Solve for x. Round to the nearest tenth. 34° 90% (Figure is not necessarily drawn to scale) O x 3.1 0x 2.7 x=2 C= 5.9​

Solve For X. Round To The Nearest Tenth. 34 90% (Figure Is Not Necessarily Drawn To Scale) O X 3.1 0x

Answers

Answer 1

Answer:

x=2.7

Step-by-step explanation:

tan34 = x/4

x = 4tan34 = 2.7


Related Questions

NEED ASAP
What is the rule for the function that is graphed?

Answers

Answer:

C

Step-by-step explanation:

The y-intercept if the graph is 2 and the slope is 2 so the rule is y=2x+2

What is the perimeter of triangle JKL (same triangle as question #1)?

Answers

Answer:

x=30

Step-by-step explanation:

You have to use intercept theorem, also known as Thales's theorem to slvoe this.

Ok help me I don’t understand stand this

Answers

Answer:

Step-by-step explanation:

Comment

It is not possible to figure out what choices are are given for the first blank. I will say that the probable choice has the word product in it.

The second blank is the actual number of choices. It is 3 page count times color or 3*4 = 12 different choices.

Answer

product

12

B Christian installed an electric pump to pump water from a borehole into a 30 000 litre cement dam. If the water is pumped at a rate of 75 litres per minute. How long does it take to fill the dam?
A.4 h
B.6 h 40 min
C.6 h 20 min
D.3h 40 min ​

Answers

Given the amount of water needed to fill the cement dam and the water pump rate, the time needed to fill the dam is 400 minutes or 6hours 40minutes.

Option B)6h 40min is the correct answer.

How long does it take to fill the dam?

Given that;

Amount of water needed to fill the dam A = 30000 litresPump rate r = 75 litres per minuteTime needed to fill the dam T = ?

To determine how long it take to fill the dam, we say;

Time need = Amount of water needed ÷ Pump rate

T = A ÷ r

T = 30000 litres ÷ 75 litres/minute

T = 400 minutes

Note that; 60min = 1hrs

Hence,

T = 6hours 40minutes

Given the amount of water needed to fill the cement dam and the water pump rate, the time needed to fill the dam is 400 minutes or 6hours 40minutes.

Option B)6h 40min is the correct answer.

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What characteristics do all points in Quadrant I share?
A. The x-coordinate is positive and the y-coordinate is positive.
B. The x-coordinate is negative and the y-coordinate is negative.
C. The x-coordinate is positive and y-coordinate is negative.
D. The x-coordinate is negative and y-coordinate is positive.

Answers

Answer:

Option A

Step-by-step explanation:

Remember the things.

In Q1

x>0,y>0

in Q2

x<0,y>0

in Q3

x<0,y<0

in Q4

x>0,y<0

Answer:

A. The x-coordinate is positive and the y-coordinate is positive.

Step-by-step explanation:

The Cartesian plane is divided into four regions by the x-axis and y-axis.

These regions are called "quadrants".

Quadrant I is the top right region, where x and y coordinates of points are positive.

From here, move in a counterclockwise direction.  

Therefore, Quadrant II is the top left region, where the x-coordinate is negative and the y-coordinate is positive.

Quadrant I → (x, y)

Quadrant II → (-x, y)

Quadrant III → (-x, -y)

Quadrant IV → (x, -y)

A plane has a speed of 840 km/h in still air. It can travel 3120 km with the wind in the same time it would take to travel 1920 km against the wind. Find the speed of the wind.​

Answers

Answer:

200 KM/H

Step-by-step explanation:

A plane has a speed of 840 km/h in still air. It can travel 3120 km with the wind in the same time it would take to travel 1920 km against the wind. Find the speed of the wind.

let x=speed of wind

(840+x)=speed of plane with wind

(840-x)=speed of plane against wind

Travel time = distance/speed (same with and against the wind)

3120/(840+x)=1920/(840-x)

cross-multiply

3120*840-3120x=1920*840+1920x

3120*840-1920*840=1920x+3120x

5040x=1008000

x=200 km/hr

answer

Speed of wind=200 km/hr

Help will mark brainliest!

Answers

a) The compound interest equation is [tex]C = 4250 \cdot 0.9675^{t}[/tex].

b) There is an approximate loss of $ 987.16.

c) The stock will take approximately 12.979 to decrease by half.

