Tina bought a painting while on vacation in 2009. The table below shows the value of the painting in2009,2010,and2011. If this trend continues, what will be the value of the painting in 2030?

Year: 2009, 2010, 2011
Value of painting: $75, $88.50, $104.43

A) $1,915.42
B) $2,044.19
C) $2,103.73
D) $2.279.55
E) $2,424,28

(The Year and value thing is a table, the first one listed on year goes with the first one listed on the value and so on)

Please help!!

Answers

Answer 1

Answer:

The answer is E

Step-by-step explanation:

We first are going to look at our first term on the table(the number that comes up first) which is $75.

Then we have to find the common factor. So, you divide the second number by the first number( 88.50 divided by 75 which gets us 1.18).

Now, since we found the first term and the common factor, we are going to have to find the exponent for our f(x) equation.  

We know that she bought the painting in 2009! Now the problem is asking how much the painting will cost in 2030. So, you will subtract 2030-2009 which gets you 21! So 21 is your exponent!

Equation:   F(x)= 75(1.18) ^21

The answer that you get is:    $2424.28

Let me know if you have any questions!

:)

Answer 2

The value of the painting in 2030 would be $2424.28.

What is the value of the painting in 2030?

From the given table, it can be observed that the painting increases in value over the years. Increase in value of the painting from 2009 to 2010 = ($88.50 / $75) - 1 = 18%.

The formula for determining the future value of the painting is:

FV = P (1 + r)^nm

FV = Future value

P = Present value

R = interest rate

N = number of years

The value of the painting in 2030 = $75 x (1.18)^21 = $2424.28

To learn more about future value, please check: https://brainly.com/question/18760477


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Answer:

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Nothing further can be done with this topic. Please check the expression entered or try another topic.

6

centimeters

...................................................................................................................................................

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Answers

Answer:

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Step-by-step explanation:

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[tex]\huge\red{\boxed{\tt{\colorbox{pink}{ANSWER:}}}}[/tex]

[tex] \frac{ {x}^{12} - {6x}^{10} + {15x}^{8} - {20x}^{6} + {15x}^{4} - {6x}^{2} + 1 }{ {x}^{6} } [/tex]

[tex]\huge\red{\boxed{\tt{\colorbox{pink}{Solution:}}}}[/tex]

[tex](x - 1 \div x) {}^{6} [/tex]

Arrange the powers

[tex] \frac{x {}^{12} - {6x}^{10} + {15x}^{8} - {20x}^{6} + {15x}^{4} - {6x}^{2} + 1 }{ {x}^{6} } [/tex]

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Answer:

[tex] \frac{10}{53 \times 46 \times 26} [/tex]

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The probability of matching the number drawn on the gold ball is

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This is your answer

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Answer:

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The long division work is in the image.

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Answers

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