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Answer:

All functional groups in organic chemistry

Functional groups include: hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl.

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Answer:

In the question the mass has two significant figures; thus the mass of O2 released would be 4.0 g (two significant figures). 122.55 g of KClO3 yields 3*32 g of O2

Explanation:

Answer:

Following are the responses to the given question:

Explanation:

In the given question the OH could be generated as the H-bond with both the N (nitrogen), which is used to place its N as the partially positive value(+). It is used to simplifies the addition for either its  AA with the imine C. In the above H-bond, the w N is not required as the possibility to use the OCH3

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Answer: The correct answer is actually: The final temperature is 400 K, while volume is kept constant.

Explanation: Got it right on test!

Answer:

don't know really and don't know at alll

Answer:

22.1 ppm

Explanation:

The equation of the reaction is;

Pb2+ (aq)  + 2NaI(s) ------>PbI2(s) + 2 Na^2+

Mass of precipitate =  55.1x10-3 g

Number of moles of precipitate =  55.1x10-3 g/461.01 g/mol = 1.2 * 10^-4 moles

1 mole of  Pb2+  yields 1 mole of PbI2

Hence 1.2 * 10^-4 moles of  Pb2+  also yields  1.2 * 10^-4 moles of PbI2.

Hence mass of Pb2+ present = 1.2 * 10^-4 moles * 207 g/mol = 0.025 g or 25 mg

Mass of solution = Density of solution * volume of solution

Mass of solution = 1.00 kg/L * 1.13 L

Mass of solution = 1.13 Kg

Concentration in mg/Kg(ppm) = mass of solute/mass of solution

= 25 mg/1.13 kg

= 22.1 ppm

Answer:

See explanation and image attached

Explanation:

Hydrogen peroxide is made up of two atoms of hydrogen and two atoms of oxygen as shown in the image attached.

The two oxygen atoms are joined together by a single covalent bond and each of the oxygen atoms are bonded to one hydrogen atom each.

There are two lone pairs on each of the oxygen atoms.

The Lewis(dot) structure for hydrogen peroxide is shown in the image attached to this answer.

Answer: When fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

Explanation:

The chemical energy present in fuels actually releases when these fuels are burned or by combustion.

Hence when fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

For example, gasoline present in vehicles burns and undergoes chemical change which is then converted into thermal energy. This thermal energy then converts into mechanical energy due to which car moves.

Thus, we can conclude that when fuels are burned, the chemical energy that is released can be used to generate another form of energy, such as heat, light, motion, or electricity. This is called combustion.

Answer:

Also, the number of atoms in a reaction remains the same. Mass cannot be created or destroyed in a chemical reaction. The law of conservation of mass states that the total mass of substances taking part in a chemical reaction is conserved during the reaction.

Answer: The volume of given container is 3.83 L.

Explanation:

Given: Mass of [tex]H_{2}[/tex] = 0.224 g

Mass of [tex]N_{2}[/tex] = 1.06 g

Mass of Ar = 0.834 g

Since, moles is the mass of a substance divided by its molar mass. Therefore, moles of given substances present in the mixture are as follows.

Moles of  [tex]H_{2}[/tex] are:

[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.224 g}{2 g/mol}\\= 0.112 mol[/tex]

Moles of [tex]N_{2}[/tex] are:

[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.06 g}{28 g/mol}\\= 0.038 mol[/tex]

Moles of Ar are:

[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.834 g}{40 g/mol}\\= 0.021 mol[/tex]

Total moles = (0.112 + 0.038 + 0.021) mol = 0.171 mol

Now, using ideal gas equation the volume is calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

[tex]V = \frac{nRT}{P}\\= \frac{0.171 mol \times 0.0821 L atm/mol K \times 273 K}{1 atm}\\= 3.83 L[/tex]

Thus, we can conclude that the volume of given container is 3.83 L.

Answer:

The brick has more matter because it has more mass.

Explanation:

Answer:

Answer:

A. Orange light

Explanation:

According to the band spectrum of white light ( ROYGBIV )

Answer:

I think it blue light is higher

Answer:

Density = 2.137 gram per liter (Approx.)

Explanation:

Given:

Gaseous fuel Butane C4H10

Pressure = 0.897 atm

Temperature = 24°C = 24 + 273 = 297 k

Find:

Density of butane gas

Computation:

We know that molar mass of butane = 58.12 g/mol

Density = [molar mass x pressure] / Rt

Density = [58.12 x 0.897] / [0.0821 x 297]

Density = [52.13] / [24.3837]

Density = 2.137 gram per liter (Approx.)

Answer: A balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Explanation:

The reaction equation between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is as follows.

[tex]Na_{2}CO_{3}(aq) + AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + NaNO_{3}(aq)[/tex]

Here, number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

To balance this equation, multiply [tex]AgNO_{3}[/tex] by 2 on reactant side and multiply [tex]NaNO_{3}[/tex] by 2 on product side.

Hence, the equation can be rewritten as follows.

[tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex]

Since, the atoms on both reactant and product side are same. Hence, the equation is now balanced.

Thus, we can conclude that a balanced chemical equation for the reaction between [tex]Na_{2}CO_{3}[/tex] and [tex]AgNO_{3}[/tex] is [tex]Na_{2}CO_{3}(aq) + 2AgNO_{3}(aq) \rightarrow Ag_{2}CO_{3}(s) + 2NaNO_{3}(aq)[/tex].

Answer:

2

Explanation:

Given :

Molarity of HCl solution, M = 0.686 M.

Number of moles, n = 0.037 moles.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

[tex]M = \dfrac{Number \ of \ moles \ of \ solute}{Volume \ in \ liter}\\\\0.686 = \dfrac{0.037}{V}\\\\V = \dfrac{0.037}{0.686}\ L\\\\V = 0.053935 \ L \\\\V = 53.94 \ ml[/tex]

Hence, this is the required solution.

Answer:

Explanation:

photosynthesis

the given chemical reaction is photosynthesis.

During photosynthesis carbon dioxide absorbed by plants reacts with water in presence of sunlight to give glucose and oxygen.

Atoms of the same elements differing in the number of neutrons in their nuclei are known as isotopes. Thus, isotopes of an element have the same atomic number but different atomic mass number. Isotopes of an element have similar chemical properties but different physical properties.

Explanation:

[tex] = 2.5\% \times 2000 \\ = \frac{2.5}{100} \times 2000 \\ = 50 \: g[/tex]

Answer:

The molecular formula of the compound is C10H16O.

Explanation:

Based on the given information, the mass of an unknown compound is 152 mg or 0.152 g, which was dissolved to produce 75 ml of solution.

The osmotic pressure of the solution is 0.328 atm at 27 degrees C or 300 K.

The formula of osmotic pressure is,

P = CRT

Now putting the values in the formula we get,

0.328 = C*0.0821*300

C = 0.013317

C = (mass/molecular mass) * (1000/volume of solution in ml)

0.013317 = (0.152/Molecular mass) * (1000/75)

Molecular mass = 152.186

C mass = 152.186 * 0.789 = 120.07 grams

C mole = 120.07/12 = 10

H mass = 152.186 * 0.1059 = 16.11 grams

H mole = 16.11/1 = 16

O mass = 152.186 - 120.07 - 16.116 = 16 grams

O mole = 16/16 = 1

Thus, the molecular formula of the compound will be,

C10H16O

The given question is incomplete, the complete question is:

A chemist adds 35.0mL of a 6.19 * 10^−4/mmol magnesium fluorideMgF2 solution to a reaction flask. Calculate the mass in micrograms of magnesium fluoride the chemist has added to the flask. Round your answer to

3 significant digits.

Answer:

The correct answer is 1.35 microgram.

Explanation:

Based on the given information,

The volume of magnesium fluoride given is 35 ml, and the concentration of magnesium fluoride is 6.19 × 10⁻⁴ mmol/L.

Now the moles of MgF₂ can be determined by using the formula,

Moles = Concentration × Volume

Moles of MgF₂ = Concentration of MgF₂ × Volume of MgF₂

= 6.19 × 10⁻⁴ mmol/L × 35 ml × L/1000 ml

= 217 × 10⁻⁷ mmol

The molecular mass of magnesium fluoride is 62.3 gram per mole

Thus, the mass of MgF₂ is,

= 217 × 10⁻⁷ mmol × 62.3 g/mol

= 13500 × 10⁻⁷ mg

= 1.35 microgram

Answer:

TRUE ,hope it helped you

Explanation:

Answer:100

Explanation: