Answer:
7.28 m/s^2.
Explanation:
To find the magnitude of the resultant acceleration of the particle, we can use the equation for Newton's second law of motion:
F = ma
Where F is the resultant force, m is the mass of the particle, and a is the resultant acceleration.
Since the forces are acting at a 90 degree angle to each other, we can treat them as two separate forces and use the Pythagorean theorem to find the magnitude of the resultant force:
F = sqrt((300 N)^2 + (500 N)^2)
= sqrt(90000 N^2 + 250000 N^2)
= sqrt(340000 N^2)
= sqrt(340000) N
= 582.67 N
We can now use this value for the resultant force to find the resultant acceleration:
a = F/m
= 582.67 N / 80 kg
= 7.28 m/s^2
Therefore, the magnitude of the resultant acceleration is 7.28 m/s^2.
The _____________ variable is observed, measured, and affected by the independent variable.
Answer: It would be the dependent variable.
Explanation:
The dependent variable is limited and can be affected by the changes and manipulation of the independent variable.
What is the origin behind the term " cell phone "
Answer:
Rae Young at Bell Labs. They diagrammed a network of wireless towers into what they called a cellular layout. Cellular was the chosen term because each tower and its coverage map looked like a biological cell. Eventually, phones that operated on this type of wireless network were called cellular phones.
Explanation:
What do you call the shot that starts on the right side and continues through to the left
side for a right handed player?
Answer:
When a right-handed golfer’s tee shot curves to far to the left, the shot is described as a “hook.” This shot typically occurs when the club head moves across the ball from left to right, imparting side-spin on the ball
please answer soon
a car is traveling along the highway at a constant velocity, what must be true about all the forces acting on the car?
Look at the circuit diagram. A rectangular box of lines with the long horizontal side. The left side has a circle with an X in it. The top side from left has a small circle connected to another small circle by a horizontal line and then a circle with an X in it. The right side from the top has a small circle connected to another small circle by a horizontal line and then a circle with an X in it. The bottom side has a stack of vertical lines, which are from left short, very short, short, very short. What does the diagram show? one battery, two light bulbs, and three resistors one battery, two switches, and three light bulbs one switch, one resistor, and three light bulbs one switch, one light bulb, and three batteries
Answer:
it is b on edge not d, well atleast for me it was b
Explanation:
Answer:
B) one battery, two switches, and three light bulbs
Explanation:
______ charges repel each other.
Answer:
like I commented it yesterday can i have brainiest
Explanation: oh and HI
Answer:
Like
Explanation:
I put it before but my answer got deleted
a transfer of energy without a transfer of mass describes what?
Explanation:
Wave motion
ex...longitudinal wave.
plzz help mee
What do you notice about how we write out the symbols for the different elements?
Many of the symbols are the first one or two letters of the element’s name in English. The first letter of a symbol is always written as a capital letter (uppercase) and the second letter as a small letter (lowercase).
For example
(i) hydrogen, H
(ii) aluminium, Al and not AL
(iii) cobalt, Co and not CO.
Symbols of some elements are formed from the first letter of the name and a letter, appearing later in the name.
Examples are: (i)chlorine, Cl, (ii) zinc, Zn etc.
Other symbols have been taken from the
names of elements in Latin, German or Greek.
For example, the symbol of iron is Fe from its Latin name ferrum, sodium is Na from natrium, potassium is K from kalium. Therefore, each element has a name and a unique chemical symbol.
A Navy vessel is traveling due north during wartime. A torpedo has been launched by an enemy directly toward the stern (rear) of the vessel. Can the vessel outrun the torpedo if both continue in a straight line due north?
A) Yes, the Navy vessel is faster
B) No, the Navy vessel is slower
C) Maybe, since both travel at the same speed
D) Maybe, based on the temperature of the water
Answer:
The correct option is;
B) No, the Navy vessel is slower
Explanation:
The speed of some torpedoes can be as high as 370 km/h. The average speed of a fast Navy vessel is approximately 110 km/h
Therefore, the torpedoes travel approximately 3 times as fast as the (slower) Navy vessel, such that the torpedo covers three times the distance of the Navy vessel in the same time and therefore, if the Navy vessel and the torpedo continue in a straight line (in the same direction) due north the vessel can not outrun the torpedo
Therefore, no the Navy vessel travels slower than a torpedo.
What happens to energy when it is consumed?
Answer:
It converts to other energy
A point source emits sound waves with a power output of 135 watts. What is the sound level (in dB) at a distance of 10 m
Answer:
The sound level of the point source at a distance of 10 meters is approximately 110.294 decibels.
Explanation:
First, we calculate the intensity ([tex]I[/tex]), in watts per square meter, by the Inverse-Square Law:
[tex]I= \frac{\dot W}{4\pi\cdot r^{2}}[/tex] (1)
Where:
[tex]\dot W[/tex] - Power, in watts.
[tex]r[/tex] - Radius, in meters.
And the sound intenity level ([tex]L[/tex]), in decibels, is expressed by:
[tex]L = 10\cdot \log_{10} \frac{I}{I_{o}}[/tex] (2)
Where [tex]I_{o}[/tex] is the reference sound intensity, in watts per square meter.
If we know that [tex]\dot W = 135\,W[/tex], [tex]r = 10\,m[/tex] and [tex]I_{o} = 10^{-12}\,\frac{W}{m^{2}}[/tex], then we find that sound level at a distance of 10 meters is:
[tex]I= \frac{\dot W}{4\pi\cdot r^{2}}[/tex]
[tex]I = 0.107\,\frac{W}{m^{2}}[/tex]
[tex]L = 10\cdot \log_{10} \frac{I}{I_{o}}[/tex]
[tex]L \approx 110.294\,dB[/tex]
The sound level of the point source at a distance of 10 meters is approximately 110.294 decibels.
HELP ME ASAP PLZ!
What is the relationship between an electromagnetic wave and the vibrations of the electric and magnetic fields it moves through.
PLEASE HELP !!!
Which statement correctly describes protons?
A.
They have no charge and are present in the nucleus of an atom.
B.
They have a negative charge and travel around the nucleus of an atom.
C.
They have a positive charge and travel around the nucleus of an atom.
D.
They have a positive charge and are present in the nucleus of an atom along with the neutrons.
Answer:
A
Explanation:
The answer is A because proton number is the same as atomic number
A charge of +3.5 nC and a charge of +5.0 nC are separated by 40 cm. Find the equilibrium position for a -6.0 nC charge.
Answer: [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.
Explanation:
Given
The magnitude of the first charge is [tex]Q_1=3.5\ nC[/tex]
The magnitude of the second charge is [tex]Q_2=5\ nC[/tex]
[tex]-6\ nC[/tex] charge must be placed in between the two charges to establish equilibrium
The electrostatic force is given by
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Equilibrium will be established when force by both the charges balance out each other. Suppose [tex]-6\ nC[/tex] is placed at a distance of [tex]x[/tex] cm from [tex]3.5\ nC[/tex] . So, we can write
[tex]\Rightarrow \dfrac{k(3.5)(-6)}{x^2}=\dfrac{k(5)(-6)}{(40-x)^2}[/tex]
Canceling similar terms
[tex]\Rightarrow \left [ \dfrac{40-x}{x}\right ]^2=\dfrac{10}{7}\\\\\Rightarrow \dfrac{40-x}{x}=\sqrt{\dfrac{10}{7}}=1.195\\\\\Rightarrow 40-x=1.195x\\\Rightarrow 40=2.195x\\\Rightarrow x=18.22\ cm[/tex]
Thus, the equilibrium position is [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.
Answer:
What school do you go to?
Explanation:
The National Aeronautics and Space Administration (NASA) studies the physiological effects of large accelerations on astronauts. Some of these studies use a machine known as a centrifuge. This machine consists of a long arm, to one end of which is attached a chamber in which the astronaut sits. The other end of the arm is connected to an axis about which the arm and chamber can be rotated. The astronaut moves on a circular path, much like a model airplane flying in a circle on a guideline. The chamber is located 20.0 m from the center of the circle. At what speed must the chamber move so that an astronaut is subjected to 5.64 times the acceleration due to gravity
Answer:
w = 1,662 rad / s, v = 33.25 m / s
Explanation:
This this exercise indicates that the acceleration felt by the astronauts is
a = 5.64 g
in a circular motion the centripetal acceleration is
a_c = v²/ r
angular and linear variables are related
v = w r
we substitute
a_c = w² r
we finally have
5.64 g = w² r
w² = 5.64 g / r
let's calculate
w = [tex]\sqrt{ \frac{5.64 \ 9.8}{20.0} }[/tex]
w = 1,662 rad / s
linear velocity is
v = w r
v = 1,662 20
v = 33.25 m / s
A net force of 40 N south acts as an object with a mass of 20kg. What is the object's acceleration
Answer:
a = 2 m/s²
Explanation:
Given: 20 g, 40N
To find: Acceleration (a)
Solution: To find the acceleration (A), divide the force by the weight
A = F ÷ m
= 40 ÷ 20
= 2 m/s²
Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.
