Answer: I believe the answer is A. The order of amino acids in the protein.
Explanation:
Which of the following does NOT represent a balanced reaction?
Answer:
letter D i thinkExplanation:
correct me if im wrong
cómo se puede comprobar el efecto universo
Answer:
???! huhhhjhhh no I speak English
Explanation:
?
Answer:
vifucivud UKvi uiiijhhh
True or False: A higher vapor pressure (evaporates easily) corresponds to strong intermolecular forces.
[H] = 1.00 x 10^-7 M
a. Acidic
b. Basic
c. Neutral
Find the % composition for each element in Zinc Chlorate
Answer:
chlorine ~ 30%
zinc ~ 28%
oxygen ~ 41%
Explanation:
What is (aq),(I), and (g) mean in H2O2(aq) -> H2O(l) + O2(g) and why is it nesesary to have (aq),(I), and (g)
Explanation:
A matter can be present in different states like solid, liquid or gas. When we write a chemical equation then states of species involved are also mentioned.
This is because it tells in what state the reactants were present and in what state the products are then formed.
For example, [tex]H_{2}O_{2}(aq) \rightarrow H_{2}O(l) + O_{2}(g)[/tex]
Now here, (aq) means aqueous, (l) means liquid and (g) means gas.
So, these states denoted are necessary as it tells that [tex]H_{2}O_{2}[/tex] in aqueous state dissociates to give [tex]H_{2}O[/tex] in liquid state and [tex]O_{2}[/tex] in gaseous state.
Consider the energy diagram below.
AY
B
Free Energy
Reaction Progression
Which line indicates a higher reaction rate?
A because it has a lower activation energy.
B because it has a lower activation energy.
Answer:
B because it has a lower activation energy.
Explanation:
Just took the test
Draw a schematic diagram of a circuit with an output device, a energy source and a controller.
Answer:
ch∪pαpi munαn0?
Explanation:
7. What is the mass of a piece of copper (Cu) that undergoes a 25.0 °C
temperature change with the loss of 428 J of energy?
Answer:
0.0428 kg or 42.8 g
Explanation:
Applying,
Q = cmΔt.............. Equation 1
Where Q = heat lost of heat gained, c = specific heat capacity of copper, m = mass of copper, Δt = temperature change.
make m the subject of the equation above
m = Q/cΔt.................. Equation 2
From the question,
Given: Q = 428 J, Δt = 25 °C
Constant: c = 400 J/kg.°C
Substitute these values into equation 2
m = 428/(25×400)
m = 0.0428 kg
m = 42.8 g
How many different chlorinated products
are based in the following reaction.
CH3CH2CH2CH3 + Cl2 heat
Answer: if I’m not mistaken it would be 8
Explanation:
Answer:
2
Explanation:
:)
the mass concentration the mass concentration for a solution containing 45 g of calcium carbonate is 100 cm3
Answer: The mass concentration for a solution containing 45 g of calcium carbonate for 100 [tex]cm^{3}[/tex] is 0.045 M.
Explanation:
Given: Mass of calcium carbonate = 45 g
Volume = [tex]100 cm^{3}[/tex]
Convert [tex]cm^{3}[/tex] into L as follows.
[tex]1 cm^{3} = 0.001 L\\100 cm^{3} = 100 cm^{3} \times \frac{0.001 L}{1 cm^{3}}\\= 0.1 L[/tex]
Moles of calcium carbonate (molar mass = 100 g/mol) is as follows.
[tex]No. of moles = \frac{45 g}{100 g/mol}\\= 0.45 mol[/tex]
Molarity is the number of moles of solute present in a liter of solution.
Hence, molarity (or mass concentration) of given solution is calculated as follows.
[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.45 mol}{0.1 L}\\= 0.045 M[/tex]
Thus, we can conclude that the mass concentration for a solution containing 45 g of calcium carbonate for 100 [tex]cm^{3}[/tex] is 0.045 M.
A chemistry student weighs out 0.021 kg of an unknown solid compound X and adds it to 650. mL of distilled water at 30. 0C. After 10 minutes of stirring, all of the X has dissolved. Just to be sure, the student adds a further 11. mg of X to the solution, and it, too, dissolves. Using only the information above, can you calculate the solubility of X in water at 30. 0C?
Answer:
"No" I can't calculate the solubility of X.
