Answer:
from someone watching the bulldozer from the cab of the truck or from elsewhere on the flatbed.
Explanation:
Explain how the graphic organizer helped you formulate your decision and participate in the discussion.
Answer:
The graphic organizers help to keep track of the details. They are a visual representation of knowledge that rescue the important aspects of a concept using labels within a scheme. They also present information in a concise manner, highlighting the organization and the relationship of the concepts. Graphic organizers help students organize their thinking process and their writing.
Explanation:
Two forces act on a block as shown in the picture. What is the net force of the block?
30 N to the right
30 N to the left
10 N to the left 10
10 N to the right
Answer:
10 N to the left.
Explanation:
Since the forces are acting in opposite directions, you need to calculate the difference.
20 N - 10 N = 10 N
More force is being exerted to the left. Therefore, the net force is 10 N to the left.
Ginny is snowboarding down a ski slope. Her total mass (including the snowboard) is 68.5 kg. When she reaches the bottom of the slope, she is moving at 6.55 m/s. The coefficient of friction between the snowboard and the ground is 0.088 . How fast will Ginny be moving 2 seconds after reaching the bottom of the slope?
1) 5.71 m/s
2)5.91 m/s
3)4.82 m/s
4)4.08 m/s
Answer:
Explanation:
Assuming the run out at the bottom of the slope is horizontal
μ = Ff/N = Ff/mg
Ff = μmg
a = Ff/m = μmg/m = μg
v = u + at
v = u + μgt
v = 6.55 - 0.088(9.81)(2)
v = 4.82 m/s
After reaching the bottom of the slope, it will take a speed of 4.8m/s to reach. So, the correct option is (C).
What is Friction?Friction is the force which opposes the relative motion of solid surfaces, fluid layers, and material elements that are sliding against each other. There are many types of friction like
Dry frictionFluid frictionLubricated friction Skin friction Internal frictionFriction can be expressed as
Ff = μFN
where, Ff is the force of friction (N)
μ is the coefficient of friction.
FN is the normal force
As per the above equation, it is actually the normal force, not the weight, which is responsible for friction.
For given information,
Assuming the bottom of the slope is horizontal
So, μ = Ff/N = Ff/mg
Ff = μmg
a = Ff/m = μmg/m = μg
v = u + at (u- initial speed, v= final speed, a= acceleration and t= time)
v = u + μgt (g= acceleration due to gravity)
u = 6.55 - 0.088(9.81)(2)
u = 4.82 m/s
Thus, after reaching the bottom of the slope, it will take a speed of 4.8m/s to reach. So, the correct option is (C).
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A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed of 1=1.31 m/s . At a lower point, the diameter of the stream has decreased by a factor of 0.805 . What is the vertical distance ℎ between these two points?
Answer:
Explanation:
as the mass cannot change, the volume per unit time is also constant so the area of the stream times the velocity is constant
If the diameter is 1 where velocity is 1.31 m/s
area is proportional to the square of the diameter A = (π/4)d²
1²(1.31) = 0.805²(v)
v = 1.31/0.805² = 2.02 m/s
v² = u² + 2as
2.02² = 1.31² + 2(9.81)h
h = 0.120819... m
h = 12.0 cm
The gradual increase in activity over time is called
Answer:Progression is the way in which an individual should increase the load. It is a gradual increase either in frequency, intensity, or time or a combination of all three components.
Explanation:
i need some help getting started on an essay for physics. i decided on the topic of roller costers and dont know how to start it. see the image on my requirements.
Explanation:
force , motion , electric current
9. If the force acting on a mass of 4kg accelerates it at a rate of 2m/s2, what will be the acceleration of the body when the force is doubled?
Explanation:
Force= mass× acceleration
Force= 4×2
= 8N
Doubling the force, 8×2= 16N
16= 4 × a
a= 16/4
= 4m/s²
1. A roller coaster with a mass of 800 kg sits stationary at the top of a section of track, 75 m above
the ground as shown. When the brake is released, it starts to roll down the track
2. For each height represented in the diagram, calculate the gravitational potential energy using
Ep = mgh. Show ONE SAMPLE calculation in the calculations section below and fill in Table 1 for
each of the heights of the roller coaster. (6 marks)
3. Assuming there is no friction, determine the mechanical kinetic energy using Ek = Etotal - Ep.
Show ONE SAMPLE calculation in the calculations section below and fill in Table 1 for each of
the heights of the roller coaster. (6 marks)
4. For each height represented in the diagram, calculate the velocity using = �2
. Show ONE
SAMPLE calculation in the calculations section below and fill in Table 1 for each of the heights of
the roller coaster. (6 marks)
5. Use your answers to graph how gravitational potential energy, mechanical kinetic energy, and
velocity change as the roller coaster changes height. Use different colours for the three lines on
the graph. Graph paper is provided below. (3 marks)
6. Repeat steps 1 – 5 above for a roller coaster cart that has a mass of 300 kg and enter your
results in Table 2.
Calculations:
800 kg roller coaster cart:
Sample calculation for gravitational potential energy:
Sample calculation for Mechanical kinetic energy:
Sample calculation for velocity:
300 kg roller coaster cart:
Sample calculation for gravitational potential energy:
Sample calculation for mechanical kinetic energy:
Sample calculation for velocity:
Results:
Table 1: Potential energy, kinetic energy, total energy, and velocity of the 800 kg roller coaster cart
Table 2: Potential energy, kinetic energy, total energy, velocity of the 300 kg roller coaster cart.
Graphs:
It’s graphing time. These graphs are a bit different than the ones you did in the
data analysis assignment at the beginning of the course. In this case you have
three things to graph on each graph. (One graph for the 800 kg roller coaster cart
and one graph for the 300 kg roller coaster cart.) You need to graph the
gravitational potential energy with respect to height, the mechanical kinetic
energy vs height, and the velocity vs height.
Let’s look at the energy graphs first. In this case both kinetic energy and
mechanical energy cover the same range of values. This means they can use the
same scale on the y-axis. So, you will use the left y-axis and the x-axis to graph
the kinetic energy vs height and the potential energy vs height. You will need a
legend to explain which line is which. Colour coding is a nice way to highlight this.
The velocity values are much different than the energy values. This means you
need a totally different scale. So, your left y-axis won’t work. You need to make a
second scale on the right y-axis for your velocity values. You will plot the points
the same way as normal, but you will use the numbers on the right-hand scale
instead. Again, be sure to add your velocity line to the legend with a separate
colour code.
Discussion Questions:
1. Describe the relationship between the gravitational potential energy and the mechanical kinetic
energy of the roller coaster on your graph. (2 marks)
2. Describe the shapes of each of the three lines in the graph. Explain why the velocity is different.
(4 marks)
3. Describe how mass affects the speed at the bottom of the roller coaster. (2 marks)
4. Describe how mass affects the gravitational potential energy and the mechanical kinetic energy
of the roller coaster. (2 marks)
5. At what point does the roller coaster have a maximum value for the following? Justify your
answer by explaining why. (2 marks each)
a. Gravitational potential energy
b. Mechanical energy
c. Velocity
6. In your calculations, you assumed that the roller coaster was frictionless. All real roller coasters
encounter friction. Describe how the actual values of the variables would differ, or not differ,
from your calculated values for a real roller coaster. (Hint: what form of energy would some of
the total energy be converted to if there was friction in the system?) (4 marks)
How you will be graded:
Grades will be based on answering questions to demonstrate an understanding of the material covered
in this unit. Point form answers are okay if ideas are complete and use vocabulary (Word Bank)
provided. For questions out of 4 marks, there are 4 responses expected.
Answer:
Give me some hint please
Based on the calculations, potential energy of this roller coaster at a height of 75 meters is equal to 588,000 Joules.
How to calculate potential energy?Mathematically, potential energy is calculated by using this formula:
P.E = mgh
Where:
P.E represents potential energy.m is the mass.h is the height.g is acceleration due to gravity.Note: Acceleration due to gravity is equal to 9.8 m/s².
At a height of 75 m, we have:
P.E = 800 × 9.8 × 75
P.E = 588,000 Joules.
At a height of 60 m, we have:
P.E = 800 × 9.8 × 60
P.E = 470,400 Joules.
At a height of 45 m, we have:
P.E = 800 × 9.8 × 45
P.E = 352,800 Joules.
At a height of 30 m, we have:
P.E = 800 × 9.8 × 30
P.E = 235,200 Joules.
At a height of 15 m, we have:
P.E = 800 × 9.8 × 15
P.E = 117,600 Joules.
In conclusion, we can deduce that the potential energy of this roller coaster decreases with a decrease in height.
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The magnetic field B at all points within the colored circle of the figure (Figure 1) has an initial magnitude of 0.780 T. (The circle could represent approximately the space inside a long, thin solenoid.) The magnetic field is directed into the plane of the diagram and is decreasing at the rate of 0.0300 T/s.
a) What is the magnitude of the induced electric field at any point on the circular conducting ring with radius r = 0.100 m ?
b) What is the direction of this field at any point on the circular conducting ring?
c) What is the current in the ring if its resistance is 4.00 Ω ?
d) What is the emf between points a and b on the ring?
e) If the ring is cut at some point and the ends are separated slightly, what will be the emf between the ends?
