The project downloaded contains a package (folder) named Q1 within the src folder. Inside Q1 is a Java class named Questions. The purpose of Question 1 is to examine your understanding of loops and branching conditions. You should implement all of your code for this question in the main method of the Questioni class. While significant detail is provided below to be sure you undertand what is required, please note that the amount of code required to solve this question (Parts a-c) is less than 10 lines (total). In the Question1 class, you are given a line of code that generates a random number between 0 and 1. Math.random(): //generates number between 0 and 1 val
You are to create a loop which, in each iteration, generates a new random value, assigns it to val using the line provided and checks to see if that val is greater than 0.5. If val is greater than 0.5, a variable named counter should be incremented. The loop should continue this process (generate random value, check if it is greater than 0.5) until a total of three random numbers generated are greater than 0.5 (values do not have to be consecutive). You should also use the variable named numIterations, which is included for you, to track how many iterations of your loop were required for you to generate three random numbers greater than 0.5. A printin() statement is included for you that displays the value of numlterations. As an example of how the program should behave, if the following sequence of random numbers are randomly generated from your loop
0.3, 0.7,0.2, 0.6,0.9
then numIterations would equal 5 (the third value greater than 0.5 occured on the fifth iteration).
If
0.6, 0.8, 0.75
was the random sequence of numbers generated by your loop, then numlterations would equal 3 (the third value greater than 0.5 occured on the third iteration).
These are two examples to illustrate the scenario given in Question 1. Since at each iteration of your loop the number generated is random, the value of numIterations that your program observes may be any value greater than or equal to 3. Note that your program does not need to print out each of the random values that it generates. The steps to solve Question 2 are broken down as follows.
a. Implement a branching condition that increases the variable counter by 1 if val is larger than 0.5 1
b. Add a loop around the code created in Part a that continues until counter equals 3.
c. Use the variable numlterations to count how many times your loop iterates.

Answer:

Where is the choices mate?

Answer:it means warning

Explanation:

Answer:

Go to any blank cell. Enter the number 91.

Select the cell that contains 91. Press Ctrl+C to copy.

Select your range the contains numbers.

Press Ctrl+Alt+V to open the Paste Special dialog.

In the top of the Paste Special dialog, choose Values. In the Operation section, choose Add. Click OK.

Explanation:

Answer: A) Who will use the database?

Answer:

It's A

Explanation:

Answer:

This is my faverrrrate part of computer science lol.

Explanation:

Answer:

TRUE

Explanation:

Answer:  customers who placed orders,  orders that are attached to customers or C E

Explanation: on edg

The records that would returned in a query based on an inner join between a table named Customers and a table named Orders includes:

In a database, this refers to the request for information stored within a database management system that maintains data.

Hence, the "customers who placed orders" and "orders that are attached to customers" will be returned in a query based on an inner join between a table named Customers and a table named Orders

Therefore, the Option C & E is correct.

Read more about query

brainly.com/question/25694408

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Answer:

The function in Python3  is as follows

def Distance(x1, y1, x2, y2):

   dist = ((x1 - x2)**2 +(y1 - y2)**2)**0.5

   return dist

Explanation:

This defines the function

def Distance(x1, y1, x2, y2):

This calculates distance

   dist = ((x1 - x2)**2 +(y1 - y2)**2)**0.5

This returns the calculated distance to the main method

   return dist

The results of the inputs is:

[tex]32, 32, 54, 12 \to 29.73[/tex]

[tex]52,56,8,30 \to 51.11[/tex]

[tex]44,94,44,39\to 55.00[/tex]

[tex]19,51,91,7.5 \to 84.12[/tex]

[tex]89,34,00,00 \to 95.27[/tex]

Answer:

very very very annoying

Answer:

yeah

Explanation:

Answer:

The program in Python is as follows:

fname = input("Enter the translation file name: ")

with open(fname) as file_in:

   lines = []

   for line in file_in:

       lines.append(line.rstrip('\n'))

myDict = {}

for i in range(len(lines)):

x = lines[i].split(":")

myDict[x[0].lower()] = x[1].lower()

print("Enter an English word to receive the Spanish translation.\nPress ENTER to quit.")

word = input("Enter an English word: ")

while(True):

if not word:

 break

if word.lower() in myDict:

 print("The Spanish word is ",myDict[word.lower()])

else:  

 print("I don’t have that word in my list.")

word = input("Enter an English word: ")

Explanation:

This prompts the user for file name

fname = input("Enter the translation file name: ")

This opens the file for read operation

with open(fname) as file_in:

This creates an empty list

   lines = []

This reads through the lines of the file

   for line in file_in:

This appends each line as an element of the list

       lines.append(line.rstrip('\n'))

This creates an empty dictionaty

myDict = {}

This iterates through the list

for i in range(len(lines)):

This splits each list element by :

x = lines[i].split(":")

This populates the dictionary with the list elements

myDict[x[0].lower()] = x[1].lower()

This prints an instruction on how to use the program

print("Enter an English word to receive the Spanish translation.\nPress ENTER to quit.")

This prompts the user for an English word

word = input("Enter an English word: ")

This loop is repeated until the user presses the ENTER key

while(True):

If user presses the ENTER key

if not word:

The loop is exited

 break

If otherwise, this checks if the word exists in the dictionary

if word.lower() in myDict:

If yes, this prints the Spanish translation

 print("The Spanish word is ",myDict[word.lower()])

If otherwise,

else:

Print word does not exist

 print("I don’t have that word in my list.")

Prompt the user for another word

word = input("Enter an English word: ")

Pistons being pistons I guess...

Answer:

Levers on the parts we cant see?

Answer:

Explanation:

This is usually an issue with the Microsoft Visual C++ redistributable. One fix that usually works is to do the following

Open Programs and Features

Uninstall and then choose Repair on Microsoft Visual C++ Redistributable (x86) and x64 version

Reinstall or repair the installation of the .NET Core SDK 1.0.1.

If this does not work, another option would be to manually change the install path of these files from "Program Files (x86) to  "Program Files"

Hope this helps solve your issue.

Answer:

word = "eggplant"

print "Your word is: " + word + "."

for i in word:

   print i + "!"

Explanation:

i don't know why but it is

Answer:

word = "eggplant"

print("Your word is !" + word + "!")

for i in word:

INDENT HERE or TAB print( i + "!")

Explanation:

Add an indentation right before the print( i + "!")

Answer: the third one

Explanation:

just trust me, the other ones dont mke sense to what I know about the subject, which is a lot

Answer:

pclex16

NIC

the graphic card must be high

Answer:

#include <stdio.h>

#include <ctype.h>

void printHistogram(int counters[]) {

   int largest = 0;

   int row,i;

   for (i = 0; i < 26; i++) {

       if (counters[i] > largest) {

           largest = counters[i];

       }

   }

   for (row = largest; row > 0; row--) {

       for (i = 0; i < 26; i++) {

           if (counters[i] >= row) {

               putchar(254);

           }

           else {

               putchar(32);

           }

           putchar(32);

       }

       putchar('\n');

   }

   for (i = 0; i < 26; i++) {

       putchar('a' + i);

       putchar(32);

   }

}

int main() {

   int counters[26] = { 0 };

   int i;

   char c;

   FILE* f;

   fopen_s(&f, "story.txt", "r");

   while (!feof(f)) {

       c = tolower(fgetc(f));

       if (c >= 'a' && c <= 'z') {

           counters[c-'a']++;

       }

   }

   for (i = 0; i < 26; i++) {

       printf("%c was used %d times.\n", 'a'+i, counters[i]);

   }

   printf("\nHere is a histogram:\n");

   printHistogram(counters);

}

answer:

press on the date thing

Answer:

A) Map

Explanation:

All gasoline (petrol) fuel systems need ways or method that will be calculating amount of the air that is entering the engine.This is true as regards mechanical fuel injection, carburetors and electronic fuel injection.Speed density system fall under one of this method. "Speed" in this context means the speed of the engine while "density" means density of the air. The Speed is been measured using the distributor, crankshaft position sensor could be used here. The Density emerge from from measuring of the air pressure which is inside the induction system, using a typical "manifold absolute pressure" (MAP) sensor as well as air temperature sensor. Using pieces of information above, we can calculate

mass flow rate of air entering the engine as well as the correct amount of fuel can be supplied. With this system,

the mass of air can be calculated. One of the drawback if this system is that

Any modification will result to incorrect calculations. Speed-Density can be regarded as method use in estimation of airflow into an engine so that appropriate amount of fuel can be supplied as well as. adequate spark timing. The logic behind Speed-Density is to give prediction of the amount of air ingested by an engine accurately during the induction stroke. Then this information could now be used in calculating how much fuel is required to be provided, This information as well can be used in determining appropriate amount of ignition advance. It should be noted The speed density fuel injection system uses the Map sensor as the primary sensor to determine base pulse width