Explanation:
Beyond certain temperatures or heat levels, a solvent's soluble has been determined by many as the proportion of something like the solution necessary for saturating the solvents' measured amount at around that atmospheric pressure.This same solution isn't absorbed throughout this situation. It is not saturated however since the addition of 11 g of something like the mixture towards the solution completely dissolved without separating a solution.This is why the preceding solution would be the proper one.
156 grams of calcium fluoride, CaF2, is dissolved in 2000 mL of solution. Determine the molarity (M).
Answer:
1 M
Explanation:
We'll begin by calculating the number of mole of in 156 g of CaF₂. This can be obtained as follow:
Mass of CaF₂ = 156 g
Molar mass of CaF₂ = 40 + (19×2)
= 40 + 38
= 78 g/mol
Mole of CaF₂ =?
Mole = mass /molar mass
Mole of CaF₂ = 156 / 78
Mole of CaF₂ = 2 moles
Next, we shall convert 2000 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
2000 mL = 2000 mL × 1 L / 1000 mL
2000 mL = 2 L
Finally, we shall determine the molarity of the solution. This can be obtained as follow:
Mole of CaF₂ = 2 moles
Volume = 2 L
Molarity =?
Molarity = mole / Volume
Molarity = 2 / 2
Molarity = 1 M
Thus, the molarity of the solution is 1 M
ACTIVITY NO.3
DIRECTIONS: Read each item carefully. Choose the letter of your answer.
1. Light travels in a
line when is passes through a single medium.
a. curve
b. straight
C. crooked
d. dotted
2. When the sound travels through solids, the vibration of the particles occurs
?
a. fast
b. slowly
c. moderately
irregularly
3. What affects the speed of sound as it travels?
a. Person receiving it
b. The origin of the sound
c. The nature of materials
d. Loudness of the sound
4. How is heart transferred in solid materials?
a. Through convection
b. Through conduction
c. Through radiation
d. Through vacuum
5. What is the direction of heat transfer?
a. From hot to cold
b. From Cold to hot
c. From bottom to top
d. From side to side
PLZ ANSWER QUICK I AM IN TIMER HELP WILL GIVE BRAINLIEST
Which is greater, the moon's period of rotation or its period of revolution?
They are equal.
the moon's revolution period around Earth
Neither are known.
the moon's rotational period
Answer:
B
Explanation:
pls help i need asap will mark brainlest
Answer:
B. 50%
Explanation:
2H₂ + CO → CH₃OHFirst we convert the given masses of the reactants into moles, using their respective molar masses:
4 g H₂ ÷ 2 g/mol = 2 mol H₂25 g CO ÷ 28 g/mol = 0.893 mol CO0.893 moles of CO would react completely with (0.893 * 2) 1.786 moles of H₂. As there are more H₂ moles than that, H₂ is the reactant in excess and CO is the limiting reactant.
Now we calculate how many CH₃OH moles would have been formed if all CO would have been consumed:
0.893 mol CO * [tex]\frac{1molCH_3OH}{1molCO}[/tex] = 0.893 mol CH₃OHThen we convert 0.893 moles of CH₃OH into grams, using its molar mass:
0.893 mol CH₃OH * 32 g/mol = 28.57 gFinally we calculate the percent yield:
14 g / 28.57 g * 100% = 49%If you have 1.82 moles of mercury (Hg), how many grams of mercury do you have?
Answer:
182
Explanation:
1 hectogram (hg) = 100 grams (g)
1.82 x 100 = 182
How do we measure the rate of this reaction A + B —> C
If you have 600g of nitroglycerin, how many moles do you have?
help please
Answer:
600
Explanation:
there's 1 mole in every nitroglycerin
I think
For each event stated below, indicate how the concentration of each species in the chemical equation will then change to reach equilibrium.
2CO(g) + O2(g) ⇌ 2CO2(g)
a. increasing the concentration of CO
b. decreasing the amount of O2
c. decreasing the the volume of the system
Answer:
See Explanation
Explanation:
When a constraint such as a change in temperature, concentration or pressure is imposed on a reaction system in equilibrium, the system will readjust itself in such a way as to annul the constraint. This readjustment occurs when the equilibrium position shifts towards the left or right in order to annul the constraint.
a. increasing the concentration of CO: When the concentration of CO is increased, the equilibrium position shifts to the right in order to annul the constraint. This means that more CO2 is produced in the system while the concentration of CO and O2 are decreased until equilibrium is reestablished.
b. decreasing the amount of O2: When the amount of O2 is decreased, the equilibrium position will shift to the left and more CO and O2 are produced while the concentration of CO2 decreases until equilibrium is reestablished.
c. decreasing the the volume of the system: When the volume of the system is decreased, the equilibrium position shifts towards the right hand side where there is less total volume. Hence the concentration of CO and O2 decreases while the concentration of CO2 increases.
