The picture shows an orange falling from an orange tree


Which forces are acting on the falling orange?

A) The force of gravity is pulling down in the orange, while the force of friction is pushing up on the orange

B) The tension force is pulling down on the orange, while the force of gravity is pushing up on the orange.

C) The force of friction is pulling down on the orange, while the normal force is pushing up on the orange.

D) The force of gravity is pulling down on the orange, while the tension force us pushing up on the orange.

The Picture Shows An Orange Falling From An Orange TreeWhich Forces Are Acting On The Falling Orange?A)

Answers

Answer 1

Answer:

Answer A is the correct one

Explanation:

The force of gravity is pulling down in the orange, while the force of resistance with the air is pushing up on the orange. This last force could be viewed as a type of "friction" force with the air.

Answer 2

A) The force of gravity is pulling down in the orange, while the force of friction is pushing up on the orange

Gravity always pulls objects down. Gravity pulls you down to the ground when you jump.Friction is the force resisting the relative motion of solid surfaces. This force pulls a sliding object in the opposing direction of another object.The forces that are acting on the falling orange are: The force of gravity is pulling down in the orange, while the force of resistance with the air is pushing up on the orange. 

For more information:

https://brainly.com/question/21400258?referrer=searchResults


Related Questions

d. If a dog has a mass of 12 kg, what is its weight on Neptune?
11.7N/kg

Answers

Answer:

133.8 N

Explanation:

Recall that the acceleration of gravity in Neptune is estimated as 11.15 m/s^2

Therefore, the weight of the dog on this planet would be:

Weight = mass x acceleration of gravity = 12 kg x 11.15 m/s^2 = 133.8 N

What is the wavelength of a wave whose velocity is 12m/s and has a frequency of .75 Hz?

Answers

Answer:

16 meters

Explanation:

Use the formula that relates frequency velocity and wavelength:

velocity = wave-length x frequency

in our case:

12 m/s = wave-length * 0.75 Hz

wave-length= 12/0.75  m = 16 meters

Calculate the RMS speed of helium atoms near the surface of the Sun at a temperature of about 5300 K.

Answers

Answer:

RMS velocity, [tex]v_{rms}=5748.75\ m/s[/tex]

Explanation:

We need to find the RMS speed of helium atoms near the surface of the Sun at a temperature of about 5300 K.

The formula for RMS speed of a gas is given by :

[tex]v_{rms}=\sqrt{\dfrac{3RT}{m}}[/tex]

Where

R is ideal gas constant, R = 8.314 J /mol K

T = 5300 K

m is molar mass of Helium, [tex]m = 4\times 10^{-3}\ Kg/mol[/tex]

Substituting all the values in above formula :

[tex]v_{rms}=\sqrt{\dfrac{3\times 8.314\times 5300}{4\times 10^{-3}}}\\\\=5748.75\ m/s[/tex]

So, the RMS speed Helium atoms 5748.75 m/s.

What is the original source of the energy stored in fossil fuels?
plants
the Sun
air
O water


The sun

Answers

Answer:

Plants the chloroplasts

A. A piece of paper near a magnet
B. An aluminum nail near a magnet
C. An iron nail, not near a magnet
D. An iron nail near a magnet

Answers

Answer:

it’s c not d

Explanation:

took the test

Answer: D!!!

Explanation: jus got it wrong from the other answer.

what is the initial position of the object?
a. 2m b. 4m c. 6m d. 8m e. 10 m
what is the velocity of the object?
a. -10 m/s b. -5 m/s c. 0 m/s d. 5 m/s e. 10 m/s
which of the following is true?
a. the object increase its velocity.
b. the object decrease its velocity.
c. the objects velocity stays unchanged.
d. the object stays at rest.
e. more information is required.​

Answers

Answer:

e:10 m   b: -5 m/s b.The object decreases its velocity.

Explanation:

Find the state of Georgia in the southeastern U.S. What can you say about the weather in this state?

Answers

The weather in Georgia isn’t like Florida, it follows along with spring, summer, autumn, winter.
I went there in March, expecting it to be warm, but it was actually fairly cold.
So it has a temperate climate.

How high does a rocket have to go above the earth's surface to be subject to a gravitational field from the earth that is 50.0 percent of its value at the earth's surface?

A) 2.650 km
B) 3,190 km
C) 9.020 km
D) 12.700 km​

Answers

Answer:

A) 2.650 km

Explanation:

The relationship between acceleration of gravity and gravitational constant is:

[tex]g = \frac{Gm}{R^2}[/tex] ---- (1)

Where

[tex]R = 6,400 km[/tex] -- Radius of the earth.

From the question, we understand that the gravitational field of the rocket is 50% of its original value.

This means that:

[tex]g_{rocket} = 50\% * g[/tex]

[tex]g_{rocket} = 0.50 * g[/tex]

[tex]g_{rocket} = 0.5g[/tex]

For the rocket, we have:

[tex]g_{rocket} = \frac{Gm}{r^2}[/tex]

Where r represent the distance between the rocket and the center of the earth.

Substitute 0.5g for g rocket

[tex]0.5g = \frac{Gm}{r^2}[/tex] --- (2)

Divide (1) by (2)

[tex]\frac{g}{0.5g} = \frac{Gm}{R^2}/\frac{Gm}{r^2}[/tex]

[tex]\frac{g}{0.5g} = \frac{Gm}{R^2}*\frac{r^2}{Gm}[/tex]

[tex]\frac{1}{0.5} = \frac{1}{R^2}*\frac{r^2}{1}[/tex]

[tex]2 = \frac{r^2}{R^2}[/tex]

Take square root of both sides

[tex]\sqrt 2 = \frac{r}{R}[/tex]

Make r the subject

[tex]r = R * \sqrt 2[/tex]

Substitute [tex]R = 6,400 km[/tex]

[tex]r = 6400km * \sqrt 2[/tex]

[tex]r = 6400km * 1.414[/tex]

[tex]r = 9 049.6\ km[/tex]

The distance (d) from the earth surface is calculated as thus;

[tex]d = r - R[/tex]

[tex]d = 9049.6\ km - 6400\ km[/tex]

[tex]d = 2649.6\ km[/tex]

[tex]d = 2650\ km[/tex] --- approximated

What is the frequency of this wave?

can someone pls explain and answer ​

Answers

Answer:

f = 1 Hz

Explanation:

From the attached figure, we find that the time period of the wave is 1 second.

It is a longitudinal wave. It travel in the form of compression and rarefaction. The relation between time period T and frequency f is given by :

[tex]f=\dfrac{1}{T}\\\\\text{As T = 1 s}\\\\f=1\ s^{-1}\\\\=1\ Hz[/tex]

Hence, the frequency of this wave is 1 Hz.

Where do magnetic fields occur?

Answers

Answer:

The Magnetosphere and Magnets

Explanation:

[tex]--------------------------------------------[/tex]

According to the National Geographic, "Earth’s magnetic field dominates a region called the magnetosphere, which wraps around the planet and its atmosphere. Solar wind, charged particles from the sun, presses the magnetosphere against the Earth on the side facing the sun and stretches it into a teardrop shape on the shadow side. The magnetosphere protects the Earth from most of the particles, but some leak through it and become trapped. When particles from the solar wind hit atoms of gas in the upper atmosphere around the geomagnetic poles, they produce light displays called auroras. These auroras appear over places like Alaska, Canada and Scandinavia, where they are sometimes called “Northern Lights.” The “Southern Lights” can be seen in Antarctica and New Zealand. The magnetic field is the area around a magnet that has magnetic force. All magnets have north and south poles."

[tex]--------------------------------------------[/tex]

Hope this helps! <3

[tex]--------------------------------------------[/tex]

a mass of 2.00 kg rest on a rough horizontal table. The coefficient of static friction between the block and the table is 0.60. The block is attached to a hanging mass by a string that goes over a smooth pulley,as shown in the diagram. Determine the largest mass that can hang in this way without forcing the block to slide.

Answers

Answer:

1.2 kg

__________________________________________________________

We are given:

Mass of the block = 2 kg

Coefficient of Static Friction = 0.6

__________________________________________________________

Friction Force on the Block:

Finding the Normal Force:

We know that the normal force will be equal and opposite to the weight of the 2 kg block

So, Normal Force = mg

replacing the variables with the given values

Normal Force = (2)(9.8)                    [Taking g = 9.8]

Normal Force = 19.6 N

Friction force on the Block:

We know that:

Coefficient of Static Friction =  Static Friction Force/Normal Force

replacing the variables

0.6 = Static Friction force / 19.6

Static Friction force = 0.6*19.6 N                 [Multiplying both sides by 19.6]

Static Friction force = 11.76 N

__________________________________________________________

Largest Mass that can Hang:

We know that the Static Friction force is 11.76 N, this means that a force of 11.76 N will be applied to keep the object at rest

So, if the weight of the second block is less than the static friction force, it will hang

Weight of the second block ≤ 11.76

We know that weight = mg

mg ≤ 11.76

m(9.8) ≤ 11.76                                                   [since g = 9.8]

m ≤ 1.2 kg                                                        [dividing both sides by 9.8]

