Answer:
The fish gobbles the mosquito at height 18 cm.
Explanation:
Initial velocity, u = 3.7 m/s
horizontal distance, d = 28 cm
Angle, A = 39 degree
Let the time is t.
Horizontal distance = horizontal velocity x time
d = u cos A x t
0.28 = 3.7 cos 39 x t
t = 0.097 s
Let the height is h.
Use the second equation of motion
[tex]h =u t-0.5 gt^2\\\\h= u sin A t - 0.5 gt^2\\\\h= 3.7 sin 39 \times 0.097 - 0.5\times 9.8\times 0.097\times0.097\\\\h =0.226 -0.046 \\\\h=0.18 m=18 cm[/tex]
The steps to determine the sum are shown. (6.74x104)+(8.95 x 104) Step 1. Rearrange the expression: (6.74+8.95) 104 Step 2. Add the coefficients: (15.69) 104 Step 3. Write in scientific notation: 1.569x 10 What is the value of k in Step 3? =
Answer:
We want to solve the sum:
6.74*10⁴ + 8.95*10⁴
first, we take the common factor 10⁴ out, so we get:
(6.74 + 8.95)*10⁴
Now we solve the sum:
(15.66)*10⁴
Now we want to rewrite it in exponential form, wo we can rewrite it as:
(15.66)*10⁴ = (1.566*10)*10⁴ = (1.566)*10*10⁴ = (1.566)*10⁴⁺¹ = 1.566*10⁵
k = 5.
The charge that passes a cross-sectional area A=10-4 m2 varies with time according
to the relation
Q=4 + 2t + t2, where Q is in coulombs and t is in seconds. (a) Find the relation
that gives the instantaneous current at time t =2 s is
Answer:
Current = dQ/dt
or I = dQ/dt
Where I represents current.
Which is the rate of flow of charge.
Q=4 + 2t + t²
dQ/dt = 2 + 2t --- This is the relation that gives the instantaneous current.
At time t=2sec
dQ/dt = I = 2 + 2t
= 2 + 2(2)
=2 + 4
= 6A.
Some radar systems detect the size and shape of objects such as aircraft and geological terrain. What is the frequency of such a system which can detect objects as small as 19.1 cm?
Answer:
[tex]f=1.57\times 10^9\ Hz[/tex]
Explanation:
Given that,
A system can detect objects as small as 19.1 cm i.e. 0.191 m. It is the wavelength.
We know that,
Frequency, [tex]f=\dfrac{c}{\lambda}[/tex]
So,
[tex]f=\dfrac{3\times 10^8}{0.191}\\\\=1.57\times 10^9\ Hz[/tex]
So, the frequency of such a system is equal to[tex]1.57\times 10^9\ Hz[/tex].
Why can’t we see the molecules moving in a solid or liquid?
Answer:
Because molecules are to small for us people to see with the bare eye, unless you use a telescope.
Explanation:
Explanation:
Because in solid form, the molecules stood in place, not moving. In liquid state, the molecules move slowly but not as fast as air molecules.
A spring with a 10-kg mass and a damping constant 15 can be held stretched 2 meters beyond its natural length by a force of 6 newtons. Suppose the spring is stretched 4 meters beyond its natural length and then released with zero velocity. Suppose the spring is stretched 4 meters beyond its natural length and then released with zero velocity.
Required:
Find the position of the mass at any time t.
Answer:
Explanation:
Given that:
mass = 10kg
damping constant C = 15 kg/s
length = 2 m
Force F = 6N
Using the Hooke's law:
F = kx
6 = 15x
k = 6 N /2 m
spring constant k = 3 N/m
For the critical damping
C² - 4k*m= 0
m = C²/4k
m = (15)²/4(3) kg
m = 225/12 kg
m = 18.75 kg
To calculate the final enthalpy of the overall chemical equation, which step must occur?
Answer:
Explanation:
Reverse the second equation, and change the sign of the enthalpy
The peak value of the electric field component of an electromagnetic wave is E. At a particular instant, the intensity of the wave is of 0.020 W/m2. If the electric field were increased to 5E, what would be the intensity of the wave?
Answer:
[tex]I_2=0.50 w/m^2[/tex]
Explanation:
From the question we are told that:
initial Intensity [tex]I_1=0.020 w/m^2[/tex]
Final Electric field [tex]E_2=5E[/tex]
Generally the equation for Relation ship between intensity and Electric field is mathematically given by
[tex]\frac{I_1}{I_2}= \frac{E_1^2}{E_2^2}[/tex]
Therefore
[tex]I_2=\frac{I_1}{ \frac{E_1^2}{E_2^2}}[/tex]
[tex]I_2=\frac{0.020}{ \frac{E^2}{5E^2}}[/tex]
[tex]I_2=0.50 w/m^2[/tex]
The rotating loop in an AC generator is a square 18 cm on each side. It is rotated at 60.0 Hz in a uniform magnetic field of 0.3T. Calculate the approximate value of the maximum amplitude of the power delivered to the loop for a loop resistance of 12 ohm ?
Answer:
The maximum amplitude power is 1.12 W
Explanation:
Given;
length of each side of the square, L = 18 cm = 0.18 m
angular frequency, f = 60 Hz
magnetic field, B = 0.3 T
resistance of the loop, R = 12 ohm
The area of the loop, A = L² = 0.18 m x 0.18 m = 0.0324 m²
The angular speed, ω = 2πf = 2π x 60 = rad/s = 377.04 rad/s
The maximum value of emf induced;
[tex]E_{max} = NBA \omega\\\\where; \\N \ is \ number \ of \ turns\\\\E_{max} = (1) \times 0.3 \times 0.0324 \times 377.04\\\\E_{max} = 3.665 \ V[/tex]
The maximum amplitude power is calculated as;
[tex]Power = \frac{(E_{max})^2 }{R} \\\\Power = \frac{(3.665)^2}{12} \\\\Power = 1.12 \ W[/tex]
Hunter is studying a new form of plastic chip that can be added onto a credit card, linking it to a bank account
separate from the main card. This chip works by passing an electric current through a sensing coil. What application
of solid-state physics is Hunter most likely working with?
O electromagnetism
O metallurgy
O quantum mechanics
O crystallography
Answer:
electromagnetism....
A certain light truck can go around a flat curve having a radius of 150m with a max speed if 26.5. What is the max speed it can go around a curve having a radius of 76.0m
Answer:
The maximum speed is 18.86 m/s.
Explanation:
initial radius, r = 150 m
maximum speed, v = 26.5 m/s
new radius, r' = 76 m
Let the new maximum speed is v'.
The formula of the maximum speed is
[tex]tan\theta = \frac{v^2}{rg}[/tex]
So,
[tex]\frac{v'^2}{v^2}=\frac{r'}{r}\\\\\frac{v'^2}{26.5\times 26.5}=\frac{76}{150}\\\\v=18.86 m/s[/tex]
Which of the following items is an example of a symbol Bernice bobs her hair
what? Is there a picture you can show us with this question
Two identical loudspeakers 2.30 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standing 5.00 m in front of one of the speakers, perpendicular to the line joining the speakers, and hears a maximum in the intensity of the sound. Part A What is the lowest possible frequency of sound for which this is possible
Answer:
By the Pythagorean Theorem the distances from the speakers os
5 and 5.5 (rounding) meters - let y be the wavelength in the solution
n y = 5 n is number of wavelengths from speaker
(n + m) y = 5.5 m must be integral for constructive interference
m y = .5 subtracting equations
m = 2 and y = ,25 for the above conditions
(n + 2) y = 5.5 substituting for m
n = 5.5 / .25 - 2 = 20
f = v / y using frequency of sound
f = 340 / .25 = 1360 / sec for lowest frequency
Check: D1 = y n = ,25 * 20 = 5
and D2 = .25 * 22 = 5.5 for the distances traveled
When a condenser discharges electricity, the instantaneous rate of change of the voltage is proportional to the voltage in the condenser. Suppose you have a discharging condenser and the instantaneous rate of change of the voltage is -0.01 of the voltage (in volts per second). How many seconds does it take for the voltage to decrease by 90 %?
Answer:
460.52 s
Explanation:
Since the instantaneous rate of change of the voltage is proportional to the voltage in the condenser, we have that
dV/dt ∝ V
dV/dt = kV
separating the variables, we have
dV/V = kdt
integrating both sides, we have
∫dV/V = ∫kdt
㏑(V/V₀) = kt
V/V₀ = [tex]e^{kt}[/tex]
Since the instantaneous rate of change of the voltage is -0.01 of the voltage dV/dt = -0.01V
Since dV/dt = kV
-0.01V = kV
k = -0.01
So, V/V₀ = [tex]e^{-0.01t}[/tex]
V = V₀[tex]e^{-0.01t}[/tex]
Given that the voltage decreases by 90 %, we have that the remaining voltage (100 % - 90%)V₀ = 10%V₀ = 0.1V₀
So, V = 0.1V₀
Thus
V = V₀[tex]e^{-0.01t}[/tex]
0.1V₀ = V₀[tex]e^{-0.01t}[/tex]
0.1V₀/V₀ = [tex]e^{-0.01t}[/tex]
0.1 = [tex]e^{-0.01t}[/tex]
to find the time, t it takes the voltage to decrease by 90%, we taking natural logarithm of both sides, we have
㏑(0.01) = -0.01t
So, t = ㏑(0.01)/-0.01
t = -4.6052/-0.01
t = 460.52 s
At a rock concert, the sound intensity 1.0m in front of the bank of loudspeakers is 0.10 W/m^2. A fan is 30.0m from the loudspeakers. Her eardrums have a diameter of 8.4mm.How much energy is transferred to each eardrum in one second?
Answer: The amount of energy transferred to each eardrum in one second is [tex]6.2 \times 10^{-9} J[/tex].
Explanation:
Given: Intensity = 0.10 [tex]W/m^{2}[/tex]
Now, at 30.0 m the intensity will be calculated as follows.
[tex]Intensity = \frac{(30.0 m)^{2}}{(1 m)^{2}}\\= 900[/tex]
This means that the intensity is 900 times less assuming that the wave is spherical.
Hence, the new intensity is calculated as follows.
[tex]\frac{0.10 W/m^{2}}{900}\\= 1.11 \times 10^{-4} W/m^{2}[/tex]
The area of ear drum is expressed as follows.
[tex]Area = \pi \times r^{2}\\= 3.14 \times (4.2 mm)^{2}\\= 5.54 \times 10^{-5} m^{2}\\[/tex]
Formula used to calculate energy is as follows.
[tex]P = I \times a[/tex]
where,
P = power or energy
I = intensity
a = area
Substitute the values into above formula as follows.
[tex]P = I \times a\\= 1.11 \times 10^{-4} W/m^{2} \times 5.54 \times 10^{-5} m^{2}\\= 6.2 \times 10^{-9} W[/tex]
Thus, we can conclude that amount of energy transferred to each eardrum in one second is [tex]6.2 \times 10^{-9} J[/tex].
The bus travelled at velocity 15 ms-l for 5 minutes before it came to a stop. By using suitable linear equation, calculate the distance the bus has travelled.
Answer:
ans: 2250 meters
Explanation:
initial velocity (U)= 15 m/s
final velocity (V) = 0m/s , since need to come in rest
total time taken (T) = 5 min= 300 seconds
total distance covered (S)= UT + 1/2 aT^2 ,
a= acceleration
S= 15 × 300 + 0.5 ×(0 - 15) × 300
since a = (V - U)/ T
S = 4500 - 2250
S= 2250 m
Friction is a (1)______
that (2)______
motion. It acts in a direction (3)______
to the motion of
the object. There is (4)______
exerted on an object that
moves on a (5)_____
than on a (6)_____
Friction opposes the motion of an object as it moves across a
surface. An object slows down (7)______
on a rough
surface than on a smooth surface.
Answer:
friction is motion heat that collect hot vibration
Three identical boxcars are coupled together and are moving at a constant speed of 28.0 m/sm/s on a level, frictionless track. They collide with another identical boxcar that is initially at rest and couple to it, so that the four cars roll on as a unit. Friction is small enough to be neglected.
Required:
a. What is the speed of the four cars?
b. What percentage of the kinetic energy of the boxcars is dissipated in the collision?
c. What happened to this energy?
Answer:
A) v = 21 m /s
B) 25%
C) ) on collision, this energy in the question appears in the form of the following namely; sound energy, heat energy etc
Explanation:
A) Let m be the mass of any of the cars
Thus:
mass of the three cars = 3m
Formula for kinetic energy = ½mv²
Thus, Kinetic energy of 3 identical and coupled cars = ½ x 3m x 28² = 1176 m
KE = 1176 m
Now mass of 4 coupled cars together = 4m
From conservation of linear momentum, we can find the speed of the four cars. Thus;
m1v1 = m2v2
We are told that the 3 coupled moved together with a speed of 28 m/s
Thus;
4m × v = 3m × 28
v = 3m x 28 / 4m
v = 21 m /s
B) from earlier, we saw the formula for kinetic energy. Thus, kinetic energy with of mass of 4 coupled cars together. Thus;
K = ½ x 4m x 21²
K = 882m
Loss of kinetic energy
ΔK = 1176 m - 882 m
ΔK = 294 m
Therefore, percentage of loss is;
%loss = (294 / 1176 ) x 100
%loss = 25 %
C) on collision, this energy in the question appears in the form of the following namely; sound energy, heat energy etc
You throw a football straight up. Air resistance can be neglected. When the football is 4.00 mm above where it left your hand, it is moving upward at 0.500 m/sm/s. What was the speed of the football when it left your hand
Answer:
u=8.868 m/s
Explanation:
The displacement of the ball is 4 meters
The final speed of the ball is 0.5 m/s
The initial speed of the ball is to be calculated. Using the equation of the rectilinear motion,
[tex]v^{2} =u^{2} +2as[/tex]
Plugging the values in the above expression,
[tex]\\0.5^{2} =u^{2} +2*(-9.8)*4\\\\u^{2} =78.4+0.25\\\\u^{2} =78.65\\\\u=8.868 m/s[/tex]
what
is the half for physics
one
2
some one help me I need i
Answer:
This Displacement Calculator finds the distance traveled or displacement (s) of an object using its initial velocity (u), acceleration (a), and time (t) traveled. The equation used is s = ut + ½at2; it is manipulated below to show how to solve for each individual vvariation
__5. The study of weather patterns can predict the trajectory and intensity of this
event via satellite imagery.
A. Hurricanes
B. Tornadoes
C. Floods
D. Forest fires
Answer:
its hurricane
Explanation:
beacuse almost all the time hurricanes cause alot of trajectory in the compasses and weather maps
The study of weather patterns can predict the trajectory and intensity of hurricanes. So, option A.
What is meant by weather ?The state of the atmosphere, which includes factors such as temperature, air pressure, wind, humidity, precipitation, and cloud cover, is referred to as the weather.
Here,
Weather condition is the local climate over a specific time period, which might range from one to several weeks. Meteorological conditions are those that are characteristic for a certain place or seasons.
The study of weather and atmospheric patterns across time is known as climatology. This branch of science is devoted to observing, examining, and comprehending global weather patterns, as well as the atmospheric circumstances that lead to them.
The atmosphere's current condition can be determined by combining data from weather stations, satellites, and even data collected by aircraft.
Following that, meteorologists use what they know about atmospheric processes to predict how the atmosphere will change, so altering the weather.
Hence,
The study of weather patterns can predict the trajectory and intensity of hurricanes. So, option A.
To learn more about weather, click:
https://brainly.com/question/3789422
#SPJ3
sanaysay tungkol sa pangangalaga ng mga endangered animals
An LC circuit is built with a 20 mH inductor and an 8.0 PF capacitor. The capacitor voltage has its maximum value of 25 V at t = 0 s.(a)How much time does it take until the capacitor is fully discharged for the first time? (b)What is the inductor current at that time?
Answer:
a) the required time is 0.6283 μs
b) the inductor current is 0.5 mA
Explanation:
Given the data in the question;
The capacitor voltage has its maximum value of 25 V at t = 0
i.e V[tex]_m[/tex] = V₀ = 25 V
we determine the angular velocity;
ω = 1 / √( LC )
ω = 1 / √( ( 20 × 10⁻³ H ) × ( 8.0 × 10⁻¹² F) )
ω = 1 / √( 1.6 × 10⁻¹³ )
ω = 1 / 0.0000004
ω = 2.5 × 10⁶ s⁻¹
a) How much time does it take until the capacitor is fully discharged for the first time?
V[tex]_m[/tex] = V₀sin( ωt )
we substitute
25V = 25V × sin( 2.5 × 10⁶ s⁻¹ × t )
25V = 25V × sin( 2.5 × 10⁶ s⁻¹ × t )
divide both sides by 25 V
sin( 2.5 × 10⁶ × t ) = 1
( 2.5 × 10⁶ × t ) = π/2
t = 1.570796 / (2.5 × 10⁶)
t = 0.6283 × 10⁻⁶ s
t = 0.6283 μs
Therefore, the required time is 0.6283 μs
b) What is the inductor current at that time?
[tex]I[/tex](t) = V₀√(C/L) sin(ωt)
{ sin(ωt) = 1 )
[tex]I[/tex](t) = V₀√(C/L)
we substitute
[tex]I[/tex](t) = 25V × √( ( 8.0 × 10⁻¹² F ) / ( 20 × 10⁻³ H ) )
[tex]I[/tex](t) = 25 × 0.00002
[tex]I[/tex](t) = 0.0005 A
[tex]I[/tex](t) = 0.5 mA
Therefore, the inductor current is 0.5 mA
The time taken for the capacitor to fully discharge is 6.28 x 10⁻⁷ s.
The current in the inductor at the given time is 0.0005 A.
Angular velocity of circuitThe angular velocity of the circuit is calculated as follows;
[tex]\omega = \frac{1}{\sqrt{LC} } \\\\\omega = \frac{1}{\sqrt{20 \times 10^{-3} \times 8 \times 10^{-12} } } \\\\\omega = 2.5 \times 10^6 \ rad/s[/tex]
Time for the capacitor to fully dischargeV = V₀(sinωt)
sinωt = V/V₀
sinωt = = 25/25
sin(ωt) = 1
ωt = sin⁻¹ (1)
ωt = π/2
2.5 x 10⁶ t = π/2
t = 1.57 / (2.5 × 10⁶)
t = 6.28 x 10⁻⁷ s
Inductor current at the given timeThe current in the inductor at the given time is calculated as follows
[tex]I(t) = V_0 \sqrt{\frac{C}{L} } \\\\I = 25 \times \sqrt{\frac{8\times 10^{-12}}{20 \times 10^{-3}} } \\\\I = 0.0005 \ A[/tex]
Learn more about inductor current here: https://brainly.com/question/4425414
If you exert a force of 5 N into a nutcracker, and it outputs a force of 20 N, what is the mechanical advantage of the nutcracker. Show formula PLSSS HELPPPP!!! i'll make you brainliest
Answer: 4
Explanation:
MA = output force / input force
MA = 20 / 5
MA = 4
Hope this helps. Please mark brainliest.
if a glass rod rubbed with Silk piece is taken to a ball pen rubeed with wool the ball pen_____
Answer:
The glass rod remains charged due to electrification by the silk
Effects of global warming is
A-decrease in temperature
B-melting of polar ice caps
C-breathing problems
Answer:
B- the melting of polar ice caps
Explanation:
As the world's temperature increases, polar ice caps will no longer be able to remain solid.
According to Coulomb's law, rank the interactions between charged particles from highest potential energy to lowest potential energy.
a. 1+ charge and 1- charge seperated by 200pm
b. 1+ charge and 1+ charge seperated by 100pm
c. 1+ charge and 1- charge seperated by 100pm
d. 2+ charge and 1- charge seperated by 100pm
According to Coulomb's law, rank the interactions between charged particles from highest potential energy to lowest potential energy.
Highest potential energy to lowest potential energy.
b. 1+ charge and 1+ charge seperated by 100 pm
a. 1+ charge and 1- charge seperated by 200 pm
c. 1+ charge and 1- charge seperated by 100 pm
d. 2+ charge and 1- charge seperated by 100 pm
[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]
g:p:e = gravitational field strength x height
gravitational field strength = 9.8N/kg
Answer:
kdfihiyfxnlL chapter kar kaam
Explanation:
off influx teenon Palin
Lab: Energy Transfer Instructions Click the links to open the resources below. These resources will help you complete the assignment. Once you have created your file(s) and are ready to upload your assignment, click the Add Files button below and select each file from your desktop or network folder. Upload each file separately. Your work will not be submitted to your teacher until you click Submit. Documents Descriptive Lab Report Guide Descriptive Lab Report Rubric
Answer:
The second one says cant open file............
URGENT
The component of solid-state physics that works with and/or heats metals and alloys to give them certain desired
shapes or properties is..
Answer:
the is metallurgy .....
A marshmallow in a vacuum becomes
A) larger.
B) smaller.
C) does not change.
puffs up because of aur traping in marshmallow
therefore A is the answer
thank you