The acceleration of the 20 N force is 6.67 m/s^2. The acceleration of the 4N force is 1.33 m/s^2.
What is force?We define the force that acts on a body as that which is able to cause an acceleration or that which is able to change the direction of an object. Recall that from the Newton first law, an object would continue in its state of rest or uniform motion unless the object is acted upon by an external force.
Now the frictional force is the force that tends to resist the motion of two surfaces that are in contact. Owing to the fact that it is a resistive force its direction is always opposite the force that seeks to move the object forward.
Now;
F = ma
a = F/m
a = 20 N/3Kg
a = 6.67 m/s^2
If the force is 4N;
a = F/m
a = 4N/3Kg
a = 1.33 m/s^2
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Missing parts;
How would you calculate the acceleration if you push with a 20 N horizontal force on a 3 kg block on a horizontal friction-free air table? What is the acceleration if the friction force is 4 N?
why do air waves move faster than earthquake waves?
Answer:
P-waves and S-waves are body waves that propagate through the planet. P-waves travel 60% faster than S-waves on average because the interior of the Earth does not react the same way to both of them. ... The energy is thus less easily transmitted through the medium, and S-waves are slower.
Explanation:
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How can you cause a cart moving to the right at a constant speed to move to the left at a constant speed.
Answer:
The answer is below hoped it helped
Explanation:
Forces, when unbalanced, cause objects to accelerate. And the direction of the acceleration is the same as the direction of the extra force. Just because an object is moving to the right does not mean there is more right force than left force. Whether the right or the left force is bigger depends on whether the object is speeding up or slowing down. There must be more right force than left force if an object is moving to the right and speeding up. There must be more left force than right force if an object is moving to the right and slowing down.
BEFORE COLLISION
MASS = 4200 kg
MASS = 990 kg
V = 10 m/s
AFTER COLLISION
V = ?
V = 2 m/s
What is the velocity after the crash?
Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.
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Suppose that a cart is moving along a road at a constant velocity. Give two examples of ways to cause the cart to decelerate, explaining how the net force is affected. (2 points)
The cart moving at a constant velocity will decelerate when a braking force is applied or the road is made to become rougher.
Deceleration is also known as negative acceleration. It occurs when velocity decreases with time. There are two ways by which the cart moving at constant velocity can be made to decelerate. These two ways are;
By applying a braking force: A braking force causes the velocity to decrease with time. When a braking force is applied the frictional force exceeds the forward force hence the net force decreases.By increasing the roughness of the road: When the roughness of the road is increased, the frictional force also increases causing the net force on the cart to decrease hence it decelerates.Learn more: https://brainly.com/question/14281129
There are many isotopes of the element technetium (TC).
What do the nuclei of different technetium isotopes have in common?
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Answer:
hikknn says he is not happy birthday hun
If acceleration of a body starting from the rest is 0.5m/s^2 how long will it take the body to travel 400m(if u are genius answer this)
Answer:
[tex]\huge\boxed{\sf t = 40\ seconds}[/tex]
Explanation:
Given data:
Acceleration = a = 0.5 m/s²
Initial Velocity = Vi = 0 m/s
Distance = S = 400 m
Required:
Time = t = ?
Formulas used:
2 formulas
Third Equation of motion (2as = Vf²-Vi²)First Equation of motion (Vf = Vi + at)Solution:
Using third equation of motion firstly
2as = Vf²-Vi²
2(0.5)(400) = Vf² - 0²
400 = Vf²
Taking sqrt
Vf = 20 m/s
Now, Using First equation of motion:
Vf = Vi + at
20 = 0 + 0.5t
0.5 t = 20
Divide both sides by 0.5
t = 40 seconds
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807You find a rock that is about 20 grams large. This rock contains about 10 grams of Uranium-235 and 10 grams of the element it decays into (Thorium-231). The half life of Uranium-235 is 700 million years. How old is this rock?
The age of the given rock is 700 million years.