How to find stock losses by compound interest model

Compound interest model represents the gain of a deposit as a function of the number of periods and initial amount. The model is represented below:

[tex]C = C_{o}\cdot (1+r)^{t}[/tex]     (1)

Where:

[tex]C_{o}[/tex] - Initial capital, in monetary units.[tex]r[/tex] - Interest rate.[tex]t[/tex] - Period number.[tex]C[/tex] - Current capital, in monetary units.

Capital decreases in time when interest rate is a negative number. The equation that models the situation is [tex]C = 4250 \cdot 0.9675^{t}[/tex] and the current capital after eight years is:

C = 4250 · 0.9675⁸

C = 3262.84

That represents an approximate loss of $ 987.16.

And the number of periods required to decrease the capital by half is:

[tex]2125 = 4250 \cdot 0.9675^{t}[/tex]

[tex]0.5 = 0.9675^{t}[/tex]

㏒ 0.5 = t · log 0.9675

t ≈ 20.979

The stock will take approximately 12.979 to decrease by half.

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11. 6.2 m B 1.8m Calculate the value of x. NOT TO SCALE​

Answers

Answer:

24.19

Step-by-step explanation:

[tex] \tan(x) = \frac{6.2}{13.8} \\ x = { \tan}^{1} \frac{6.2}{13.8} \\ x = 24.19320899[/tex]

or the value of x can be 24.20

A number cube with the numbers 1 through 6 is rolled. What is the theoretical probability, as a decimal, of the number cube showing a 1? Round the decimal to the nearest hundredth

Answers

Answer:

0.17 (rounded)

Step-by-step explanation:

There's only one way a 1 can appear on a number cube out of 6 possible sides. Thus, the theoretical probability of the number cube showing a 1 is 1/6, or 0.17 rounded.

How is 0.136¯¯¯¯ written as a fraction in simplest form?



Enter your answer in the box.

Answers

Answer:

[tex]\frac{3}{22}[/tex]

Step-by-step explanation:

the bar above 36 means that the digits 36 are being repeated

we require 2 equations with the repeating digits placed after the decimal point.

let x = 0.13636.. ( multiply both sides by 10 and 1000 )

10x = 1.3636... (1)

1000x = 136.3636... (2)

subtract (1) from (2) thus eliminating the repeating digits

990x = 135 ( divide both sides by 990 )

x = [tex]\frac{135}{990}[/tex] = [tex]\frac{3}{22}[/tex] ← in simplest form

Eliminate the parameter:
x = (3t+ 2)² y = t - 2

Answers

Solve for t in terms of y :

[tex]y = t - 2 \implies t = y + 2[/tex]

Substitute this into the parametric equation for x :

[tex]x = (3t + 2)^2 \implies x = (3(y + 2) + 2)^2 \implies \boxed{x = (3y+8)^2}[/tex]

please, I really need this answer the soon as possible. I'm going to be so thankful if anyone could help me with this...​

Answers

Answer:

5/6

Step-by-step explanation:

i'm not rly confident,, but i used a calculator and solved it,,

so im sry if im wrong. Good luck!!

What substitution should be used to rewrite 6(x 5)2 5(x 5) – 4 = 0 as a quadratic equation?

Answers

The answer is u=(r+5)

Answer the follwing grade 5 questions of HFC and LCM

Answers

Answer:

give clear image is next question

Step-by-step explanation:

i will give you the answer

Write an equation for each translation y=sin x, pi/4 units to the right

Answers

The equation of the translation is y = sin(x - π/4)

How to determine the translation?

The equation is given as:

y = sin(x)

The rule of translation to the right is:

(x,y) => (x - h,y)

This gives

(x,y) => (x - π/4,y)

So, we have:

y = sin(x - π/4)

Hence, the equation of the translation is y = sin(x - π/4)

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COSINE LAW: Solve triangle PQR. round angles to the nearest tenth​

Answers

Answer:

Hi,

Step-by-step explanation:

PR²=PQ²+QR²-2*PQ*QR*cos(51°)

=15²+12²-2*15*12*cos(51°)

=142,444659....

PR=11.9350...

