Answer:
No, the mass will never come to rest
Explanation:
It is so because even at arbitrarily small distance it will experience some amount of force (irrespective of how small the value of force is).
This does not allow the mass to become stationary or in a equilibrium state as it is still subject to some amount of force.
Hence, the the mass will never come to rest
7. The work done in picking the same chair up 1 meter would be about
A. 4J
B. 40J
C. OJ
D. 400J
a shiny object reflects light. will a shiny object make a shadow when light shine on it? explain your answer
Answer:
yes I think it is possible
1+1=69 how is it possible
Answer:
you add 67 to 1+1 is this clear also chicken nuggets
Answer:
i dont know
Explanation:
Bob and Sally sit on a 4 m long see-saw that has its fulcrum smack in the center of the board. If 50 kg Sally is sitting at one end of the plank, where should 70 kg Bob sit on the other side relative to the fulcrum so the net Torque is zero?
Answer:
1.43m
Explanation:
Given data
m1= 50kg
m2=70kg
We are told that Sally m1= 50 sat at one end which is 2m from the center
Hence, the summation of clockwise moment = summation of anticlockwise moment
See the attached image for your reference
50*2= 70*x
100= 70x
x= 100/70
x=1.43m
Hence the mass m2 will be at the 1.43m mark for the net torque to be zero
Can someone help me here
Answer:
1. grass Can survive by itself because it is not dependent on food, it is self-sustaining. and since grass it's not dependent on food it is a producer.
2. and 3. they would all decrease, since the prairie dogs are herbivores they eat basically plants such as grass and if half of the grass is gone then they would have less to eat and therefore decrease.
since ferrets eat prairie dogs, if the prairie dogs population decreases the ferrets would have less to eat and therefore decrease as well.
one of the predators of ferrets are foxes and if the ferrets decrease then the fox would also decrease since it will have less to eat.
4. if we would continue advancing years soon the ferret, prairie dogs and foxes would be no more because if there is less grass they would keep on decreasing over the years until they would be extinct.
35 POINTSS!!! PLSSSS HELLPPP!!!
Work is the transfer of power from one object to another.
Please select the best answer from the choices provided
T
F
Answer:
T
beacuse:
Energy can be transferred from one object to another by doing work. ... When work is done, energy is transferred from the agent to the object, which results in a change in the object's motion (more specifically, a change in the object's kinetic energy).
How far could you walk backwards in one hour? Use your speed from the 10m test to calculate the answer. Show your work or you will not receive credit.
Answer: Sweetheart i'm not walking backward for an hour for your little assignment
Explanation: Do it yourself lazy! Have a great day!
A rocket weighs 1.000. N on the surface of Earth. What is its weight at a distance of two Earth radii above the
surface of Earth?
P.5B
0 111.0 N
250.0 N
333.0 N
5000 N
Answer:
0 111.0N be cause the rest do not add up
A 51.0 kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 225 N. For the first 10.0 m the floor is frictionless, and for the next 10.5 m the coefficient of friction is 0.17.
What is the final speed of the crate after being pulled these 20.5 meters?
Answer:
The final speed of the crate is 12.07 m/s.
Explanation:
For the first 10.0 meters, the only force acting on the crate is 225 N, so we can calculate the acceleration as follows:
[tex] F = ma [/tex]
[tex] a = \frac{F}{m} = \frac{225 N}{51.0 kg} = 4.41 m/s^{2} [/tex]
Now, we can calculate the final speed of the crate at the end of 10.0 m:
[tex] v_{f}^{2} = v_{0}^{2} + 2ad_{1} [/tex]
[tex] v_{f} = \sqrt{0 + 2*4.41 m/s^{2}*10.0 m} = 9.39 m/s [/tex]
For the next 10.5 meters we have frictional force:
[tex] F - F_{\mu} = ma [/tex]
[tex] F - \mu mg = ma [/tex]
So, the acceleration is:
[tex] a = \frac{F - \mu mg}{m} = \frac{225 N - 0.17*51.0 kg*9.81 m/s^{2}}{51.0 kg} = 2.74 m/s^{2} [/tex]
The final speed of the crate at the end of 10.0 m will be the initial speed of the following 10.5 meters, so:
[tex] v_{f}^{2} = v_{0}^{2} + 2ad_{2} [/tex]
[tex] v_{f} = \sqrt{(9.39 m/s)^{2} + 2*2.74 m/s^{2}*10.5 m} = 12.07 m/s [/tex]
Therefore, the final speed of the crate after being pulled these 20.5 meters is 12.07 m/s.
I hope it helps you!
what happens when the north pole of one bar magnet is near the north pole of another bar magnet?
Answer:
C
Explanation:
magnet poles with the same polarization reject each other.
Answer:
the answer c because they will push away from each other
S
In a game of pool, the cue ball rolls toward the stationary eight ball with a velocity of 1.35,
and they collide. The mass of the cue ball is 170 grams, and the mass of the eight ball is
156 grams. The velocity of the cue ball immediately after the collision is 0.060
What is the velocity of the eight ball immediately after the collision?
Your answer should have three significant figures.
m
You might need: Calculator
S
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9:0
The velocity of the eight ball immediately after the collision is 1.41 m/s.
What is the final velocity of the eight ball after the collision?
The final velocity of the eight ball after the collision is calculated by applying the principle of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of the cue ballu₁ is the initial velocity of the cue ballm₂ is the mass of the eight ballu₂ is the initial velocity of the eight ballv₁ is the final velocity of the cue ballv₂ is the final velocity of the eight ball(0.17)(1.35) + (0.156)(0) = (0.17)(0.06) + (0.156v₂)
0.2295 = 0.0102 + 0.156v₂
0.156v₂ = 0.2193
v₂ = 1.41 m/s
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the image below shows how the temperature of 10 g of ice changes as energy is added. which statement is correct?
The correct statement is the water absorbed energy continuously, but the temperature increased only when all of the water was in one phase.
this is explained by the latent heat of fusion. The melting point of ice ( at which ice melts into water) is 0 degree Celcius. This temperature remains constant till all 10 g of ice melts completely and water comes in the same phase of liquid.
The latent heat of fusion, also known as enthalpy of fusion, is defined as the total amount of heat energy supplied to a solid substance to start a change in its physical state from a solid to a liquid state. Given the pressure of the environment is constant.
The correct option is (b).
The given question is incomplete, the complete question is
The image below shows how the temperature of 10 g of ice changes as energy is added. which statement is correct?
(a) The water absorbed energy continuously and temperature increases while water is changing phase.
(b) The water absorbed energy , but the temperature increased only when all of the water was in one phase.
(c) Temperature of the water remained constant.
(d) Temperature always increases.
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A train whistle produces a sound at a frequency of 600 Hz. If the train is moving toward a stationary observer at a constant speed, which of the following may be the frequency of the whistle as detected by the observer?
Thomson observed that cathode beams can pass undeflected through crossed electric and magnetic fields. Which of the following quantities must then be common to the particles making up these beams? A. Mass B. Size C. Magnitude of charge D. Sign of charge E. Sign and magnitude of charge F. Velocity
Answer:
e must have the charge of the particle
Explanation:
In this experiment, the particles that the cathode rays are found where from an electric field and another magnetic field, for the particle to pass without deviating the magnetic force must have the same modulus of the entricar force, and be in the opposite direction.
the expression for the magnetic force is
F_m = q v xB
the expression for the electric force is
F_e = q E
when warning the check two formulas we must have the charge of the particle
In the playground game of tetherball, a ball tied to a rope circles a pole, wrapping the rope around the pole is it goes. Opponents compete to wrap the ball around the pole in one direction or the other; the game ends when the rope is entirely wrapped around the pole and the ball touches the pole. If you get the ball going around in one direction, as the rope shortens and the ball goes in smaller and smaller circles, the ball goes around with a shorter and shorter period.
Required:
Explain why this happens.
As the rope becomes shorter, the length of the rope is decreased and the centripetal force decreases according causing the ball to move in smaller circles.
What is centripetal force?The centripetal force is defined as the force that keeps an object moving in a circular path. Also, the centripetal force is equal to the tension in the rope and the tension in the rope depends on the length of the rope.