Which hand is negatively changed?
A.
B.
C.
D.
Answer:
I think B
Explanation:
There are more negative ions than positive ions
2) Choose the best answer. Which type of reaction is this? NaOH + H2O → Na+ + OH strong base dissociation strong acid dissociation weak base dissociation neutralization weak acide dissociation
Answer:
strong Base Dissociation
Explanation:
NaOH is baseNaOH is strong base that means strong acids ionizes almost completely when dissolved in water.Products will form faster if___
A) temperature is decreased
B) the reaction is not stirred
C) the particle size of the reactants are larger
D) concentration of the reactants are increased
Answer:
C(btw this could be wrong)
Explanation:
Answer:
B is the answer
Explanation:
write a story of your life when you were hurted by someone whom you trusted blindly...
Answer:
Sis I think it happened with me but I am not able to remember if u want u can share if it happened with u
In the lab, you are asked to plan an investigation that shows how the structure of substances can explain the strength of the electrical forces between
particles. To show this, you decide to determine how much tinfoil will melt when the heat of different objects touches it. One of the objects you test
releases 5.7 kJ of heat. How much of the tinfoil will melt?
AHjus=7.029 kJ/mol
O
A. 16.99
B. 20.89
C. 84.39
D. 96.39
is this correct im just asking because my little brother not sure for his answer
Place the following in order of increasing entropy at 298 K.
Ne Xe He Ar Kr
A) He < Kr < Ne < Ar < Xe.
B) Xe < Kr < Ar < Ne < He.
C) Ar < He < Ar < Ne < Kr.
D) Ar < Ne < Xe < Kr < He.
E) He < Ne < Ar < Kr < Xe.
Answer:
E
Explanation:
The simple rule of thumb is that as the atomic or molar mass of an atom increases, the entropy increases. This means that more the mass more will be entropy.
The atomic mass of various elements is as follows
Ne = 20 g/mol
Xe = 131 g/mol
He = 4 g/mol
Ar = 40 g/mol
Kr = 84 g/mol
Therefore, the order of increasing entropy must be
He<Ne<Ar<Kr<Xe.
Hence, option E is the correct answer.
Which particles appear in equal numbers in all uncharged atoms? Proton, Neutron, Electron, None
Answer:
In an uncharged atom, the number of protons is always equal to the number of electrons. Apr 24, 2017
Explanation:
Neutron: An uncharged particle found in the nucleus of an atom.
There is only one stable atom that does not have neutrons. It is an isotope of the element hydrogen called protium. Protium, which contains a single proton and a single electron, is the simplest atom.
Answer both of these true or false correctly
brainliest if correct
Answer:
There both true.
Explanation:
Hope this helps
Answer:
The first one is True
The second one is false
Explanation:
How many grams of carbon dioxide will be produced if 76.4 grams of
C2H3Br3 reacted with 49.1 grams of O2? How many grams of the
excess reactant will be left after the reaction is over? Consider the
equation: C2H3Br3+O2 -> CO2+H2O+Br2
Answer:
Assuming that all of the oxygen is used up, 1.53×4111.53×411 or 0.556 moles of C2H3Br3 are required. Because there are only 0.286 moles of C2H3Br3 available, C2H3Br3 is the limiting reagent.
Limiting Reagent What is the limiting reagent if 76.4 grams of C2H3Br3 were reacted with 49.1 grams of O2? C2H3Br3 + 11O2 → 8CO2 + 6H2O + 6Br2 SOLUTION Using Approach 1: A. 76.4g × (1 mol/ 266.72 g) = 0.286 moles C2H3Br3 49.1g × (1 mole/ 32 g) = 1.53 moles O2 B.
Explanation:
MRK ME BRAINLIEST PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Map%3A_Introductory_Chemistry_(Tro)/08%3A_Quantities_in_Chemical_Reactions/8.04%3A_Limiting_Reactant_and_Theoretical_Yield
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