The given parameters;
original mass of the rock, = 20 gmass of the rock remaining after decay, = 10 ghalf life of Uranium, [tex]t_{1/2}[/tex] = 700 yearsage of the rock ----------------------------- mass remaining
0 [tex](t_0)[/tex] ------------------------------------------- 20 g
1 half life ([tex]1 \ t_{1/2}[/tex] ) ------------------------------ 10 g
Age of the rock [tex]= t_{1/2} - t_0 = 700 \ - 0 = 700 \ million \ years[/tex]
Thus, the age of the given rock is 700 million years.
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25 n object requires a 5. 0 n to start moving over a horizontal surface. What is the coefficient of static friction?.
Answer:
μ=1/5=0.2
Explanation:
using the formula
Fs=Fn*μ
Where
Fs is the static force
Fn = Normal force
μ= coefficient
so if Fn=25n
and it requires 5 n to start moving, means the max Fs is 5n
5=25μ
μ=5/25
μ=1/5=0.2
What is the ideal temperature for a lithium-ion battery?.
Answer:
16 to 25 degrees f
Explanation:
Work is required to lift a barbell. How many times more work is required to lift the barbell 2 times as high
Answer:
2 time
Explanation:
when distance double the work double
Acceration is a change in motion over time:
True False
What quantity is represented by the mass number minus the atomic number?.
Answer:
Mass = mass of nucleus
Atomic Number = number of protons (charge) of nucleus
Mass - Atomic Number = number of neutrons
What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod
Answer:
C) 5ML^2
Explanation:
2 Spheres of mass M
Bug's mass 3M
Rod length 2L, radius L
Find Rotational Inertia I
I=Σmr^2
I=(3M+M+M)L^2
I=5ML^2
The rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Rotational inertia of the systemThe rotational inertia of the system is determined by summing all the masses together and multiply with the radius.
I(t) = Σmr²
Where;
m is the massr is the radiusI(t) = Inertia of the 2 spheres + inertia of the bug
I(t) = (M + M)L² + (3M)L²
I(t) = 2ML² + 3ML²
I(t) = 5ML²
Thus, the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Complete question is below:
There are 2 Spheres of mass M and Bug's mass 3M. The Rod length is 2L, radius L.
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Se lanza un balón verticalmente hacia arriba con una velocidad de 72 km/h. ¿Qué altura recorrió dicho cuerpo después de 0.05 minutos? (g = 10m/s2)
Usando la información contenida en la pregunta, la distancia que recorre la bola hacia arriba es de 15 m.
Velocidad inicial = 20 m / s
Tiempo= 3 s
Aceleración por gravedad = 10 ms-2
Velocidad final = 0 m / s
Usando la ecuación;
h = u t - 1 / 2 g t 2
h = (20 × 3) - 1/2 × 10 × (3) ^ 2
h = 60 - 45
h = 15 m
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What is the instruments used to measure light intensity, wind intensity and relative humidity
Answer:
we use : photometer to measure light intensity
:Anemometer to measure wind intensity
:Hygrometer to measure relative humidity
Does the dependenceof the orbital energy on nmake sense in terms of the total number of nodes in each type of orbital?.
Answer:The 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.
As we move away from the nucleus, the values of the principal quantum number (n) continues to increase.
As the principal quantum number (n) increases, the orbital becomes farther away from the nucleus.
The higher energy orbital are always larger than the orbitals closer to the nucleus.
Hence, the 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.
Explanation:
a uniform metre rule of mass 100g balances at the 40cm mark when a mass X is placed at the 10cm mark what is the value of x.pls help I don't know how to solve it
Answer:
The fulcrum of the metre stick is at the 40 cm mark
100 g * 10 cm = 1000 g-cm clockwise torque
x * 30 cm = 1000 gm-cm = counterclockwise torque for balance
X = 1000 / (40 -10) = 1000 / 30 = 33.3 gm at 10 cm to balance
When waves are closer together, the distance between them is _________, therefore the waves have __________ wavelength.
