Answer:
A = 10.5 cm²
Step-by-step explanation:
The area (A) of a triangle is calculated as
A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )
Here b = 7 and h = 3 , then
A = 0.5 × 7 × 3 = 10.5 cm²
Answer:
A = 10.5 cm²
Step-by-step explanation:
hope this helps
The softball in the mitt is 4.9 inches in diameter. What is its volume? (Use 3.14 for )
Volume is a three-dimensional scalar quantity. The volume of the softball is 61.6 cubic inches.
What is volume?A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
Given that the diameter of the softball is 4.9 inches. Since the radius is half the diameter, therefore, the radius of the softball can be written as,
Radius = Diameter
= 4.9 inches / 2
= 2.45 inches
Now, the volume of the softball can be written as,
Volume of the softball = (4/3) × π × r³
= (4/3) × π × (2.45 inches)³
= 61.6 inches³
Hence, the volume of the softball is 61.6 cubic inches.
Learn more about Volume:
https://brainly.com/question/13338592
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Hank's Hardware purchased a barbecue grill for $350.36 and marked it up 185%. During a sale, the store marked it down 20%. What was the discount price of the barbecue grill?
Answer:
798.82
Step-by-step explanation:
round 798.824
Please please help please
What is the area, in square units, of the shaded region? (nearest tenths place)
Answer:
169.6
Step-by-step explanation:
on a piece of paper mark a point h for home and s for school. describe how to find the set points of equidistant from h and s
Answer:
e?..............................
PLSS HELP (Write your answer with only positive exponents.)
Answer:
-g^8
Step-by-step explanation:
it would still remain the same as it is shown because the "g" is negative and the "8", the exponent, is positive
In ΔDEF, the measure of ∠F=90°, EF = 2.3 feet, and FD = 2.9 feet. Find the measure of ∠D to the nearest tenth of a degree.
Answer:
[tex]\theta=38.42 \textdegree[/tex]
Step-by-step explanation:
From the question we are told that:
Angle of F [tex]\angle F=90 \textdegree[/tex]
Length of [tex]EF = 2.3 feet,[/tex]
Length of [tex]FD= 2.9 feet,[/tex]
Generally the equation for Angle D [tex]\theta[/tex] is mathematically given by
Since [tex]\angle F=90[/tex].The triangle is a right angle Triangle
Therefore
[tex]tan \theta=\frac{EF}{FD}[/tex]
[tex]tan \theta=\frac{2.3}{2.9}[/tex]
[tex]\theta=tan^{-1} 0.793[/tex]
[tex]\theta=38.42 \textdegree[/tex]
This Question: 1 pt
1 of 20 (0 complete)
ZEFG and ZGFH are a linear pair, m ZEFG = 3n + 19, and mZGFH = 2n + 36. What are mZEFG and mZGFH?
mZEFG =
mZGFH =]
(Simplify your answers.)
[tex]\huge{ \mathfrak{ \underline{ Answer }\: \: ✓ }}[/tex]
Angles forming linear pair are :
[tex] \mathrm{\angle EFG \: \: and \: \: \angle GFH} [/tex]
And we know, they are supplymentary
[tex] \mathrm{\angle EFG \: + \: \angle GFH} = 180 \degree[/tex][tex]3n +1 9 \degree+ 2n + 36\degree = 180 \degree[/tex][tex]5n + 55\degree = 180\degree[/tex][tex]5n = 125\degree[/tex][tex]n = 25\degree[/tex]So, the measures of the given angles are :
[tex] \mathrm{\angle EFG } = 3n + 19[/tex][tex] \mathrm{ \angle EFG = (3 \times 25\degree) + 19}[/tex][tex] \mathrm{ \angle EFG = 75 \degree+ 19\degree}[/tex][tex]\mathrm{ \angle EFG = 94\degree}[/tex]And
[tex]\mathrm{ \angle GFH = 2n + 36}[/tex][tex]\mathrm{ \angle GFH = (2 \times 25\degree) + 36\degree}[/tex][tex]\mathrm{ \angle GFH = 50\degree + 36\degree}[/tex][tex]\mathrm{ \angle GFH = 86\degree }[/tex]_____________________________
[tex]\mathrm{ ☠ \: TeeNForeveR \:☠ }[/tex]
PLEASE HELP ME WITH THIS
Answer:
AB = Secant
DB = Diameter
AB = Chord
OB = Radius
BC = Tangent
Step-by-step explanation:
The image provided below is a great reference!
Note: The answers are put in order.
The lines represented by the equations y = 2x – 2 and 2y - 4x = 2 are
O perpendicular
O neither parallel nor perpendicular
O the same line
parallel
Answer:
They are parallel but not the same
Step-by-step explanation:
because they have same slope or gradient which is 2
To get the x and the y
Answer:
x = 16
y = 20
Step-by-step explanation:
the left part of the triangle can be solved first as it already has one angle and 1 side, we use trigonometry for this.
since we have 2 sides and 1 angle, to find the third side length we use the pythagoras theorem. a² + b² = c²
; 9² + 12² = c²
; 225 = c²
;√225 = c
; 15 = c
since we have all the lengths of the triangle, we can find out the angle opposite to the side length '9',
; [tex]\frac{Sin x}{9} = \frac{sin90}{15}[/tex]
; [tex]\frac{Sin 90}{15}[/tex] x 9 = Sinx
36.86 = x
now, we look at the triangle as a whole, the top angle being 90 degrees, we know that we have 36.86.
