The solubility of silver carbonate in water is approximately 1.26 × 10⁻³ mol/L. The solubility of silver carbonate in 0.22 M AgClO₃ is approximately 2.92 × 10⁻⁵ mol/L. The solubility of silver carbonate in 0.41 M Na₂CO₃ is approximately 1.20 × 10⁻⁶ mol/L.
To calculate the solubility of silver carbonate (Ag₂CO₃) in different solutions, we need to compare the solubility product (Ksp) with the concentrations of relevant ions in the solution. The balanced equation for the dissociation of silver carbonate is:
Ag₂CO₃(s) ⇌ 2Ag⁺(aq) + CO₃²⁻(aq)
(a) Solubility in water:
Since water does not contain any common ions, the concentration of Ag⁺ and CO₃²⁻ ions in water is initially zero. Therefore, we assume x as the solubility of Ag₂CO₃ in mol/L.
The equilibrium concentrations of Ag⁺ and CO₃²⁻ ions are both 2x (as the stoichiometric ratio is 1:1).
The Ksp expression is:
Ksp = [Ag⁺]²[CO₃²⁻] = (2x)²(2x) = 8x⁵
Since the Ksp is given as 8.1 × 10⁻¹², we can set up the equation:
8x⁵ = 8.1 × 10⁻¹²
Solving for x, we find:
x = (8.1 × 10⁻¹² / 8)^(1/5) ≈ 1.26 × 10⁻³ mol/L
Therefore, the solubility of silver carbonate in water is approximately 1.26 × 10⁻³ mol/L.
(b) Solubility in 0.22 M AgClO₃:
In this case, the Ag⁺ ions are already present in the solution due to the presence of AgClO₃. The concentration of Ag⁺ is given as 0.22 M. Since the Ksp expression is [Ag⁺]²[CO₃²⁻], we assume x as the solubility of Ag₂CO₃ in mol/L.
The equilibrium concentration of Ag⁺ ions will be 0.22 + 2x, and the concentration of CO₃²⁻ ions will be 2x.
The Ksp expression is:
Ksp = (0.22 + 2x)²(2x) = 8x³ + 0.88x² + 0.088x
Since the Ksp is still 8.1 × 10⁻¹², we can set up the equation:
8x³ + 0.88x² + 0.088x = 8.1 × 10⁻¹²
Solving for x, we find:
x ≈ 2.92 × 10⁻⁵ mol/L
Therefore, the solubility of silver carbonate in 0.22 M AgClO₃ is approximately 2.92 × 10⁻⁵ mol/L.
(c) Solubility in 0.41 M Na₂CO₃:
In this case, the CO₃²⁻ ions are already present in the solution due to the presence of Na₂CO₃. The concentration of CO₃²⁻ is given as 0.41 M. Since the Ksp expression is [Ag⁺]²[CO₃²⁻], we assume x as the solubility of Ag₂CO₃ in mol/L.
The equilibrium concentration of Ag⁺ ions will be 2x, and the concentration of CO₃²⁻ ions will be 0.41 + 2x. The Ksp expression is then:
Ksp = (2x)²(0.41 + 2x) = 4x³ + 1.64x² + 0.328x²
Again, setting Ksp equal to 8.1 × 10⁻¹², we can solve for x:
4x³ + 1.64x² + 0.328x² = 8.1 × 10⁻¹²
x ≈ 1.20 × 10⁻⁶ mol/L
Therefore, the solubility of silver carbonate in 0.41 M Na₂CO₃ is approximately 1.20 × 10⁻⁶ mol/L.
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What mass Na2CO3 will completely react with 150 mL of 0.15 M HNO3?
a) write the balanced equation
b) construct the pathway of how you would approach the problem.
c) write out the calculation
d) calculate
a) Balanced equation:
2Na2CO3 + 2HNO3 -> 2NaNO3 + H2O + CO2
b) Pathway:
To determine the mass of Na2CO3 required to react with 150 mL of 0.15 M HNO3, we need to follow these steps:
Write the balanced equation to determine the stoichiometry between Na2CO3 and HNO3.
Convert the volume of HNO3 to moles using its molarity.
Use the stoichiometry from the balanced equation to determine the moles of Na2CO3 required.
Convert the moles of Na2CO3 to grams using its molar mass.
c) Calculation:
Given:
Volume of HNO3 = 150 mL = 0.150 L
Molarity of HNO3 = 0.15 M
Step 1: Balanced equation:
2Na2CO3 + 2HNO3 -> 2NaNO3 + H2O + CO2
Step 2: Convert volume of HNO3 to moles:
Moles of HNO3 = Volume (L) × Molarity
= 0.150 L × 0.15 M
= 0.0225 moles of HNO3
Step 3: Use stoichiometry to find moles of Na2CO3:
From the balanced equation, we can see that 2 moles of Na2CO3 react with 2 moles of HNO3.
Therefore, the moles of Na2CO3 required = 0.0225 moles of HNO3
Step 4: Convert moles of Na2CO3 to grams:
Molar mass of Na2CO3 = (2 × atomic mass of Na) + atomic mass of C + (3 × atomic mass of O)
= (2 × 22.99 g/mol) + 12.01 g/mol + (3 × 16.00 g/mol)
= 105.99 g/mol
Mass of Na2CO3 = Moles × Molar mass
= 0.0225 moles × 105.99 g/mol
= 2.384 g
d) Calculation:
The mass of Na2CO3 required to completely react with 150 mL of 0.15 M HNO3 is 2.384 grams.
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One tank of gold fish is fed the normal amount of food once a day. A second tank is fed twice a day. A third tank is fed four times a day during a six week study. The fish's weight is recorded daily. What is the problem and the hypothesis?
Answer:
Problem: What is the effect of the amount of fish feed on the mass of goldfish?
Hypothesis: I think that feeding the goldfish four times a day will greatest increase in the mass of the goldfish.
Explanation:
The problem tends to ask question to which the research is conducted. It open ways for ideas towards a particular topic.
While the hypothesis is a tentative or assumed stand on a subject. It is further tested through an experiment or survey and if after many trials it gives same results and the obtained results is concordant with the hypothesis, the hypothesis will then become accepted and a theory or law is formed thereafter.
What is Chemical bond ?
Answer:
Chemical bonding, any of the interactions that account for the association of atoms into molecules, ions, crystals, and other stable species that make up the familiar substances of the everyday world.
Explanation:
Have a nice day:)
Answer: A connection between two surfaces or objects that have been joined together, especially by means of an adhesive substance, heat, or pressure.
Explanation: The bond may result from the electrostatic force or attraction between oppositely charged icons as in iconic bonds or through the sharing of electrons as in covalent bonds.
consider the energy diagram for an exothermic reaction. what would you expect for the reverse reaction? a) to be exothermic and require the same activation energy b) to be endothermic and require the same activation energy c) to be endothermic and require a higher activation energy d) to be endothermic and require a lower activation energy e) to be exothermic and require a lower activation energy
Considering the energy diagram for an exothermic reaction, the expectations for the reverse reaction is: (c) The reverse reaction would be endothermic and require a higher activation energy.
In an exothermic reaction, the products have lower energy than the reactants, resulting in the release of energy. The energy diagram for an exothermic reaction typically shows a downward slope from the reactants to the products, with the energy of the products being lower than the energy of the reactants.
When considering the reverse reaction of an exothermic reaction, it would involve the conversion of products back into reactants. Since the energy diagram for the forward reaction shows a decrease in energy from reactants to products, the reverse reaction would be expected to have an increase in energy from products to reactants.
In the reverse reaction, energy would need to be absorbed from the surroundings, making it an endothermic process. Additionally, the activation energy for the reverse reaction is expected to be higher because the reverse reaction has to overcome a higher energy barrier to convert the products back into the reactants.
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assuming the compound is dissolved in water, what is the formula for phosphorous acid? name symbol phosphate phosphite phosphorus p h3p h3po4 hp h3po3
The formula for phosphorous acid is H₃PO₃. It can also be written as HPO(OH)₂, which is the hydrated form of the compound.
Phosphorous acid is a diprotic acid that contains one P(III) center and two -OH groups. It is a colorless and odorless solid that is highly soluble in water. When it is dissolved in water, it can act as a reducing agent because it can easily donate electrons. The formula for phosphate is PO₄³⁻. It is a polyatomic ion that contains one central phosphorus atom and four oxygen atoms arranged in a tetrahedral structure.
Phosphate has a negative three charge and is commonly found in minerals such as apatite. The formula for phosphite is PO₃³⁻. It is a polyatomic ion that contains one central phosphorus atom and three oxygen atoms arranged in a trigonal pyramidal structure. Phosphite has a negative two charge and is commonly used as a reducing agent and a chelating agent in chemical reactions involving metal ions.
