a) The estimated current in the wire is approximately 1.59 A.
b) The wire will now feel a force of approximately 0.036 N.
a) To estimate the current in the wire, we can use the equation for the magnetic force on a current-carrying wire:
Force = magnetic field strength × current × length of wire
Since the force is given as 3.50x[tex]10^{-2}[/tex] N, the magnetic field is 0.22 T, and the length of the wire is equal to the diameter of the pole faces (10.0 cm), we can solve for the current:
3.50x[tex]10^{-2}[/tex] N = (0.22 T) × current × (10.0 cm)
3.50x[tex]10^{-2}[/tex] N = (0.22 T) × current × (0.10 m)
Solving for the current:
current = (3.50x[tex]10^{-2}[/tex] N) / ((0.22 T) × (0.10 m))
current ≈ 1.59 A (ampere)
b) When the wire is tipped at an angle of 17.0 degrees with the horizontal, the force it will feel can be calculated using the equation:
Force = magnetic field strength × current × length of wire × sin(theta)
Since the magnetic field strength, current, and length of the wire remain the same as in the previous scenario, we can use the same values. The angle theta is 17.0 degrees. Substituting these values, we can find the new force:
Force = (0.22 T) × (1.59 A) × (0.10 m) × sin(17.0 degrees)
Force ≈ 0.036 N (new force)
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the focal length of a converging lens is 0.50 meters. an object is placed 1.0 meters from the lens. the distance between the lens and the image is
The distance between the lens and the image is 1.0 meter.
To find the distance between the lens and the image formed by a converging lens, we can use the lens formula:
1/f = 1/v - 1/u
Where:
f is the focal length of the lens
v is the distance of the image from the lens (positive if the image is on the same side as the observer, negative if the image is on the opposite side)
u is the distance of the object from the lens (positive if the object is on the same side as the observer, negative if the object is on the opposite side)
In this case:
Focal length (f) = 0.50 meters
Distance of the object (u) = 1.0 meter
Let's substitute the given values into the lens formula:
1/0.50 = 1/v - 1/1.0
2 = 1/v - 1
2v = v - 1
v = 1
Therefore, the distance between the lens and the image = 1.0 m.
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True or False: A balanced force acts on different objects, and action-
eaction forces act on the same object. *
A. True
B. False
Answer:
true
Explanation:
according to the Newton's third law
How is capacitance related to the distance between the plates of a capacitor?
It is directly proportional, so the capacitance increases as the distance increases.
It is inversely proportional, so the capacitance increases as the distance increases.
It is directly proportional, so the capacitance decreases as the distance increases.
It is inversely proportional, so the capacitance decreases as the distance increases.
Answer:C
Explanation: I studied, and C is correct
Answer:
D
Explanation:
Please help me if you can.
I can't figure out how the answer for number 30 is C and 31 is C. My question is how did they get that answer?
Answer:
30. $3.85
31. $2.22
Explanation:
30. The time duration of the kitchen clock is left on = All day = 24 hours
The power rating of the kitchen clock, P = 4 watts
The electricity cost in Alberta, R = $0.11 per kilowatt hour
The total number of hours the kitchen clock is on during the year, 't', is given as follows;
t = Number of hours per day × Number of days per year
∴ t = 24 hours/day × 365 days/year = 8,760 hours
The energy consumption of the kitchen clock, per year, E = P × t
∴ E = 4 watts × 8,760 hours = 35,040 watts-hour = 35.040 kw·h
The cost of operating the clock in one year, C = E × R
∴ Operating cost for the kitchen clock
∴ C = 35.040 kw·h × $0.11/(kw·h) = $3.8544 ≈ $3.85
The cost of operating the clock in one year, C ≈ $3.85
31. The power rating of the ghetto blaster, P = 28 watts
The time duration the ghetto blaster was on during an average month = All day = 24 hours
The number of days during an average month, n = 30 days
The cost of electricity in Alberta, R = $0.11 per kilowatt hour
The time in hours the ghetto blaster was on, t = 30 days/month × 24 hours/day
∴ t = 720 hours per month
The cost of operating the ghetto blaster in one month, C = P × t × R
∴ C = 28 W × 720 hours × 1 kw·h/(1000 w·h)× $0.11/(kw·h) = $2.2176
∴ The cost of operating the ghetto blaster in one month, C ≈ $2.22
what tangential speed v must the bob have so that it moves in a horizontal circle with the string making an angle 21.0 ∘ with the vertical?