Answer:

The complete program is as follows:

m_str = input('Input m: ')

mass = float(m_str)

e = mass * 300000000**2

print("e = ",e)

Explanation:

This is an unchanged part of the program

m_str = input('Input m: ')

This converts m_str to float

mass = float(m_str)

This calculates the energy, e

e = mass * 300000000**2

This is an unchanged part of the program

print("e = ",e)

Answer:

Explanation:

1. Decide what to back up  

If you've stored anything valuable on your hard drive , you'll need to back that up yourself.

 2. Choose backup media  

You'll need to store your backup on a separate form of digital media - such as Go-ogle Drive, One  Drive for Business or an external hard drive

 3. Back up your data  

The backup method will vary depending on your choice of software and operating system Once that's done, schedule regular future backups.

4. Store it safely  

You don't want to lose your PC and your backup. So, be smart and keep your backup somewhere safe.

5. Check that it works

Errors and technical glitches can happen without you even noticing. You may only find out later when you actually need to use that data that something went wrong. Avoid the worry by checking your backups once in a while and confirming that the data is being properly backed up.

Answer:

Explanation:

class TableInput{

    Object key;

    Object value;

    TableInput(Object key, Object value){

       this.key = key;

       this.value = value;

   }

}

abstract class HashTable {

   protected TableInput[] tableInput;

   protected int size;

   HashTable (int size) {

       this.size = size;

       tableInput = new TableInput[size];

       for (int i = 0; i <= size - 1; i++){

           tableInput[i] = null;

       }

   }

   abstract int hash(Object key);

   public abstract void insert(Object key, Object value);

   public abstract Object retrieve(Object key);

}

class ChainedTableInput extends TableInput {

   ChainedTableInput(Object key, Object value){

       super(key, value);

       this.next = null;

   }

    ChainedTableInput next;

}

class ChainedHashTable extends HashTable {

   ChainedHashTable(int size) {

       super(size);

       // TODO Auto-generated constructor stub

   }

   public int hash(Object key){

       return key.hashCode() % size;

   }

   public Object retrieve(Object key){

       ChainedTableInput p;

       p = (ChainedTableInput) tableInput[hash(key)];

       while(p != null && !p.key.equals(key)){

           p = p.next;

       }

       if (p != null){

           return p.value;

       }

       else {

           return null;

       }

   }

   public void insert(Object key, Object value){

       ChainedTableInput entry = new ChainedTableInput(key, value);

       int k = hash(key);

       ChainedTableInput p = (ChainedTableInput) tableInput[k];

       if (p == null){

           tableInput[k] = entry;

           return;

       }

       while(!p.key.equals(key) && p.next != null){

           p = p.next;

       }

       if (!p.key.equals(key)){

           p.next = entry;

       }

   }

   public double distance(Object key1, Object key2){

       final int R = 6373;

       Double lat1 = Double.parseDouble(Object);

   }

   }

Answer:

Explanation:

Given

The above table definition

Required

Statement to update the table

The syntax of an update statement is:

UPDATE table-name SET column-name = 'value' WHERE column-name = 'value'

Using the above syntax, the right statements is as follows:

The above sets the title to 'With Or Without You' where song id is 200

The above sets the artist to 'Aritha' where song id is 300

The above sets the release year to '2021' for all release year greater than 1990

Answer:

Was this a TROLL?

Explanation:

Answer:

Explanation:

The following code is written in Java. I created both versions of the program that was described in the question. The outputs can be seen in the attached images below. Both versions are attached as txt files below as well.

