Can someone help me find the equivalent expressions to the picture below? I’m having trouble
Answer:
Options (1), (2), (3) and (7)
Step-by-step explanation:
Given expression is [tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex].
Now we will solve this expression with the help of law of exponents.
[tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex]
[tex]=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}[/tex]
[tex]=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}[/tex]
[tex]=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}[/tex]
[tex]=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}[/tex]
[tex]=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}[/tex]
[tex]=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }[/tex] [Option 2]
[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex] [Option 1]
[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex]
[tex]=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }[/tex]
[tex]=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }[/tex] [Option 3]
[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }[/tex]
[tex]=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}[/tex] [Option 7]
Therefore, Options (1), (2), (3) and (7) are the correct options.
i need help. Also need the answer in step by step form
Answer: GIVEN : f(x)= -3x+1
f(x)= -5
REQUIRE: x=?
CALCULATION:
f(x)= -3x+1
As, given f(x)= -5.
Hence,
-5= -3x+1
OR
-3x+1= -5
-3x= -5-1
-3x=-6
x= -6/-3
x= 2
Please help me! I will give you Brainlist if you get it right!
Answer:
B
Step-by-step explanation:
Find the area of the circle with r = 36/2 Area1 = π r²
divide Area1 by two since the upper part of the figure is a semi-circle
then finally add and area of the rectangle Area2 = (18)(36)
Total area = Area 1 + Area 2
Answer:
1156.7 cm^2
Step-by-step explanation:
for finding area of semi circle
diameter=36 cm
radius=diameter/2
=36/2
=18 cm
area of semi circle=πr^2/2
=3.14*(18)^2/2
=3.14*324/2
=1017.36/2
=508.68 cm^2
area of rectangle=length*breadth
=18 cm *36 cm
=648 cm^2
area of the figure=area of semi circle + area of rectangle
=508.68 + 648
=1156.68
=1156.7 cm^2
58% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the number of U.S. adults who have very little confidence in newspapers is (a) exactly five, (b) at least six, and (c) less than four.
a) P(5)=
(b) P(x≥6)=
(c) P(x<4)=
Answer:
.216165788
.582225057
.417774943
Step-by-step explanation:
We need to use a binomial distribution here
A.
10C5*.58⁵*(1-.58)⁵= .216165788
B.
I honestly think the fastest way to solve this is adding the probabiblity of exactly 6,7,8,9,10
which means we write
10C6*.58⁶*(1-.58)⁴+10C7*.58⁷*(1-.58)³+10C8*.58⁸*(1-.58)²+10C9*.58⁹*(1-.58)+10C10*.58¹⁰= .582225057
C.
To solve this just take the compliment of answer B
1-.582225057= .417774943
A farmer finds there is a linear relationship between the number of bean stalks, n, she plants and the yield, y, each plant produces. When she plants 30 stalks, each plant yields 31 oz of beans. When she plants 36 stalks, each plant produces 29 oz of beans. Find a linear relationship in the form y=mn+b that gives the yield when n stalks are planted.
Answer:
[tex]y = -\frac{1}{3}m + 41[/tex]
Step-by-step explanation:
Linear equation:
A linear function has the following format:
[tex]y = mn + b[/tex]
In which m is the slope and b is the y-intercept.
When she plants 30 stalks, each plant yields 31 oz of beans. When she plants 36 stalks, each plant produces 29 oz of beans.
This means that these two points belong to the line: (30,31), (36,29).
Finding the slope:
When we have two points, the slope is given by the change in the output divided by the change in the input.
Change in the output: 29 - 31 = -2
Change in the input: 36 - 30 = 6
Slope:
[tex]m = \frac{-2}{6} = -\frac{1}{3}[/tex]
Thus
[tex]y = -\frac{1}{3}m + b[/tex]
Finding b:
We take one of the points and replace on the equation.
(30,31) means that [tex]m = 30, y = 31[/tex]. Thus
[tex]y = -\frac{1}{3}m + b[/tex]
[tex]31 = -\frac{1}{3}(30) + b[/tex]
[tex]31 = -10 + b[/tex]
[tex]b = 41[/tex]
Thus
[tex]y = -\frac{1}{3}m + 41[/tex]
6h+(−8.1d)−14+5d−2.5h
Answer:
3.5h-3.1d-14
Step-by-step explanation:
6h+(−8.1d)−14+5d−2.5h
Combine like terms
6h -2.5h -8.1d +5d -14
3.5h-3.1d-14
The tread life on tires produced at one factory has a standard deviation of sigma equals 4 comma 000 miles. What is the standard deviation of the sampling distribution of the sample means given the sample size is 4
Answer:
[tex]\sigma_x = 2000[/tex]
Step-by-step explanation:
Given
[tex]\sigma = 4000[/tex]
[tex]n = 4[/tex]
Required
The sample standard deviation
The sample standard deviation cannot be calculated directly. However, we can use the value of standard error because standard error approximates to sample standard deviation.
So, we have:
[tex]\sigma_x = \frac{\sigma}{\sqrt n}[/tex]
[tex]\sigma_x = \frac{4000}{\sqrt 4}[/tex]
[tex]\sigma_x = \frac{4000}{2}[/tex]
[tex]\sigma_x = 2000[/tex]
Hence, the sample standard deviation is 2000
What is the distance between 3x - 5y + 3 =0 and 6x - 10y -12 =0
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Answer:
(9/34)√34 ≈ 1.543
Step-by-step explanation:
The second equation can be rewritten as ...
6x -10y -12 = 0
3x -5y -6 = 0
3x -5y = 6
__
The formula for the distance from point (x, y) to line ax+by+c=0 is ...
d = |ax+by+c|/√(a²+b²)
Then the distance from a point to the first line is ...
d = |3x -5y +3|/√(3² +(-5)²)
We know from the rearrangement of the second equation that points on its line satisfy (3x-5y) = 6. Substituting this value for (3x -5y) in the distance formula gives ...
d = |6 +3|/√34
Simplifying and rationalizing the denominator gives a distance of ...
d = (9/34)√34 ≈ 1.543
An item was marked down 64% from its original price, x. The amount discounted was $30. Which equation can be
used to find the original price?
0.64(x) = 30
0.64(30) = x
30 +0.64 = x
x + 0.064 = 30
Answer:
0.64(x) = 30
Step-by-step explanation:
Hope that's correct.
Pls help I need a good grade
Hello~
I used Cymath for this!
https://www.cymath.com/answer?q=(0.4%20*10%5E-6)%20(0.7%20*%2010%5E-2)
In short the answer is B.
The link has the step by step answers!
I highly recommend this sight by the way, its always correct!
Ary~
96 sq meters
144 sq meters
84 sq meters
102 sq meters
Pls show work I get different answers from people every time
Answer:
84 sq meters
Step-by-step explanation:
1. Approach
In order to solve this problem, one will have to divide the figure up into simple shapes. A picture is attached showing how the shape is divided up for this answer. Find the area of each region, then add up the results to find the total area.
2. Area of Region 1
As one can see, the length of (Region 1), as given is (6), the width is (3). To find the area multiply the length by the width.
Length * width
6 * 3
= 18
3. Area of Region 2
In (Region 2), the length is given, (12). However, one must find the width, this would be the size of the total side, minus the width of (Region 1). Multiply the length by the side to find the area.
Length * width
= 12 * (8 - 3)
= 12 * 5
= 60
4. Area of Region 3
In (Region 3), the length of the figure is (2), the width is (3). To find the area, multiply the length by the width.
Length * width
= 2 * 3
= 6
5. Total area
Now add up the area of each region to find the total rea,
(Region 1) + (Region 2) + ( Region 3)
= 18 + 60 + 6
= 84
Ryder is building a workbench.
The top of the workbench is a rectangular piece of plywood that is 6.25 feet long and 1.83 feet wide.
Part A
Round the length and width to the nearest whole number.
Then estimate the perimeter of the workbench.
Which of the following equations models this estimate of the perimeter?
A. 6 + 6 + 2 + 2 = 16
B. 6 × 2 = 12
C. 7 + 7 + 2 + 2 = 18
D. 7 × 2 = 14
Part B
Round the length and width to the nearest tenth.
Then estimate the perimeter of the workbench.
Which of the following equations models this estimate of the perimeter?
A. 6.2 + 6.2 + 1.8 + 1.8 = 16
B. 6.2 × 1.8 = 11.16
C. 6.3 + 6.3 + 1.8 + 1.8 = 16.2
D. 6.3 × 1.8 = 11.34
Solve the inequality: 7x + 5 > 2. - 35 Show all work on the "Scratch pad".
It took Fred 12 hours to travel over pack ice from one town to another town 360 miles away. During the return journey it took him 15 minutes
Step-by-step explanation:
what is your question please
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct
This question is incomplete, the complete question is;
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.
In other words, how many 5-tuples of integers ( h, i , j , m ), are there with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?
Answer:
the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120
Step-by-step explanation:
Given the data in the question;
Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1
this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.
So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'
Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;
[tex]\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right][/tex]
= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]
= [( n + 4 )!] / [ 5!( n-1 )! ]
= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120
Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120
Please help it’s a riddle can you find the correct answer
Solve the system of equations Y=-2x+5 and y=x^2+3x+9
I think
x= -4, -1 and y=13, 8
(-4, 13) and (-1, 8)
If x = 35°, which two lines can be proven parallel?
a)n and o
b)l and m
c)n and l
d)m and o
Answer:
a) n and o
Step-by-step explanation:
by the concept of corresponding angles, angles that are equal when a line intersects 2 parallel lines .
l is the line that intersects n and o, and since x = 35, theyre corresponding angles resulting in n and o being parallel
Answer:
a) n and o
Step-by-step explanation:
Corresponding angles
For the following equation, determine the values of the missing entries. Reduce all fractions to lowest terms.
x2 + y2 = 49
Note: Each column in the table represents an ordered pair. If multiple solutions exist, you only need to identify one.
Table:
X 0 [ ] 16 9 [ ]
Y [ ] √2 [ ] [ ] -√5
Answer:
Following are the solution to the given question:
Step-by-step explanation:
Given:
[tex]\to x^2+y^2=49[/tex]
When
[tex]x=0\\\\0^2+y^2=49\\\\y^2=49\\\\y= \pm 7[/tex]
So, order pass [tex](0,\pm 7)[/tex]
Similarly When
[tex]y=0\\\\x^2+0^2=49\\\\x^2=49\\\\x= \pm 7[/tex]
So, order pass [tex](\pm 7,0)[/tex]
[tex]x \ \ \ \ \ \ \ 7 \ \ \ \ \ \ \ -7\ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ 0 \\\\y \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ 7 \ \ \ \ \ \ \ -7 \\\\[/tex]
Find the area of the figure round to the nearest tenth
Answer:
Area of given figure = 60.8 mm² (Approx.)
Step-by-step explanation:
Given:
Length of figure = 9.3 mm
Width of figure = 7.8 mm
Height of triangular cut = 3 mm
Find:
Area of given figure
Computation:
Area of given figure = [(Length)(Width)] - Area of triangle
Area of given figure = [(9.3)(7.8)] - [(1/2)(b)(h)]
Area of given figure = [(9.3)(7.8)] - [(1/2)(7.8)(3)]
Area of given figure = [(9.3)(7.8)] - [(1/2)(7.8)(3)]
Area of given figure = [72.54] - [(1/2)(7.8)(3)]
Area of given figure = [72.54] - [11.7]
Area of given figure = 60.8 mm² (Approx.)
2x -20 = -30
What is x?