The formula for phosphorus is P. It is a chemical element that has the atomic number 15 and the symbol P. Phosphorus is a nonmetal that is essential for life and is found in DNA, RNA, and ATP. It is also used in the production of fertilizers, detergents, and other industrial chemicals.
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why is the molar specific heat of a gas at constant pressure larger than the molar specific heat at constant volume?
Match the words in the left column to the appropriate blanks in the sentences on the right. options: on done by isochoric isobaric
volume pressure According to the first law of thermodynamics, the heat transferred to the gas equals the sum of the change in thermal energy and the work________ the gas. During an _______ process the work is zero. In process with a constant _________ with increasing temperature some energy leaves the system as work.
The heat transferred to the gas equals the total of the change in thermal energy and the work done on the gas, according to the first law of thermodynamics. During an isochoric process the work is zero. In process with a constant pressure with increasing temperature some energy leaves the system as work.
The heat provided to a gas (Q) equals the change in thermal energy (U) plus the work performed by the gas (W), as stated by the first law of thermodynamics. During an isochoric (constant volume) process, the work done by the gas is zero (W = 0) because there is no change in volume. In this case, all the heat energy transferred to the gas increases its thermal energy, resulting in a larger temperature increase and a larger molar specific heat at constant volume.
In a process with a constant pressure (isobaric), the gas can expand and do work against the external pressure. As the gas expands, it does work by pushing against the external pressure, and some of the heat energy is used to perform this work. Therefore, less heat energy is available to solely increase the thermal energy of the gas. This results in a smaller temperature increase compared to the constant volume process, leading to a smaller molar specific heat at constant pressure.
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Would glucose be considered a natural resource of synthetic product?
How much heat will be produced when 0.58 moles of
hydrogen peroxide (H2O2) decomposes? *
98 kJ + 2H,02(1) → 2H2O(l) + O2(g)
Answer:57.6 kJ
Explanation:
a polymer with which type of tacticity is expected to exhibit the lowest degree of crystallinity? atactic isotactic syndiotactic
A polymer which is expected to exhibit the lowest degree of crystallinity is an atactic tacticity (Option A).
What is tacticity?Tacticity is the configuration or spatial arrangement of monomer units in a polymer chain with respect to each other. It defines the regularity of the orientation of the pendant groups that are attached to the main chain of the polymer. Tacticity is a critical element that determines the physical and chemical properties of the polymer.
The three types of tacticities are atactic, isotactic, and syndiotactic. Atactic polymers have no specific tacticity because their pendant groups are randomly arranged with respect to each other. Since atactic polymers lack long-range order, they have the lowest degree of crystallinity.
Isotactic polymer have all of their pendant groups arranged in the same orientation, with respect to the main chain. As a result, these polymers have a high degree of crystallinity. Syndiotactic polymers have pendant groups that alternate in orientation along the main chain. The degree of crystallinity in syndiotactic polymers is moderate.
The degree of crystallinity for each type of polymer depends on the extent to which their pendant groups align, which affects their chain packing and orientation in the solid-state.
Thus, the correct option is A.
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Balanced Equations and Reaction Types. Write balanced, net ionic equations for each of the five reactions and, using the scheme outlined in the introduction, indicate the reaction type for each: redox, acid/base, or precipitation. Part 1: Cu(s) + 4 HNO_3(aq) rightarrow Cu(NO_3)_2(aq) + 2 NO_2(g) + 2 H_2O(l) Part 2: Cu(NO_3)_2(aq) + 2NaOH(aq) rightarrow Cu(OH)_2(s) + 2NaNO_3(aq) Part 3: Cu(OH)_2(s) rightarrow CuO(s) + H_2O(l) Part 4: CuO(s) + H_2SO_4(aq) rightarrow CuSO_4(aq) + H_2O(l) Part 5: Zn(.s) + CuSO_4(aq) rightarrow Cu(s) + ZnSO_4(aq)
Part 1: Cu(s) + 4 HNO₃(aq) ⇒ Cu(NO₃)2(aq) + 2 NO₂(g) + 2 H₂O(l) is a redοx reactiοn
Hοw dο yοu cοnstruct a reactiοn-specific balanced equatiοn?The reactants and prοducts are placed οn the left and right sides οf the arrοw, respectively, tο create a balanced equatiοn. Cοefficients, which appear as a number befοre a chemical fοrmula, represent mοles οf a cοmpοund. The number οf atοms in a single mοlecule is indicated by the subscripts (numbers belοw an atοm).