The magnitude of the induced electrical field is 0.0015V/m, the field is pointing towards the clockwise direction while the current in the ring will be 0.0002355A if the resistance is 4 ohms. The emf between point a and b is zero and the EMF across the point if they're slightly separated between the ends is 0.000942V
To solve this question, we would have to go about each one individually
Data:
[tex]r=10cm=0.1m\\[/tex]
a.
The magnitude of the induced electrical field at any point within the radius is
[tex]\int\limits^a_b {E} \, du=\frac{dU}{dt}=\pi \frac{dB}{dt}=\pi r^{2}\frac{dB}{dt}\\E*2\pi r=\pi r^{2}\frac{dB}{dt} \\E=\frac{r}{2}\frac{dB}{dt}=\frac{0.1}{2}*0.03=0.0015V/m[/tex]
b.
The field is pointing towards the clockwise direction.
c.
The current in the ring if we are given a resistance of 4ohms
[tex]I=\frac{emf}{R}=\frac{\pi r^{2}\frac{dB}{dt} }{R} =\frac{\pi (0.1)^2*0.03}{4} =0.0002355A[/tex]
d.
The emf between point a and b is zero
e.
The EMF across two points if they're separated by small distance across the ring is
we would use the formula to solve for the EMF
[tex]E=\pi r^{2}\frac{dB}{dt}=\pi (0.1)^2*0.03=0.000942V[/tex]
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Which variable mentioned in Table 2-1 is kept constant? a. amount of time spent swimming b. type of swimming stroke c. number of calories used d. the person swimming
Answer:
a. amount of time spent swimming
You hang a light in front of your house using an
elaborate system to keep the 12-kg object in static
equilibrium (Figure 1). What are the magnitudes of the
forces that the ropes must exert on the knot connecting
the three ropes if 02 = 639 and 03 = 45° ?
The magnitudes of the forces that the ropes must exert on the knot connecting are :
F₁ = 118 N F₂ = 89.21 N F₃ = 57.28 NGiven data :
Mass ( M ) = 12 kg
∅₂ = 63°
∅₃ = 45°
Determine the magnitudes of the forces exerted by the ropes on the connecting knota) Force exerted by the first rope = weight of rope
∴ F₁ = mg
= 12 * 9.81 ≈ 118 kg
b) Force exerted by the second rope
applying equilibrium condition of force in the vertical direction
F₂ sin∅₂ + F₃ sin∅₃ - mg = 0 ---- ( 1 )
where: F₃ = ( F₂ cos∅₂ / cos∅₃ ) --- ( 2 ) applying equilibrium condition of force in the horizontal direction
Back to equation ( 1 )
F₂ = [ ( mg / cos∅₂ ) / tan∅₂ + tan∅₃ ]
= [ ( 118 / cos 63° ) / ( tan 63° + tan 45° ) ]
= 89.21 N
C ) Force exerted by the third rope
Applying equation ( 2 )
F₃ = ( F₂ cos∅₂ / cos∅₃ )
= ( 89.21 * cos 63 / cos 45 )
= 57.28 N
Hence we can conclude that The magnitudes of the forces that the ropes must exert on the knot connecting are :
F₁ = 118 N, F₂ = 89.21 N, F₃ = 57.28 N
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consider a throw ball to the air ,whre lagragian is given by ,L( m /2+Y^ '2 +Z^' 2 ]- msz, find the two concider momuntum when it is invariant under translation at x&x+E and y&yE(both x and y are cyclic cordinate)
Explanation:
ANDSHESAIDSHESAIDSHESAID☹️ SHE'S FROMHAWAIIYOUKNOWHOWTOSPEAKCUTEIN JAPANESE KAWAII
did the deadliest hurricanes happen recently or in the distant past
Answer:
Galveston hurricane of 1900
Explanation:
also called Great Galveston hurricane, hurricane (tropical cyclone) of September 1900, one of the deadliest natural disasters in U.S. history, claiming more than 8,000 lives.
Determine the rTo understand the concept of nodes of a standing wave.
The nodes of a standing wave are points where the displacement of the wave is zero at all times. Nodes are important for matching boundary conditions, for example that the point at which a string is tied to a support has zero displacement at all times (i.e., the point of attachment does not move).
Consider a standing wave, where y represents the transverse displacement of a string that extends along the x direction. Here is a common mathematical form for such a wave:
y(x,t)=Acos(kx)sin(ωt),
where A is the maximum transverse displacement of the string (the amplitude of the wave), which is assumed to be nonzero, k is the wavenumber, ω is the angular frequency of the wave, and t is time.
Part A
Which one of the following statements about wave y(x,t) is correct?
adius of the 236U nucleus.
Answer:
The nodes of a standing wave are points where the displacement of the wave is zero at all times nodes are important for matching boundary conditions for example that the point at which a string is tied to a support has zero displacement at all times ie the point of attachment does not move consider a standing
How do you find the capacitance in this?
Answer:
Explanation:
parallel capacitances add directly
Series capacitances add by reciprocal of sum of reciprocals.
Ceq = [ C ] + [1 / (1/C + 1/C)] + [1 / (1/C + 1/C + 1/C)]
Ceq = [ C ] + [C / 2] + [C / 3]
Ceq = [ 6C/6 ] + [3C / 6] + [2C / 6]
Ceq = 11C/6
What is the significance of Isaac's name?
[tex] \large \bf{Answer:-}[/tex]
The name Isaac means “one who laughs” or “one who rejoices.” In the Old Testament of the Bible, Isaac is the firstborn son of Abraham. He is one of the three biblical patriarchs revered by Jews, Christians, and Muslims.
What are the symmetry operations of molecule AB4, where the molecule b lies at the center of the square and A lies at the center of the square and is not coplaner with B atoms. How to find the multiplication table
The symmetry operations of molecule AB₄ is tetrahedral and they are :
E : Identity4C₃ : axis of rotation 3C₂ : axis of rotation3S₄ : Rotation-reflection axis 6бdTo find the multiplication table we have to apply the multiplication table for Td symmetry ( attached below )
Given that molecule B lies at the corners of the square and molecule A lie at the center and is not coplanar with molecule B the symmetry operations of the molecules AB₄ will belong to a tetrahedral symmetry group which contains :
E : Identity4C₃ : axis of rotation 3C₂ : axis of rotation3S₄ : Rotation-reflection axis 6бdLearn more about tetrahedral symmetry group : https://brainly.com/question/1968705
During a car accident on the NJ Turnpike, the airbags deploy. A 79 kg passenger traveling at 32 m/s makes impact with the airbag over a time of 0.25 seconds. What
was the impact force experienced by the passenger?
Hi there!
Recall that:
Impulse = Δ in momentum = mΔv
Impulse = Force · time
Begin by calculating the change in momentum, or impulse.
I = mΔv = m(vf - vi)
I = (79)(0 - 32) = -2528 Ns
Now, we can use the equation relating force and time to impulse.
I = Ft
Rearrange for time:
I/F = t
-2528/0.25 = -10112 N
**OR, if magnitude ⇒ |-10112| = 10112 N
how is the atomic mass determined?
Answer:
Atomic mass is defined as the number of protons and neutrons in an atom, where each proton and neutron has a mass of approximately 1 amu (1.0073 and 1.0087, respectively). The electrons within an atom are so miniscule compared to protons and neutrons that their mass is negligible.
Explanation:
How do we become children of Abraham and sons of God?
Answer:
we already are.
Explanation:
God created us, and we are the descendants of Abraham. if you want to choose to live against it, you'll be doing something similar to fighting a current. gods love is unfathomable. he is the only true God, and is our father in heaven.
A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when the back pressure is sea-level standard. If the upstream tank temperature is 400 K, estimate (a) the tank pressure and (b) the mass fl ow
The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.
The given parameters:
Throat area of the nozzle, [tex]A^*[/tex] = 10 cm² = 0.001 m²The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²Air pressure at sea level = 101.325 kPaThe ratio of the areas of the converging-diverging nozzle is calculated as follows;
[tex]= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896[/tex]
From supersonic isentropic table, at [tex]\frac{A}{A^*} = 2.896[/tex], we can determine the following;
[tex]M_e = 2.6 \ kg/s\\\\\frac{P_o}{P_e} = 19.954[/tex]
The tank pressure is calculated as follows;
[tex]\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa[/tex]
Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.
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A block of mass m=10 kg at rest slides down a rough incline plane of θ=30° and length l=5 m. The coefficient of kinetic friction between the block and the incline is μ_k=0.1. At the bottom of the plane the block continues to slide on a frictionless surface and hits a spring with spring constant k=100 N/m.
The speed of the block at point B = 6.36 m/s
Given data :
Mass ( m ) = 10 kg
Angle of inclination ( θ ) = 30°
Length of incline = 5 m
Determine the speed of the block at a point B on the incline
First step : Calculate the work done by frictional force
given that there is no friction on the horizontal plane. Vinclined = Vhorizontal
∴ Work done by frictional force ( Wf ) = F * L cos 180
= - ( μ_k * N ) L
= - (0.1 * 84.86 ) * 5 = - 42.4 Joule
where N = mg cos 30°
= 10 * 9.8 * 0.866 = 84.86
Next step : Calculate the speed of the block at point B
applying work energy theorem
Wf = ΔK.E + ΔP.E
= ( 1/2 mv² - 0 ) + ( 0 - mgh )
∴ - 42.48 = 1/2 mv² - mgh
1/2 mv² = mgh - 42.48
= 10 * 9.8 * 5 sin 30° - 42.4
v² = 40.52
V ( speed of the block at point B ) = 6.36 m/s
Hence we can conclude that the speed of the block at point B = 6.36 m/s
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Attached below is the complete question related to your question
If you have a final velocity of 50 m/s and travelled for 120 seconds. What
is your acceleration?
Answer:
a=v-u/t
Explanation:
use this formula and initial velocity is 0
Answer:
Acceleration (a) is 0.416666667 m/ s^2
Explanation:
Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation
a = Δv/Δt.
hey if you talk to me i will mark you as a brainliest and if you answer all my question
huh huh huh
Answer:
what will happen if i will answer ur questions?
Explanation:
is there gonna be a bad thing or a good thing
PLEASE ANSWER THIS QUICK
GIVING BRAINLIEST TO THE ONE WHO ANSWERS
Rust is a compound that occurs when the element iron and oxygen combine. Do they create a physical or a chemical change?
Answer:
I think it's a chemical change.
4. Trilobites are animals that lived during the Paleozoic era. They populated all parts of the
ocean showed consistent evolution over time and left behind fossils that are large
enough to be studied without a microscope. All of these characteristics make trilobites
the ideal
a. Trace fossil
b. Keystone species
c. Index fossil
d. Reference point
dnreserve the remains of dead
Answer:
c. index fossil
Explanation:
Trilobite fossils are found worldwide, with many thousands of known species. Because they evolved rapidly, and molted like other arthropods, trilobites serve as excellent index fossils. (Arthropods periodically shed their old exoskeletons, or molt.) An index fossil is one that is useful for dating and correlating the strata in which it is found.
a rocket ship is moving through space at 1000 m/s. It accelerates in the same direction at 4m/s/s. What is its speed after 100 seconds
Answer:
Acceleration = (final velocity - starting velocity) / time
4 = (x-1000) / 100
<br/>x = 1400 m/s
Explanation:
The final velocity of the rocket ship which is moving with an initial velocity of 1000 m/s and acceleration of 4 m/s² after 100 seconds is 1400 m/s.
What is velocity?Velocity of a moving body is the rate of its speed. Mathematically velocity is the ratio of distance travelled to the time taken with a unit of m/s. Acceleration is the rate of change in velocity of moving body. The unit of acceleration is 4 m/s² .
Thus acceleration can be determined from the change in velocity with respect to the change in time. Now, the relation between initial velocity, acceleration, a and time, t with the final velocity is written in the equation below:
v = u + at.
Where, v is the final velocity and u be the initial velocity.
Given here the initial velocity is 1000 m/s. Acceleration of the rocket is 4 m/s² . Thus the velocity after 100 seconds is calculated as follows:
v = 1000 m/s + ( 4 m/s² × 100 s )
= 1400 m/s.
Hence, the speed of the rocket after 100 seconds will be 1400 m/s.
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What is the unit of pressure
is it P=F/A?
Answer:
Units of pressure include: Pa, bar, at, atm, torr, lbf/in^2
Explanation:
P = F/A is a formula for pressure not a unit.
Pa = Pascal
Bar = Bar
at = Technical Atmosphere
Torr = Torr
lbf/in^2 = pounds per square inch
Sophie applies a 50 n force to push a box 2 meter across the floor calculate the smount of work done in the box
Ram jumps onto a cement floor from a height of 1m and comes to rest in 0.1sec.
Then he jumps onto a sand floor from a height of 9m and comes to rest in 1sec.
Find the ratio of forces of cement floor and sand floor.
Answer:
3/10 F.
Explanation:
Height ( h ) = 1m
Time taken ( t ) = 0.1 second
Height² ( h² ) = 9m
Time taken² ( t² ) = 1 second
Solution,
F = ma
= m ( v - u ) / t
= m √2gh / t
now,
F/F² = √h/h² × t/t²
F¹ = 3/10 F.
answer !!