The vertices of a triangle are located on a coordinate grid as follows: A (2,2) ,B (2,-6) , and C (-5,-6) . What is the area of ABC ? A. 6 square units B. 12 square units C. 28 square units D. 56 square units
The perimeter of a square garden is 12 km. Find its area.
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.
cot x sec4x = cot x + 2 tan x + tan3x
(sin x)(tan x cos x - cot x cos x) = 1 - 2 cos2x
1 + sec2x sin2x = sec2x
sine of x divided by one minus cosine of x + sine of x divided by one minus cosine of x = 2 csc x
- tan2x + sec2x = 1
Answer:
Step-by-step explanation:
1)
[tex]cot x sec^4 x = cotx + 2tanx + tan^3 x[/tex]
[tex]RHS =[/tex]
[tex]=\frac{cosx}{sinx} + 2 \frac{sinx }{cosx} + \frac{sin^3x }{cos^3x}\\\\[/tex]
[tex]= \frac{cosx(cos^3x) + 2sinx(sinx \ cos^2x ) + sin^3x(sinx)}{sinx \ cos^3x}\\\\[/tex] [tex][\ taking LCM \ ][/tex]
[tex]=\frac{cos^4x + 2sin^2xcos^2x +sin^4x }{sinx cos^3x}[/tex]
[tex]= \frac{(sin^2 x + cos^2x)^2 }{sin x \ cos^3 x}[/tex] [tex][ \ a^4 + 2a^2b^2 + b^4 = (a^2 + b^2 ) ^2 \ ][/tex]
[tex]= \frac{1}{sinx \ cos^3 x}\\\\= \frac{1 \times cosx}{sinx \times cos^3x \times cosx}[/tex] [tex][ \ multiplying\ and \ dividing \ by \ cosx \ ][/tex]
[tex]= \frac{cosx}{sinx} \times \frac{1}{cos^4x}\\\\=cot x \ sec^4 x[/tex]
[tex]= LHS[/tex]
2)
[tex]sin x \ ( tanx \ cosx - cotx \ cosx) = 1 - 2cos^2x[/tex]
[tex]LHS =[/tex]
[tex]=sinx( [ \frac{sinx}{cosx} \times cosx)] - [ \frac{cosx}{sinx}\times cosx] )\\\\= sinx (sinx - \frac{cos^2x}{sinx})\\\\=sin^2x - cos^2 x\\\\=(1 - cos^2x ) -cos^2 x[/tex] [tex][ \ sin^2x = 1 -cos^2 x \ ][/tex]
[tex]= 1 -cos^2x - cos^2 x \\\\= 1 - 2cos^2x \\\\=RHS[/tex]
3)
[tex]1 + sec^2x \ sin^2x = sec^2 x[/tex]
[tex]LHS =[/tex]
[tex]= 1 +sec^2x \sin^2x \\\\= 1 + (\frac{1}{cos^2x} \times sin^2x )\\\\= 1 + \frac{sin^2 x}{cos^2x}\\\\= 1 + tan^2x \\\\= sec^2 x\\\\=RHS[/tex]
4)
[tex]\frac{sinx}{1 -cosx} + \frac{sinx}{1+cosx} = 2 \ cosec x[/tex]
[tex]LHS =[/tex]
[tex]=\frac{sinx}{1 -cosx} + \frac{sinx}{1+cosx} \\\\= \frac{sinx(1 +cosx)}{(1-cosx)(1+cosx)} + \frac{sinx(1-cox)}{(1+cosx)(1-cosx)}\\\\= \frac{sinx +sinx\ cosx}{(1 - cos^2x)} + \frac{sinx - sinx \ cosx}{1 - cos^2x}\\\\=\frac{sinx + sinx \ cosx + sinx - sinx \ cosx}{1 - cos^2x}\\\\=\frac{2sinx}{sin^2x}\\\\=\frac{2}{sinx}\\\\=2 cosec\ x\\\\=RHS[/tex]
5)
[tex]- tan^2 + sec^2 x = 1\\\\[/tex]
[tex]sin^2 x + cos^2 x = 1\\\\\frac{sin^2x }{cos^2x} + \frac{cos^2x}{cos^x} = \frac{1}{cos^2x}\\\\tan^2x + 1 = sec^2x \\\\1 = sec^2 - tan^2x \\\\-tan^2x + sec^2 x = 1[/tex]
Describe the shape that would result from a horizontal slice of the figure below.
PLEASE ANSWER FAST ILL MARK BRAINLEIST.!!!
Answer:
A triangular prism and a trapezoidal prism, if I understand the question
Step-by-step explanation:
There wound be a trapezoid and a triangle if you cut it horizontally. If you mean vertically, it would be a right triangular prism
The manager of a furniture factory finds that it costs $3000 to manufacture 80 chairs in one day and $4800 to produce 280 chairs in one day. (a) Express the cost C (in dollars) as a function of the number of chairs x produced, assuming that it is linear. C
9514 1404 393
Answer:
C = 9x +2280
Step-by-step explanation:
The 2-point form of the equation for a line can be a place to start.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
C = (4800 -3000)/(280 -80)(x -80) +3000 . . . . . use given values
C = 1800/200(x -80) +3000 . . . . simplify some
C = 9x -720 +3000 . . . . eliminate parentheses
C = 9x +2280
NO LINKS!!!
What is the volume of this solid?
220 cubic units.
Answer:
Solution given:
for small cylinder
r=1
and for large cylinder
R=5+1=6
height for both [h]=2
Now
Volume of solid=πR²h-πr²h=πh(R²-r²)
=3.14*2(6²-1²)=219.8 =220 units ³.
Small cylinder is r=1
Large cylinder is R= 5+1 =6
Height (h) =2
Volume of solid,
→ πR²h-πr²h
→ πh(R²-r²)
→ 3.14 × 2(6²-1²)
→ 219.8
→ 220 cubic units
Calculating area of rectangle.
Your measurements Another student's measurements
Length (cm) 20.70 20.74
Width (cm) 10.44 10.46
Area (cm2) ________ ________
Required:
Why might two students have different calculated areas when measuring the same rectangle?
Answer:
Your measurements; Area = 216.108 cm²
Another student's measurements; Area = 216.9404 cm²
- Difference in area could be as a result of human error or perhaps that they made use of different measuring tools.
Step-by-step explanation:
For Your measurements;
Length of rectangle = 20.70 cm
Width of rectangle = 10.44 cm
Area of rectangle is given by; A = length × width = 20.7 × 10.44 = 216.108 cm²
For Another student's measurements;
Length of rectangle = 20.74 cm
Width of rectangle = 10.46 cm
Area = 20.74 × 10.46
Area = 216.9404 cm²
The areas they both obtained are not of equal values and this could be as a result of human error or perhaps that they used different measuring tools.
Find the distance between the points (6,5) and (4,-2). use of the graph is optional
Answer ? Anyone
Answer:
√53
Step-by-step explanation:
Distance between two points =
√(4−6)^2+(−2−5)^2
√(−2)^2+(−7)^2
= √4+49
=√53
= 7.2801
Hope this helps uwu
9514 1404 393
Answer:
option 2: √53
Step-by-step explanation:
The distance formula is useful for this:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((4-6)² +(-2-5)²) = √((-2)² +(-7)²) = √(4+49)
d = √53
The distance between the given points is √53.
Compute 7,953,000 / 1000.
Answer:
The answer is 7,953.
Step-by-step explanation :
When you divide like this you are basically being asked how many times something can go into something else. In this case, we are being asked to calculate how many times 1000 can go into 7,953,000. You can use basic math skills or do long division.
I'm going to go with the easier way, basic math skills.
There are three 0's in the back of the number 7,953,000, and notice 1000 has three 0's as well in the back. When you divide those three 0's in the back of both numbers basically cancel out. Well, what does that leave us with?
7953 is what were left with. The answer is 7,953.