The function f(x) = In(x) has a domain of all real numbers greater than zero and a range of all real numbers. The
inverse of this function is f^-1(x) = e^x

Which conclusion can be drawn by comparing the two functions?

The domain of f^-1(x) is all real numbers and the range is all real numbers.

The domain of f^-1(x) is all real numbers greater than 0 and the range is all real numbers.


The domain of f^-1(x) is all real numbers and the range is all real numbers greater than 0.


The domain of f^-1(x) is all real numbers greater than 0 and the range is all real numbers greater than 0.

Answer: y= 1/2x + 7

Step-by-step explanation:

Answer: IJ = 15

J

15. x

H. I

14

Two congruent Angles —-> Isosceles Triangle

Opposite sides must be congruent.

J

15 15

H. I

14

Answer:

B

Step-by-step explanation:

If you go to -4, 0 the line intersects that point

Answer:

(2,11)

Step-by-step explanation:

what i did was actually substitution

It's like ..what I do when I've forgotten how to solve a particular equation in math or even physics

But I'd recommend you find the real solution cuz there's a formula

The correct word form of 8.16 is b. eight and sixteen hundredths

Since the number is 8.16, we have 8.16 = 8 + 0.16 = 8 + 16/100

Since we have 8 in the units place, it is pronounced eight.

Also, we have our decimal part 0.16 = 16/100 which is pronounced as sixteen hundredths.

So, combining both we have eight and sixteen hundredths.

So, the correct word form of 8.16 is b. eight and sixteen hundredths

Learn more about decimals here:

https://brainly.com/question/8829988

Answer:

Uuuuh thats kind of suspicious, maybe you could post your question without  a link? But links are usually scams, so dont do that :)

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation that goes through (5,4) and (10,2)

[tex](\stackrel{x_1}{5}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{5}}}\implies \cfrac{-2}{5} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{2}{5}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{5}{2}}\qquad \stackrel{negative~reciprocal}{+\cfrac{5}{2}\implies \cfrac{5}{2}}}[/tex]

Answer:

Step-by-step explanation:

f(x) = 2x + 1

g(x) = ?

h(x) = ln(x)

hgf(x) = ½ln(2x - 3)

All h(x) does is take a natural log of a number, therefore the output

gf(x) = [tex]\sqrt{2x - 3}[/tex]

the change between f(x) and fg(x) is a subtraction of 4 then raising the result to a power of ½.

g(x) = [tex]\sqrt{x - 4}[/tex]

Answer:

Measure of Angle B = 25°

Step-by-step explanation:

Something to keep in mind: Angle A and B are Vertical Angles so they will always be equal

so;

Angle A = Angle B

(4x + 5) = (-2(x - 17.5))

4x + 5 = -2x + 35   (<= Solved by distributive property)

6x + 5 = 35

6x = 30

x = 5

Now we can find the measure of Angle B, by substituting x by 5 in the B equation;

-2 (x - 17.5) = Angle B

-2 (5 - 17.5) = Angle

-2 (-12.5) = Angel B

25 = Angle B

so measure of angle B = 25

Hope this helps!

Answer: 12% of people responded as City D

Answer:

Solution:

3/7x = 12

3/7x ÷ 3/7 = 12 ÷ 3/7 ( divide 3/7 in both sides )

x = 12 ÷ 3/7 (divide)

x = 84/3 (simply divide 84 and 3)

x = 28

_______________________

(solution for dividing the fraction and the whole number 12 and 3/7, for those who don't know how to divide fractions and whole numbers...)

12/1 ÷ 3/7

12/1 ÷ 7/3 (reciprocal method)

12/1 × 7/3 (change operation to multiplication)

12/1 × 7/3 = 84/3 (multiply)

84/3 ⇒ 28 (simplify)

Answer:

p = 0.07

p-hat = 0.035

p0 = 0.07

p-value = 0.003

Step-by-step explanation:

p = population parameter, in this case, the rate of infestations across all trees in the forest

p-hat = test statistic, in this case, the rate of infestations found in the sample of trees, i.e. those in Doug's backyard

p0 = the null hypothesis, in this case, the rate of infestations within the forest is correctly evaluated at 0.07 or 7%

p-value = the likelihood any difference between p and p-hat is down to chance

In this case 0.003 as the p-value means there is only 0.3% probability of our statistic value of 0.035 being down to variability and chance meaning it is 99.7% likely that there is some reason behind this difference;

We would accept the alternative hypothesis which says the current parameter value, 0.07, is in fact incorrect (either too high or too low, in this case, likely too high).