From this, we can say that the maximum mass of the second block is 1.2 Kg

Among the elements potassium, lithium, and iron, the metallic bonds are likely to be strongest in

Answers

彼が好きな男のような話は妻と関係があったのでそう

Explanation:これが難しい場合はコメントで教えてくださいが何でも

lol okay

from: a random person :)

Answer: Iron

Explanation: Gradpoint

A 100 kg. football player and a 20 kg. child sit on rolling carts and push off
from each other. Which person applies more force?*20 kg. child applies more force
100 kg. football player applies more force
Same force is applied

Answers

Answer:

the forces are the same

Explanation:

Your electric drill rotates initially at 5.21 rad/s. You slide the speed control and cause the drill to undergo constant angular acceleration of 0.311 rad/s2 for 4.13 s. What is the drill's angular displacement during that time interval?

Answers

Answer:

The drill's angular displacement during that time interval is 24.17 rad.

Explanation:

Given;

initial angular velocity of the electric drill, [tex]\omega _i[/tex] = 5.21 rad/s

angular acceleration of the electric drill, α = 0.311 rad/s²

time of motion of the electric drill, t = 4.13 s

The angular displacement of the electric drill at the given time interval is calculated as;

[tex]\theta = \omega _i t \ + \ \frac{1}{2}\alpha t^2\\\\\theta = (5.21 \ \times \ 4.13) \ + \ \frac{1}{2}(0.311)(4.13)^2\\\\\theta = (21.5173 ) \ + \ (2.6524)\\\\\theta =24.17 \ rad[/tex]

Therefore, the drill's angular displacement during that time interval is 24.17 rad.

(1-dimension) A fish has a mass of 6 kg and is moving at a speed of 4m/s to the right. What is its momentum?

Answers

Answer:

24 kg m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 6 × 4

We have the final answer as

24 kg m/s

Hope this helps you

Which scenario is an example of the transfer of thermal energy by radiation?

A. Water boils in a pan.

B. Hot air circulates in an oven.

C. An ice cube melts in a person's hand.

D. A frozen lake melts under the Sun.

Correct answer is D

Answers

Answer:

its D: A frozen lake melts under the sun.

Explanation:

Radiation is the transfer of heat energy through space by electromagnetic radiation. Most of the electromagnetic radiation that comes to the earth from the sun is invisible. Only a small portion comes as visible light. Light is made of waves of different frequencies.

d i hope this helps the person above me told you the right answer!!

Two objects of equal mass are a distance of 5.0 m apart and attract each other with a gravitational force of 3.0 x 10^-7 N find their mass.
A) 150 kg
B) 9.8 kg
C) 11.000 kg
D) 340 kg​

Answers

Answer

I Think Its 150

3.00 kg block moving 2.09 m/s right hits a 2.22 kg block moving 3.92 m/s left. afterwards, the 3.00 kg block moves 1.71 m/s left. find the velocity of the 2.22 kg block afterwards

Answers

Momentum is conserved, so the total momentum before collision is equal to the total momentum after collision. Take the right direction to be positive. Then

(3.00 kg) (2.09 m/s) + (2.22 kg) (-3.92 m/s) = (3.00 kg) (-1.71 m/s) + (2.22 kg) v

where v is the velocity of the 2.22 kg block after collision. Solve for v :

6.27 kg•m/s - 8.70 kg•m/s = -5.13 kg•m/s + (2.22 kg) v

(2.22 kg) v = 2.70 kg•m/s

v = (2.70 kg•m/s) / (2.22 kg)

v ≈ 1.22 m/s

i.e. a velocity of about 1.22 m/s to the right.

Carter's favorite ride at playland amusement park is the rollercoaster. The roller coaster
car and passengers have a combined mass of 1620kg and they descend the first hill at
an angle of 45.0 degrees to the horizontal. With what force is the rollercoaster pulled
down the hill?

Answers

Answer:

F = 11226.02 N

Explanation:

The roller coaster  car and passengers have a combined mass of 1620kg.

They descend the first hill at  an angle of 45.0 degrees to the horizontal.

We need to find force is the rollercoaster pulled  down the hill.

We firstly find the rectangular component of the downward. The force acting in the downward direction is mgsinθ such that,

F = mgsinθ

= 1620 × 9.8 × sin(45)

= 11226.02 N

So, the roller coaster is pulled down the hill with a force of 11226.02 N.

A 100kg couch is being pushed with 196N of force. As it slides along the ground it experiences a coefficient of friction of 0.1. What is the net force in this situation?

A 300N
B 202N
C 398N
D 98N

Answers

Answer:98

Explanation:hope this helps!

3) A 10kg object rests on a frictionless surface when it is struck by a 300N force. At what rate will it accelerate?

3m/s/s
30m/s/s
0.3m/s/s
300m/s/s

Answers

Answer: 0.3m/s/s

(i'm really sorry if i'm wrong)

:(

Ask For
6.
A horizontal 100 N force is applied to a 50 kg classmate resting on a level tile
floor. The coefficient of kinetic friction is 0.15.
a. Draw a force diagram to represent this situation.
b. What is the acceleration of the classmate?
c. Suppose the classmate was resting on a carpet where the coefficient of static
friction is 0.25. Is the horizontal 100 N force sufficient to cause the classmate to
accelerate? Draw a force diagram, and then explain why or why not.

Answers

I think c I’m not sure tho

Hey guys this is Ap physics please help I need this to pass i will mark brainliest for a good attempt

Answers

Split up the forces into components acting parallel to and perpendicular to the slope. See the attached picture for the reference axes.

The box stays on the surface of the plane, so that the net force acting perpendicular to it is 0, and the only acceleration is applied in the parallel direction.

Let m be the mass of the box, θ the angle the plane makes with the ground, and a the acceleration of the box. By Newton's second law, we have

• net parallel force

∑ Force (//) = W (//) - F = m a

(that is, the net force in the parallel direction is the sum of the parallel component of the weight W and the friction F which acts in the negative direction)

• net perpendicular force

∑ Force (⟂) = W (⟂) + N = 0

Notice that

W (//) = W sin(θ) … … … which is positive since it points down the plane

W (⟂) = -W cos(θ) … … … which is negative since it points opposite the normal force N

So the equations become

W sin(θ) - F = m a

-W cos(θ) + N = 0

Solving for a gives

a = (W sin(θ) - F ) / m

which is good enough if you know the magnitude of the friction force.

If you don't, you can write F in terms of the coefficient of kinetic friction between the box and plane, µ, as

F = µ N

so that

a = (W sin(θ) - µ N ) / m

and the normal force itself has a magnitude of

N = W cos(θ)

so that

a = (W sin(θ) - µ W cos(θ) ) / m

The weight W has magnitude m g, where g is the magnitude of the acceleration due to gravity, so

a = (m g sin(θ) - µ m g cos(θ) ) / m

a = g (sin(θ) - µ cos(θ))

A sled is pulled with a force of 540 N at an angle of 40° with the horizontal. What are the horizontal and vertical components of this force?

Answers

Answer:

Fx = 467.65N

Fy = 270N

Explanation:

Given

Force = 540N

angle of inclination = 40 degree

Horizontal component Fx = Fcos 30

Fx = 540cos30

Fx = 540(0.8660)

Fx = 467.65N

Hence the horizontal component is 467.65N

Vertical component Fy = Fsin 30

Fy = 540sin30

Fy = 540(0.5)

Fy = 270N

Hence the vertical component is 270N

in the case shown below, the 1 kg rock rides on a horizontal disk that rotates at constant speed 5m/s about its vertical axis. the radius of the disk is 1 meter. What is the magnitude of the friction?

Answers

Answer:

25

Explanation:

The Slingshot is a ride for two people. It consists of a single passenger cage, two towers, and two elastic bands. Potential energy is stored in the elastic bands and the passenger cage is released. On the way up, this potential energy in the elastic bands is converted into the kinetic energy of the cage. At the maximum height of the ride, the energy has been converted into gravitational potential energy of the cage. The slingshot has two towers of height h = 76 m. The towers are a distance d = 31 m apart. Each elastic band has an unstretched length of L0 = 41 m and a spring constant of k = 310 N/m. The total mass of the passengers and cage is m = 410 kg. The car is pulled down to the ground in the middle of the two towers.

Calculate the maximum height, in meters, of the ride.

Answers

my bad I was in a herie last time can you please answer my question , I am going to give you the 5 points back for this question and extra 30 points ,

Explanation:

first its going to say 10 points for my question but after that I well make answer a small question and give you 30points. like whats your favorite color . stay tuned .

Answer:

The maximum height reached by the ride after it was pulled to the ground is 51.6 m.

The given parameters;

Distance between the two towers, d = 31 mHeight of the tower, h = 76 mUnstretched length of the band, L₀ = 41 mElastic constant of the band, k = 310 N/m

The distance half-way between the bands;

[tex]\frac{d}{2} = \frac{31}{2} = 15.5 \ m[/tex]

The maximum length of the band when stretched is calculated as;

[tex]c^2 = 15.5^2 + 76^2\\\\c^2 = 6016.25\\\\c = \sqrt{6016.25} \\\\c = 77.57 \ m[/tex]

The extension of the elastic band;

x = 77.57 m - 41 m

x = 36.37 m

The elastic potential energy stored in the band;

[tex]E = \frac{1}{2} kx^2\\\\E = \frac{1}{2} \times 310 \times (36.57)^2\\\\E = 207,291.56 \ J[/tex]

The elastic potential energy of the elastic band will be converted into kinetic energy of the ride and the speed of the ride is calculated as;

[tex]E = \frac{1}{2} mv^2\\\\207,291.56 = \frac{1}{2} \times 410 \times v^2\\\\v^2 = \frac{207,291.56}{(0.5\times 410)} \\\\v^2 = 1011.178\\\\v = \sqrt{1011.178} \\\\v = 31.8 \ m/s[/tex]

The maximum height reached by the ride is calculated as;

[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{(31.8)^2}{(2\times 9.8)} \\\\h = 51.6 \ m[/tex]

Thus, the maximum height reached by the ride is 51.6 m.

Learn more here: https://brainly.com/question/156316

HELPP physics final will give brainliest

Answers

0.5 m/s^2

Please give me brainliest! You don’t have to though :3

If two exactly the same cars are driving down a road, which one would have the most kinetic energy. The one that is moving faster, the one that is moving downhill, the one that is moving uphill, or the one that is moving slower.

Answers

Answer: the car that is moving downhill

Explanation:

8x = -6. What does x equal?

Answers

Answer:

x=-3/4

Explanation:

A skier is moving 8.33 m/s when
he starts to slide UP a 8.44°
frictionless slope. How much time
does it take him to come to a stop?
(Unit = s)

Answers

Answer:

5.79

Explanation:

Vf=Vi+at

0=8.33+(-9.8)sin8.44t

t=8.33/(9.8sin8.44)=0.83/sin 8.44

=5.79

Other Questions
________ is a technique used in perspective to create the illusion of an object receding strongly into the distance or background. The illusion is created by the object appearing shorter than it is in reality, making it seem compressed. * Is there an example used in the text, house on mango street ? For each incorrect answer on a test, the teacher changes the total points possible by 4 points. The total number of points possible on a test is 64. If a student has 9 incorrect answers, what will be that students score? The two-way table shows the ages of the players on different sOCcer teams.Team D3Total21231458Team CTeam A4Team B8 Years Old9 Years Old10 Years OldTotal4313351641514Which statement is true?O The probability that a randomly selected player on TeamA is 8 years old isO The probability that a randomly selected 8-year-old player is on Team C isO The probabilty that a randomly selected player on Team C is 10 years old isO The probability that a randomly selected 10-year-old player is on Team B is 1358 Aakash can complete a work in 10 days. If he worked for 4 days andthe remaining work is done by Safal, how much work is done by Safal? Write the standard form of the line that contains a slope of 1/2 and y-intercept of 1. Include your work in your final answer. Type your answer in the box provided to submit your solution. A middle school is selling candy bars to raise money for new calculators. The graph shows the number of candy bars sold, x, and the amount of money collected, y. IS THIS CORRECT OR NAH Ms. Ruiz bought 12 packages of plates for the party. Each package contains 15 plates. She bought 10 packages of small plates and 2 packages of large plates. How many small plates did she buy? How many large plates did she buy? How many plates did she buy all together How do I find the measurement indicated in each parallelogram. Which are the planning, design, building,and implementation phases considered to be Triangle DEFDEFD, E, F is similar to triangle PQRPQRP, Q, R. Solve for k. Enter the simplified form of the complex fraction in the box.Assume no denominator equals zero. Please I beg someone to help me Which most likely accounts for the increase in the number of male butterflies in the five years after the initial parasite problem? Grade 7 Unit 4 District Assessment 2020-21 Question: 1 Jacob saw a model of a building that will be built in his city. The model has a height of 40 centimeters and will be built to a scale of 1:50. What is the actual height of the building? (1 m = 100 cm) Line 34, "Sits on thy skin like morning dew," and line 38, "and now, like am'rousbirds of prey," are examples of:O A. denotations..O B. allusions.O c. hyberboles.O D. metaphor..E. similes. Identify when an object has a kinetic energy of zero joules.Question 9 options:when an object is no longer in motion.when the energy has been destroyed.just after a ball it leaves your hand pitching a ball.as a pendulum swings downward. 50 pointsIs this right?Look at both screenshots (b) At Smith's Bike Rentals, it costs $26 to rent a bike for 6 hours.How many hours of bike use does a customer get per dollar? Please read the attached Newsela article, "Pets can make people feel happier and healthier" and complete the attached Double Entry Literature form.