Answer:

thanks for the point and have a great day

Answer:

Explanation:

The following code is written in Java. It reads every input and checks to see if it is valid. If it is it writes it to the output file.

import java.io.File;

import java.io.FileNotFoundException;

import java.io.FileWriter;

import java.io.IOException;

import java.util.Scanner;

class Brainly {

           public static void main(String[] args) {

               try {

                   File myObj = new File("C:/Users/Gabriel2/AppData/Roaming/JetBrains/IdeaIC2020.2/scratches/input.txt");

                   Scanner myReader = new Scanner(myObj);

                   FileWriter myWriter = new FileWriter("C:/Users/Gabriel2/AppData/Roaming/JetBrains/IdeaIC2020.2/scratches/output.txt");

                   while (myReader.hasNextLine()) {

                       String data = myReader.nextLine();

                       int sum = 0;

                       for (int x = 0; x < 5; x++ ) {

                           sum += data.charAt(x);

                       }

                       int remainder = (sum % 10);

                       System.out.println(remainder);

                       System.out.println(data.charAt(5));

                       if (remainder == Integer.parseInt(String.valueOf(data.charAt(5)))) {

                           System.out.println("entered");

                           try {

                               myWriter.write(data + "\n");

                               System.out.println("Successfully wrote to the file.");

                           } catch (IOException e) {

                               System.out.println("An error occurred.");

                               e.printStackTrace();

                           }

                       }

                       sum = 0;

                   }

                   myWriter.close();

                   myReader.close();

               } catch (FileNotFoundException e) {

                   System.out.println("An error occurred.");

                   e.printStackTrace();

               } catch (IOException e) {

                   e.printStackTrace();

               }

           }

       }

The question is a programming exercise that involves the use of Multi-Dimensional Arrays. See below for the definition of a Multi-Dimensional Array.

A Multi-Dimensional Array is an array that has over one level and at least two dimensions. You could also state that it is an array that contains a matrix of rows and columns.

The array or output table may be created using the following lines of code:


<!DOCTYPE html>

<html>

<head>

 <title>Multi-Dimensional Arrays</title>

 <meta http-equiv="Content-Type" content = "text/html; charset=UTF-8"

</head>

<body>

 <?php

 $cars = array

  (

  array("Volvo", 22, 18),

  array("BMW", 15, 13),

  array("Kia", 5, 2),

  array("Land Rover", 17, 15),

  array("Toyota", 16, 18),

  array("Volkswagen", 20, 10),

  array("Audi", 19, 10),

  array("Mercedes Benz", 50, 5),

  array("Mazda", 11, 12),

  array("Ford", 14, 13),

  );  

  echo "<table border =\"1\" style='border-collapse: collapse'>";

  echo '<tr><th>Brand name</th><th>Number of Stock in Store</th><th>Quantity Sold</th></tr>';

  foreach($cars as $cars)

  {

   echo '<tr>';

   foreach($cars as $key)

   {

    echo '<td>'.$key.'</td>';

   }

   echo '</tr>';

  }

  echo "</table>";

 ?>

</body>

</html>

See the attached for the result of the code when executed.

Learn more about Multi-Dimensional Arrays at:

https://brainly.com/question/14285075

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Answer:

see picture

Explanation:

The result is 55, which can also be verified using the formula:

(n)(n-1)/2 => 10*9/2 = 55

Answer:

The function in Python is as follows:

def factorial(n):

  if n == 1 or n == 0:

      return n

  else:

      return n*factorial(n-1)

Explanation:

This defines the function

def factorial(n):

This represents the base case (0 or 1)

  if n == 1 or n == 0:

It returns 0 or 1, depending on the value of n

      return n

If n is positive, then this passes n - 1 to the factorial function. The process  is repeated until n = 1

  else:

      return n*factorial(n-1)

The items that will be examined when performing a binary search for monkeys are Antelope, Baboon, Cheetah, Elephant, and Giraffe in the first half of the cycle.

A search algorithm known as binary search in computer science, also known as half-interval search, logarithmic lookup, or binary chop, asserts to have discovered the location of a target value within a sorted array.

The target value is compared to the middle element of the array using binary search. A successful approach for finding an item in a sorted list of elements is binary search.

Therefore, in the first half of the cycle, the following objects will be looked at when conducting a binary search for monkeys: antelope, baboon, cheetah, elephant, and giraffe.

To learn more about binary search, refer to the link:

https://brainly.com/question/12946457

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