When catiοns and aniοns in an aqueοus sοlutiοn react tο generate a precipitate, an insοluble iοnic sοlid, precipitatiοn prοcesses take place. The sοlubility principles fοr typical iοnic sοlids can be used tο determine whether οr nοt such a reactiοn takes place.
Part 2: Cu(NO₃)₂(aq) + 2NaOH(aq) ⇒ Cu(OH)2(s) + 2NaNO₃(aq) is a dοuble displacement reactiοn οr a precipitatiοn reactiοn.
Part 3: Cu(OH)₂ (s) ⇒ CuO(s) + H₂O(l) is a Decοmpοsitiοn reactiοn
Part 4: CuO(s) + H₂SO₄(aq) ⇒ CuSO₄(aq) + H₂O(l) is an acid-base neutralizatiοn reactiοn.
Part 5: Zn(.s) + CuSO₄(aq) ⇒ Cu(s) + ZnSO₄(aq) is a displacement reactiοn
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consider a hydrogen atom in the ground state. what is the energy of its electron? = j now consider an excited‑state hydrogen atom. what is the energy of the electron in the =5 level?
The energy of an electron in a hydrogen atom can be determined based on its quantum state. In the ground state, the energy of the electron is -13.6 eV.
In a hydrogen atom, the energy of the electron is quantized, meaning it can only exist in certain discrete energy levels. The ground state is the lowest energy level, where the electron resides when it is not excited. The energy of the electron in the ground state is a well-known constant value of -13.6 eV.
When the hydrogen atom is excited to an excited state, such as the n=5 level, the energy of the electron in that level can be determined using the formula E = -13.6 eV/n^2. Here, n represents the principal quantum number, which corresponds to the energy level. Plugging in n=5 into the formula, we find that the energy of the electron in the n=5 level is -13.6 eV/5^2 = -0.544 eV.
In summary, the energy of an electron in a hydrogen atom depends on its quantum state. The ground state has an energy of -13.6 eV, while an excited state, such as the n=5 level, can be calculated using the formula E = -13.6 eV/n^2. For the n=5 level, the energy of the electron is -0.544 eV.
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Is riding the bus or riding a bike a quicker way to get to school?
TRUE OR FALSE
“Acids are electrolytes”
Answer:
True mark brainlest
Explanation:
For the reaction CH3 COOH → CH3 COO^- + H+, which statement is true?
O CH3 COO^- is a Brønsted-Lowry acid.
O CH3 COO^- is a conjugate base.
O CH3 COOH is a Brønsted-Lowry base.
O CH3 COO^- is an Arrhenius base.
In the given reaction CH3COOH → CH3COO^- + H+, the statement "CH3COO^- is a conjugate base" is true.The statement "CH3COO^- is a conjugate base" is true for the given reaction.
In the Brønsted-Lowry theory of acids and bases, an acid is a species that donates a proton (H+), while a base is a species that accepts a proton. In this reaction, CH3COOH donates a proton to form CH3COO^- and H+. The species that remains after the acid donates a proton is called the conjugate base.
In the reaction, CH3COOH acts as the acid by donating a proton, and CH3COO^- is the species that forms after the donation. Since CH3COO^- accepts the proton, it is considered the conjugate base of CH3COOH.
To determine whether a species is an acid or a base, we need to consider its behavior in a given reaction. In this case, CH3COOH donates a proton, making it the Brønsted-Lowry acid, while CH3COO^- accepts the proton, making it the conjugate base.
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Identify the variables that must remain constant to maintain an equilibrium constant and equilibrium position. : Color Variables that Must Remain Constant Variables that Do Not Need to Remain Constant : Concentration :
Equilibrium in a chemical reaction is reached when the rates of the forward and reverse reactions become equal. For a reversible reaction, the equilibrium constant is the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium.
The following variables need to remain constant for an equilibrium constant and position to remain constant:
Temperature: The temperature of the reaction vessel needs to remain constant. An increase in temperature would cause the forward reaction to speed up and the reverse reaction to slow down. As a result, the equilibrium constant would change. A decrease in temperature would cause the forward reaction to slow down and the reverse reaction to speed up, resulting in a change in the equilibrium constant. Pressure: For gaseous reactions, the pressure of the system must remain constant to maintain the equilibrium constant and position. A change in pressure would result in a shift in the equilibrium position to balance out the pressures. Concentration: The concentrations of the reactants and products must remain constant to maintain the equilibrium constant and position. A change in concentration would cause the equilibrium position to shift. For example, increasing the concentration of reactants would cause the equilibrium position to shift towards the products to consume the excess reactants. Colour: Color doesn't have any influence on the equilibrium constant and position, therefore, colour doesn't have to remain constant.know more about equilibrium constant
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Brainliest and a free hug :) thank you!!
The mass in a chemical reaction is found in
the energy produced by the reaction
the explosion produced by the chemical reaction
the atoms involved in the chemical reaction
the bonds involved in the chemical reaction
Answer:atoms involved in reaction. Mass remains same in reaction
Explanation: hug would be fine!
If 0.9% saline solution is isotonic to a cell, 0.5% saline solution Answers is hypertonic will cause crenation would result in water osmosing into the cell would result in water osmosing outside of the cell
If a 0.9% saline solution is isotonic to a cell, a 0.5% saline solution would be hypotonic. A hypotonic solution has a lower solute concentration compared to the cell. Hence, the correct answer is:
A 0.5% saline solution would result in water osmosing into the cell.
In a hypotonic solution, water tends to move from an area of lower solute concentration (outside the cell) to an area of higher solute concentration (inside the cell) in order to equalize the concentration on both sides. This can lead to an influx of water into the cell, potentially causing it to swell or burst (lysis) depending on the cell type.
It's important to note that a hypertonic solution has a higher solute concentration compared to the cell, which would result in water osmosing outside of the cell. In the given scenario, a 0.5% saline solution is hypotonic, not hypertonic. Therefore, the correct answer is:
A 0.5% saline solution would result in water osmosing into the cell.
The given question is incomplete and the completed question is given as,
If 0.9% saline solution is isotonic to a cell, 0.5% saline solution
Answers
is hypertonic will cause crenation would result in water osmosing into the cell would result in water osmosing outside of the cellLearn more about Osmosis from the link given below.
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If there are 27 grams of nitrogen dioxide at STP how many liters does this occupy?
Answer:
30 liters
Explanation:
an substance that is being dissolved by another object?
Answer:
Solute - The solute is the substance that is being dissolved by another substance. In the example above, the salt is the solute. Solvent - The solvent is the substance that dissolves the other substance.
Explanation:
Which of the following contains an element in a +1 oxidation state?CO2, PbO2, CaO, N2O5, Cu2O
The element Cu₂O (copper(I) oxide) contains a +1 oxidation state. Option E is correct.
This is because oxygen (O) typically has a -2 oxidation state, and since there are two oxygen atoms in Cu₂O, their combined oxidation state is -4. Therefore, in order for the compound to be electrically neutral, the oxidation state of copper must be +1.
CO₂ (carbon dioxide) contains carbon (C) in a +4 oxidation state and oxygen (O) in a -2 oxidation state.
PbO₂ (lead(IV) oxide) contains lead (Pb) in a +4 oxidation state and oxygen (O) in a -2 oxidation state.
CaO (calcium oxide) contains calcium (Ca) in a +2 oxidation state and oxygen (O) in a -2 oxidation state.
N₂O₅ (dinitrogen pentoxide) contains nitrogen (N) in a +5 oxidation state and oxygen (O) in a -2 oxidation state.
Hence, E. is the correct option.
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--The given question is incomplete, the complete question is
"Which of the following contains an element in a +1 oxidation state? A) CO₂, B) PbO₂, C) CaO, D) N₂O₅, E) Cu₂O
What is the number of particles after gluecose is mixed with water
Answer: dissolves
Explanation:
When you stir a spoonful of sugar into a glass of water, you are forming a solution. This type of liquid solution is composed of a solid solute, which is the sugar, and a liquid solvent, which is the water. As the sugar molecules spread evenly throughout the water, the sugar dissolves.
Complete and balance the following half-reaction in acidic solution
Sn²+(aq) → Sn** (aq)
The complete and balanced half-reaction for [tex]Sn^{2+}[/tex] → Sn** in the acidic solution can be given as follows: [tex]Sn^{2+}[/tex](aq) → [tex]Sn^{4+}[/tex](aq) + 2[tex]e^-[/tex] (oxidation half-reaction)
Here, [tex]Sn^{2+}[/tex] undergoes oxidation to [tex]Sn^{4+}[/tex]. In this reaction, the oxidation state of Sn changes from +2 to +4. It means Sn loses 2 electrons in this reaction. Hence, it is an oxidation half-reaction.
2[tex]H^+[/tex](aq) + 2e- → [tex]H_2[/tex](g) (reduction half-reaction)
This half-reaction represents the reduction of [tex]H^+[/tex] ions. In this reaction, [tex]H^+[/tex] ions gain 2 electrons to form [tex]H_2[/tex]. This reaction occurs in an acidic solution.
