Solve the system
x+2y=-11
3y=x+1

I don't see the picture. Can you send it in the message.

Answer:

(9) x = 9

(10) I cannot see the image clearly, sorry :(

(11) x = 54

(12) I cannot see the image clearly, sorry :(

(13) ∠P = 64°

(14) ∠Q = 26°

(15) ∠U = 47°

(16) ∠W = 43°

Step-by-step explanation:

(9)

To find an unknown side length in a right triangle, we need to use a trigonometric function.

⭐ What is a trigonometric function?

⭐ What are the trigonometric functions?

To determine which trigonometric function to use, we need to see which type of side lengths we are given (hypotenuse/opposite/adjacent).

We are given side length x, which is opposite of the 37 degrees, and side length 15, which is the hypotenuse of the triangle. Therefore, we will use sin(θ).

Substitute the angle measure we are given and the side lengths into sin(θ).

[tex]sin(37) = \frac{x}{15}[/tex]

[tex]15sin(37) = x[/tex]

Compute this equation into a scientific calculator. I recommend using the Desmos Scientific Calculator.

[tex]9.0 = x[/tex]

(10) I'd need to see x clearly to solve.

(11) To find an unknown side length in a right triangle, we need to use a trigonometric function.

⭐ What is a trigonometric function?

⭐ What are the trigonometric functions?

To determine which trigonometric function to use, we need to see which type of side lengths we are given (hypotenuse/opposite/adjacent).

We are given side length x, which is the hypotenuse of the triangle, and side length 14, which is adjacent to the 75 degrees. Therefore, we will use cos(θ).

Substitute the angle measure we are given and the side lengths into cos(θ).

[tex]cos(75) = \frac{14}{x}[/tex]

[tex]\frac{14}{cos(75)} = x[/tex]

Compute this equation into a scientific calculator. I recommend using the Desmos Scientific Calculator.

[tex]54 = x[/tex]

(12) I'd need to see x clearly to solve.

(13) To find the angle measure of an angle in a right angle triangle, we need to use the inverses of the trigonometric functions.

⭐ What are the inverses of the trigonometric functions?

First, we need to see the type of side lengths we are given (adjacent/hypotenuse/opposite) to determine which inverse trigonometric function we use for each angle.

∠P is adjacent to side length 8, and side length 18 is the hypotenuse of the triangle. Therefore, we will use [tex]cos^-1(adjacent/hypotenuse) =[/tex].

Substitute the side lengths and compute using a scientific calculator. I recommend using the Desmos Scientific Calculator.

[tex]cos^-1(\frac{8}{18})[/tex]

∴ ∠P = 64°

(14) To find the angle measure of an angle in a right angle triangle, we need to use the inverses of the trigonometric functions.

∠Q is opposite of side length 8, and side length 18 is the hypotenuse of the triangle. Therefore, we will use [tex]sin^-1(opposite/hypotenuse) =[/tex].

Substitute the side lengths and compute using a scientific calculator.

[tex]sin^-1(\frac{8}{18})[/tex]

∴ ∠Q = 26°

(15) To find the angle measure of an angle in a right angle triangle, we need to use the inverses of the trigonometric functions.

∠U is opposite of side length 11, and side length 15 is the hypotenuse of the triangle. Therefore, we will use [tex]sin^-1(opposite/hypotenuse) =[/tex].

Substitute the side lengths and compute using a scientific calculator.

[tex]sin^-1(\frac{11}{15})[/tex]

∴ ∠Q = 47°

(16) To find the angle measure of an angle in a right angle triangle, we need to use the inverses of the trigonometric functions.

∠W is adjacent to side length 11, and side length 15 is the hypotenuse of the triangle. Therefore, we will use [tex]cos^-1(adjacent/hypotenuse) =[/tex].

Substitute the side lengths and compute using a scientific calculator.

[tex]cos^-1(\frac{11}{15})[/tex]

∴ ∠W = 43°

Calculating acceleration involves dividing the change in velocity by the change in time.. The equation is a = (v-u)/t, where a is acceleration, v is the final velocity, u is the initial velocity, and t is the time.

Acceleration is the rate of change in velocity over time. To calculate acceleration, you need to know the initial velocity (u), the final velocity (v), and the time (t) of the motion. The formula for calculating acceleration is a = (v-u)/t. To use this formula, subtract the initial velocity from the final velocity and divide by the time. This will give you the acceleration. For example, if the initial velocity is 10 m/s, the final velocity is 20 m/s, and the time is 2s, then the acceleration is (20-10)/2 = 10 m/s2. This means that the velocity has increased by 10 m/s every second.If the initial velocity is 10 m/s, the final velocity is 20 m/s, and the time is 2s, then the acceleration is (20-10)/2 = 10 m/s2.

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Answer:

1st Q: -20

2nd Q: C,B,A

Step-by-step explanation:

Its correct

Answer:

Step-by-step explanation:

given the formula

[tex]h(t)=16t^{2}+230t[/tex]

Find the axis of symmetry

[tex]t=\frac{-b}{2a}[/tex]

Notice the function is of the form

[tex]h(t)=at^{2}+bt[/tex]

where

[tex]a=16, b=230[/tex]

To find the time at which the rocket reached its highest point, use the formula for the axis of symmetry. Substitute 16 for a and 230 for b. This gives you,

[tex]t=\frac{-(230)}{2(16)}[/tex]

simplify the arithmetic expression..

[tex]t=\frac{-230}{32}[/tex]

[tex]t[/tex]≈-7.2 seconds

I THINK the answer should be -7.2 seconds but I do not know how this would really play into the problem being that seconds should be positive, not negative... hope this helps!

Answer:B

Step-by-step explanation:

Which graph represents the solution set of the system of inequalities? {y>−2x−2y≤x+4 A system of 2 linear inequalities graphed on a coordinate plane. The horizontal x-axis ranges from negative 5 to 5 in increments of 1. The vertical y-axis ranges from negative 5 to 5 in increments of 1. A dashed line passes through begin ordered pair negative 0.5 comma negative 1 end ordered pair, begin ordered pair negative 1 comma 0 end ordered pair and begin ordered pair 0 comma negative 2 end ordered pair. A solid line passes through begin ordered pair negative 0.5 comma negative 1 end ordered pair, begin ordered pair 0 comma 1 end ordered pair and begin ordered pair negative 1 comma negative 3 end ordered pair. The region below the dashed line and above the solid line is shaded. A system of 2 linear inequalities graphed on a coordinate plane. The horizontal x-axis ranges from negative 5 to 5 in increments of 1. The vertical y-axis ranges from negative 5 to 5 in increments of 1. A da

The value of x in the given sequence is found as 225.

20/2 = 10     (0.5)

10x10 = 1      (1)

10x1.5 = 15    (1.5)

15x2 = 30     (2)

30x2.5 = 75   (2.5)

There is an increase of 0.5 in each term and then multiplies it with the previous term.

So,

{ 2.5 + 0.5 = 3 }

75x3 = 225    (3)

Thus, the value of the x in the given sequence is found as 225.

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An asymptote is a line that a curve approaches but never touches. There are two types of asymptotes: horizontal and vertical. Few examples of asymptotes are f(x) = 1/x, f(x) = 1/x² + 1 and f(x) = 1/(x-3).

Here are some examples of functions with horizontal asymptotes:

The function f(x) = 1/x has a horizontal asymptote at y = 0.

f(x) = 1/x

As x gets larger and larger, the value of the function approaches 0, but never quite reaches it. This means that the horizontal line y = 0 is an asymptote for the function f(x) = 1/x.

The function f(x) = 1/x² + 1 has a horizontal asymptote at y = 1.

f(x) = 1/x² + 1

As x gets larger and larger, the value of the function approaches 1, but never quite reaches it. This means that the horizontal line y = 1 is an asymptote for the function f(x) = 1/x² + 1.

Here is an example of a function with a vertical asymptote:

The function f(x) = 1/(x-3) has a vertical asymptote at x = 3.

f(x) = 1/(x-3)

As x gets closer and closer to 3, the value of the function approaches infinity, but never quite reaches it. This means that the vertical line x = 3 is an asymptote for the function f(x) = 1/(x-3).

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The previous water level is -9.9 feet. The correct option is B.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols.

The numerical variables and operations denoted by the addition, subtraction, multiplication, and division signs are combined in the mathematical expression. They can also denote the operation order and other properties of the logical syntax.

Given that after a heavy storm, the water level of a river is −3.7 feet. This level is 1/2 times 2.5 feet more than the previous water level.

The previous water level is calculated as,

1/2 ( x + 2.5 ) = -3.7

x + 2.5 = -7.4

x  = -7.4 - 2.5

x = -9.9

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Step-by-step explanation:

Let's solve this problem step by step. The current water level is -3.7 feet, which is 1/2 times 2.5 feet more than the previous water level. Let's call the previous water level "x".

So, we can write an equation to represent this relationship:

-3.7 = x + (1/2) * 2.5

Now, let's solve for x:

-3.7 = x + 1.25

x = -3.7 - 1.25

x = -4.95

So, the previous water level was **-4.95 feet**.

Out of the answer choices you provided, the closest value to the correct answer is **-4.9**.

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Converting 140 kilograms to pounds is: 308.56 pounds.

Here, we have,

given that,

Convert 140 kilograms to pounds.

now, we know that,

1 kilogram = 2.204 pounds

so, we get,

we would multiply 140 by 2.204

i.e.

140 × 2.204 = 308.56

which would give the answer which is 308.56 pounds.

Hence, Converting 140 kilograms to pounds is: 308.56 pounds.

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To see if the two triangles are similar, you first have to get them both in the same direction. You do this by rotating (turning) one shape to align with the other. Such a transformation is called a rotation.

Geometry transformations are movements of two-dimensional shapes in two dimensions, or within their plane. Like restricted game pieces on a game board, you can move two-dimensional shapes in only three ways:

Transform one of the triangles such that the orientation of the triangles is the same.

Identify the corresponding sides of the triangles and write each set of corresponding sides as a ratio. If the ratios of the side lengths are the same for all 3 sides, then the triangles are similar.

Hence, by performing two rigid motions, we can prove the congruence between these two triangles. Now once the triangles are superimposed, we can identify the corresponding parts by checking which side and angle of the initial triangle is superimposed on the transformed triangle.

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Answer: 270 is the answer

Step-by-step explanation:

I don't see the picture. Can you send it in the message.

The value of the given mixed fraction 997 1 / 3 is equal to 2992 / 3.

As given in the question,

Given expression is equal to,

997 1 / 3

Simplify the mixed fraction using following method in standard form :

Q R / D = [ (  D × Q ) + R ] / D

In the  numerator multiply divisor (D) to the quotient (Q) and add it to the remainder (R).

Denominator of the expression remain same.

Here  Q = 997 , R = 1 and D = 3

Substitute the value in the formula we get,

997  1 / 3

= [ ( 3 × 997 ) + 1 ] / 3

= ( 2991 + 1 ) / 3

= 2992 / 3

Therefore, the value of the given mixed fraction is equal to 2992 / 3.

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Answer: a = 70%

b 6.5 times

c  green = 16%

2.  ?????  Very poorly worded question

2. a 54%

b. 46%

c. 70%

d.  27%

Step-by-step explanation:

Students in a class were asked to tell their favorite color.

a. What percent said red, blue, or yellow? __% said red, blue, or yellow.  

red is .26

blue is .40

yellow is .04

---------------------

               .70   = 70 %

b. How many times more students said red than yellow?

red  .26

yellow is .04

.26/.04 =  6.5 times

c. What percent of students said green? __% said green.

The circle must total 100 %

Red + blue + yellow + purple + green = 100

26+     40 +     4           + 14     +  green = 100

84 + green = 100

Subtract 84 from each side

84-84 + green = 100-84

green = 16

2. Which two methods could be used to find the percent of students who said green?

We can either convert the percents to decimals or the decimals to percents

The total percents must equal 100%

The total decimal must equal 1

a. Find the sum of the percents given in the circle graph.

If they only want the ones written on the graph as percents

(14+40) = 54%

b. Find the sum of the percent forms of the numbers given in the circle graph. Subtract the result from 100%.

100 - 54% = 46%

c. Find the sum of the decimal forms of the numbers given in the circle graph. Subtract that sum from 1. Change the result to a percent.

.26+.04 = .3

1-.3 = .7

70%

d. Find the sum of half of the percents given in the circle graph. Subtract that total from 50%.

1/2 (46%) = 23%

50 -23 = 27%

Total Productive Maintenance (TPM) practices ensure D. equipment downtime is maximized

According to TPM, operators are in charge of sanitizing, enhancing, and maintaining their workstations to guarantee quality and safety throughout production cycles. The objective of TPM is to maintain equipment in top working order to ensure that production processes go without hiccups or delays.

Through the optimization of equipment availability and performance, TPM seeks to increase overall productivity and quality. The 5S methodology, a method of workforce organization that aids in streamlining and standardizing facility procedures, is the foundation on which TPM is based.

Therefore, the correct option is D.

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The probability that the mean time for the sample of 100 returns for this year is greater than 92 is 0.0764.

The term probability in math refers the possibility of occurring the event.

Here we have given that Bones brothers & associates prepare individual tax returns. Over prior years, bones brothers has maintained careful records regarding the time to prepare a return.

And we need to find the probability that the mean time for the sample of 100 returns for this year is greater than 92

As per the given question, we know the following values,

=> mean,μ=90

=> population standard deviation,σ=14

=> sample size ,n=100

Then the standard error is 1.4

Therefore, the z value is obtained by the z table is 0.9236.

Then the resulting probability is calculated.

=> 1 - 0.9236

=> 0.0764

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Answer:

As far as I know, in math, Δ means:

Examples:

ΔABC ≅ ΔDEF

Δ = [tex]\frac{1}{2}[/tex]

Answer:

Therefore for this distance combined speed is to be taken. Time taken to cover 2800 miles = 2800/(60+40) = 28 hours.

Step-by-step explanation:

We can assume that B leaves Los Angeles not at noon but at 2pm Eastern Time, so 5 hours later than A leaves New York.

In 5 hours A covers 5*40=200 miles. So, A and B together should cover 3,000-200=2,800 miles.

Combined rate = 40 + 60 = 100 miles per hour.

To cover 2,800 miles they'll need 2,800/100=28 hours.

2pm Eastern Time on Monday + 28 hours = 6pm Eastern Time on Tuesday

Answer: 15 years

Step-by-step explanation:

6000 x 1.05^x = 12000

1.05^x=2

log(1.05^x)=log(2)(Take log of both sides)

x*(log(1.05))=log(2)

x= log(2)

log(1.05)

x=14.206699

15 years

A null set is a set that contains no elements in mathematics, that is it is empty. It is also called empty set or void set.

It is denoted by the Greek letter Ф (phi). It is expressed as {}.

A null set is formed by intersection of two disjoint sets. For example, a set of odd numbers, say A = {1, 3, 5, ...} and set of even numbers say B = {0, 2, 4, ...}. A set of number of both odd and even is a null set as these sets A and B doesnt have any element in common, that is they are disjoint set.

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Answer:

its provide cretion nt exit e business to advet

There are several hypotheses regarding how 0 was created. The idea of utilising 0 as a numeric value is thought to have originated in India. According to legend, Aryabhatta invented zero by using it as a placeholder number in the fifth century.

However, the idea of zero was not always present. Although the idea of nothingness or emptiness existed, applying it numerically had a profound effect on mathematics. The principles for zero were laid forth by Brahmagupta in the seventh century.

In America, the Mayans developed the idea of zero as a placeholder in the 4th century. But though being skilled in mathematics, they never thought the idea of using it in equations.

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The value of the Discriminant is 0 so we have equal roots  = b/2a = 6/2 = 3

The given equation is a quadratic equation.

x^2+6x+9 = 0.

To tell the nature of the roots we have to understand how to find the root of a quadratic equation.

The roots of a quadratic equation are the values of the variables that fulfil the equation. In other words, if f(α) = 0, then x = α is a root of the quadratic equation f(x).

The term Discriminant is used in quadratic equations.

The discriminant of a quadratic equation is the expression [tex](b^2 - 4ac)[/tex] in the quadratic formula. A quadratic equation's discriminant shows the nature of roots.

Discriminant important thing is that it is used to find the nature of roots.

x^2+6x+9 = 0. a =1, b = 6, c=9

discriminant d = b^2 - 4*a*c = 36-4*1*9 = 36-36 = 0

So the value of the discriminant is 0 so we have equal roots  = b/2a = 6/2 = 3

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Due to the closing of a growth plates in bones, the majority of people's height would not increase after the ages of 18 to 20. The average human height is about 6 feet, but some individuals can reach heights of more than 9 feet.

Your height varies slightly throughout the day as a result of the decompression and compression of a discs in your spine.

Thus, the formula for finding the height is -

Full height = Present height/% of full height at present x 100

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A quadratic inequality of the form

y>a[tex]x^{2}[/tex]+bx+c

(or substitute <,≥ or ≤ for > ) represents a region of the plane bounded by a parabola .

A quadratic inequality of the form

y>a[tex]x^{2}[/tex]+bx+c

(or substitute <,≥ or ≤ for > ) represents a region of the plane bounded by a parabola .

To graph a quadratic inequality, start by graphing the parabola. Then fill in the region either above or below it, depending on the inequality.

If the inequality symbol is ≤ or ≥ , then the region includes the parabola, so it should be graphed with a solid line.

Otherwise, if the inequality symbol is < or > , the parabola should be drawn with a dotted line to indicate that the region does not include its boundary.

Example:

Graph the quadratic inequality.

y≤[tex]x^{2}[/tex]−x−12

The related equation is:

y=[tex]x^{2}[/tex]−x−12

First we notice that a , the coefficient of the x2 term, is equal to 1 . Since a is positive, the parabola points upward.

The right side can be factored as:

y=(x+3)(x−4)

So the parabola has x -intercepts at −3 and 4 . The vertex must lie midway between these, so the x -coordinate of the vertex is 0.5 .

