Solve this addition question by substituting numbers for the given letters to find the value of START. Each letter represents a unique digit.

JOAN+CAN=START

Answers

Answer 1

Solved the given question by addition rules and the value of START is 10430.

Given-

The given problem is from the alphabetical puzzle. In the given problem the equation given is,

JOHN + CAN = START.

It can be written as,

   J  O  H  N

+      C  A  N

__________

S  T  A  R  T

__________

S must be 1, because, even if we assume all the missing digit are 9 ( the largest possible value), the sum will be smaller than than 10999 or equal to the 10998.

Similarly the value of T must be 0 because, even if we assume all the missing digit are 9 ( the largest possible value), the sum will be smaller than than 10999 or equal to the 10998.

Now as the T is two times in the solution of addition, and the value of T is 0 as we found. But T is the addition of N and N. Hence N must be 5 to make the addition 10 for the 0 value of the T.

                N

            +  N

            ____

              1 0

            ____

J must be 9 with carried 1 to make the T 0.

A must be more than 10 to have a carry on J. A can not 1 as S has 1 digit. 2 and 3 disturbs the equation. Thus a must be 4. and for this o and c must be 6 and 7.

If a is 4 than the H and R must be 8 and 3.

The sum will look like,

  9  6  8  5

 +   7  4  5

________

1  0  4  3  0

_________

Hence, solved the given question by addition rules and the value of START is 10430.

For more about the addition follow the link below-

https://brainly.com/question/1709448


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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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