As the rope shortens, the tension in the rope decreases and the centripetal force on the ball decreases hence the ball moves in smaller and smaller circles, the ball goes around with a shorter and shorter period.
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n unit-vector notation, what is the torque about the origin on a particle located at coordinates (0, −4.0 m, 3.0 m) if that torque is due to (a) force F1 with components F1x = 2.0 N, F1y = F1z = 0, and (b) force F2 with components F2x = 0, F2y = 2.0 N, F2z = 4.0 N?
n unit vector notation, -22j is the torque about the origin on a particle located at coordinate (o, -4.0m, 3.0m)
Torque is defined as the force that can cause an object to rotate along an axis is measured as torque. Estimate the angle between the vector connecting the force's application point and the pivot point and the direction of the applied force. You may calculate the torque by multiplying r by F and sin.
T=R (distance) x F (Force)
R=-4j+3k
F=2J
Hence, t= R x F vector product
=(-4j+3k)x2j
=-4x2x(y x J)
=+3x2y(k x r)
=-8x(-k)+6j
=(6j+8k) nm
b) F^2=2J+4K
Hence, t=r x f^2
=(-4j+3k)x(2j+4k)
=0-16( J x k)+6(K x J)+0
=-16j-6j
=-22j
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All EM waves (light waves) travel at the same speed through the vacuum of space. If the different types of waves are distinguished by their frequency, what basic characteristic of the waves determines their difference
Answer:
Their different wavelengths.
Explanation:
trust me
All EM waves (light waves) travel at the same speed through the vacuum of space. If the different types of waves are distinguished by their frequency, the basic characteristic of the waves that determine their difference is the wavelength of the electromagnetic waves.
What is Wavelength?It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.
It is the total length of the wave for which it completes one cycle.
The wavelength is inversely proportional to the frequency of the wave as from the following relation.
C = νλ
where c is the speed of light
ν is the frequency of the wave
λ is the wavelength of the wave
As we know electromagnetic waves (light waves) travel at the same speed through the vacuum of space which is the speed of light which is 3×10⁸ meter/second
All EM waves (light waves) travel at the same speed through the vacuum of space. If the different types of waves are distinguished by their frequency, the basic characteristic of the waves that determine their difference is the wavelength of the electromagnetic waves.
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A 69.5-kg person throws a 0.0475-kg snowball forward with a ground speed of 31.5 m/s. A second person, with a mass of 57.5 kg, catches the snowball. Both people are on skates. The first person is initially moving forward with a speed of 2.35 m/s, and the second person is initially at rest. What are the velocities of the two people after the snowball is exchanged
Answer:
- After throwing the snow, velocity of the thrower is 2.33 m/s
- the velocity of the receiver is 0.026 m/s
Explanation:
Given the data in the question;
Using conservation of momentum,
Initial thrower has a momentum of mv; [tex]m_{total[/tex]v
(69.5 kg + 0.0475 kg) × 2.35 m/s = 163.4366 kg.m/s
Now, When he throws it at 31.5 m/s, these constitutes a momentum of;
(0.0475 kg )(31.5 m/s) = 1.49625 kg.m/s
hence his momentum now is: 163.4366 - 1.49625 = 161.94035 kg.m/s
To get his velocity, we say;
161.94035 = mv
{ he lost weight of the snow ball so, m = 69.5 kg )
161.94035 = 69.5 × v
v = 161.94035 / 69.5
v = 2.33 m/s
Therefore, After throwing the snow, velocity of the thrower is 2.33 m/s
Next is the Receiver;
the receiver will gain momentum of 1.49625 kg.m/s
he has no momentum initially and after he catches the snow ball;
1.49625 kg.m/s = mv
1.49625 kg.m/s = ( 57.5 kg + 0.0475 kg ) × v
1.49625 kg.m/s = 57.5475 kg × v
v = ( 1.49625 kg.m/s ) / 57.5475 kg
v = 0.026 m/s
Therefore, the velocity of the receiver is 0.026 m/s
4. Juanita has taken two IQ test in her life. When she was 30 she scored 130 on her first IQ test. She then took another test when she turned 40. What is MOST likely to be true of Juanita's score on the second test
The score on the second test should be higher as 10 improves with age
The score on the second test should be close to 130 as IQ is a steady measurement
The score on the second test should be lower as IQ peaks at age 35 and then decreases
The score on the second test should be 10 points lower due to Juanita's mental age.
Answer:
It is most likely that the score on the second test should be close to 130 as IQ is a steady measurement. Intelligence quotient (IQ) is a measure of a person's cognitive ability and is typically considered to be a stable trait that does not change significantly over time. While some research has suggested that certain aspects of cognitive ability may improve with age, the overall IQ score is generally considered to be a consistent measure of cognitive ability. Therefore, it is unlikely that Juanita's score on the second test would be significantly different from her score on the first test.
Sorry if I answered it late :D
Sound wave with of frequency of 300 HZ is traveling with a wavelength of 1 m what is the speed?
Answer:
300m/s
Explanation:
f = c/λ
f = frequency
c = speed
λ = wave length
f = c/λ
300 = c/1
c = 300m/s
A car crashes into a wall with an impulse of 40,000 kg.m/s. The collision took 2 seconds. How much force did the wall exert?
Answer:
i hate physics lol but its 20,000N
Explanation:
Which one of the statements below is true about mechanical waves?
They must travel in empty space.
They can travel in a vacuum.
Both sound and light are examples of mechanical waves.
They require a medium to travel through.
Answer:
The answer is B
Explanation:
Two satellites are monitored as they orbit the Earth; satellite X is eight (8) times as far from the Earth's center as is satellite Y. Using Kepler's 3rd Law, by what factor is the the period (or revolution) of satellite X that of satellite Y
Answer:
[tex]\frac{T_x}{T_y} = 22.63[/tex]
Explanation:
Kepler's third law is an application of Newton's second law for circular motion
T² = K a³
let's apply this expression for each satellite
satellite X
Tₓ² = K aₓ³
satellite Y
[tex]T_y^2 = K a_y^3[/tex]
the relation of the periods is
[tex]\frac{T_x}{T_y} = \sqrt{ (\frac{a_x}{a_y} )^3 }[/tex]
they indicate us
aₓ = 8 a_y
substitutes
[tex]\frac{T_x}{T_y} = 8^{3/2}[/tex]
[tex]\frac{T_x}{T_y} = 22.63[/tex]
help me besties PLEASE ;-;
Answer:
Current in resistors = 1.5 amp
Current in resistors = 0.18 amp
P = 93.75 watts
Explanation:
Given:
1. Three 5 ohm resistor(series)
Voltage = 10 volt
2. Three 5 ohm resistor(parallel)
Voltage = 9 volt
3. Three 5 ohm resistor(series)
Voltage = 6 volt
Find:
Current in resistors
Current in resistors
Total power of circuit
Computation:
1. Total resistor (Series) R = R1 + R2 + R3
Total resistor (Series) R = 5 + 5 + 5
Total resistor (Series) R = 15 ohm
I = V/R
Current in resistors = (15)/(10)
Current in resistors = 1.5 amp
2. Total resistor (Series) R = 1/[1/R1 + 1/R2 + 1/R3
Total resistor (Series) R = 1[1/5 + 1/5 + 1/5]
Total resistor (Series) R = 1.67 ohm
I = V/R
Current in resistors = (1.67)/(9)
Current in resistors = 0.18 amp
3. Total resistor (Series) R = R1 + R2 + R3
Total resistor (Series) R = 5 + 5 + 5
Total resistor (Series) R = 15 ohm
I = V/R
I = (15)/(6)
I = 2.5 amp
P = I²(R)
P = (2.5)²(15)
P = 93.75 watts
A police siren of frequency fsiren is attached to a vibrating platform. The platform and siren oscillate up and down in simple harmonic motion with amplitude Ap and frequency fp. Use v for the speed of sound. Part A Find the maximum sound frequency that you would hear at a position directly above the siren. At what point in the motion of the platform is the minimum frequency heard
Answer:
he maximum frequency occurs when the denominator is minimum
f’= f₀ [tex]\frac{343}{343 + v_s}[/tex]
Explanation:
This is a doppler effect exercise, where the sound source is moving
f = fo [tex]\frac{v}{v-v)s}[/tex] when the source moves towards the observer
f ’=f_o [tex]\frac{v}{v+v_{sy}}[/tex] Alexandrian source of the observer
the maximum frequency occurs when the denominator is minimum, for both it is the point of maximum approach of the two objects
f’= f₀ [tex]\frac{343}{343 + v_s}[/tex]
The flux through a loop of wire changes at a uniform rate from 4x10-'Wb to 5x10-5 Wb in 0.10 s. Determine the emf induced in the coil 5.0 x 10 V 4.0x10v O 1.0 x 10-4 v O 6,0 x 10-57 A 0.50
In 0.10 s, total flux through such a wiring loop increases uniformly from 4x10-'Wb through 5x10-5 Wb. The coil experiences an induced emf of 1*10⁻⁴ v.
What are the SI unit and flux?A distribution of something like the electromagnetic field or the velocity at which the electric field moves throughout a specific area can both be measured as electric flux. The Greek letter e is used to represent electric flow. Electric flux is measured in SI units as or Nm 2 C – 1.
What is the same as flux?E is the amplitude of the electrostatic potential (with units of V/m), and if the magnetic charge is constant, the electric flux (E) travelling through a material of vector area S equals: E = ES = EScos.
Briefing:change in magnetic flux d∅ = (5*10⁻⁵ - 4*10⁻⁵) wb
d∅ = 1*10⁻⁵wb
time = 0.10 sec.
induce emf, e = -d∅/ dt
[e] = d∅/ dt
[e] = 1*10⁻⁵ / 0.10 v
[e] = 1*10⁻⁴ v.
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(20 points) You are at the center of a boat and have been rowing the boat for a long time. You weigh only 80 kg and your 120 kg buddy Bubba has been riding at the front of your 60 kg, 4 m long boat. You come to a stop in the water and then switch places. A) What is the center of mass before you switch places
Answer:
Explanation:
From the given information:
Let the first weight be [tex]m_ 1[/tex] = 80 kg
The weight of the buddy be [tex]m_2[/tex] = 120 kg
The weight of Bubba be [tex]m_3[/tex] = 60 kg
Also, since you and Budda are a distance of 4m to each other, then the length to which both meet buddy will be:
[tex]x_1 = x_3 = \dfrac{4}{2} \\ \\ = 2[/tex]
The length of the boat be [tex]x_2[/tex] = 4 m
∴
We can find the center of mass of the system by using the formula:
[tex]X_{CM} = \dfrac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3} \\ \\ X_{CM} = \dfrac{(80 \times 2)+(120\times4)+(60\times2)}{80+120+60} \\ \\ X_{CM} = \dfrac{160+480+120}{260} \\ \\ \mathbf{X_{CM} = 2.923}[/tex]
A car starting from rest moves with constant acceleration of 2.0 m/s2 for 10 s, then travels with
constant speed lor another 10 s, and then finally slows to a slop will conslanl acceleration of
-2.0 m/s2. How far does it travel?
Answer:
Secondary SchoolPhysics 5+3 ptsA body starts from rest and moves with a uniform acceleration.
One of the advantages of alternating current (ac) over direct current (dc) is the ease with which voltage levels can be increased or decreased.
a. True
b. False
Answer:
True
Explanation:
In an alternating current, voltage levels can be easily increased or decreased as per the requirements of the energy distribution in practical world.
Hence, the given statement is true
PLEASE HELP ME WITH THIS ONE QUESTION
A piston has a volume change of 7 x 10^-6 m^3. Assuming atmospheric pressure is 101,325 J, what is the work needed to change the piston volume?
Correct question:
A piston has a volume change of 7 x 10^-6 m^3. Assuming atmospheric pressure is 101,325 Pa, what is the work needed to change the piston volume?
Answer:
The work needed to change the piston volume is 0.709 J
Explanation:
Given;
volume of the piston, V = 7 x 10⁻⁶ m³
atmospheric pressure, P = 101,325 Pa
The work needed to change the piston volume is calculated as follows;
W = PV
W = (7 x 10⁻⁶ m³) x (101,325 Pa)
W = 0.709 J
Therefore, the work needed to change the piston volume is 0.709 J