Therefore, to obtain a completely balanced reaction, we have to combine both half-reactions as follows:
[tex]Sn^{2+}[/tex](aq) + 2[tex]H^+[/tex](aq) → [tex]Sn^{4+}[/tex](aq) + [tex]H_2[/tex](g)
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seaborgium mass number =
Explanation:
seaborgium Is a type of corn that is grown in warm countries.
answer is SG
Answer:
269 u
Explanation:
A sample of milk is found to have arsenic at a concentration of 3.57 ug/L. What is the concentration in ounces per gallon? 1 qt 946.4 mL 1 gal 4 qt 16 oz- 1 lb 1 lb- 0.4536 kg A) 2.68 x 103 oz/gal B) 4.77 x 10-7 oz/gal C) 2.46 ozlgal D) 3.84 x 104 oz/gal E) 3.32 x 108 oz/gal
The concentration of arsenic in milk, which is 3.57 μg/L, can be converted to ounces per gallon. The correct answer is option D) 3.84 x 10^4 oz/gal.
To convert the concentration of arsenic from micrograms per liter (μg/L) to ounces per gallon (oz/gal), we need to follow a series of conversion steps. First, we need to convert micrograms (μg) to grams (g). There are 1,000 micrograms in a milligram (mg) and 1,000 milligrams in a gram, so 3.57 μg is equivalent to 0.00357 mg. Next, we need to convert milliliters (mL) to gallons (gal). Since 1 liter (L) is equal to 1,000 milliliters (mL) and 1 gallon is approximately 3,785.41 milliliters, we can calculate that 946.4 mL is approximately 0.25 gallons. Now, we can calculate the concentration in ounces per gallon. One pound (lb) is equal to 16 ounces (oz), and we know that 1 lb is approximately 0.4536 kg. Since 1 gallon is equal to 4 quarts (qt), and 1 quart is equal to 32 ounces, we can multiply all the conversion factors together:
0.00357 mg/L * 0.25 gal * 16 oz/lb * (1 lb/0.4536 kg) = 3.84 x 10^4 oz/gal
Therefore, the concentration of arsenic in ounces per gallon is approximately 3.84 x 10^4 oz/gal, which corresponds to option D).
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What is the formula mass of the fictitious compound: AB2?
Were any paint chip cards missing from your set? How did you determine they were or were not missing? How would you describe the missing cards to someone?
Answer:
A continuous color sequence is a pattern that can be used to determine if paint chips are missing from the set. If the color change from chip to chip is not continuous, a chip is probably missing. This pattern is useful to display paint chips for customers.
An electron is a positively charged particle inside of an atom, just like the proton.
True
False
Answer:
no it's is false because an electron have negative charges and it is not inside the atom and it is found out side the nucleus
A solution of 6.2 M H2SO4 is diluted from 2.0 L to 3.0 L. What is the molarity of the resulting solution?
Answer:
Here's link to the answer:
bittuly/3a8Nt8
Explanation:
According to molar concentration, molarity of the resulting solution is 4.32 molar.
What is molar concentration?Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.
The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.
In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.Substitution in formula M₁V₁=M₂V₂ gives M₂=6.2×2/3=4.32 M.
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a sample of an unknown gas is placed in a vessel with a volume of 4,372 ml at a temperature of 32.3 °c. if the pressure is 5.7 atm, how many moles of gas are present?
There are 0.893 moles of gas present in the sample.
The ideal gas law is PV = nRT, which expresses the relationship between the pressure, volume, temperature, and amount of gas present. We can use this equation to find the number of moles of gas present in a sample. Here's how: PV = nRTn = PV / RT, where P is the pressure in atm, V is the volume in litres, T is the temperature in Kelvin, R is the universal gas constant (0.0821 L atm/mol K), and n is the number of moles of gas. Let's convert the volume to litres and the temperature to Kelvin. 4,372 ml = 4.372 L, and 32.3 °C + 273.15 = 305.45 K. Now we can plug in the values: n = (5.7 atm) (4.372 L) / (0.0821 L atm/mol K) (305.45 K)n = 0.893 mol.
Therefore, there are 0.893 moles of gas present in the sample.
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Balancing chemical equation
_CoBr3 + _CaSO4 -> _CaBr2 + _Co2 (SO4)2
- solution please
Answer:
2 CoBr3 + 3 CaSO4 = 3 CaBr2 + Co2(SO4)2
Explanation: