unlike acceleration and velocity, speed does not need to specify

Answer:Gamma-Ray Telescopes

Explanation:

Gamma-Ray Telescopes are used for detecting the gamma-ray part of the Electromagnetic Spectrum. These can detect very high-energy gamma-rays from radio galaxies, gamma-ray bursts from stars, supernovae events, and Quasars.

Radio Waves Telescope

Answer:its 3 and 5

Explanation:

j

Carbon -14 is a dating method that is applicable to only samples of organic origin which are less than 50,000 years old.

When living things contain carbon- 14. Carbon - 14 is a radioactive isotope of carbon that decays by beta emission. As long as a plant or animal is alive, there is a balance between its intake and output of carbon -14.

However, when the plant or animal dies, this carbon - 14 begins to decay. The half life of carbon - 14 is 5700 years and it can be used to measure the age of materials or organic origin that are less than 50,000 years old.

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Answer:

Uranus

Explanation:

brainliest please?

Answer: gravity

Explanation:

Answer:

b i think

Explanation:

hope this helps

Answer:  A B C or D which one

Explanation:

Hi there!

We can use impulse for this situation:

I = Δp = mΔv

Impulse = Force × time, so:

I = 63.9(24) = 1533.6 Ns

Find force by dividing by time:

I/t = 1533.6/1.2 = 1278 N

AU is the distance from the earth to the sun, and solar mass represents a measurement equal to the mass of our sun.

The units applied in astronomy is quite different from the units applied in daily life. The unit called astronomical units (AU) describes the distance from the earth to the sun. The unit solar mass represents the mass of the sun and is taken to be equal to 1.989 x 10^30 kilograms.

Therefore, the difference between the AU and solar mass is that; AU is the distance from the earth to the sun, and solar mass represents a measurement equal to the mass of our sun.

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Density of water=1g/cm^3

Now all metals has greater mass in comparison to water.

[tex]\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}[/tex]

[tex]\\ \sf\longmapsto Density\propto Mass[/tex]

Gold has higher mass hence it will cause the biggest rise.

Option A

Silver will cause biggest rise in water

Density of an object is a measure of its mass per unit volume.

density = mass / volume

since all have same mass , so metal which have higher volume will cause the biggest rise in water level .

since , density is inversely proportional to volume , hence material having low density will have higher volume

hence , silver will cause biggest rise in water

correct option B) Silver

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Answer:

Identify the name of the individual, group or institution that created the website. A reliable website should clearly state the name of its creator. Generally, websites created by government institutions (.gov) and educational institutions (.edu) are considered more reliable.

speed- the rate something moves or operates

Can I have brainlist please

The Speed are distance covered by the object in unit time.The S.I unot of speed is metre per second written as m/sec.It is a scalar quantity.

The speed is measured in metres per second ( ms- ¹ )

Where denoted by s

The distance travelled is measured in metres (m) and denoted by d

t is the amount of time spent and measured in seconds s

Answer:

C.69 kJ

Explanation:

kinetic energy

[tex] = 1 \div 2mv {}^{2} [/tex]

The ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].

The given parameters;

The electrostatic force between the two electrons is calculated as follows;

[tex]F_c = \frac{kq^2}{r^2} \\\\[/tex]

The gravitational force between the two electrons is calculated as follows;

[tex]F_g = \frac{Gm_e^2}{r^2}[/tex]

The ratio of the electric force to the gravitational force between the two electrons is calculated as follows;

[tex]\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{1}{\frac{Gm^2}{r^2} } \\\\\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{r^2}{Gm^2} \\\\\frac{F_c}{F_g} = \frac{kq^2}{Gm^2}\\\\[/tex]

[tex]\frac{F_c}{F_g} = \frac{(8.99 \times 10^9) \times (1.6 \times 10^{-19}))^2}{(6.67 \times 10^{-11} ) \times (9.11 \times 10^{-31})^2} \\\\\frac{F_c}{F_g} = 4.2 \times 10^{42}[/tex]

Thus, the ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].

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You can't. Velocity and acceleration measure two different things, so their units are incompatible. It's like asking, "How many meters does this book weigh?"

Maybe you mean "find" acceleration using given velocities, or a velocity function?

Hi there!

We can begin by calculating the acceleration using the kinematic equation:

d = vit + 1/2at²

Since the rocket starts from rest, we can rewrite this as:

d = 1/2at²

Plug in given values:

4.2 = 1/2a(0.137²) ⇒ a = 447.55 m/s²

Now, we can use Newton's Second Law to find the appropriate force:

∑F = m · a

∑F = 50,000 · 447.55 = 22,377,500 N

Answer:

weight =m x g =2kg × 10m/s 2 = 20N

weight = m × gravity

=unit for weight is newtons

Mass=weight ÷ gravity

= unit for mass is kilograms

Gravity=weight ÷ mass

=unit for gravity is 10m/sec 2

Answer:

Wavelength and speed both depend on the material of the medium.