Answer:
less' shorter
Explanation:
be cuase science
Answer:
The answer is D.
Explanation:
When waves are closer together, the distance between them is less, therefore the waves have longer wavelength.
(50 POINTS!!) 3. Make a model that shows the forces acting on two blocks on a flat, frictionless surface:
a. A 1 N block at rest
b. A 1 N block with 2 N of force applied in one horizontal direction
Include arrows to represent the forces and labels to indicate the magnitude of each force. Use your model to compare and explain the motion of each block.
The change in position of an object is known as motion. Force is external that causes a body to change its position
For a body is to be at rest, the sum of all the forces acting on the object must be zeroFor a 1N block to be at rest, the normal force acting opposite to the weight must also be 1N.For 1 N block with 2 N of force applied in one horizontal direction, the image of the body is as shown in the attachmentLearn more about force here: https://brainly.com/question/20955770
Answer:
In short terms. the 1N block at rest will stay still and the 1N block with 2N applied will move forward.
what is radiation?....
Answer:
the emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles which cause ionization.
is called radiation
Answer:
Radiation is energy that comes from a source and travels through space at the speed of lightExplanation:
I hope it's help u
Help, please. I am not sure what to do.
Answer:
option D) -3m
Explanation:
if 6m is diplaced by -3m then it would be -3+6=3m
feel free to ask if you are confused
What is the magnitude of the total displacement of the school bus.
Answer:
400 or 500
Explanation:
What is the force on a 2kg object that is moving right at 6 m/s2?
0 3.0N
Ο ΟΝ
.33N
12.0N
Answer:
12N
Explanation:
By Newton second law force is the product of the mass of the object times it's acceleration. That makes it [tex]2\cdot 6 kg \cdot m/s^2 = 12 N[/tex]
Josh tests an unknown liquid substance using litmus paper. When he compared the used litmus paper to a pH scale, the color matches with a 3.5 of the scale. What kind of substance did Josh test?
Answer:
acid
Explanation:
because ph below 7 is acid
what is the meaning of life?
Answer:
the condition that distinguishes animals and plants from inorganic matter, including the capacity for growth, reproduction, functional activity, and continual change preceding death.
Explanation:
hope this helps
What unit of pressure in ideal gas law.
The product of pressure and volume of any gas equals a constant, k. What variable(s) must not change in order for the value of k to remain constant
What is the mass, in kilograms, of a large dog that weighs 441 newtons?
Answer:
441 Newtons equals 44.97 kilograms.
The range of a target is found to be 20km. A shell leaves a gun with a velocity of 500m/s . What must be the angle of elevation of the gun if the ground is level
The angle of elevation of the shell must be approximately 25.840° in order to have a reach of 20 kilometers.
The shell experiments a parabolic motion, which is a combination of horizontal uniform motion and vertical uniform accelerated motion. If initial height of the shell is the same that its final height, then the range of the shell ([tex]d[/tex]), in meters, is described by the following expression:
[tex]d = \frac{v^{2}}{g}\cdot \sin 2\theta[/tex] (1)
Where:
[tex]v[/tex] - Initial speed of the shell, in meters per second[tex]g[/tex] - Gravitational acceleration, in meters per square second[tex]\theta[/tex] - Angle of elevation, in sexagesimal degreesIf we know that [tex]v = 500\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]d = 20000\,m[/tex], then the angle of elevation is:
[tex]\sin 2\theta = \frac{d\cdot g}{v^{2}}[/tex]
[tex]\theta = \frac{1}{2}\cdot \sin^{-1} \frac{d\cdot g}{v^{2}}[/tex]
[tex]\theta = \frac{1}{2}\cdot \sin^{-1} \frac{(20000\,m)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{\left(500\,\frac{m}{s} \right)^{2}}[/tex]
[tex]\theta \approx 25.840^{\circ}[/tex]
The angle of elevation of the shell must be approximately 25.840° in order to have a reach of 20 kilometers.
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