A 30 gram ball rolls along a flat surface at a constant speed in the same direction over 4 meters in 20 seconds. Which is the speed of the
ball? (speed = distance = time)
A. 0.2 meters per second
OB. 0.5 meters per second
c. 20 meters per second
D. 80 meters per second
Please answer this FAST!
HELPPP
A 1.50-kg cart rolls along a horizontal table at a constant speed of 1.70 m/s. A ball of soft putty is dropped from a stationary hand onto the cart as it passes underneath. If the speed of the cart is reduced to 1.53 m/s, calculate the mass of the ball of putty. This collision is completely inelastic
Answer:
0.17 kg
Explanation:
mc = mass of cart
mb = mass of ball
vc = speed of cart before collision
vb = speed of ball before collision (vb = 0)
v' = speed of cart and ball after collision
mc . vc + mb . vb = (mc + mb) . v'
(1.5)(1.7) + mb(0) = (1.5 + mb) . 1.53
2.55 + 0 = (1.5 + mb) . 1.53
2.55/1.53 = 1.5 + mb
5/3 = 3/2 + mb ( I change it to fraction)
mb = 5/3 - 3/2 = 10/6 - 9/6 = 1/6 kg
mb = 1/6 kg = 0.17 kg
PLSS HELPP
Are humans evolving? What will humans look like in 100,000 years in the future or longer?
Answer:
yes
Explanation:
PLEASE EXPLAIN IN TWO PARAGRAPHS (A PARAGRAPH IS 4-5 SENTENCES) SOME HEALTHFUL TIPS THAT CAN HELP PREVENT YOU FROM GETTING PHYSICAL FITNESS INJURIES.
Answer:
A workout injury can happen to anyone, no matter your experience or fitness level. People hurt themselves in all kinds of ways when they work out. Even walking can cause an injury. But you can significantly cut your risk of getting hurt by following certain workout precautions. There are simple steps that can help keep you injury-free during your workout.
Every workout should begin with a warm-up and end with a cool-down period. A warm-up helps your body get ready for exercise. It gradually increases your heart rate and loosens your muscles and joints. Cool-down after you work out so, it brings your heart rate back to normal. Walking for 5 to 10 minutes after you work out is one way to cool down. Do dynamic stretching before and after you work out. This will help increase flexibility. Don't push yourself too hard. As your fitness abilities increase and you will be able to challenge yourself more.
Hope this helps
Maintaining physical fitness is very important in today's world. Each and everyone should be involved in physical fitness.nowaday people are so busy with their work that they have forgotten health is wealth.
Even if we get engaged in physical fitness activity we can some time get insuries . some of tips that can help prevent from getting physical fitness injury, warm up exercises should be done before exercise to avoid muscle strength.safety precautions should be taken if you are dealing with heavy objects .
hence we should maintain physical fitness with getting rid of injury that may occur
mark me
what is the main function of the circulatory system
Answer:
B
Explanation:
Answer:
The main function of the circulatory system is to carry nutrients to cells and waste away from cells.
Explanation:
Calculate the Kinetic energy of: 1. a rabbit weighing 10
kg moving at a speed of 5 m/s.
Answer:
125
Explanation:
use the formula e=1/2mv² and use m=10 and v=5
this produces the equation e=1/2x10x25=125
dont forget the units (J) ;)
Answer:
125J
Explanation:
K.e=1/2mv^2
=1/2(10)(5)^2
=125J
when do i know if the acceleration (a) in newtons second law is 0?
Answer:
When the sum of all forces applied to the object is 0.
Explanation:
N2L states that net force equals an object's mass times its acceleration (F = ma). If the net force is 0, the acceleration of the object is 0.
On the second note, when an object has 0 acceleration (which means it has a constant velocity), it is in equilibrium (N1L).
What will be the final velocity of a rock if we drop it off of a bridge and it strikes the ground 2.8s later (ignoring air resistance)?
An RC circuit consists of a resistor with resistance 1.0 kΩ, a 120-V battery, and two capacitors, C1 and C2, with capacitances of 20.0 μF and 60.0 μF, respectively. Initially, the capacitors are uncharged; and the switch is closed at t = 0 s. How much charge will be stored in eah capacitor after a long time has elapsed (capacitor one 2.4 x 10^-3 C) (capacitor 2 7.2 x 10^-3 C) and what will the total charge on both capacitors two time constants after the switch is closed? (8.3 x 10^-3)
Answer:
[tex]Q_t= 8.3 * 10^3 C[/tex]
Explanation:
From the question we are told that:
Resistor [tex]R=1000ohms[/tex]
Voltage [tex]v=120_V[/tex]
Capacitance of c_1 [tex]c_1=20 \mu F[/tex]
Capacitance of c_2 [tex]c_2=60 \mu F[/tex]
Time [tex]t=0[/tex]
Generally the equation for charges is mathematically given by
[tex]For C_1\\Charge\ on\ C_1 = CV = 20*120 = 2400 μC = 2.4 x 10^-3 C\\Charge\ on\ C_1 = 2400 μC = 2.4 x 10^-3 C\\Charge\ on\ C_1 = 2.4 x 10^-3 C\\[/tex]
[tex]ForC_2\\Charge on C_2 = 60*120 =7200 μC = 7.2 x 10^-3\\Charge on C_2 = 7.2 x 10^-3[/tex]
Generally the equation for voltage across capacitors is mathematically given by
[tex]V_c(t)=V(1-e^{-t/RC})[/tex]
[tex]C=C_1+C_2=80 \mu f\\t=2RC=>160000s[/tex]
[tex]V_c(t)=120(1-e^{-(160000)/1000*(80)})[/tex]
[tex]V_c(t)=103.7598[/tex]
Generally the equation for charges is mathematically given by
[tex]Q1(t) = C1Vc(t)\\Q1(t) = 20*103.7598\\Q1(t) = 2075.196\\\\Q2(t) = 60*103.7598\\Q2(t) = 6225.6\\[/tex]
Generally the equation for total charges [tex]Q_t[/tex] is mathematically given by
[tex]Q_t=Q1(t)+Q2(t)[/tex]
[tex]Q_t= 8.3 * 10^3 C[/tex]
The semi-major axis of this ellipse is 8.8 cm, and the distance from one of the foci to the
center is 4.4 cm. What is the eccentricity of the ellipse?
The eccentricity is 0.5
What is the power of a circuit with voltage 12 V and current 8.0
A?
Answer:96 W
Explanation:
Minh spent the weekend on his Wii and now has carpal tunnel syndrome. His 120 V outlet has an electrical current of 8A. What is the resistance in the Wii?
The resistance is 15 ohms.
Also, it's dissipating 960 watts whenever it's turned on. So it's almost as hot as a toaster, and Minh no longer has hands.
is silver magnetic or not ?
Answer:
Yes, but its magnetic power is very weak so its not that noticeable to the average person whos not paying attention.
How do you rationalize the tension being used in Tennis Racket strings using the concept of impulse and momentum?
Answer:
The momentum, ΔP, and therefore, kinetic energy given to the ball in a serve is the result of the product of the tension force, 'F', in the string and the time of contact, Δt, between the ball and the string
ΔP = F × Δt
Explanation:
The impulse, ΔP, is the produce of the force, 'F', applied to a body for a given period of time, Δt', that gives motion to the body, and it is equal to the change of momentum of the body
ΔP = F × Δt
The momentum, 'P', of a body is the product of the mass, 'm', of the body and its velocity, 'v'
P = m × v
Tension is the axial pulling force of a string
T = Axial Force, F[tex]_{axial}[/tex]
The tension used in Tennis Racket strings is between 40 to 65 lbs.
When high tension is used in the string, the string is taut, and the contact duration between the Racket string and the ball is minimal, and the player needs to use more force to obtain a high momentum, and therefore, energy in the ball, which reduces control, and increase stress, as force is more emphasized
When low tension is used in the string, the Tennis Racket strings are more elastic. During a serve, the ball pushes the strings further back into the racket, such that the ball spends more time in contact with the string, (Δt is larger), and therefore, the impulse, F·Δt = ΔP, given to the ball is larger, therefore, the ball has a larger change in momentum, and therefore more energy in the intended direction.
However, a very slackened string will increase the increase area and time (large Δt) of contact of the ball and the racket such that the force given to the ball, F = ΔP/(large Δt) is reduced and therefore reduce the likelihood of gaining points from a serve against an opponent with a much forceful return of a serve.