The double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be ____ and are delocalized around the ring.
Answers
Answer: The double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be in conjugation and are delocalized around the ring.
Explanation:
Chemical compounds that have conjugated planar ring systems where there are delocalized pi-electron clouds are present in place of individual alternate and single bonds.
This means that electrons present in a double bond of alkene are in conjugation.
Therefore, we can conclude that the double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be in conjugation and are delocalized around the ring.
Answer:
In resonance
Explanation:
Got it right on Acellus.
Related Questions
The chemical formula for gold (III) oxide
ionic compounds
Answers
Answer:
Gold(III) oxide (Au2O3) is an inorganic compound of gold and oxygen with the formula Au2O3. It is a red-brown solid that decomposes at 160 °C. (Au203 <---)
If 0.0015 moles of NaOH is dissolved in 11 L of water, what is the pH of the
solution?
Answers
Answer:
pH = 10.15
Explanation:
NaOH is a strong base so it dissolves completely.
Calculate your [OH-] first by dividing the moles of OH- by the volume.
0.0015 mol OH- / 11 L = 0.00014
Then, calculate the pOH:
pOH = -log[OH-] = -log(0.00014) = 3.85
pOH + pH = 14, so pH = 14 - pOH = 14 - 3.85 = 10.15
What is the net ionic equation for the following reaction?
Rb2CrO4(aq) + 2AgClO(aq) --> 2RbClO(aq) + Ag2CrO4(s)
Group of answer choices
Rb+(aq) + ClO-(aq) --> RbClO (s)
2Rb+(aq) + CrO42+(aq) --> Rb2CrO4 (s)
Ag+(aq) + ClO-(aq) --> AgClO (s)
2Ag+(aq) + CrO42+(aq) --> Ag2CrO4 (s)
Answers
Choose the correct name for each acid. Click here
to access the common polyatomic ion sheet.
HNO2:
DONE
HI:
DONE
H3PO4 :
DONE
Answers
The correct name of HNO₂, HI and of H₃PO₄ is nitrous acid, hydroiodic acid and phosphoric acid respectively.
What are acids?Acids are those substances in which carboxylic acid (-COOH) is present and pH value of acids falls in the range of 0 to 6.9.
Name of the HNO₂ compound is nitrous acid, of HI is hydroiodic acid and of H₃PO₄ is phosphoric acid.
Hence name of the HNO₂, HI and of H₃PO₄ is nitrous acid, hydroiodic acid and phosphoric acid respectively.
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Answer: HNO2 nitrours acid
HI Hydroiodic acid
H3PO4 phosphoric acid
Explanation: edu
Write a nuclear equation for each description below.
Stronitum-84 combines with an alpha particle, creating sodium-25 and a daughter nucleus. 4 pts
Answers
Answer:
Sr-84 + He-2 -> Na-25 + Pm-61
Explanation:
What is the mass of an atom with 8 protons, 8 electrons, and 8 neutrons?
Answers
Answer:An oxygen atom usually has 8 protons, 8 neutrons, and 8 electrons. Looking at the periodic table, oxygen has atomic number 8 and atomic weight 15.999.
Explanation:
The mass of the atom with 8 protons, 8 electrons, and 8 neutrons would be approximately 16 atomic mass units as the number of electrons has an almost negligible contribution to the mass of the atom.
What is atomic mass?It is the sum of the mass of all the protons as well as the neutrons that are present inside the nucleus.
Atomic mass = total number of protons present in the nucleus + total number of neutrons present in the nucleus of an atom,
As given in the problem we have to find the atomic mass of the atom with eight protons, eight electrons, and eight neutrons,
This given specified atom clearly represents the oxygen atom as it has eight electrons protons and neutrons each.
Thus, the atomic mass of the given atom would be 16.
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Can someone double check my work? (Ideal Gas Law Equation)
I am solving for the amount of moles in two gases.
For one, it was 4.75mL at 0.5C (273.65K) and 1.2atm.
n=(1.2*4.75)/(0.0821/273.65)=(5.7/22.456)=0.25361653 moles
For the other gas, it was 4.6mL at 0.5C and 1.2atm.
n=(1.2*4.6)/(0.0821/273.65)=(5.52/22.456)=0.24581403 moles
Please double check these for any errors in math or whatever. Thank you.
Answers
I did not see any errors, i may be wrong but what i can see is that it is correct
Determine the representative particles of
0.075 mol Ti
2.10 mol CO2
Answers
Answer:
0.o75 mol Ti = 4.5x10∧22
2.10 mol CO2 = 1.26x10∧24 molecules
hope this helped
A 25.0g piece of aluminum sits in a room and cools. It loses 4300.0 J of heat. If the initial temperature of aluminum is 125.3°C, what is the final temperature? The specific heat capacity of aluminum is 0.900 J/g°C.
Answers
Answer:
-65.8C
Explanation:
Please help :)
It’s a science thing for 7th grade
Answers
Answer: The first question is chemical The second one is Physical
Explanation:
What type of molecule is shown below? A. Alcohol B. Ether C. Ketone D. Aldehyde
Answers
B. Etherrrrrrrrrrrrrrrrrrrrrrrrrrrrrr
Ether is the type of molecule. Hence, option B is correct.
What is organic chemistry?Organic chemistry teaches us about the structure, properties, composition, reactions, and preparation of carbon-containing compounds.
Ether is an organic compound with an oxygen atom bonded to two alkyl or aryl groups. Ether's structure is same as alcohol.
Hence, option B is correct.
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helpppppppppppp plzzzzzzzzzzz
Answers
Answer: we'll for sunny days that we'll be high pressure and for low pressure that we'll be cloudy and foggy moist days .
Explanation:
The amount of solar radiation changes due to the
WILL MARK BRAINLIEST!!
Answers
Due to the variations in the sun-earth distance.
Hope it helps *-*An industrial synthesis of urea obtains 87.5 kg of urea upon reaction of 68.2 kg of ammonia with excess carbon dioxide. Determine the theoretical yield of urea and percent yield for the reaction.
Answers
Answer:
The theoretical yield of urea = 120.35kg
The percent yield for the reaction = 72.70%
Explanation:
Lets calculate -
The given reaction is -
[tex]2NH_3(aq)+CO_2[/tex] →[tex]CH_4N_2O(aq)+H_2O (l)[/tex]
Molar mass of urea [tex]CH_4N_2O[/tex]= 60g/mole
Moles of [tex]NH_3[/tex] = [tex]\frac{62.8kg/mole}{17g/mole}[/tex] (since [tex]Moles=\frac{mass of substance}{mass of one mole}[/tex])
= 4011.76 moles
Moles of [tex]CO_2[/tex] = [tex]\frac{105kg}{44g/mole}[/tex]
= [tex]\frac{105000g}{44g/mole}[/tex]
= 2386.36 moles
Theoritically , moles of [tex]NH_3[/tex] required = double the moles of [tex]CO_2[/tex]
but , [tex]4011.76<2\times 2386.36[/tex] , the limiting reagent is [tex]NH_3[/tex]
Theoritical moles of urea obtained = [tex]\frac{1 mole CH_4N_2O}{2mole NH_3}\times4011.76 mole NH_3[/tex]
= [tex]2005.88mole CH_4N_2O[/tex]
Mass of 2005.88 mole of [tex]CH_4N_2O[/tex] =[tex]2005.88 mole \times\frac{60g CH_4N_2O}{1mole CH_4N_2O}[/tex]
= 120352.8g
[tex]120352.8g\times \frac{1kg}{1000g}[/tex]
= 120.35kg
Therefore , theroritical yeild of urea = 120.35kg
Now , Percent yeild = [tex]\frac{87.5kg}{120.35kg}\times100[/tex]
72.70%
Thus , the percent yeild for the reaction is 72.70%
Eight ounces (1 fl. Oz = 29.57 ml) of orange juice contains 160% of the recommended daily allowance of vitamin c (rda = 75-90 mg for adults). How many milliliters of the orange juice will provide 100% of the recommended daily allowance?
Answers
What is 3 pointing to
Answers
Answer:
Electrons
Explanation:
Electrons is the outside of the nucleus
What volume is occupied by 2.33 miles of an ideal gas at 0.953 atm and 44°C
Answers
Answer:
6663.6
Explanation:
For a solution, [H+] = 3 x 10-11M.
What is the pH?
Answers
Answer:
pH≈10.5
Explanation:
-log(3 x 10-11)≈10.5
Venus Fly trap is a great example of which type of tropism?
a
Thigmotropism
b
Gravitropism
c
Phototropism
d
Hydrotropism
Answers
Turbo or supercharger
Answers
Help ASAP I’ll mark you as brainlister
Answers
Answer:
2.51g Mg
Explanation:
The empty crucible had a mass of 35.84. With the magnesium added, it had a mass of 38.45. This means that you should subtract the mass of the empty crucible from the mass of the crucible with Mg to find how much was added.
38.35g - 35.84g = 25.1g
show the path to the formation of sodium calcium and aluminum bases please help me
Answers
Answer:
i hope this helps :)
Explanation:
please mark brainlest
Answer:
dunno
Step-by-step explanations:
Which of the following chemical equations follows the law of conservation of mass?
Answers
Answer:
The third choice
Explanation:
The law of conservation of mass tells us that the mass of the reactants and products in a chemical reaction will be equal to one another. Equations follow the law of conservation of mass when they are balanced, which means that they have the same number and type of atoms on each side.
When individual atoms are counted, the third choice has the same number and type of atoms on each side: 1 gallium, three cesium and three fluorine.
One example of parasitism is the relationship between barnacles and whales or sea turtles. True or false? If false, why?
PLEASE ANSWER QUICKKK
Answers
Answer:
True
Explanation:
it is a Predation
What’s the Mole ratio between fe and s
Answers
Answer:1:1
Hope this helps!
Explanation:
(science)Which type of harmful alleles may disappear from a population more slowly when the individual may still reproduce?
a.a dominant allele
b.a recensive allele
c.a double allele
d.a single allele
Answers
How many liters are in 2.88 moles of CH4? Round your answer to the hundredths place (2 decimal place)
HELPPO ME PLZ
Answers
At higher altitudes would there be more or less
oxygen available to breathe?
a. Less oxygen is available at higher altitudes.
b. More oxygen is available at higher altitudes.
Answers
Answer: less oxygen available at higher altitudes
Explanation:
The higher in elevation you get, the lower the air pressure, allowing oxygen atoms to spread out farther, therefore making available oxygen less.
the higher up you get the higher the air pressure is
Which tiny, round “factory” puts together protein and is often found in the endoplasmic reticulum?
Golgi body
ribosome
chromosome
chloroplast
Answers
A sample of a compound containing only carbon and hydrogen atoms is completely combusted, producing
11.0 g of CO, and 4.5 g of H,O.
Which of the following is the empirical formula of the compound?
Choose 1 answers
CH
B
CH
CH3
C2H
Answers
The empirical formula will be C2H.
What is empirical formula?The easiest whole-number proportion of the numerous elements in a molecule is represented by an empirical formula.
Calculation of empirical formula
Given data:
C = 11.0 g
H = 4.5 g
The atomic mass of C = 12
The atomic mass of H = 1
Now, divide the mass by atomic mass.
1) For carbon atom= 11 / 12 =0.91
2) For hydrogen atom = 4.5 / 1=4.5
Now, divide the lowest term by the obtaining whole number.
1) For carbon atom = 11/ 0.91 = 12
2) For hydrogen atom = 4.5/0.91 = 5
Therefore, the empirical formula will be C2H,
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