Explanation:

Let [tex]f[/tex] denote the frequency of a wave. Let [tex]v[/tex] denote the speed of that wave in a given medium. Let [tex]\lambda[/tex] denote the wavelength of that wave in this medium.

The frequency [tex]f[/tex] of a wave stays the same regardless of the material of the media. However, the speed [tex]v[/tex] of a wave indeed depends on the material of the medium (density of the medium, etc.)

[tex]\lambda = v / f[/tex] and [tex]f[/tex] stays the same regardless of the medium. Thus, the wavelength [tex]\lambda[/tex] of this wave in a given medium would be proportional to the speed [tex]v[/tex] in that medium.

For example, the speed of sound in materials with a larger density (e.g., water) is generally larger than that in materials with lower density (e.g., air.)

When a sound wave travels from air into water, the frequency [tex]f[/tex] of this wave would stay the same. However, since the speed [tex]v[/tex] of the wave would increase, the wavelength [tex]\lambda[/tex] of this wave would also increase.

The beginning of the formation of galaxies and clusters of galaxies are the slight fluctuations seen in maps of the cosmic background radiation. So, the correct option is C.

The cosmic background radiation is defined as the microwave radiation that fills all of space which is a remnant that provides an important source of data on the early universe. With a standard optical telescope, the background space between stars and galaxies is almost completely dark.

It is also called the Cosmic Microwave Background (CMB) or electromagnetic radiation filling the universe which is a residual effect of the Big Bang that happened 13.8 billion years ago. The beginning of the formation of galaxies and clusters of galaxies are the slight fluctuations seen in maps of the cosmic background radiation.

Therefore, the correct option is C.

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Your question is incomplete, most probably the complete question is:

What are the slight fluctuations seen in maps of the cosmic background radiation?

a. uncertainties in the map

b. variations in the instrument's sensitivity

c. the beginning of the formation of galaxies and clusters of galaxies

d. dark matter

e. none of the above

Answer:

2.5m/s^2

Explanation:

Since there is no friction, the only force acting on the box is the applied force

We can now use the equation Fnet = ma

and we can rearrange for a

a = Fnet/m

now input the values

a = 50N/20kg

a = 2.5 m/s^2

Answer:

it traveled 180km

Explanation:

Answer:

the change of speed!

Explanation:

if light speeds up or slow down more it bend more

Answer:

Explanation:

Answer: molecular solid

Explanation:

Answer:

I'm no expert, but multitasking is a no bueno. Because multitasking reduces your efficiency and performance because your brain can only focus on one thing at a time. When you try to do two things at once, your brain lacks the capacity to perform both tasks successfully.

Therefore I would choose A, considering he could easily workout another time, whilst the test is a one time thing. He can't redo the test, but he can workout again. So my answer is A.

If he HAS to workout and study at the same time, then C would be appropriate.

I hope this helps!

The net force acting on the mass along the incline is equal to 16 Newton.

Given the following data:

To determine the net force acting on the mass along the incline:

First of all, we would find the acceleration of the mass by using the second equation of motion:

[tex]S = ut+ \frac{1}{2} at^2\\\\4 = 0(1) + \frac{1}{2} a(1)^2\\\\4=\frac{a}{2}\\\\a=2\times 4[/tex]

Acceleration, a = 8 [tex]m/s^2[/tex]

For the net force, we would apply Newton's Second Law of Motion:

[tex]F_{net} = mass \times acceleration\\\\F_{net} =2 \times 8[/tex]

Net force = 16 Newton.

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Answer:

chemical symbol

Explanation:

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The Correct statement is ~

Acceleration is a vector quantity.

Answer:

Acceleration is a vector quantity.

Newton's second law and graphical analysis allow us to find the correct answer for the measure of the constant b is:

    D) Stack several filters to change the mass measure the acceleration of the system.

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the bodies.  

         ∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

They indicate that the drag force on the filters is

         F = - b v

Where b is a positive constant that depends on the shape and area of ​​the filter and v is the speed of the filter.

Let's write Newton's second law.

         W - fr  = ma

         W -bv  = ma

In the experiment the students indicate that they can measure the position, velocity and acceleration of the body.

Based on the above, if we place several filter weights and measure their speed and acceleration in each case, we can make a graph of velocity versus acceleration, we can take the value of the constant b from the slope.

Let's analyze the different answers:

A) False. The constant b depends on the shape of the filter therefore it must be kept constant.

B) False. The constant depends on the area, so it must be kept constant.

C) May be. In this case, since we have the terminal velocity, the acceleration is zero, Newton's second law remains.

                    B v - W = 0

                    b = [tex]\frac{W}{v}[/tex]  

The problem with the method is the difficulty of measuring the compression terminal velocity.

D) True. According to the discussion of the velocity versus acceleration. graph, the constant b is equal to the slope of the graph.

E) May be. The problem with this method is finding a reliable value for the terminal velocity.

In conclusion, using Newton's second law and graphical analysis we can find the correct answer for the measure of the constant b is:

 D) Stack several filters to change the mass measure the acceleration of the system.

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