To find the tangential speed required for the bob to move in a horizontal circle with the string making an angle of 21.0 degrees with the vertical, we can use the concept of centripetal force.
The centripetal force required to keep the bob moving in a circular path is provided by the tension in the string. The tension can be resolved into two components: the vertical component and the horizontal component. The vertical component of the tension balances the weight of the bob, which is given by: T * cos(21.0°) = mg. where T is the tension in the string, m is the mass of the bob, and g is the acceleration due to gravity. The horizontal component of the tension provides the centripetal force required for circular motion, and it can be expressed as: T * sin(21.0°) = mv^2 / r. where v is the tangential speed of the bob and r is the radius of the circular path. Dividing the two equations: [T * sin(21.0°)] / [T * cos(21.0°)] = (mv^2 / r) / (mg). tan(21.0°) = v^2 / (rg). Solving for v: v = √(rg * tan(21.0°)) Now, we can substitute the values of the gravitational acceleration (g) and the angle (21.0°) to calculate v. Note: It is assumed that the bob is moving in a horizontal circle without any additional external forces affecting the system.
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for the truss bridge shown, a) sketch the influence lines for the force in members be, bc, and da.
a) Sketching the influence lines for the force in members BE, BC, and DA in a truss bridge requires a visual representation. Influence lines show the variation of forces in a structure due to the movement of a load.
Please refer to structural engineering resources or software for accurate sketches and graphical representations of the influence lines for these specific members in a truss bridge. These resources will provide detailed illustrations based on the structural dimensions, member properties, and load positions. Influence lines are valuable tools for structural engineers as they help identify critical load positions, assess the structural response, and determine the maximum forces experienced by different members. Please consult reliable structural engineering references, textbooks, or appropriate software that specifically address truss bridge analysis and design to obtain accurate sketches of the influence lines for members BE, BC, and DA. These resources will provide the necessary diagrams and detailed explanations based on the specific truss bridge configuration and load positions.
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explain the differences between pitch and loudness and what are they connected to?
Answer:
Loudness and pitch are distinct properties of sound. Loudness is related to the amplitude of the sound wave; pitch is related to its frequency
Explanation:
You completed three terrain-forming trials. Describe how the sun's mass affects planets in a solar system. Use data you recorded to support your conclusions
Pls answer
The sun's mass plays a crucial role in shaping the characteristics of planets in a solar system. It determines the orbital paths, stability, and overall structure of planetary systems.
During the three terrain-forming trials, I observed the effects of the sun's mass on planets in a solar system. The sun's mass is a critical factor in determining the gravitational forces experienced by planets. Through these trials, I recorded data that supported several conclusions
Firstly, I observed that the sun's mass directly influences the orbital paths of planets. Planets closer to the sun experience stronger gravitational forces, leading to faster orbital speeds and shorter orbital periods. In contrast, planets farther from the sun have slower orbital speeds and longer orbital periods. This data confirms Kepler's laws of planetary motion, which state that the square of a planet's orbital period is directly proportional to the cube of its average distance from the sun.
Secondly, the sun's mass affects the stability of planetary systems. A more massive sun exerts stronger gravitational forces, providing stability by preventing planets from being pulled out of their orbits. The recorded data revealed that planets in systems with a less massive sun tended to have unstable orbits, resulting in irregular paths and potential ejections from the system.
Lastly, the sun's mass influences the overall structure of planetary systems. Higher-mass stars tend to form larger and more massive planets, as the gravitational forces they exert allow for the accumulation of larger amounts of planetary material. The data collected during the trials supported this conclusion, demonstrating a correlation between the mass of the sun and the sizes and masses of the planets in the system.
The recorded data from the terrain-forming trials provided empirical evidence supporting these conclusions, highlighting the significant impact of the sun's mass on the planets it governs.
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A group of students are doing a reading activity in their classroom. They suddenly hear the noise of a truck in the parking lot of their school. They can hear it but cannot see it. Which of the following explains why they can hear the truck, but cannot see it?
Answer:
The answer is the sound waves can travel through some material (not all) and visible light cannot.
Explanation:
I did this question on study island so I know the answer.
Answer:
the answer is: sound can be transmitted through the walls, but visible light cannot.
Explanation:
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sciencephysicsphysics questions and answersa 6.50 μf capacitor that is initially uncharged isconnected in series with a 4500 ω resistor and a503 v emf source with negligible internal resistance.a)just after the circuit is completed, what is the voltagedrop across the capacitor? vc= vb)just after the circuit is completed, what is the voltagedrop across the resistor?
Question: A 6.50 ΜF Capacitor That Is Initially Uncharged Isconnected In Series With A 4500 Ω Resistor And A503 V Emf Source With Negligible Internal Resistance.A)Just After The Circuit Is Completed, What Is The Voltagedrop Across The Capacitor? Vc= Vb)Just After The Circuit Is Completed, What Is The Voltagedrop Across The Resistor?
A 6.50 μF capacitor that is initially uncharged isconnected in series with a 4500 Ω resistor and a503 V emf source with negligible internal resistance.
a)Just after the circuit is completed, what is the voltagedrop across the capacitor?
Vc= V
b)Just after the circuit is completed, what is the voltagedrop across the resistor?
VR = V
c)Just after the circuit is completed, whatis the charge on the capacitor?
Qo= C
d)Just after the circuit is completed, whatis the current through the resistor?
IR= A
e)A long time after the circuit is completed(after many time constants), what are the values of the precedingfour quantities?
Vc, V R, I,Q= V, V, A, C
The voltage across the capacitor (Vc) will be equal to the emf of the source (V) which is 503 V, the voltage drop across the resistor ([tex]V_R[/tex]) will be zero, the current through the resistor ([tex]I_R[/tex]) will be 0.112 A, and the charge on the capacitor (Q) will be at its maximum value (Q = CV).
a) Just after the circuit is completed, the voltage drop across the capacitor (Vc) is equal to the emf of the source (V). Therefore, Vc = V = 503 V.
b) Just after the circuit is completed, the voltage drop across the resistor ([tex]V_R[/tex]) is zero since the capacitor is initially uncharged and behaves like a open circuit. Therefore, [tex]V_R = 0 V[/tex].
c) Just after the circuit is completed, the charge on the capacitor (Q₀) is zero since the capacitor is initially uncharged. Therefore, Q₀ = 0 C.
d) Just after the circuit is completed, the current through the resistor ([tex]I_R[/tex]) can be calculated using Ohm's Law:
[tex]I_R[/tex] = V / R = 503 V / 4500 Ω ≈ 0.112 A
e) A long time after the circuit is completed (after many time constants), the capacitor will be fully charged and behave like an open circuit. The charge on the capacitor (Q) will be at its maximum value (Q = CV).
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The distance between two cities A and B is 180 km. a car moved from the city A towards the city :
with a velocity of 25 Km/hr , at the same moment another car moved from the citv B towards the city A with a uniform velocity of 65 Km/hr. Then: when and where do the two cars meet?
The two cars will meet at a distance of 50 km from city A, and the meeting will occur 2 hours after they start moving.
To determine when and where the two cars meet, we need to calculate the time it takes for them to meet and then use that time to find the meeting location.
In this case:
Distance between cities A and B = 180 km
Velocity of the car starting from city A = 25 km/hr
Velocity of the car starting from city B = 65 km/hr
Let's assume the meeting point is at a distance of x km from city A. Since the total distance between the two cities is 180 km, the distance traveled by the car starting from city A is x km, and the distance traveled by the car starting from city B is (180 - x) km.
Using the formula:
Time = Distance / Velocity
The time taken by the car starting from city A to reach the meeting point is:
Time for car from A = x km / 25 km/hr = x/25 hr
The time taken by the car starting from city B to reach the meeting point is:
Time for car from B = (180 - x) km / 65 km/hr = (180 - x)/65 hr
Since the two cars meet at the same time, we can set their time equations equal to each other:
x/25 = (180 - x)/65
Now, we can solve this equation to find the value of x:
65x = 25(180 - x)
65x = 4500 - 25x
90x = 4500
x = 50
Therefore, the meeting point is 50 km from city A.
To find the time it takes for the cars to meet, we can substitute this value of x back into either of the time equations:
Time = Distance / Velocity
Time = 50 km / 25 km/hr
Time = 2 hours
So, the two cars will meet after 2 hours.
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Two objects collide elastically. The first has a mass of 5.00kg and a
velocity of 8.00 m/s. The second has a mass of 2.50 kg and a velocity
of -4.00m/s. If the velocity of object 1 after the collision is -4.00m/s,
what is the velocity of object 2?
Answer:
Explanation:
General formula
m1 * vi + m2*v2 = m1*v3 + m2*v4
Givens
m1 = 5
m2 = 2.5
v1 = 8 m/s
v2 = - 4 m/s
v3 = -4 m/s
v4 = x
Solution
5 * 8 - 2.5 * 4 = 5 * -4 + 2.5*x
40 - 10 = -20 + 2.5x
30 = - 20 + 2.5x
50 = 2.5x
x = 50/2.5
x = 20 m/s in the positive direction
Remark
Does this answer make sense? It should. You have 5 kg moving 8m/s in the plus direction. That's a lot of momentum. In addition after the collision, it turns around which is more momentum needed.
It has to give up that extra momentum to the 2.5 kg mass.
Which of the following describes half-life? Choose which apply.
A. Half-life is the amount of time it takes for half of a sample to decay.
B. The shorter the half-life, the more unstable the nuclide.
C. Half-life cannot be calculated for nuclides.
D. The longer the half-life, the more stable the nuclide
Answer:
дангггггггггггггггггггггггггггггггггггггггггггггг
Answer: D.
Explanation: I took the test
basketball center steve tootall is 7 feet 2 inches in height. what is steve’s height in inches?
Steve Tootall's height is 86 inches. To calculate his height in inches, we convert feet to inches and then add the remaining inches.
Steve Tootall's height is given as 7 feet 2 inches. To calculate his height in inches, we convert feet to inches and then add the remaining inches.
1 foot is equal to 12 inches. So, 7 feet would be 7 * 12 = 84 inches.
Adding the remaining 2 inches, Steve's height in inches would be:
84 inches + 2 inches = 86 inches.
Therefore, Steve Tootall's height is 86 inches.
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assume+that+kish+inc.+hired+you+as+a+consultant+to+help+estimate+its+cost+of+capital.+you+have+obtained+the+following+data:+d0+=+$0.90;+p0+=+$47.50;+and+g+=+7.00%
The cost of capital is the rate of return on a firm's investments that must be earned to meet the cost of financing. The cost of capital refers to the opportunity cost of making a specific investment. This opportunity cost is the rate of return that could have been earned by placing the same capital into a different investment that has equivalent risk.
Consultant is a professional who provides expert advice in a specific area such as management, accounting, human resources, and information technology. They provide guidance to an organization to assist them in improving their performance or solving particular problems.
The components of the cost of capital are the cost of debt and the cost of equity. Cost of DebtCost of debt is the interest rate that a firm pays on its debt. It is calculated as follows: Cost of debt = (Interest rate) x (1 - Tax rate)Here, D0 = $0.90, P0 = $47.50, and G = 7.00%.The current dividend is D0.
The next dividend is calculated as follows:D1 = D0 (1 + G) = $0.90 (1 + 0.07) = $0.963Dividend yield can be calculated as follows:Dividend yield = D1 / P0= $0.963 / $47.50= 0.0203 = 2.03%.
The cost of equity can be calculated using the following formula: Cost of Equity = (Dividend Yield) + (Growth Rate of Dividends).
Cost of Equity = 2.03% + 7.00% = 9.03%.
The cost of capital for Kish Inc. is the weighted average of the cost of debt and the cost of equity.
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It is observed that 55.00 mLmL of water at 20∘C∘C completely fills a container to the brim. When the container and the water are heated to 60∘C∘C, 0.35 gg of water is lost.
What is the coefficient of volume expansion of the container? Density of water at 60 ∘C∘C is 0.98324 g/mLg/mL.
The coefficient of volume expansion of the container is 1.64 x 10⁻⁴ °C⁻¹.
Initial volume of water, V₁ = 55 mL
Initial temperature of the water, T₁ = 20°C
Final temperature of the water, T₂ = 60°C
Density of water at 60°C, d = 0.983 g/mL
Mass of water lost during heating, m = 0.355 g
The change in volume of water is,
ΔV = m/d
ΔV = 0.355/0.983
ΔV = 0.361 mL
Volume expansion occurs when a solid, whether it be in the form of a cube, cuboid, sphere, or another shape, rises in volume as a result of heating.
The expression for the coefficient of volume expansion of the container is given by,
α = ΔV/VΔT
α = 0.361/[55 x (60 - 20)]
α = 0.361/(55 x 40)
α = 0.361/2200
α = 1.64 x 10⁻⁴ °C⁻¹
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Jenise is buying a car for $7,020. The TAVT rate is 9.1%.
What is the amount of tax that Jenise will have to pay on her car?
Answer:
$7,658.82
Explanation:
Sales Tax Calculations:
Sales Tax Amount = Net Price x (Sales Tax Percentage / 100)
Total Price = Net Price + Sales Tax Amount
Net Price: $ 7,020.00
+Sales Tax (9.1%): $ 638.82
Total Price: $ 7,658.82
Therefore, the amount of tax that Jenise has to pay on her car is $7,658.82
If it is known that a motor battery has an input voltage of 12V and a capacity of 6 Ah, how much power and resistor value is required to turn on 8 lamps with a parallel circuit, with the specifications of each lamp having a maximum voltage of 3V and an electric current of 140 mA? How long did all the lights go on until they off?
Answer:
Part A
The power to turn on the lamp, ∑P = 3.36 W
Part B
The Resistor required is approximately 8.04 Ohms
Part C
The time for all the lights to go out is approximately 21.43 hours
Explanation:
The input voltage of the motor battery , V = 12 V
The capacity of the battery, Q = 6 Ah
The number of lamps in parallel = 8 lamps
The maximum voltage of each lamp, = 3 V
The electric current in each lamp = 140 mA
The energy available in a battery, E = Q × V
For the battery, we have;
E = 6 Ah × 12 V = 72 Wh
The energy available in a battery, E = 72 Wh
Part A
The power used by the lamps, [tex]P_i[/tex] = [tex]I_i[/tex] × [tex]V_i[/tex]
∴ The total power used by the lamp, ∑P = 8 × 0.14 A × 3 V = 3.36 W
The power to turn on the lamp, ∑P = 3.36 W
Part B
The resistance required, is given as follows;
Resistor required = (Battery voltage - Lamp voltage)/(The sum of bulb current)
∴ Resistor required = (12 V - 3 V)/(8 × 0.14 A)
The Resistor required = 8.03571429 Ohms
The Resistor required ≈ 8.04 Ohms
Part C
The time for all the lights to go out = The time for the lamps to use all the power available in the battery
The time for all the lights to go out, t = E/∑P
∴ t = 72 Wh/(3.36 W) = 21.4285714 h
∴ The time for all the lights to go out, t ≈ 21.43 h
The time for all the lights to go out = The time for the lamps to use all the power available in the battery = t ≈ 21.43 h
∴ The time for all the lights to go out ≈ 21.43 hours.
A box m=87 kg is being pulled by a constant force F=124 N at an angle of θ =43 degrees. The initial speed of the box is zero. A 33\% Part (a) Write an expression for the work done by force F as the block moves a horizontal distance d. A3\% Part (b) How much work, in joules, was done in moving the block 4.1 m ? A 33% Part (c) What is the speed of the box at d=4.I m if the surface is frictionless?
Part (a) involves writing an expression for the work done by force F as the box moves a horizontal distance d. Part (b) requires calculating the amount of work done in moving the box 4.1 m. Part (c) asks for the speed of the box at a distance of 4.1 m, assuming a frictionless surface.
(a) The work done by a force is given by the formula W = Fd cos(θ), where W represents work, F is the force applied, d is the distance moved, and θ is the angle between the force and the displacement. In this case, since the force is applied horizontally ([tex]\theta[/tex] = 0), the expression for the work done by force F becomes W = Fd cos(0) = Fd.
(b) To calculate the work done in moving the box 4.1 m, we can substitute the given values into the equation from part (a). Thus, the work done is W = (124 N)(4.1 m)(cos 0) = 124 N * 4.1 m = 508.4 J (joules).
(c) If the surface is frictionless, the work done is converted entirely into kinetic energy. We can use the work-energy principle to find the speed of the box. The work done (508.4 J) is equal to the change in kinetic energy. Assuming the initial speed is zero, the final kinetic energy is 508.4 J. We can calculate the speed using the equation [tex]KE = (1/2)mv^2[/tex], where KE is the kinetic energy, m is the mass, and v is the speed. Rearranging the equation, [tex]v = \sqrt(2KE/m)[/tex]. Given the mass m = 87 kg, the speed at d = 4.1 m can be calculated.
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An electron and a proton are both released from rest, midway between the plates of a charged parallel-plate capacitor. The only force on each of the two particles is the force from the uniform electric field due to the capacitor. Each particle accelerates until striking one of the plates of the capacitor. (There is no gravity in this problem and we ignore the small force between the electron and the proton.) How do the final kinetic energies and final speeds (just before striking a plate) compare
Answer:
Explanation:
Let the potential difference between the middle point and one of the plate be ΔV .
electric potential energy will be lost and it will be converted into kinetic energy .
Electrical potential energy lost = Vq , where q is charge on charge particle .
For proton
ΔV× q = 1/2 M V² ( kinetic energy of proton )
where M is mass and V be final velocity of proton .
For electron
ΔV× q = 1/2 m v² ( kinetic energy of electron )
where m is mass and v be final velocity of electron . Charges on proton and electron are same in magnitude .
As LHS of both the equation are same , RHS will also be same . That means the kinetic energy of both proton and electron will be same
1/2 M V² = 1/2 m v²
(V / v )² = ( m / M )
(V / v ) = √ ( m / M )
In other words , their velocities are inversely proportional to square root of their masses .
(a) Does the index of refraction vary as you change the wavelength of light. (B) What is the angle of the ray that leaves the glass square (emergent ray) relative to the ray that enters it? (c) What can you say about the path of emergent ray relative to that of the incident ray?
(a) Yes, the index of refraction varies with the wavelength. (b) The emergent ray is refracted at a different angle. (c) The path of the emergent ray deviates from the incident ray.
(a) Yes, the index of refraction varies as you change the wavelength of light.
The index of refraction (n) of a material is a measure of how much the speed of light is reduced when it passes through that material compared to its speed in a vacuum.
The index of refraction is wavelength-dependent and typically varies slightly with different wavelengths of light. This phenomenon is known as dispersion.
One way to express this variation is through the refractive index as a function of wavelength, often represented by a refractive index versus wavelength graph.
In general, different wavelengths of light are bent or refracted by different amounts when passing through a medium due to their interaction with the material's atoms or molecules.
This bending is a result of the change in the speed of light, which is dictated by the refractive index.
The index of refraction does vary as you change the wavelength of light. This variation is responsible for phenomena like dispersion, where different colors of light are separated when passing through a prism, for example.
(b) The angle of the emergent ray leaving a glass square relative to the incident ray depends on the angle of incidence and the refractive index of the glass.
According to Snell's law, the relationship between the angle of incidence (θ₁), the angle of refraction (θ₂), and the refractive indices of the two media involved can be expressed as:
n₁ * sin(θ₁) = n₂ * sin(θ₂)
In the case of a glass square, let's assume light is incident on one of its faces. If we know the angle of incidence (θ₁) and the refractive index of the glass (n₂), we can calculate the angle of the emergent ray (θ₂) using Snell's law.
The angle of the emergent ray leaving the glass square relative to the incident ray depends on the angle of incidence and the refractive index of the glass, and it can be calculated using Snell's law.
(c) The path of the emergent ray relative to the incident ray can be different due to refraction.
When light passes from one medium to another, it changes direction due to the change in its speed caused by the change in the refractive index. This change in direction is called refraction. Therefore, the emergent ray may have a different direction compared to the incident ray.
The emergent ray will still follow the law of refraction (Snell's law) and will be bent towards or away from the normal depending on the refractive indices of the two media involved and the angle of incidence.
The amount of bending depends on the difference in refractive indices and the angle at which the light strikes the boundary between the two media.
The path of the emergent ray relative to the incident ray can be different due to refraction, as the emergent ray changes direction upon passing from one medium to another.
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Please help me with 17 and 18!!!!!! (It's related to 16) It's due today!!!!! NO LINK PLEASE!!!!!!!!
Answer:17: A wave can be defined as follows: It is important to realize that a wave is quite a different object than a particle. A baseball thrown though a window transfers energy from one point to another, but this involves the movement of a material object between two points.
Explanation:
18: In this way, we classify waves into electromagnetic and mechanical waves. The main difference between mechanical and electromagnetic waves is that electromagnetic waves do not require a medium to propagate whereas mechanical waves require a medium in order to propagate.
PLS HELP MEEEE (NO LINKS PLEASE)
The difference between visible light and gamma rays is that
a.
the amplitude of visible light is greater.
c.
they travel through a different medium.
b.
the speed of gamma rays is greater.
d.
the frequency of gamma rays is greater.
Answer:
Gamma rays occupy the short-wavelength end of the spectrum; they can have wavelengths smaller than the nucleus of an atom. Visible light wavesare one-thousandths the width of human hair--about a million times longer than gamma rays. Radio waves, at the long-wavelength end of the spectrum, can be many meters long.
Answer:D "the frequency of gamma rays is greater."
Explanation:Trust
an iron anchor of density 7810.00 kg/m3 appears 152 n lighter in water than in air. (a) what is the volume of the anchor? (b) how much does it weigh in air
The volume of the anchor is approximately 0.0195 m^3. The weight of the anchor in air is approximately 1492 N.
To find the volume of the anchor, we can use Archimedes' principle, which states that the buoyant force experienced by an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
Given that the anchor appears 152 N lighter in water than in air, we can equate this weight difference to the buoyant force experienced by the anchor in water.
Weight difference = Buoyant force
= Weight in air - Weight in water
Let's assume the weight of the anchor in air is W_air and the weight of the anchor in water is W_water.
W_air - W_water = 152 N
We know that weight = mass × acceleration due to gravity (W = m × g), and density is defined as mass divided by volume (ρ = m/V), where ρ is the density, m is the mass, and V is the volume.
Therefore, W_air = ρ_anchor × g × V × (1), and
W_water = ρ_water × g × V × (2).
Given that the density of water, ρ_water, is 1000 kg/m^3, and the density of the anchor, ρ_anchor, is 7810.00 kg/m^3, we can substitute these values into equations (1) and (2):
7810.00 × g × V - 1000 × g × V = 152
Simplifying the equation:
6810.00 × g × V = 152
V = 152 / (6810.00 × g)
Using the standard acceleration due to gravity, g = 9.8 m/s^2:
V = 152 / (6810.00 × 9.8)
≈ 0.0195 m^3
Therefore, the volume of the anchor is approximately 0.0195 m^3.
To calculate the weight of the anchor in air, we can use the formula:
Weight in air = ρ_anchor × g × V
Substituting the values:
Weight in air = 7810.00 × 9.8 × 0.0195
≈ 1492 N
Therefore, the weight of the anchor in air is approximately 1492 N.
The volume of the anchor is approximately 0.0195 m^3, and its weight in air is approximately 1492 N.
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A 29 kg child jumps to the ground from the top of a fence that is 1.8 m high. You analyze the problem using upward as the positive x direction.
A. Taking x=0 to be at the bottom of the fence, what are the initial potential energy of the child-Earth system and the chnage in the system kinetic energy during the jump? (Ui , change of U)
B.Repeat the previous part for x=0 at the top of the fence (Ui , change of U)
The initial potential energy of the child-Earth system is 509.4 J, and the change in system kinetic energy during the jump is 509.4 J.
In the first scenario, with x=0 at the bottom of the fence, we can calculate the initial potential energy (Ui) using the formula Ui = mgh, where m is the mass of the child (29 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the fence (1.8 m). Substituting the values, Ui = 29 kg × 9.8 m/s^2 × 1.8 m = 509.4 J.
Since there is no external work done on the child during the jump, the change in system kinetic energy (change of U) is equal to the negative of the initial potential energy. Therefore, the change of U = -509.4 J.
In the second scenario, with x=0 at the top of the fence, the initial potential energy (Ui) is still the same, i.e., 509.4 J. However, since the child is starting from a higher position, the change in system kinetic energy (change of U) will be different. The change of U will still be equal to -509.4 J since it depends on the initial potential energy, regardless of the reference point.
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12. Which of the following statements is accurate?
A. If an object's velocity is changing, it's experiencing either acceleration or deceleration.
B. If an object's velocity decreases, then the object is accelerating
C. If an objects said to be decelerating, its velocity must be increasing,
D. If an object's velocity remains constant, its acceleration must be increasing.
Answer:
Option (a) is correct
Explanation:
The acceleration of an object is defined as the rate of change of velocity. Mathematically, it can be written as :
[tex]a=\dfrac{v-u}{t}[/tex]
Where
v and u are final and initial velocity
It is clear that if there is some change in velocity, it means the object is experiencing either acceleration or deceleration. Hence, the correct option is (a).
Answer:
a
Explanation:
Purpose:You will use the radioactive decay rate and original-daughter element ratios of carbon-14and uranium-238 to determine the ages of different objects.
Procedure:1.Load PhET Radioactive Dating Game
2.Click on the tab for Decay Rates
3.Select Carbon-14.Using the graph, the estimated half-life for C-14 is5,200years.
4.Move the bucket slider all the way to the right.This will place 1000 C-14 atoms onto the screen.a.Click on the Start/Stop to stop the C-14 decay.Click on Reset All Nucleib.Click on theStart/Stop to start the C-14 decay.Stop the decay as you get close to one half-life.c.Use the Step button to stop decay at one half-life.After 1 half-life, how many C-14 atoms of the 1000 original remain?
After one half-life, the number of remaining C-14 atoms can be calculated by multiplying the initial number of atoms (1000) by 0.5 (since half of the atoms decayed).
Based on the given procedure, after one half-life of carbon-14 (C-14), the number of C-14 atoms remaining can be determined. Since the estimated half-life of C-14 is 5,200 years, we can use this information to answer the question. After one half-life, the number of remaining C-14 atoms can be calculated as half of the original number of C-14 atoms. Given that the initial number of C-14 atoms is 1000, after one half-life: Remaining C-14 atoms = (1/2) * 1000. Remaining C-14 atoms = 500
after one half-life of carbon-14 (C-14), the number of C-14 atoms remaining can be determined.
Therefore, after one half-life, 500 C-14 atoms of the 1000 original atoms remain.
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How much work is done when a car is moved 10 m with a force of 3.4 N?
Answer:
34J I assume
Explanation:
force×distance is work done. 10×3.4 is 34. therefore its 34 joules of work done
Answer:
34J
Explanation:
The formula for work is W=Force x Distance
W=FxD
F=3.4N
D=10m
W=10x3.4
W=34 Joules
Is O2 classified as a compound?
Answer: NO.
Explanation: Oxygen is not a compound. It has only one element in it.
what is the velocity of a car that traveled 6 meters in .96 seconds
The velocity of the car is approximately 6.25 meters per second.
To determine the velocity of a car that traveled 6 meters in 0.96 seconds, we can use the formula for velocity: velocity = distance / time. In this case, the distance traveled is 6 meters and the time taken is 0.96 seconds.
Plugging these values into the formula, we have:
velocity = 6 meters / 0.96 seconds
= 6.25 meters per second.
Velocity is a measure of the rate at which an object changes its position. In this context, the car is traveling at a constant speed of 6.25 meters per second. It means that for every second that passes, the car moves 6.25 meters forward.
It's important to note that velocity is a vector quantity, meaning it has both magnitude (the numerical value) and direction. However, in this scenario, we were only given the distance and time, so we calculated the magnitude of the velocity.
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