; 90 - 36.86 = 53.13
[tex]\frac{y}{Sin 90} = \frac{12}{Sin 36.86}[/tex]
; [tex]\frac{12}{sin 36.86}[/tex] x Sin 90 = 20
y = 20
again, since we have 2 sides of a right angled triangle we use a² + b² = c²
we arrange this formula since we have the hypotenuse
; 20² - 12² = 256
; √256 = x
; 16 = x
solving equations
x+4=24
Answer:
x = 20
Step-by-step explanation:
x + 4= 24
Subtract 4 rom both sides
x = 20
Answer:
Your answer is
x=20
Step-by-step explanation:
x=24 -4
A store sells 3 hats for a total of $47.25. The cost of each hat is the same. What is the cost, in dollars, of
one hat at the store?
^
Enter your answer in the box.
dollars
Answer:
Each hat is $15.75
Step-by-step explanation:
When you take $47.25 since there is three hats you divide by 3, so you get 15.75.
What is the solution set of the equation (x - 2)(x - 8) = 0?
1)-2 and 8
2)-2 and -8
3) 2 and 8
4) 2 and -8
Answer:
Step-by-step explanation:
2 and 8
PLZ HELPPPPPPPPPPPPPP
Answer:
i believe it is a if not im sorry
Step-by-step explanation:
(Part 2) PLZ HELP
this is due today:(
It takes 3 hours for a boat to travel upstream against the current and 1.8 hours to travel the same distance downstream with the current. What is the speed of the boat in still water if the speed of the current is 3 mph?
Answer:
Step-by-step explanation:
There are a couple of things to know before we set up the table for this problem. First, we need to remember that if the boat is traveling against the current, that the current is going to slow the boat down; likewise, going with the current will speed the boat up. Second, we need to realize that if the boat's distance against the current is the same as the distance with the current, then the distances in the equations will be set equal to one another.
Set up the table with U (against the current) and D (with the current) on the outside and fill in what we are given:
d = r x t
U
D
This is the table. Now we will fill it in:
d = r x t
U r - 3 x 3
D r + 3 x 1.8
The formula for the distance equation is at the top of the table as d = rt. We already decided that the distances that the boat traveled upstream and downstream were the same so we will set those d values equal to each other, but we first need to get the d value for each row. If distance = rate times time, then for the first row:
d = (r - 3)3 and
d = 3r - 9. For the second row:
d = (r + 3)1.8 and
d = 1.8r + 5.4. Setting them equal to each other:
3r - 9 = 1.8r + 5.4 and
1.2r = 14.4 so
r = 12 mph
What’s the area of the shape?
Answer:
Hello! answer: 113.04
Step-by-step explanation:
It looks like you already selected the correct answer! What you do to find it is radius squared × 3.14 so
6 × 6 = 36 36 × 3.14 = 113.04 therefore that is the answer Hope that helps!
Does anyone know this
Answer:
8 2/3
Step-by-step explanation:
26/3
CONVERT TO A MIXED FRACTION
8 2/3
Answer:
Step-by-step explanation:
3[tex]\frac{1}{4}[/tex] ÷[tex]\frac{3}{8}[/tex]
4*3+1/4 * 8/3
13/4*8/3
13*8/4*3
104/12
26/3
not :when u change division sign into multiplication then do the reciprocal .
-2x^3(3x^2-4x+7)
?????
Answer:
[tex]-6x^5+8x^4-14x^3[/tex]
Step-by-step explanation:
[tex]-2x^3(3x^2-4x+7)[/tex] Use distributive property
[tex]-2x^3[/tex] · [tex]3x^2[/tex] = [tex]-6x^5[/tex]
[tex]-2x^3[/tex] · [tex]-4x[/tex] = [tex]8x^4[/tex] Product becomes positive because of two negatives
[tex]-2x^3[/tex] · [tex]7[/tex] = [tex]-14x^3[/tex]
Group all of those numbers together (in order)
[tex]-6x^5+8x^4-14x^3[/tex]
In a roll of aluminum foil, the inner cardboard tube has a diameter of 1.75 inches and a height of 18 inches I the tube is cut and unfolded to form a rectangle, what is the lateral area?
what is the correct answer?
Answer:
well we can see the sign's a trapezoid
area of trapezoid = 1/ 2 × sum of parallel sides × height
= 1/ 2 × (7+5) × 4
= 1/ 2 × 12 × 4
= 24 Sq feet
that's first option
what number lies in between 18 and 24
Answer:
21
Step-by-step explanation:
24 - 18 = 6
6/2 = 3
18 + 3 = 21
Answer: 21
Step-by-step explanation:
18, 19, 20, 21, 22, 23, 24
1 2 3 3 2 1
21 is in the middle
PLEASE HELP ASAP !!
