What is Kepler’s first law?

Answers

Answer 1

Answer:

Kepler's First Law: each planet's orbit about the Sun is an ellipse. The Sun's center is always located at one focus of the orbital ellipse. The Sun is at one focus. The planet follows the ellipse in its orbit, meaning that the planet to Sun distance is constantly changing as the planet goes around its orbit.

Answer 2

Answer:

Explanation:

Kepler 's first law - sometimes referred to as the law of ellipses - explains that planets are orbiting the sun in a path described as an ellipse. An ellipse can easily be constructed using a pencil, two tacks, a string, a sheet of paper and a piece of cardboard. Tack the sheet of paper to the cardboard using the two tacks.


Related Questions

Please help! Question is attached.​

Answers

Answer:

a. 6

b. 6 m/s²

c. 300 m to the right

d. 30 secs

Explanation:

slope = rise /run

60-0/10-0

= 6

b. slope = acceleration = 6 m/s²

c. d=ut+1/2at²

t=10 (segment A last for 10 secs)

u - initial velocity = 0

so d = 0(10)+1/2*6*10²

=300 m

This should be pretty easy i think.

Describe the components within the system involved in the collision between pilot and landing zone.

Answers

Answer:

its a sure for not but i think its a 192583

A student did 24 J of work on a chair. She applied a force of 12 N and moved the chair 2 m. What else do you need to know to determine the amount of power used?

Answers

Answer:

time

Explanation:

power = work done ÷ time

Interpreting Graphics
11. Look at the model of an atom below. Does the
model represent a metal atom or a nonmetal
atom? Explain your answer.
ng

Answers

answer:
This is a metal atom

explanation:
metal atoms have fewer electrons in their outer shells than non-metal atoms do.

By looking at the model shown in the problem one can clearly say that this model represents the metal because there are a total of 12 electrons revolving around the nucleus which clearly represents the Magnesium metal.

What are metalloids?

The elements of the periodic tables that behave as metals, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.

As given in the problem, there is a graphical representation of the model of an atom,

One can see that the model in the problem accurately depicts the metal by looking at the total of 12 electrons circulating around the nucleus, which is a clear representation of the magnesium metal.

To learn more about metalloids here, refer to the link given below

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#SPJ5

6. Explain the importance of the law of conservation of mass.

Answers

Answer:

According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.

Explanation:

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A 0.5kg ball falls from a building that Is 50m high. how much kinetic energy will it have when it has fallen half way to the ground?

Answers

calculate velocity at halfway to the ground.

vfinal = root 2ad

v = root (2*9.81m/s^2*25)

v = 69.367175234 m/s

Kinetic energy = 1/2mv^2

Kinetic energy = 1/2 * (69.367175234 m/s^s^2

Ek = 2405.9025 Joules

Football players boots have spikes at their sole

Give reason​

Answers

Answer:

it prevents slipping on the grass while playing

Answer:

to keep their grip on the ground so they won't fall

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm. A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Answers

We have that for the Question, it can be said that the amount by which the length of the stack decreases is

[tex]dl'=3.621*10^{-4}m[/tex]

From the question we are told

A copper (Young's modulus 1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each cylinder has a radius of 0.24 cm.

A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack decreases.

Generally the equation for copper cylinder   is mathematically given as

[tex]dl=\frac{Flo}{yA}[/tex]

[tex]dl=\frac{7900*3*10^-^2}{1.1*10^{11}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=1.19064778*10^-^4[/tex]

Generally the equation for brass cylinder   is mathematically given as

[tex]dl=\frac{7900*5*10^-^2}{9*10^{10}*\pi(0.24*10^{-2})^2}[/tex]

[tex]dl=2.43*10^{-4}[/tex]

Therefore Total change in length

[tex]dl'=1.191*10^-^4+(2.43*10^{-4})[/tex]

[tex]dl'=3.621*10^{-4}m[/tex]

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What is the difference between a low tide and a high tide

Answers

A high tide means when the water has risen and is higher up(closer to high up land). Low tide is when it’s receded

Answer:

High water level during a tide is called High tide.

Low water level during a tide is called Low tide.

Help me quick!!! please!!

Calculate the power of an engine which raises a mass of 1000 kg to a height of 40 m in 10 s.

Answers

Answer:

39.240 W

Explanation:

Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is [tex]w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J[/tex]

At this point we can simply apply the definition of power, that is [tex]P = \frac wt[/tex], to get the power of the engine is [tex]39.240 W[/tex]

Answer:

P=39200W

Explanation:

P=(mgh)/t

P=(40×9.8×1000)/10

P=39200W

When did the objects that we now see as asteroids and comets form in the solar system?.

Answers

Answer:

After solid particles condensed from the gas but before the planets finished forming

what is potentiometer​

Answers

Answer:

potentiometer is a device used to measure potential difference across the circuit

1. Look at this data table


What data seems to be inconsistent with the rest? What are 2 different explanations for this data?

Answers

Using visual inspection and knowledge of linear regression , the inconsistent input is the last data point (30, 12.0).

Looking at the data, there is a negative relationship between the depth of water sample and the amount of dissolved oxygen.

As the depth increases, the amount of dissolved oxygen decreases. However, the last data point does not concur with this trend.

This might have been caused by imputation error or error in the measuring device used.

Therefore, the inconsistent data point is (30, 12.0)

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28
If it takes 1,697 m to stop a car initially moving at 46 m/s, what distance is required to stop a car moving at a quarter
of the initial speed under the same conditions?

Answers

Answer:

Approximately [tex]106\; \rm m[/tex], [tex](1/16)[/tex] of the original distance, assuming that the acceleration is constant.

Explanation:

Let [tex]v[/tex] and [tex]u[/tex] denote the final and initial velocity of the vehicle ([tex]v = 0\; \rm m \cdot s^{-1}[/tex] since this vehicle has come to a stop.)Let [tex]a[/tex] denote the acceleration of the vehicle (a constant under the assumption.) Let [tex]x[/tex] denote the displacement of the vehicle.

If the acceleration on this vehicle is constant, the SUVAT equations would apply:

[tex]\displaystyle v^{2} - u^{2} = 2\, a\, x[/tex].

Rearrange this equation to find an expression for [tex]x[/tex], the displacement required for the vehicle to come to a stop:

[tex]\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{-u^{2}}{2\, a} && (\text{$v = 0\; \rm m \cdot s^{-1}$})\end{aligned}[/tex].

Thus, under these assumptions, [tex]x[/tex] would be proportional to [tex]u^{2}[/tex]. In other words, the distance required for this vehicle to come to a stop would be proportional to the square of the initial velocity of this vehicle.

If the initial velocity [tex]u[/tex] is reduced to [tex](1/4)[/tex] (a quarter) of the initial value, the distance required for stopping this vehicle would be [tex](1/4)^{2} = (1/16)[/tex] of the initial value:

[tex]\begin{aligned}1,\!697\; {\rm m} \times \frac{1}{16} \approx 106\; \rm m\end{aligned}[/tex].

What would be the acceleration of a block sliding down an inclined plane that makes an angle of 45° with the horizontal if the coefficient of sliding friction between two surfaces in 0.3? 141

Ans: 4.95 m/sec?​

Answers

Answer:

unfortunately we have not received a reply to the park yet but

Explanation:

mohamedz and he had killed him

What water pressure must a pump that is located on the first floor supply to have water on the thirteenth of a building with a pressure of 35 lb/in2 Assume that the distance between each floors is 10ft.

Answers

The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

The given parameters;

Pressure on the 13 th floor, P₁ = 35 PSIDistance between each floor, d = 10 ft

The vertical pressure of the water is calculated as follows;

[tex]P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\[/tex]

The vertical height of the first floor from the 13th floor = 130 ft

The vertical height of the 13 ft floor = 10  ft

[tex]P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI[/tex]

Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

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A child sits on a rotating merry-go-round, 2.1 m from its center. If the speed of the child is 2.2 m/s, what is the minimum coefficient of static friction between the child and the merry-go-round that will prevent the child from slipping?

Answers

We have that the the minimum coefficient of static friction  is mathematically given as

[tex]\mu= 0.235[/tex]

Force

Generally the equation for the Force   is mathematically given as

[tex]F=n\mu\\\\Where\\\\n = mg\\\\Given\\\\Fc = m(vt2/R)\\\\Therefore\\\\\mu = vt2/gR\\\\\mu = 2.22/(9.8(2.1)) \\\\[/tex]

[tex]\mu= 0.235[/tex]

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People who drink coffee are more likely to develop cancer

Answers

Answer:

The answer is False

False

Hope this helps

a gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3 before returning to its initial state as shown in the figure below. how much work is done in one cycle?

Answers

The work done on the given gas in one cycle is -405.3 kJ.

The given parameters;

initial pressure of the gas, P₁ = 2 atmfinal pressure of the gas, P₂ = 6 atminitial volume of the gas, V₁ = 1 m³final volume of the gas, V₂ = 3 m³

Convert the pressure to Pascal (N/m²);

1 atm = 101325

The work done in one cycle is the area of the triangle and it is calculated as follows

[tex]Area = \frac{1}{2} \times base \times height\\\\Area = \frac{1}{2} \times (3 \ m^3\ -\ 1 \ m^3)\times (6 \ atm \ - \ 2 \ atm)\\\\Area = 4 \ atm -m^3\\\\Area = 4 \ atm -m^3 \ \times \frac{101325 \ Pa}{1 \ atm} \\\\Area = 405,300 \ m^3.Pa\\\\Area = 405,300 \ m^3. (N/m^2)\\\\Area = 405,300 \ Nm\\\\Area = 405,300 \ J\\\\Area = 405.3 \ kJ[/tex]

the net work done on the gas = - 405.3 kJ

Thus, the work done on the given gas in one cycle is -405.3 kJ.

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Déterminer la charge de noyau d’atome d’oxygène en coulomb C

Answers

Answer:

determine a large mam I have no idea

Which of the following processes generated heat during earths formation that is still a source of heat in earths interior

Answers

Answer:

There are three main sources of heat in the deep earth: (1) heat from when the planet formed and accreted, which has not yet been lost; (2) frictional heating, caused by denser core material sinking to the center of the planet; and (3) heat from the decay of radioactive elements

A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.

Answers

The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].

The given parameters;

initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃Pi

The initial and final momentum of the ball is calculated as;

[tex]P_i = m_ivi[/tex]

[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]

The initial and final kinetic energy of the ball is calculated as;

[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]

The change in the kinetic energy is calculated as;

[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]

Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].

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The horizontal movement of air from an area of high pressure to an area of lower pressure

options:

wind


weather


heat


conduction

Answers

Answer:

Explanation:

A wind is the horizontal movement of air from an area of high pressure to an area of lower pressure. Winds are caused by differences in air pressure. Most differences in air pressure are caused by unequal heating of the atmosphere

I will give 100 Points, 5-stars, and Brainliest

Direct contact is necessary for which type of energy transfer?

A. Conduction

B. Sound Waves

C. Conduction

D. Convection

Answers

Answer:

Conduction

Explanation:

Because when a molecule is transferred to another molecule then this in going into direct contact

For example if we have a pan and it is boiling well the heat that is on the pan holder that stays in place and it won`t move anywhere else like there is Radiation and Convection but for this question the answer would be Conduction

someone throws a rubber ball vertically upward from the roof of a building 8.2m in height. the ball rises, then falls.it just misses the edge of the roof, and strikes the ground.if the ball is in the air for 6.2s, what was its initial velocity?(disregard air resistance. a=-g=-10m/s²

Answers

Answer:

H = V t - 1/2 g t^2         V and g are in different directions

-8.2 = V * 6.2 - 1/2 * 10 * 6.2*2 = 6.2 V - 192.2

V = 184 / 6.2 = 29.7 m/s

Check: find time for ball to return to zero height

0 = 29.7 T - 5 T^2

T = 29.7 / 5 = 5.94 sec

The ball must have fallen 8.2 m in (6.2 - 5.94) sec = .26 sec

S = 29.7 * .26 + 5 * .26^2 = 8.1

A 34. 8 n object is in free fall. What is the magnitude of the net force which acts on the object? answer in units of n.

Answers

Answer:

-34.8n

Explanation:

when object in free fall, only force is the Force by weight,

which is 34.8 and direction is down.

what is the formula for calculating potentiometer​

Answers

This is the answer, (Vout )=V / (R1 + R2) x R2

Hello everyone, I just want to know the formula to solve this problem:

What is the speed of sound at 62°C?

and how to solve this kind of problem? My brain isn't working.. :)​

Answers

Answer:

367 m/s

Explanation:

Use simplified formula:

[tex]v=331.3\sqrt{1+T/273.15}[/tex] , where T- temperature in Celsius

Wire coils spinning between two magnets will produce …?



A: cold
B : electricity
C: chemicals
D: Steam

Answers

Answer:

B

Explanation:

I don't know but its b

The answer is B.

Magnetic fields can be used to make electricity
Moving a magnet around a coil of wire, or moving a coil of wire around a magnet, pushes the electrons in the wire and creates an electrical current. Electricity generators essentially convert kinetic energy (the energy of motion) into electrical energy.

Why are people so rude???

Answers

Answer:

It could be low self-esteem

Explanation:

There probably insecure have problems and issues of their own could be that were abused growing up and weren’t treated right who knows.

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