) |x1 - 1| ≤ a|x0 - 1|² for some a > 0, which implies that the iteration converges quadratically to 1 if x0 is sufficiently close to 1.

1. Consider the fixed-point iteration Pk= g(Pk), where g is continuously differentiable on [a, b].

(a) To converge to the fixed point p ∈ (a, b) for any p0 in that interval, the following conditions are required:

i. g(p) = p for p ∈ [a, b].ii. | g'(p) | < 1 for p ∈ (a, b).

(b) For g(x) = 1/3x²-2/3x+4/3, we have two fixed points: 1 and 4.

Let x be sufficiently close to 1:Then, x₁ = g(x₀) = 1/3x₀²-2/3x₀+4/3.

Since g is twice continuously differentiable on (1, 4), by Taylor’s theorem with the integral form of the remainder, we obtain x₁ - 1 = 1/2g"(c)(x₀ - 1)² ≤ 1/2k(x₀ - 1)², where k = supc∈[1,x] | g"(c) | < ∞.

Therefore, |x₁ - 1| ≤ a|x₀ - 1|² for some a > 0, which implies that the iteration converges quadratically to 1 if x0 is sufficiently close to 1.

Similarly, if x is sufficiently close to 4, the iteration converges quadratically to 4.

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We cannot construct a square that equals the sum of the areas of two given squares. This statement contradicts the mathematical principles and properties of squares and the Pythagorean theorem.

The statement that given any two squares, we can construct a square that equals the sum of the two given squares is actually false. This statement goes against the well-known mathematical concept known as the Pythagorean theorem.

The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. This theorem holds true for right-angled triangles, but it does not hold true for squares.

In fact, if we take two squares and try to add their areas together, the result will not be a square with an area equal to the sum of the two given squares. The resulting shape will be a non-square rectangle or some other irregular shape.

Therefore, we cannot construct a square that equals the sum of the areas of two given squares. This statement contradicts the mathematical principles and properties of squares and the Pythagorean theorem.

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Answer:

The sample is the amount of people because not everyone is getting chosen

Step-by-step explanation:

I also agree, the coach choose certain people to march cuz not everyone is gonna be able to get used.

To multiply 4/5 by 1/3 using the rectangular model, follow the given steps below:

Step 1: Draw a rectangle and divide it into equal parts (columns and rows) based on the denominator of the given fractions. Here, 5 parts in a row (horizontally) and 3 parts in a column (vertically).

Step 2: Shade in the portion of the rectangle that corresponds to 4/5.

Step 3: Shade in the portion of the rectangle that corresponds to 1/3. You can do this by dividing the height into three equal parts and shading the top part of the rectangle.

Step 4: Find the area of the shaded region of the rectangle. The area of the shaded region of the rectangle is the product of the fractions 4/5 and 1/3. In other words, it is the product of the number of shaded squares in both the shaded regions.

Step 5: Simplify the answer. In this case, you should simplify the product 4/5 × 1/3 before finding the answer. The rectangular model of 4/5 by 1/3 is shown below:

Given fractions: 4/5 and 1/3To find: Multiplication of 4/5 and 1/3 using the rectangular model. The rectangular model is one of the methods to find the multiplication of two fractions visually.

By using this method, we can multiply two fractions by drawing a rectangle that is divided into equal parts based on the denominators of the given fractions and shade in the required portions of the rectangle.

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Answer:

91in^2

Step-by-step explanation:

First, add 11 and 15:   11 + 15 = 26

Second, divide it by 2: 26/2 = 13

Third, multiply it by the height: 13 * 7 = 91in^2

Answer:

The number will decrease in value

Step-by-step explanation: For example if we had 638.23 if I move the decimal to the left 3 times it would be .63823, and if we add zeros it would look like this, 0.63823 so the number would decrease in value

Answer:

B. 5

Step-by-step explanation:

This table does not describe a linear relationship. This is because the table does not have a constant rate of change; between the first two points, the function changes by

(1/2 - 1/10)/(0--1) = (5/10 - 1/10)/(1) = 5/10 - 1/10 = 4/10 = 2/5

Between the second two points, the function changes by

(5/2-1/2)/(1-0) = (4/2)/1 = 4/2 = 2

Comparing the first two y-coordinates, we have 1/10 and 1/2 = 5/10. This is the result of multiplication by 5.

Comparing the second two y-coordinates, we have 1/2 and 5/2. This is the result of multiplication by 5.

Comparing the rest of the y-coordinates, we can see that each time, the y-coordinate is multiplied by 5. This means the rate of change is 5.

Answer: Randomization prevents the researchers from specifically assigning all adults who regularly stay up late to complete assigned tasks late at night.

-Randomization ensures each group will be similar in everything except the time of day they are assigned to work.

-Randomization prevents the adults from selecting their own group.

Step-by-step explanation:

The options include:

a. Randomization ensures each group will be similar in everything except the time of day they are assigned to work.

b. Randomization prevents the adults from selecting their own group.

c. Randomization eliminates lurking variable from the experiment.

d. Randomization prevents the researchers from specifically assigning all adults who regularly stay up late to complete assigned tasks late at night.

e. Randomization ensures that there'll be an equal number of adults in each group.

Randomization refers to a method that is based on chance alone whereby the participants in a particular study are assigned to treatment group. Based on the information given, it us important that the researchers use randomization to assign each of the adults to a group because:

• Randomization ensures each group will be similar in everything except the time of day they are assigned to work.

• Randomization prevents the researchers from specifically assigning all adults who regularly stay up late to complete assigned tasks late at night.

• Randomization prevents the adults from selecting their own group.

Answer:

Hi how are you doing today Jasmine

Answer:

x= -1/3•log10(9/2)

x= -0.218

The given differential equation is shown to be homogeneous, and the solution to the equation with the initial condition y(1) = 4 is :

y = 6x^2 * e^(-x/2) - 2x.

i) To show that the differential equation is homogeneous, we need to verify that it is invariant under the transformation y = ux, where u is a function of x.

Let's substitute y = ux into the given differential equation:

dy/dx = 3xy + y^2 / x^2 + xy

Using the chain rule, we can express dy/dx in terms of u and x:

dy/dx = d(ux)/dx = u + x * du/dx

Substituting this into the differential equation:

u + x * du/dx = 3x(ux) + (ux)^2 / x^2 + x(ux)

Simplifying the equation:

u + x * du/dx = 3u + u^2 / x + u

The equation can be further simplified:

x * du/dx = 2u + u^2 / x

We can see that the resulting equation is independent of x. Hence, the original differential equation is homogeneous.

ii) To solve the homogeneous differential equation, let's substitute y = xv back into the equation:

x * du/dx = 2u + u^2 / x

Multiplying through by x:

x^2 * du/dx = 2xu + u^2

Rearranging the equation:

x^2 * du / (2u + u^2) = dx

We can now integrate both sides:

∫ x^2 * du / (2u + u^2) = ∫ dx

The left-hand side can be further simplified using partial fraction decomposition:

∫ (A/u + B/(u+2)) du = ∫ dx

Solving for A and B, we get:

A = -2, B = 1

Substituting back into the integral:

∫ (-2/u + 1/(u+2)) du = ∫ dx

Simplifying the integral:

-2ln|u| + ln|u+2| = x + C

Now substituting u = y/x:

-2ln|y/x| + ln|(y/x)+2| = x + C

Using properties of logarithms, we can simplify this equation further:

ln((y+2x)/x^2) = -x/2 + C

Taking the exponential of both sides:

(y+2x)/x^2 = e^(-x/2+C)

Simplifying the right-hand side by combining e^C into a constant A:

(y+2x)/x^2 = A * e^(-x/2)

Now, solving for y:

y + 2x = Ax^2 * e^(-x/2)

Finally, rearranging the equation to solve for y:

y = Ax^2 * e^(-x/2) - 2x

Given the initial condition y(1) = 4, we can substitute x = 1 and y = 4 into the equation:

4 = A * e^(-1/2) - 2

Solving for A:

A * e^(-1/2) = 6

A = 6 * e^(1/2)

Substituting the value of A back into the equation, we have:

y = 6x^2 * e^(-x/2) - 2x

So the solution to the differential equation with the initial condition y(1) = 4 is y = 6x^2 * e^(-x/2) - 2x.

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Using the MGF and its derivatives, we have shown that the mean and variance of the standard normal distribution are both 0.

The MGF for the standard normal distribution is given as:

M(t) = e^(t²/2)

To find the mean of the standard normal distribution, we take the first derivative of the MGF with respect to t and evaluate it at t = 0:

M'(t) = (1/2)e^(t²/2) × 2t

Evaluating at t = 0:

M'(0) = (1/2)e⁰ × 2(0) = 0

Since the first derivative of the MGF evaluated at t = 0 is 0, this implies that the mean of the standard normal distribution is 0.

To find the variance of the standard normal distribution, we take the second derivative of the MGF with respect to t and evaluate it at t = 0:

M''(t) = (1/2)e^(t²/2) × 2t² + (1/2)e^(t²/2)×2

Evaluating at t = 0:

M''(0) = (1/2)e⁰ × 2(0)² + (1/2)e⁰ × 2

= 0 + 1

= 1

Since the second derivative of the MGF evaluated at t = 0 is 1, this implies that the variance of the standard normal distribution is 1.

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To best collect a sample of books from the 13,000 titles at the bookstore, Miguel should use a cluster sampling method.

The best sampling method Miguel should use is a cluster sample.

A cluster sample involves dividing the population into clusters or groups and randomly selecting entire clusters to include in the sample.

In this situation, Miguel could divide the bookstore's titles into clusters, such as by genre or shelf location, and randomly select clusters to sample books from.

his method would help ensure representation from different areas of the bookstore and provide a diverse sample of books.

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Answer:

4

Step-by-step explanation:

Answer:

Just multiply the exponents of the numbers

So this is the order from top to below and I'll mark as 1 to 5

2

1

4

5

3

The middle is a square with side length of 12cm

Area of the square = 12 x 12 = 144 cm^2

There are 4 triangles with base of 13cm and height of 8 cm

Area of triangle = 1/2 x base x height

Area = 1/2 x 12 x 8 = 48cm^2 each

48 x 4 = 192 cm^2

Total area = 144 + 192 = 336 cm^2

Answer:

periodttt. get out ya bag n make det money up.

Step-by-step explanation:

brainliestt:)?

Answer:

i dont what an ellipse is but here's the answer:

8x + 32y = 121

Answer:

123‐10×40y=0

10×+40y=123

Answer:

The format of this equation is wrong

Answer:

(240,20)

Step-by-step explanation:

The correct answer is, [–5, 3]. In the other words, the interval in which the function [tex]f(x) = \sqrt{x^2 + 2x - 15}[/tex] is increasing is [–5, 3].

To determine the interval in which the radical function [tex]f(x) = \sqrt{x^2 + 2x - 15}[/tex] is increasing, we need to find the interval(s) where the derivative of the function is positive.

Let's first find the derivative of f(x):

[tex]f'(x) = (1/2) * (x^2 + 2x - 15)^(-1/2) * (2x + 2)[/tex]

To find where f'(x) > 0, we set f'(x) = 0 and solve for x:

[tex](1/2) * (x^2 + 2x - 15)^(-1/2) * (2x + 2) = 0[/tex]

Since the derivative is never equal to zero (since the denominator (x^2 + 2x - 15)^(-1/2) is never equal to zero), there are no critical points.

To determine the intervals of increase, we can evaluate f'(x) at test points in each interval. We'll consider the intervals defined by the given answer choices:

[3, ∞):

Choose a test point x > 3, let's say x = 4.

Evaluate [tex]f'(4) = (1/2) * (4^2 + 24 - 15)^{(-1/2)} * (24 + 2)[/tex]

[tex]= (1/2) * (16 + 8 - 15)^{(-1/2)} * 10[/tex]

[tex]= (1/2) * (9)^{(-1/2)} * 10[/tex]

= (1/2) * (1/3) * 10

= 5/3

Since f'(4) > 0, the function is increasing in the interval [3, ∞).

(4, ∞):

Choose a test point x > 4, let's say x = 5.

Evaluate f'(5) = (1/2) * (5^2 + 25 - 15)^(-1/2) * (25 + 2)

= (1/2) * (25 + 10 - 15)^(-1/2) * 12

= (1/2) * (20)^(-1/2) * 12

Since f'(5) = 0, the function is not increasing in the interval (4, ∞).

[–5, 3]:

Choose a test point x in the interval, let's say x = 0.

Evaluate [tex]f'(0) = (1/2) * (0^2 + 20 - 15)^{(-1/2)} * (20 + 2)[/tex]

[tex]= (1/2) * (-15)^{-1/2} * 2[/tex]

[tex]= (1/2) * (1/\sqrt{15}) * 2[/tex]

[tex]= 1/\sqrt{15}[/tex]

Since f'(0) > 0, the function is increasing in the interval [–5, 3].

(–∞, –5] ∪ [3, ∞):

Since we have already determined the function is increasing in [–5, 3] and [3, ∞), this interval is valid.

Therefore, the correct answer is, [–5, 3]. In the other words, the interval in which the function [tex]f(x) = \sqrt{x^2 + 2x - 15}[/tex] is increasing is [–5, 3].

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