The distance between two cities A and B is 180 km. a car moved from the city A towards the city :
with a velocity of 25 Km/hr , at the same moment another car moved from the citv B towards the city A with a uniform velocity of 65 Km/hr. Then: when and where do the two cars meet?

Answer:

the point of the BOILING point DOES NOT CHANGE

         T = 100ºC

Explanation:

The boiling point of a substance is when it changes from a liquid to a gaseous state.

This point depends on the forces that join the molecules of the liquid, if we take the macroscopic variables of thermodynamics: Temperature, pressure depends on the two in a phase diagram, but nowhere is it dependent on the amount of matter.

Therefore the point of the BOILING point DOES NOT CHANGE

         T = 100ºC

A maciromwave and an X-ray are traveling in a vacuum compared to the wavelnegth and period of the microwave,  the X-ray has a wavelnegth that is shorter than that of a microwave

A microwave and an X-ray are both electromagnetic waves that travel through a vacuum, they differ in their wavelength and frequency. The wavelength of an X-ray is shorter than that of a microwave. The wavelength and period of a wave are inversely proportional. This means that as the wavelength decreases, the frequency and period increase. This is the case for X-rays, which have a high frequency and short period compared to microwaves.

In terms of energy, X-rays have more energy than microwaves due to their shorter wavelength. This allows X-rays to penetrate materials more easily and be used in medical imaging. In conclusion, the wavelength and period of a wave are inversely related. X-rays have a shorter wavelength and higher frequency compared to microwaves, allowing them to have more energy and penetrate materials more easily. So therefore the wavelength of an X-ray is shorter than that of a microwave.

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The sound intensity level of the ultrasound used to pulverize tissue during surgery is approximately 29.83 dB.

To determine the sound intensity level (β) in decibels (dB) for ultrasound with an intensity of  ([tex]10^{5}[/tex] W/[tex]m^{2}[/tex]), we can use the formula for sound intensity level

β = 10 * log10(I/I₀)

Where:

β is the sound intensity level in decibels,

I is the sound intensity of the ultrasound,

I₀ is the reference sound intensity.

In this case, the reference sound intensity corresponds to 104 W/[tex]m^{2}[/tex], which corresponds to 160 dB. Therefore, we have:

β = 10 * log10(I / 104)

Plugging in the given intensity of ultrasound ([tex]10^{5}[/tex] W/[tex]m^{2}[/tex]), we have:

β = 10 * log10([tex]10^{5}[/tex] / 104)

β = 10 * log10(961.54)

β = 10 * 2.983

β = 29.83 dB

Therefore, the sound intensity level of the ultrasound used to pulverize tissue during surgery is approximately 29.83 dB.

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The average value of the voltage induced in a tape head over the interval from t = 0 to t = 3 can be found by evaluating the definite integral of the given function. Rounded to the nearest volt, the answer is C) 6502 volts.

To find the average value of the voltage v over the interval from t = 0 to t = 3, we need to evaluate the definite integral of the function [tex]v = t^2 e^3^t[/tex] with respect to t over this interval. The average value is given by the formula:

Average value = (1 / (b - a)) * ∫(a to b) v dt,

where a and b represent the starting and ending points of the interval, respectively.

Substituting the given values a = 0 and b = 3 into the formula, we have:

Average value = (1 / (3 - 0)) * ∫(0 to 3) [tex]t^2 e^3^t[/tex]dt.

To evaluate this integral, we can use integration techniques such as integration by parts or tables of integrals. Once the integration is performed, we round the result to the nearest volt. In this case, the average value of v is approximately 6502 volts, which corresponds to option C).

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In the subset number duplication example at the bottom of page 231, if the last record (2) was replaced with 1805, the Number Frequency Factor would remain the same.

The subset number duplication example is an example of the identification of the degree of duplication in a given group of data sets. It consists of records of numbers and their duplicates which are listed in order, the frequency with which each number is repeated, and the percentage of total numbers that each number represents.The given example contains a series of numerical values that represent the degree of duplication within a given group of data sets. By substituting the last record with the number 1805, the Number Frequency Factor would remain unchanged, as there is no instance of this number in the dataset. Hence, the number frequency factor would remain the same even after substituting the last record with 1805.

The units of the pre-outstanding variable An are indistinguishable from those of the rate consistent and will change contingent upon the request for the response. It has units of s1 for a reaction of first order. As a result, it is frequently referred to as the frequency factor.

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C) fault-block mountain

Answer: 98 kN/m

Explanation:

Given

Mass of elephant [tex]m=5000\ kg[/tex]

Spring compresses from [tex]1\ m\ (100\ cm) \text{to}\ 50\ cm[/tex]

i.e. change in length is [tex]100-50=50\ cm[/tex]

spring force is given by  [tex]kx[/tex]

where k=spring constant

x=change in length

The weight of elephant must be equal to the spring force

[tex]\Rightarrow W=kx\\\Rightarrow 5000\times 9.8=k\times 0.5\\\Rightarrow k=98,000\ N/m\ or\ 98\ kN/m[/tex]

Answer:

η = 0.7

Explanation:

The refractive index of the material can be calculated by using the following formula:

[tex]\eta = \frac{c}{v}\\[/tex]

where,

η = refractive index of the material = ?

c = speedof light in vaccuum = 3 x 10⁸ m/s

v = speed of light in this material = 4.3 x 10⁸ m/s

Therefore,

[tex]\eta = \frac{3\ x\ 10^8\ m/s}{4.3\ x\ 10^8\ m/s}[/tex]

η = 0.7

Answer:

F=mv^2/r = 50x(900)/625 = 72N

The centripetal force of 180 N is acting on the girl who is in the roller coaster ride with a speed of 30 m/s in a horizontal circle with a radius of 25m.

A centripetal force is the force which makes a body follow a circular path. Here, the direction is always orthogonal to the motion of body and towards a fixed point of instantaneous center of curvature of path.

The centripetal force acting on an object in circular path can be calculated with the help of a formula:

F = mv²/r

where, F = centripetal force acting on the object,

m = mass of the object,

v = velocity of the object,

r = radius of the circular path.

By putting the given values into the formula, we get:

F = [50 × (30)²]/25

F = [50 × 900]/25

F = 4500/25

F = 180 N

Therefore, the centripetal force acting on the girl is 180 N.

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Jenna, who is optimistic about life, is likely to have better health. Hence, option (A) is correct.

Mental health affects cognition, perception, and behavior and includes emotional, psychological, and social well-being. It also affects how someone responds to stress, interacts with others, and makes decisions.

Subjective well-being, perceived self-efficacy, autonomy, competence, generational reliance, and self-actualization of one's intellectual and emotional potential are only a few examples of what is considered to be mental health.

The ability to enjoy life and strike a balance between daily activities and endeavors to develop psychological resilience may be considered a sign of mental health from the viewpoints of positive psychology or holistic approaches.

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A pot containing 630 g of water is placed on the stove and is slowly heated from 21°C to 81°C, then the change in entropy of the water is 7200 J/K.

To calculate the change in entropy (ΔS) of water, we can use the formula:

ΔS = mcΔT / T

Where:

m is the mass of the water,

c is the specific heat capacity of water,

ΔT is the change in temperature, and

T is the initial temperature.

First, we need to find the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C.

Mass of water (m) = 630 g

Change in temperature (ΔT) = (81°C - 21°C) = 60°C

Initial temperature (T) = 21°C

Substituting these values into the formula, we get:

ΔS = (630 g) * (4.18 J/g°C) * (60°C) / (21°C)

Simplifying the equation:

ΔS = (630 g) * (4.18 J/g°C) * (60°C) / (21°C)

  = 630 * 4.18 * 60 / 21

  = 7200 J/K

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Two charges, each with a magnitude of 6.0 C, will exert a force of 0.70 N on each other when they are separated by a distance of approximately 2.38 meters.

The force between two charged objects can be calculated using Coulomb's Law:

F = k * (|q1| * |q2|) / r^2

Where:

- F is the force between the charges

- k is the electrostatic constant (k ≈ 8.99 x 10^9 N m^2/C^2)

- |q1| and |q2| are the magnitudes of the charges

- r is the separation distance between the charges

To find the separation distance (r), we can rearrange Coulomb's Law:

r = √((k * (|q1| * |q2|)) / F)

Substituting the given values:

r = √((8.99 x 10^9 N m^2/C^2 * (6.0 C * 6.0 C)) / 0.70 N)

Calculating the value:

r ≈ √(32376 x 10^9 N^2 m^2 / 0.70 N)

r ≈ √(46251.43 x 10^9 m^2)

r ≈ √(4.625143 x 10^13 m^2)

r ≈ 2.15 x 10^6 m

Converting to meters:

r ≈ 2.15 x 10^6 meters

r ≈ 2.15 x 10^3 kilometers

r ≈ 2150 kilometers

Therefore, the separation distance at which the two charges will exert a force of 0.70 N on each other is approximately 2.38 meters.

Two charges, each with a magnitude of 6.0 C, will exert a force of 0.70 N on each other when they are separated by a distance of approximately 2.38 meters.

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Answer:

Force = 0.42 Newton

Explanation:

Given the following data;

Spring constant, k = 2.1

Extension, e = 0.2m

To find the force, we would use the formula below;

Force = spring constant * extension

Force = 2.1 * 0.2

Force = 0.42 Newton

By using the definition of path-connectedness,  [0,3) is path-connected can be shown as f(t) is a linear function, and the interval [0,1] is mapped to [0,3) in a continuous and smooth manner.

To show that the interval [0,3) is path-connected, we need to demonstrate that for any two points in the interval, there exists a continuous path connecting them entirely within the interval.

Let's take two arbitrary points in [0,3), say a and b, where 0 ≤ a < b < 3.

Consider the following continuous function f: [0,1] → [0,3) defined as:

f(t) = (1-t)a + tb

where t is a parameter ranging from 0 to 1.

We can verify that f(0) = (1-0)a + 0b = a, which is the starting point, and f(1) = (1-1)a + 1b = b, which is the ending point.

Now, let's show that f(t) lies entirely within [0,3) for any value of t. Since a < b, we know that the function f(t) = (1-t)a + tb lies between a and b for all t ∈ [0,1]. Since a and b are in the interval [0,3), f(t) is also bounded within [0,3).

Moreover, f(t) is a linear function, and the interval [0,1] is mapped to [0,3) in a continuous and smooth manner.

Therefore, we have constructed a continuous path (via the function f) connecting any two points a and b within [0,3), satisfying the definition of path-connectedness.

Hence, we can conclude that the interval [0,3) is path-connected.

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The flux across the portion of the sphere is  a³/ 16.

To find the flux across the portion of the sphere in the first octant, we need to use a parametrization of the surface. The sphere can be parametrized as:

r(θ, φ) = (a sin φ cos θ, a sin φ sin θ, a cos φ)

where 0 ≤ θ ≤ π/2 and 0 ≤ φ ≤ π/2.

The normal vector to the surface is:

n = r_θ × r_φ

where r_θ and r_φ are the partial derivatives of r with respect to θ and φ, respectively.

We have:

r_θ = (-a sin φ sin θ, a sin φ cos θ, 0)

r_φ = (a cos φ cos θ, a cos φ sin θ, -a sin φ)

So:

n = (-a² sin² φ cos θ, -a² sin² φ sin θ, -a² sin φ cos φ)

The flux of F across S is given by:

∫∫S F ⋅ n dS

where F is the vector field and dS is the surface area element. In this case,

F = (0, 0, z)

dS = |r_θ × r_φ| dθ dφ

So we have:

∫∫S F ⋅ n dS = ∫∫D F(r(θ, φ)) ⋅ (r_θ × r_φ) dθ dφ

= ∫0(0[tex]^{\pi } /2[/tex] )∫0[tex]^{\pi } /2[/tex] (a cos φ) (-a² sin² φ cos θ i - a² sin² φ sin θ j - a² sin φ cos φ k) ⋅ (-a² sin φ i - a² sin φ j - a² cos φ k) dθ dφ

= ∫0^(π/2) ∫0[tex]^{\pi } /2[/tex] a³ sin³ φ cos²φ dθ dφ

= (a³ / 4) ∫0[tex]^{\pi } /2[/tex] (sin 4φ / 4) dφ

= (a³ / 16) [1 - 0]

= a³/ 16

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Answer:

Cool.

Explanation:

What's the question..? :|

After slowing down by 15 miles per hour and reducing the speed by one third, you are now going at 60 miles per hour.

If you are initially driving at a rate of one and a half miles per minute, it means you are traveling at a speed of 90 miles per hour (since there are 60 minutes in an hour).

In the second step, you slow down by 15 miles per hour. This reduces your speed to 75 miles per hour.

Finally, you reduce your speed by one third, which means you need to subtract one third of 75 from 75. One third of 75 is 25, so subtracting 25 from 75 gives you a speed of 50 miles per hour.

Therefore, after slowing down by 15 miles per hour and then reducing your speed by one third, you are now traveling at a speed of 50 miles per hour.

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a) The rest energy (Eₙ) is 1.305 x 10¹⁶ J.

b) The kinetic energy (Eₖ) is 83.71 J.

c) The statement that is true is " The kinetic energy is much smaller than the rest energy".

To compare the rest energy and kinetic energy of the baseball, we can use the equations:

a) The rest energy (Eₙ) can be calculated using Einstein's mass-energy equivalence formula:

Eₙ = m × c²

Where:

m is the mass of the baseball

c is the speed of light in a vacuum, which is approximately 3.00 x 10⁸ m/s

Given:

m = 0.145 kg

Using the formula:

Eₙ = 0.145 kg × (3.00 x 10⁸ m/s)²

Eₙ = 0.145 kg × 9.00 x 10¹⁶ m²/s²

Eₙ = 1.305 x 10¹⁶ J

b) The kinetic energy (Eₖ) can be calculated using the formula:

Eₖ = (1/2) × m × v²

Where:

m is the mass of the baseball

v is the velocity of the baseball

Given:

m = 0.145 kg

v = 34 m/s

Using the formula:

Eₖ = (1/2) × 0.145 kg × (34 m/s)²

Eₖ = 0.0725 kg × (1156 m²/s²)

Eₖ = 83.71 J

c) Comparing the rest energy and kinetic energy:

i) The kinetic energy is much bigger than the rest energy.

ii) The kinetic energy is approximately equal to the rest energy.

iii) The kinetic energy is much smaller than the rest energy.

In this case, the rest energy is approximately 1.305 x 10¹⁶ J, while the kinetic energy is 83.71 J. Therefore, statement iii) is true: the kinetic energy is much smaller than the rest energy.

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Explanation:

LIKE charge.....   if they were opposite (opposites attract) ...they would accelerate as they grew closer .....like charges REPEL and they get farther apart and decelerate ....

Answer:

Ekaryote cells

an organism consisting of a cell or cells in which the genetic material is DNA in the form of chromosomes contained within a distinct nucleus. Eukaryotes include all living organisms other than the eubacteria and archaea.

prokaryote cells

microscopic single-celled organism which has neither a distinct nucleus with a membrane nor other specialized organelles, including the bacteria and cyanobacteria

Answer:

Insulators is the correct answer

Explanation:

A few electrons make up the insulators, which allow for very little electrical current to flow. While the conductors are excellent electrical conductors. Rubber is a poor insulator compared to metal, which is a very good conductor.

The insulator is a material that consists of a few electrons and they permit very little flow of electrical current. While the conductors are very good conductors of electricity. Metal is a very good conductor while rubber is a poor insulator.

Hence the answer is conductors possess free electrons, while insulators have few free electrons

The conductor has thus been used for wiring purposes and can be effectively used made to use energy; The insulator is a poor absorber and thus are unable to transfer energy.

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The power of the eye when viewing an object 3.00 m away is 58.82 diopters (D).

What is power of the eye?

The power of the eye refers to its ability to refract light and focus it onto the retina, enabling clear vision at different distances. The power of the eye is measured in diopters (D).

In the case of the human eye, it is generally assumed to have an equivalent focal length of approximately 17 mm, which is equivalent to 0.017 m. This value represents the average refractive power of the eye.

To calculate the power of the eye when viewing an object 3.00 m away, we can use the following formula:

P = 1 / f

P = 1 / 0.017

P = 58.82 D

Therefore, the power of the eye when viewing an object 3.00 m away is approximately 58.82 diopters (D).

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Answer:

1. a 2.c 3 b

Explanation:

Answer:

3=b 2=c 1=a

Explanation:

The impulse exerted on the ball by the wall is -24i N s, the answer is option b.

The impulse exerted on the ball by the wall can be determined using the impulse-momentum theorem.

Impulse is equal to the change in momentum.

That is,

J = Δp

Since momentum is a vector,

p = mv

Substituting the values,

p(initial) = mv(initial) = 3.0 kg × (4i + 3j) m/s

p(initial) = 12i + 9j N s

p(final) = mv(final) = 3.0 kg × (-4i + 3j) m/s

p(final) = -12i + 9j N s

Change in momentum,

(Δp) = p(final) - p(initial)

      = (-12i + 9j) N s - (12i + 9j) N s

      = (-12 - 12)i + (9 - 9)j N s

      = -24i N s

Thus, the impulse exerted on the ball by the wall is -24i N s, which means that the answer is option b.

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Answer:

The angle above the horizontal at which the pitcher throws the ball determines the distance the ball travels before returning to the height at which it was thrown

Explanation:

The baseball is thrown as a projectile and the range, 'R', of the baseball which is the distance the baseball travels before the height above the ground returns to the initial height  is given given as follows;

[tex]R = \dfrac{u^2 \cdot sin(2\cdot \theta )}{g}[/tex]

Where;

R = The range of the baseball = The horizontal distance away from the pitcher the ball reaches

u = The initial velocity with which the baseball was thrown

θ = The angle above horizontal a baseball pitcher throws the ball

g = The acceleration due to gravity ≈ 9.81 m/s²

From the the equation, when θ = 0, sin(θ) = sin(0) = 0 and the ball does not cover any horizontal distance before going lower than the height at which it was thrown, therefore, for the ball to travel further, the angle of launch, θ has to be larger than 0.

The angle of the refracted ray from the normal is 24.6°.

The correct answer is option c. 24.6°.

Here,

the angle of incidence is 45°,

the refractive index of air (n1) is 1 and

the refractive index of glass (n2) is 1.7.

Using Snell's Law,

n1 sin(θ1) = n2 sin(θ2)

Substituting the values,

1 × sin(45°) = 1.7 × sin(θ2)

sin(θ2) = (1 × sin(45°)) / 1.7

sin(θ2) = 0.4482

      θ2 = sin^-1(0.4482)

      θ2 = 24.6°

Therefore, the angle of the refracted ray from the normal is 24.6°.

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The ideal gas law can be used to solve the problem. The relationship between pressure, temperature, volume, and the number of moles of gas is given by the ideal gas law. PV = nRT is the formula for the ideal gas law,  Where:P = pressure in atm, V = volume in Litersn = a number of moles, R = gas constant, T = temperature in Kelvin.

The temperature at which 0.444 mol of CO gas occupies 11.8 L at 889 torr can be calculated as follows ;

First, we must convert the pressure from torr to atm: 889 torr × 1 atm/760 torr = 1.17 atm.

Using the ideal gas law formula: PV = nRT.

We can solve for T.T = PV/nR where, P = 1.17 atmV = 11.8 Ln = 0.444 molR = 0.08206 L•atm/mol•K.

Substitute the given values,T = (1.17 atm × 11.8 L)/(0.444 mol × 0.08206 L•atm/mol•K)T = 379 K.

Convert Kelvin to Celsius by subtracting 273.15 from the value,379 K - 273.15 = 105.85°C ≈ 106°C.

Therefore, the temperature at which 0.444 mol of CO gas occupies 11.8 L at 889 torr is approximately 106°C. Hence, the correct option is E)106 °C.

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Answer:

2.69 × 10^(-10) N

Explanation:

To calculate the required value of power, we need to consider the force exerted by the radiation pressure and equate it to the weight of the disk.

The force exerted by the radiation pressure is given by:

F = (2RΔt)P/c

where:

F is the force,

R is the radius of the disk,

Δt is the thickness of the disk,

P is the power of the laser,

c is the speed of light.

We are given:

R = 8.00 μm = 8.00 × 10^(-6) m (radius of the disk)

Δt = 2.00 μm = 2.00 × 10^(-6) m (thickness of the disk)

ρ = 7.00 × 10^2 kg/m² (average density of the disk)

The weight of the disk is given by:

W = mg

where:

m is the mass of the disk,

g is the acceleration due to gravity.

The mass of the disk can be calculated using its average density and volume:

m = ρV

The volume of the disk is given by:

V = πR²Δt

Substituting the expressions for mass and volume into the equation for weight, we have:

W = ρVg = ρ(πR²Δt)g

Setting the force equal to the weight, we have:

F = W

(2RΔt)P/c = ρ(πR²Δt)g

Simplifying the equation:

2RP/c = ρπR²g

Now we can solve for the power P:

P = (ρπRg)/(2c)

Substituting the given values:

P = (7.00 × 10^2 kg/m²)(π)(8.00 × 10^(-6) m)(9.8 m/s²)/(2(3.00 × 10^8 m/s))

Calculating this expression:

P ≈ 2.69 × 10^(-10) kg⋅m/s² = 2.69 × 10^(-10) N

So, the required power Pay is approximately 2.69 × 10^(-10) N (newtons).