PQ²=QR²+PR²-2*QR*PR*cos(R)

cos(R)=(12²+142.444...-15²)/(2*12*11.9350...)=0,21451112....

angle R=77,61315...°≈77.6°

angle P=180°-51°-77.6°≈51,4°

Find the 5th term of the sequence which has a first term of 1 and has a common ratio of 2.3. Round your answer to the nearest hundredth if necessary.

Answers

The 5th term of the sequence is 27.98

How to determine the 5th term?

The given parameters are:

First term, a = 1Common ratio, r = 2.3

The nth term of a geometric sequence is calculated using:

[tex]T_n = ar^{n-1[/tex]

So, we have:

[tex]T_5 = 1 * 2.3^{5-1[/tex]

Evaluate the difference

[tex]T_5 = 1 * 2.3^4[/tex]

Evaluate the product

[tex]T_5 = 27.98[/tex]

Hence, the 5th term of the sequence is 27.98

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What is value of x in the equation 6x+7-2x=3+5x-9

Answers

Answer: x = 13

Step-by-step explanation: First, we simplify the equation to get 4x + 7 = 5x - 6. Then, from there, we subtract 7 on both sides to get 4x = 5x - 13. Then we subtract 5x from both sides, which would give us -x = -13. Finally, we can divide both sides by -1 (because remember, x = 1) to get that x = 13. Hope this helps!

Pls help! I don't get this!!

Answers

Answer:

5;   2n + 5 ≤ 15

6;   n/5 ≤ 15

7;   5n ≥ 15

Step-by-step explanation:

"a number" means a variable denoted "n"

"product" means to multiply

"quotient" means to divide

"The sum" means to add

"is at least" means greater than or equal to or  ≥

"is no greater than" means less than or equal to or ≤

"Is at most" means less than or equal to or ≤

Find the solution to each system please show your work!

Answers

Answer:

infinite number of solutions

Step-by-step explanation:

x + y = 1 → (1)

3y = - 3x + 3 ( add 3x to both sides )

3x + 3y = 3 ( divide through by 3 )

x + y = 1 → (2)

since the 2 equations are the same, this indicates the system has an infinite number of solutions

Solve the system by elimination. 8x+3y=4 2x+y=2​

Answers

Answer:

 x = -1

y = 4

Step-by-step explanation:

Solving system of linear equations by elimination method.

    8x +  3y = 4 ---------------(I)

    2x  + y = 2 --------------(II)

Multiply the second equation by (-3) and then add them.Thus y will be eliminated and we will obtain the value of 'x'.

       (I)                8x  +  3y = 4

     (II)*(-3)         -6x - 3y = -6   {Now add}

                           2x         = -2

                                     x = -2/2

                           [tex]\sf \boxed{\bf x = -1}[/tex]

Plugin x = (-1) in any one of the equations. Here I have chosen equation (II)

2*(-1) + y = 2

    -2 + y  = 2

           y = 2 + 2

            [tex]\sf \boxed{\bf y = 4}[/tex]

A bank converts U.S. dollars to European euros at a rate of $1 for 0.88 euros. Kelsey wants 100 euros for her trip to Europe.

How much money, in dollars, does Kelsey need to give the bank

Answers

Answer:

$113.64

Step-by-step explanation:

0.88 x $113.636364 = 100 euros

= $113.64

(Hope this helps ^-^)

5. If the longer side of the rectangle is 25.5 in., what are its width, perimeter, and area?

Answers

Step-by-step explanation:

1) The width of the rectangle is 10.2 in.

2) The perimeter of the rectangle is 71.4 in.

3) The area of the rectangle is 260.1 sq.in

An amusement park charges $5 as an admittance fee and $1.50 per ride. Jason has $20 to spend, but used $3 to buy a
drink and hot dog.
A. Write an inequality that represents the situation,
B. What is the maximum number of rides Jason can go on.

Answers

Answer:

a=

b=8

Step-by-step explanation:

20-5=15 (admittance fee)

15-3=12 (food and drink)

12÷1.5=8 rides because 1.50 is price for every ride

Selma's house is 1,450 cm long. How many meters
long is Selma's house?

Answers

Answer:

14.5 Meters

Step-by-step explanation:

1 centimeter= 0.01 Meters

1450 cm x 0.01 =14.5

A bag has 4 red marbles,5 blue, 3 green and 1 yellow. what is the probability of pulling a red marble.
Answer as a fraction, decimal and percent

Answers

Answer:

4/13 is the answer

total = 4+3+5+1= 13

let a be the event of getting red marbles= total is 4

probability=4/13

given,

number of red marbles = 4

number of blue marbles = 5

number of green marbles = 3

number of yellow marbles = 1

total number of marbles = 4 + 5 + 3+1 = 13

Probability of pulling a red marble is ,

P (red marble ) = number of red marbles/total number of marbles

P(red) = 4/13

Hence ,

As a fraction the probability is 4/13

As a decimal , the probability is 4/13 = 0.307

And as a percent , probability = 4/3 x 100 = 30.7

Acellus
Type SSS, SAS, ASA, SAA, or HL to
justify why the two larger triangles are
congruent?

Answers

The answer is sas
Solution:
The right angle sides of two triangles are equal to each other and the included angle on both sides is 90 degrees so the two large triangles are congruent

It's always a good idea to check your solutions to any equation in the original equation. When solving an absolute value equation, when must you check for extraneous solutions?

A. Sometimes, when u only get one solution
B. Never
C. Always
D. Sometimes, when the variable appears both inside and outside the absolute value expression

Answers

You should must check for an extraneous solution when  the variable appears both inside and outside the absolute value expression

What is an extraneous solution?

An extraneous solution is a solution that in obtained after completely solving an equation but it does not  work in the original given equation.

You should must check for an extraneous solution when  the variable appears both inside and outside the absolute value expression (Option D).

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Solve 7p+ 13 = 30 Give your answer as a fraction in its simplest form.​

Answers

Answer:  p = 2 3/7

Step-by-step explanation:

7p+13 = 30

7p = 17

p = 17/7

p = 2 3/7

A fraction is written in the form of a numerator and a denominator where the denominator is greater than the numerator.

The value of p as a fraction in its simplest form is 17/7

What is a fraction?

A fraction is written in the form of a numerator and a denominator where the denominator is greater than the numerator.

Example:

1/2, 1/3 is a fraction.

2/4 is a fraction but we can simplify further since there is a common factor of 2 with 2 and 4.

2/4 = 1/2 is a fraction.

4/16 = 4/(4x4) = 1/4 is a fraction.

We have,

7p + 13 = 30

Solve for p.

Subtract 13 on both sides.

7p + 13 - 13 = 30 -13

7p = 17

Divide both sides by 7.

p = 17/7

We can not further simplify the fraction as there are no common factors between 17 and 7.

Thus,

The value of p as a fraction in its simplest form is 17/7

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How do you solve this?​

Answers

[tex]\text{L.H.S}\\\\=\begin{vmatrix} 1 & bc& b+c\\ 1 & ca& c+a\\ 1 &ab&a+b\end{vmatrix}\\\\\\=\begin{vmatrix} 1 & bc& b+c-(a+b+c)\\ 1 & ca& c+a-(a+b+c)\\ 1 &ab&a+b-(a+b+c)\end{vmatrix}~~~~~~~~~~~~~~~;c_3\rightarrow c_3 -(a+b+c)c_1\\\\\\=\begin{vmatrix} 1 & bc& -a\\ 1 & ca& -b\\ 1 &ab&-c\end{vmatrix}\\\\\\=\dfrac 1{abc}\begin{vmatrix} a & abc& -a^2\\ b & abc& -b^2\\ c &abc&-c^2\end{vmatrix}\\\\\\=-\dfrac {abc}{abc}\begin{vmatrix} a & 1& a^2\\ b & 1& b^2\\ c &1&c^2\end{vmatrix}\\[/tex]

[tex]=-1\begin{vmatrix} a & 1& a^2\\ b & 1& b^2\\ c &1&c^2\end{vmatrix}\\\\\\=-1 \times -1 \begin{vmatrix} 1 & a& a^2\\ 1 & b& b^2\\ 1 &c&c^2\end{vmatrix}\\\\\\=\begin{vmatrix} 1 & a& a^2\\ 1 & b& b^2\\ 1 &c&c^2\end{vmatrix}\\\\\\=\text{R.H.S}\\\\\text{Showed.}[/tex]

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