A car company’s profit can be modeled by the equation P = –2x^2 + 44x – 42, where P is the profit in millions of dollars and x is the number of cars sold in thousands.
(a.) How many cars are sold when the company breaks even?
(b.) What is the company’s maximum profit? How many cars sold gives the maximum profit?
Answer:
Step-by-step explanation:
In order for a company to break even, it earns no profit but it also incurs no loss. In other words, set the quadratic equal to 0 and factor to find x.
If you factor this using the quadratic formula you will get that the number of cars sold for the company to neither earn nor lose money is 1 or 21. Right in the middle is where we will find the maximum value (the vertex). This max value will give us the number of cars sold, h, and its corresponding value, k.
To solve for h easily, use the formula
[tex]h=-\frac{b}{2a}[/tex] where a and b are the coefficients found in the standard form of a polynomial [tex]ax^2+bx+c[/tex]:
[tex]h=-\frac{44}{2(-2)}=11[/tex] and for k, use:
[tex]k=c-\frac{b^2}{4a}[/tex]:
[tex]k=-42-\frac{44^2}{4(-2)}=200[/tex]
This means our vertex is (11, 200) and in the context of our problem, we know that when the company sells 11,000 cars it makes a max profit of 200 million dollars.
What is the length of the hypotenuse?
A. 10
B. 14
C. 48
D. 100
Option A= 10
ProcessUsing Pythagoras Theorem,
8²+6²= (hypotenuse)²
64+36= (hypotenuse)²
(hypotenuse)²= 100
hypotenuse= √100
hypotenuse= 10
So Option A= 10
Hope This Helps You ❤️Answer:
The hypotenuse is A. 10.
Step-by-step explanation:
To find the length of hypotenuse we can use the pythagoras theorem formula:
[tex]a^{2} +b^{2} =c^{2}[/tex]
[tex]=>6^{2} +8^{2} = c^{2}[/tex]
[tex]=> 36 + 64 = c^{2}[/tex]
[tex]=> 100 =c^{2}[/tex]
[tex]=> c = \sqrt{100}[/tex]
∴ [tex]c[/tex] [tex]= 10[/tex]
Eric's tackle box has 4 sections for fishing lures. Eric has 28 lures.
He wants to put the same number of lures in each section.
How many lures should he put in each section?
Eric should put 7 lures in each section.
28/4=7
can someone tell me plis how are they equivalent ?
Answer:
A) 5/9 times 4/3 = 20/27
B) 2/4 times 5 = 10/20
Step-by-step explanation:
s=10 what is the volume of the prism
HELP I DONT UNDERSTAND.
Answer:
Step-by-step explanation:
the answer " I need because" isn't even correct.. :P
it should be " I need one more side of each triangle , because then I can use the side angle side rule to say the triangles are the same. "
What is percentage of values available between first and third quartile of this data set (8, 7, 3, 8, 14, 15, 20)?
Answer:
[tex]\%Pr =71.43 \%[/tex]
Step-by-step explanation:
Given
[tex]S = \{8, 7, 3, 8, 14, 15, 20\}[/tex]
[tex]n(S) = 7[/tex]
Required
Percentage of values between Q1 and Q3
We have:
[tex]S = \{8, 7, 3, 8, 14, 15, 20\}[/tex]
Sort
[tex]Sorted = \{3, 7, 8, 8, 14, 15, 20\}[/tex]
Q1 is calculated as:
[tex]Q_1 = \frac{n+1}{4}th[/tex]
[tex]Q_1 = \frac{7+1}{4}th[/tex]
[tex]Q_1 = \frac{8}{4}th[/tex]
[tex]Q_1 = 2nd[/tex]
The second element is: 7; So:
[tex]Q_1 = 7[/tex]
Q3 is calculated as:
[tex]Q_3 = 3*\frac{n+1}{4}th[/tex]
[tex]Q_3 = 3*\frac{7+1}{4}th[/tex]
[tex]Q_3 = 3*\frac{8}{4}th[/tex]
[tex]Q_3 = 3*2th[/tex]
[tex]Q_3 = 6th[/tex]
The sixth element is: 15; So:
[tex]Q_3 = 15[/tex]
From the sorted dataset, the data between Q1 and Q3 is:
[tex]Q_3&Q_1 = \{7, 8, 8, 14, 15\}[/tex]
[tex]n(Q_3&Q_1) = 5[/tex]
The percentage is:
[tex]\%Pr =\frac{n(Q_3&Q_1)}{n(S)} * 100\%[/tex]
[tex]\%Pr =\frac{5}{7} * 100\%[/tex]
[tex]\%Pr =\frac{5* 100}{7} \%[/tex]
[tex]\%Pr =\frac{500}{7} \%[/tex]
[tex]\%Pr =71.43 \%[/tex]