Plugging in this x -value, we get:

y=(0.5+3)(0.5−4)

y=(3.5)(−3.5)

y=−12.25

So, the vertex is at (0.5,−12.25) .

We now have enough information to graph the parabola. Remember to graph it with a solid line, since the inequality is "less than or equal to".

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If truth values of p be F and q be T. Then, truth value of ∼(∼p∨q) is F.

A proposition's characteristic indicating whether it is true or false is the definition of a truth value. For instance, the truth value for "7 is odd" is true and can be represented by the letter T. "1 + 1 = 3" has a false truth value, which can be represented by the letter F. Truth is crucial. People's plans can be ruined and their lives could be in danger if they believe something that is false. Legal and societal repercussions may occur from telling lies. The excellent historian, good investigator, and good scientist, on the other hand, are committed to the search of truth.

Given

If truth values of p be F and q be T. Then, truth value of ∼(∼p∨q) is

b. F

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1. Your shooting percentage was 60%.

2. Your friend made 24 shots.

3. Hi Lowe's shooting percentage was 71%.

4. Julie Shootsalott made 17 shots.

5. Swish Malone's shooting percentage was 89%.

6. Slammin' Sammy made 19 shots.

7. Lightning Lizzy's shooting percentage was 94%.

8. The team's shooting percentage was 65%.

1. To calculate the shooting percentage,

divide the number of shots made (i.e..12) by the total number of shots taken(i.e.20)

                             12/20 = 0.6

Multiply this by 100 to get the percentage, which is 60%.

2. To calculate no. of shots,

multiply the shooting percentage (i.e.60%) by the total number of shots taken (i.e.40)

                                0.6 x 40 = 24

3. To calculate Hi Lowe's shooting percentage,

divide the number of shots made (i.e.25) by the total number of photos taken (i.e.35).

                                      25/35 = 0.714

Multiply this by 100 to get the percentage,

which is 71.4%

4. To calculate Julie Shootsalott's shots,

multiply the shooting percentage (34%) by the total number of shots taken (50).

                                              0.34 x 50 = 17

5. Swish Malone's shooting percentage was 89.3%. To calculate this, divide the number of shots made (i.e.25) by the total number of photos taken (i.e.28).

                                             25/28 = 0.893

Multiply this by 100 to get the percentage,

which is 89.3%

6. To calculate Slammin' Sammy shots,  

multiply the shooting percentage (i.e.95%) by the total number of shots taken (i.e.20)

                                                0.95 x 20 = 19

7. To calculate Lightning Lizzy's shooting percentage,

divide the number of shots made (i.e.34) by the total number of shots taken (i,e,36)

                                                   34/36 = 0.944

Multiply this by 100 to get the percentage,

which is 94.4%

8. To calculate The team's shooting percentage,

divide the number of shots made (i.e.44) by the total number of shots taken (i.e.68). 44/68 = 0.647

Multiply this by 100 to get the percentage,

which is 64.7%.

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y(t)= 3/5[tex]e^{-5.2}[/tex]-3/5esin2t-9/5sin2t when the IVP's is y'+5.2y=19.4sin2t, and y(0)=0 by Laplace transform and partial fraction.

Given that,

We have to solve the IVP's by the Laplace transform.

If necessary we have to use partial fraction expansion for y'+5.2y=19.4sin2t, and y(0)=0

We know that,

y'+5.2y=19.4sin2t, and y(0)=0

L(y(t))= y(s)

L(y'(t)) = sy(s) and

L(sin2t) = s/s²+4    ------->equation(1)

Thus if we take Laplace transform on both sides of the given equation

L(y'+5.2y)=L(19.4sin2t)

sy(s)-y(0)+5.2y(s) = 19.4L(sin2t)

y(s)[s+5.2]=19.4[s/s²+4]          (from equation(1))

y(s)= 19.4[s/(s²+4)(s+5.2)]  

Breaking left hand side into partial precautions,

y(s) = 3/5(1/s+5.2)-3/5(s/s²+4)-9/5(s/s²+4)

Taking inverse Laplace transform on both sides,

So,

y(t)= 3/5[tex]e^{-5.2}[/tex]-3/5esin2t-9/5sin2t

Therefore, y(t)= 3/5[tex]e^{-5.2}[/tex]-3/5esin2t-9/5sin2t when the IVP's is y'+5.2y=19.4sin2t, and y(0)=0 by Laplace transform and partial fraction.

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Answer:

Write all the equations in standard form cleared of decimals or fractions.Choose a variable to eliminate; then choose any two of the three equations and eliminate the chosen variable.

Step-by-step explanation: