The _____________ experiences a temperature increase primarily due to the absorption of gamma rays and X-rays.

Answer:

weight =m x g =2kg × 10m/s 2 = 20N

weight = m × gravity

=unit for weight is newtons

Mass=weight ÷ gravity

= unit for mass is kilograms

Gravity=weight ÷ mass

=unit for gravity is 10m/sec 2

Answer:

W = F× d

= 300×750

= 225000

E = 225000

P = 300×750/25 = 9000

P = 300× 750/10 = 22500

Answer:

Im pretty sure its number 2

Explanation:

The first one a scientific way of finding the age of something that is very old (such as a dinosaur bone) by measuring the amount of certain forms of carbon in it

Hi there!

We can begin by calculating the acceleration using the kinematic equation:

d = vit + 1/2at²

Since the rocket starts from rest, we can rewrite this as:

d = 1/2at²

Plug in given values:

4.2 = 1/2a(0.137²) ⇒ a = 447.55 m/s²

Now, we can use Newton's Second Law to find the appropriate force:

∑F = m · a

∑F = 50,000 · 447.55 = 22,377,500 N

Answer:

Explanation:

The rotational velocity vector is directed away from the jar

Explanation:

The main difference is frequency, sound waves are in Kilohertz , water waves are of course much slower. There are other differences , sound is longitudinal compression, but if you track motion of a particle in a water wave it moves in elliptic orbit as the wave passes.

She is 1.0 m higher than she is when she started. The speed at which the woman must be running when she grabs the rope is 4.427 m/s

Suppose we consider the Figure 1 to be a right-angle triangle;

where;

∴

Using Pythagoras rule;

(hyp)² = opp² + adj²

5.0² = 3.0² + x²

x² = 25 - 9

x² = 16

x = √16

x = 4 m.

When she is directly over the far edge of the ravine, the height at which she is far higher than where she started is:

= 5cm - 4cm

= 1 cm

The speed at which the woman must be running when she grabs the rope can be determined by taking both the potential energy and kinetic energy of the system, which can be computed as:

Making the speed the subject of the formula, we have:

[tex]\mathbf{v = \sqrt{2gh}}[/tex]

[tex]\mathbf{v = \sqrt{2\times 9.8 \times 1.0}}[/tex]

v = 4.427 m/s

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speed- the rate something moves or operates

Can I have brainlist please

The Speed are distance covered by the object in unit time.The S.I unot of speed is metre per second written as m/sec.It is a scalar quantity.

The speed is measured in metres per second ( ms- ¹ )

Where denoted by s

The distance travelled is measured in metres (m) and denoted by d

t is the amount of time spent and measured in seconds s

Answer:

B. 3 m

Explanation:

The position of the line at 3 seconds is 9 m and at 4 seconds is 12m .

Therefore; Displacement = 12 - 9 = 3 m

Answer:

Very simple. The charge Q= 20 C. the formula for Q= I* t. now I= Q/t = 20/1s = 20 Amps.

Explanation:

The current given that the charge is 10C and the time is 4 seconds is gotten as Current = 2.5 Amps

Given Data

Charge = 10 Columbs

Time = 4 seconds

Current = ?

Electrical current is defined by how much electric charge has been transferred per second, giving the following relationship:

Charge = Current*Time

Rearranging this we get:

Current = Charge/Time

The symbol for charge is Q , it is measured in coulombs (C).

The symbol for current is I , it is measured in amperes (A).

The symbol for time is T, it is measured in seconds (s).

Substituting our given Data into the expression we have

Current = 10/4

Current = 2.5 Amps

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Answer:

A. Longer wavelengths and less dangers

Explanation:

Radio waves are at the lowest end of the EM spectrum, they have the longest wavelength of any other EM waves, the lowest energy and, accordingly, the lowest frequency;

Their low energy and frequency means they pose little risk of harm or danger as they don't get absorbed by human being.

Answer:

it traveled 180km

Explanation:

Answer:

refers to the bending of light

the fact or phenomenon of light, radio waves, etc. being deflected in passing obliquely through the interface between one medium and another or through a medium of varying density.

Answer:

chemical symbol

Explanation:

The forces that push upward on an indoor skydiver are lift force and air resistance.

The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.

The downward forces on the indoor skydiver include the following;

The upward force on the indoor skydiver include the following;

Thus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.

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Answer:

Identify the name of the individual, group or institution that created the website. A reliable website should clearly state the name of its creator. Generally, websites created by government institutions (.gov) and educational institutions (.edu) are considered more reliable.

Answer:

the ratio of the number of turns in the primary and secondary coils.

Explanation:

hope i'm not too late!!

Answer:

Seriously Your Question Is Kinda Tremendous

Explanation:

I'll Head Is Boiling From Question That Keeps Popping Up My Head, Someone Might Give You A Positive Hand

The ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].

The given parameters;

The electrostatic force between the two electrons is calculated as follows;

[tex]F_c = \frac{kq^2}{r^2} \\\\[/tex]

The gravitational force between the two electrons is calculated as follows;

[tex]F_g = \frac{Gm_e^2}{r^2}[/tex]

The ratio of the electric force to the gravitational force between the two electrons is calculated as follows;

[tex]\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{1}{\frac{Gm^2}{r^2} } \\\\\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{r^2}{Gm^2} \\\\\frac{F_c}{F_g} = \frac{kq^2}{Gm^2}\\\\[/tex]

[tex]\frac{F_c}{F_g} = \frac{(8.99 \times 10^9) \times (1.6 \times 10^{-19}))^2}{(6.67 \times 10^{-11} ) \times (9.11 \times 10^{-31})^2} \\\\\frac{F_c}{F_g} = 4.2 \times 10^{42}[/tex]

Thus, the ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].

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The Correct statement is ~

Acceleration is a vector quantity.

Answer:

Acceleration is a vector quantity.

People with low cardiovascular fitness are more prone to heart disease than those whose cardiovascular fitness is high because those with lower cardiovascular fitness will have weaker heart muscles. Thus, the correct option is B.

Cardiovascular fitness may be defined as the accommodation of the cardiovascular system to furnish oxygenated blood to functioning muscles. It includes the muscles of the heart, lungs, blood vessels, etc.

People with low cardiovascular fitness have lower furnishing of oxygenated blood to various organs like the heart, lungs, etc. Due to this, the muscles of specific body parts or organs may undergo a state of inactivity suddenly for a fraction of seconds.

This activity constantly leads to various heart-related diseases directly or indirectly in the life of an individual.

Therefore, the correct option for this question is B.

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#SPJ1

The beginning of the formation of galaxies and clusters of galaxies are the slight fluctuations seen in maps of the cosmic background radiation. So, the correct option is C.

The cosmic background radiation is defined as the microwave radiation that fills all of space which is a remnant that provides an important source of data on the early universe. With a standard optical telescope, the background space between stars and galaxies is almost completely dark.

It is also called the Cosmic Microwave Background (CMB) or electromagnetic radiation filling the universe which is a residual effect of the Big Bang that happened 13.8 billion years ago. The beginning of the formation of galaxies and clusters of galaxies are the slight fluctuations seen in maps of the cosmic background radiation.

Therefore, the correct option is C.

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Your question is incomplete, most probably the complete question is:

What are the slight fluctuations seen in maps of the cosmic background radiation?

a. uncertainties in the map

b. variations in the instrument's sensitivity

c. the beginning of the formation of galaxies and clusters of galaxies

d. dark matter

e. none of the above

Answer:

it's ans is D because all three are wrong

1. Since the body is thrown vertically upward, the only force acting on it as it rises and falls is gravity, which causes a constant downward acceleration with magnitude g = 9.8 m/s². Because this acceleration is constant, we can use the formula

v² - u² = 2a ∆x

where

u = initial speed

v = final speed

a = acceleration

∆x = displacement

At its maximum height, some distance y above the point where the body is launched, the body has zero velocity, so

0² - (20 m/s)² = 2 (-9.8 m/s²) y

Solve for y :

y = (20 m/s)² / (2 (9.8 m/s²)) ≈ 20.4 m

2. Relative to the ground, the body's maximum height is 60 m + 20.4 m ≈ 80.4 m.

3. At any time t ≥ 0, the body's vertical velocity is given by

v = 20 m/s - gt

At the highest point, we have

0 = 20 m/s - (9.8 m/s²) t

and solving for t gives

t = (20 m/s) / (9.8 m/s²) ≈ 2.04 s

4. The body's height y above the ground at any time t ≥ 0 is given by

y = 60 m + (20 m/s) t - 1/2 gt²

Solve for t when y = 0 :

0 = 60 m + (20 m/s) t - 1/2 (9.8 m/s²) t²

Using the quadratic formula,

t = (-b + √(b² - 4ac)) / (2a)

(and omitting the negative root, which gives a negative solution) where a = -1/2 (9.8 m/s²), b = 20 m/s, and c = 60 m. You should end up with

t ≈ 6.09 s

5. At the time found in (4), the body's velocity is

v = 20 m/s - g (6.09 s) ≈ -39.7 m/s

Speed is the magnitude of velocity, so the speed in question is 39.7 m/s.

Answer:

The precise answer depends on the density and therefore the temperature of the water, but we can obtain a reasonable approximation by assuming that the density of the water is 1000 kilograms per cubic meter (kg/m³).

Since the depth of the water in the well is 10 m, the volume of water directly above an area A of a square meters (m²) at the bottom of the well is 10×a m³.

Since the density of the water is 1,000 kg/m³, the mass of water directly above area A is (1,000 kg/m³) × (10×a m³) = (1000×10×a kg) = 10,000×a kg.

Since g = 9.8 m/s², the force of gravity acting on the water directly above area A is (9.8 m/s²) × (10,000×a kg) = 9.8×10,000×a N (newtons) = 98,000×a N.

So the pressure of water acting on area A is (98,000×a N)/(a m²) = (98,000×a)/a N/m² = 98,000 pascals (pa). And since A could be any given area at the bottom of the well, this is the pressure at any point at the bottom of the well.

So the pressure at the bottom of the well is 98,000 pascals (or 98,000/101,325 standard atmospheres = 560/579 atmospheres ~ 0.967 standard atmospheres).

Please comment below if you have any questions.

Answer:

there is friction between the two things

Explanation:

Answer:

Uranus

Explanation:

brainliest please?

Answer:

Δx=7.35m

Explanation:

This is a free fall problem (g= -9.8 m/s²).

Displacement: ? <--- what you're trying to find (max height)

Initial Velocity: 12 m/s

Final Velocity: 0 m/s <-- since the can will land back in your hands

Time: Missing <-- not needed to solve

Acceleration: -9.8 m/s²

The equation that you will use is vf²=vi²+2aΔx

Now plug the information into the equation!

(0m/s)²=(12m/s)²+2(-9.8m/s²)Δx

Multiply the 2 with the acceleration (-9.8m/s²)

(0m/s)²=(12m/s)²-19.6m/s²Δx

Now you need to square the final and initial velocity

0m/s=144m/s-19.6m/s²Δx

Move 144 to the other side of the equal sign

-144m/s=-19.6m/s²Δx

Divide both sides by -19.6m/s²

7.346m=Δx

You can round it to the tenth or hundreth place, up to you!

For this example, I'll round to the hundredth...

Δx=7.35m

I would double check this answer or review it yourself to see if it's correct.

Good luck with your studies!