Answer:

5.62790697674

Step-by-step explanation:

there you go

Answer:

the annswer is 5

Step-by-step explanation: you just have to divide the highlighted numbers, which are 20 ÷ 5

Answer:

Jill plz tell if i am right

Step-by-step explanation:

give me schoology website

Answer:

.

Step-by-step explanation:

Answer:

Answer ️️

Step-by-step explanation:

5.1÷104 = 4.903846154

Answer:

xd

Step-by-step explanation:

3X+4y=8

this is the graph that represents the solution

Answer:

Do in calculator simple answer

Answer:

Step-by-step explanation:

Initial class size = 30 students

Class size now is 40% larger:

First let's find larged amount

[tex]\\ \sf\longmapsto 40\%\:of\:30[/tex]

[tex]\\ \sf\longmapsto 0.4(30)[/tex]

[tex]\\ \sf\longmapsto 12[/tex]

Class size=30+12=42students

Answer:

OOO

OOO

OO

Step-by-step explanation:

Where OOO is == 1.

OO is 2/3 of OOO.

Answer:

c

brainlest

Step-by-step explanation:

[tex]6x^2-x=2\implies 6x^2-1x-2=0 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{6}x^2\stackrel{\stackrel{b}{\downarrow }}{-1}x\stackrel{\stackrel{c}{\downarrow }}{-2}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}[/tex]

[tex]x = \cfrac{ -(-1) \pm \sqrt { (-1)^2 -4(6)(-2)}}{2(6)}\implies x = \cfrac{1\pm\sqrt{1+48}}{12} \\\\\\ x = \cfrac{1\pm\sqrt{49}}{12}\implies x = \cfrac{1\pm 7}{12}\implies x = \begin{cases} \frac{8}{12}\to &\frac{2}{3}\\[1em] -\frac{6}{12}\to &-\frac{1}{2} \end{cases}[/tex]

Answer:

Your tip is $15.00

Step-by-step explanation:

Have a nice day ^^

Answer:

[tex]\huge\colorbox{blue}{A}\huge\colorbox{orange}{N}\huge\colorbox{gray}{S}\huge\colorbox{red}{W}\huge\colorbox{yellow}{E}\huge\colorbox{purple}{R}[/tex]

hitsss

Step-by-step explanation:

subject arts and architecture what primary

Check the picture below.

notice, we have three pair of sides, let's add them all up to get the area

[tex]\stackrel{\textit{left and right}}{2(8\cdot 14)}+\stackrel{\textit{front and back}}{2(3.5\cdot 8)}+\stackrel{\textit{top and bottom}}{2(3.5\cdot 14)}\implies 378~in^2[/tex]

Answer:

-5x + 3

Step-by-step explanation:

1/3 x - 4x -5/3x + 1/3 x +3

2/3 x -4 -5/3x + 3

3/3x -4x +3

-1 1x -4x + 3

- 5x + 3

:)

Answer:

B

d(P,Q) = sqrt((xO-xQ)^2 + (yP-yQ)^2) = sqrt(16+9) = 5

There are 100 numbers in the range 100-199. Find the smallest and largest multiple of 13 in this range. We have

104 = 8•13

195 = 15•13

so there are 15 - 8 + 1 = 8 multiples of 13 between 100 and 199.

Then the sum we want is

[tex]\displaystyle \sum_{k=100}^{199} k - \sum_{\ell=8}^{15}13\ell[/tex]

or equivalently,

(100 + 101 + 102 + … + 199) - 13 (8 + 9 + … + 15)

To compute these sums, recall the following formula:

[tex]\displaystyle \sum_{i=1}^n i = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2[/tex]

Then

[tex]\displaystyle \sum_{k=100}^{199} k = \sum_{k=1}^{199} k - \sum_{k=1}^{99} k = \frac{199\cdot200}2 - \frac{99\cdot100}2 = 14,950[/tex]

and

[tex]\displaystyle \sum_{\ell=8}^{15} 13\ell = 13 \left(\sum_{\ell=1}^{15} \ell - \sum_{\ell=1}^7 \ell\right) = 13 \left(\frac{15\cdot16}2 - \frac{7\cdot8}2\right) = 1,196[/tex]

which means the sum we want is 14,950 - 1,196 = 13,754.

Answer:

.25

Step-by-step explanation: