What is the area of the triangle?
A. 35 cm
B. 35 cm2
C. 17.5 cm2
D. 17.5 cm

Answer:

yea I don't understand either kid, it's upside down.

Step-by-step explanation:

Answer:

11/12, 5/7, 1,8, 1/4, 1/2

Step-by-step explanation:

Answer:2 pizzas

Step-by-step explanation:

2 2/3 and 2 5/6 can both be rounded to 3. Double that and you get 6. Since there were 8 pizzas originally,subtract 6 from 8 to get 2 remaining pizzas.

Answer:

2 pizzas

Step-by-step explanation:

Answer:

Is B

Step-by-step explanation:

Answer:

      B

Step-by-step explanation:

Answer:

−a^2 b^2 + 2a + 2b

_________________

             a^2

Step-by-step explanation:

Please mark as brainliest if answer is right  

Have a great day, be safe and healthy  

Thank u  

XD  

Answer:

(–5 , –4)

Step-by-step explanation:

when you rotate 180° whether clockwise or counterclockwise, the value of x and y will remain the same, but you need to change the + to – and – to +

heres the answer :) uhh i need 20 wrds so uhhhhhskcljadj

Answer:

78

Step-by-step explanation:

Answer: he got 80/100 or 80% right

Step-by-step explanation:

24/30 = 12/15

12/15 as a percent:

100/15 = 6.66666666666667

12 x 6.66666666667

15 x 6.66666666667

= 80/100 or 80%

Answer:

There is no passage/short story etc. to base this question off of, but if you copy and paste it I'll come back and edit my answer :)

Answer:

A)H0: μ1 − μ2 = 0

Ha: μ1 − μ2 ≠ 0

(b)  Means

Company A___50.6___ min.

Company B___52.75___ min.

c)The t-value is -0.30107.

The p-value is 0 .764815.

C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.

Step-by-step explanation:

A)H0: μ1 − μ2 = 0

i.e there is no difference between the means of delayed flight for two different airlines

Ha: μ1 − μ2 ≠ 0

i.e there is a difference between the means of delayed flight for two different airlines

(b)

Company A___50.6___ min.

Company B___52.75___ min.

Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25

= 1265/25= 50.6

Mean of Company B = x`2= ∑x/n =

=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20

= 1055/20= 52.75

Difference Scores Calculations

Company A

Sample size for Company A= n1= 25

Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24

Mean for Company A= x`1=  50.6

Total Squared Difference (x-x`1) for Company A= SS1: 16938

s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75

Company B

Sample size for Company B= n1= 20

Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19

Mean for Company B= x`2=  52.75

Total Squared Difference (x-x`2) for Company B= SS2=7427.75

s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93

T-value Calculation

Pooled Variance= Sp²

Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)

Sp²= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65

s2x`1 = s2p/n1 = 566.65/25 = 22.67

s2x`2 = s2p/n2 = 566.65/20 = 28.33

t = (x`1 - x`2)/√(s2x`1 + s2x`2) = -2.15/√51 = -0.3

The t-value is -0.30107.

The total degrees of freedom is = n1+n2- 2= 25+20-2=43

The critical region for two tailed test at significance level ∝ =0.05 is

t(0.025) (43) = t > ±2.017

Since the calculated value of t=  -0.30107.  does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.

The p-value is 0 .764815. The result is not significant at p < 0.05.

In this exercise, it is necessary to use the knowledge given by the airlines and the flights, having as a solution:

a)[tex]H_0: \mu_1 -\mu_2 = 0\\H_a:\mu_1 -\mu_2\neq 0[/tex]

b)  Means: Company A 50.6 min.

Company B 52.75 min.

c)The t-value is -0.30107.

The p-value is 0 .764815.

C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.

A)[tex]H_0: \mu_1 -\mu_2 = 0[/tex]

There is no difference between the means of delayed flight for two different airlines:

[tex]H_a:\mu_1 -\mu_2\neq 0[/tex]

There is a difference between the means of delayed flight for two different airlines.

(b) Mean of Company A[tex]= x_1= \sum{x/n} = 1265/25= 50.6[/tex]

Mean of Company B [tex]= x_2= \sum{x/n} =1055/20= 52.75[/tex]

C) Difference Scores Calculations:

Company A:

Sample size for Company [tex]A= n1= 25[/tex]

Degrees of freedom for company [tex]A= df1 = n1 - 1 = 25 - 1 = 24[/tex]

Mean for Company [tex]A= x_1= 50.6[/tex]

Total Squared Difference for Company [tex]A= SS1: 16938\\s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75[/tex]

Company B:

Sample size for Company [tex]B= n1= 20[/tex]

Degrees of freedom for company [tex]B= df2 = n2 - 1 = 20 - 1 = 19[/tex]

Mean for Company[tex]B= x_2= 52.75[/tex]

Total Squared Difference for Company [tex]B= SS2=7427.75\\s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93[/tex]

T-value Calculation

Pooled Variance= Sp²

[tex]Sp^2= ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)\\Sp^2= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65\\s2x_1 = s2p/n1 = 566.65/25 = 22.67\\s2x_2 = s2p/n2 = 566.65/20 = 28.33\\t = (x_1 - x_2)/\sqrt{s2x_1 + s2x_2} = -2.15/\sqrt{51} = -0.3[/tex]

The t-value is -0.30107.

The total degrees of freedom is [tex]= n1+n2- 2= 25+20-2=43[/tex]

The critical region for two tailed test at significance level ∝ =0.05 is [tex]t(0.025) (43) = t > 2.017[/tex]

Since the calculated value of t=  -0.30107.  does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.

The p-value is 0 .764815. The result is not significant at p < 0.05.

Learn more: brainly.com/question/14356533

Answer:

Your answer is C :)

Answer:

[tex]0.6 + \bar 0.47 = \frac{532}{495}[/tex]

Step-by-step explanation:

Given

[tex]0.6 + \bar 0.47[/tex]

Required

Express as x/y

Let

[tex]x = \bar 0.47[/tex]

This implies that:

[tex]x = 0.4747[/tex] --- (1)

Multiply by 100

[tex]100x = 47.4747[/tex] --- (2)

Subtract 1 from 2

[tex]100x - x = 99x[/tex]

This gives

[tex]47.4747 - 0.4747 = 47[/tex]

So:

[tex]99x = 47[/tex]

Solve for x

[tex]x = \frac{47}{99}[/tex]

This implies that:

[tex]\bar 0.47 = \frac{47}{99}[/tex]

[tex]0.6 + \bar 0.47[/tex] becomes

[tex]0.6 + \bar 0.47 = 0.6 + \frac{47}{99}[/tex]

Express 0.6 as fraction

[tex]0.6 + \bar 0.47 = \frac{6}{10} + \frac{47}{99}[/tex]

Take LCM and solve

[tex]0.6 + \bar 0.47 = \frac{99*6+10*47}{990}[/tex]

[tex]0.6 + \bar 0.47 = \frac{1064}{990}[/tex]

Simplify

[tex]0.6 + \bar 0.47 = \frac{532}{495}[/tex]

Answer:

2. 112

3. 78

5. 672

7.  149.8

9. 17.5

10. 19360

11. 64 000

13. 29

14. 350240

15. 386

16. 224

17. 0.9071847

Step-by-step explanation:

They are equal. 2/5 is 4/10.

Answer: A, D, and E

Step-by-step explanation:

Answer:

3² = (√2)² + (√7)²

Step-by-step explanation:

The given sides to us are 3 , √2 and √7. We can check if these are the sides of right angled triangle.

=> h² = p² + b²

=> 3² = (√2)² + (√7)²

=> 9 = 2 + 7

=> 9 = 9

Answer:

-8.4375

Step-by-step explanation:

convert -9 9/16 to a improper fraction.

-9 x 16 = -144  

-144+9= -135

-135 divided by 16 = -8.4375

Answer:

27

32

27

Step-by-step explanation:

1) limit x->2 1/3[f(x)]^2= 27

2) limit x->2 3f(x)+5= 32

3) limit x->2 [f(x)]3/2= 27/2

"A limit is the value that a function approaches as the input approaches some value."

If limit f(x) = m and constant 'a',

limit a (f(x)) = a × m

limit (f(x))^n = (m)^n

limit (a) = a

limit (f(x) + a) = m + a

Given: limit x->2 f(x)=9.

We need to evaluate each limit.

1) limit x->2 1/3[f(x)]^2

⇒ [tex]\lim_{x \to 2} \frac{1}{3} (f(x))^2[/tex]

= [tex]\frac{1}{3} \lim_{x \to 2} (f(x))^2[/tex]

= [tex]\frac{1}{3} (\lim_{x \to 2} f(x))^2[/tex]

= [tex]\frac{1}{3} \times (9)^2[/tex]

= [tex]\frac{81}{3}[/tex]

= 27

2) limit x->2 3f(x)+5

⇒ [tex]\lim_{x \to 2} (3f(x)+5)[/tex]

= [tex]\lim_{x \to 2} 3f(x)+ \lim_{x \to 2} 5[/tex]

= [tex]3\lim_{x \to 2} f(x) + 5[/tex]

= [tex](3 \times 9)+5[/tex]

=[tex]\bold{32}[/tex]

3) limit x->2 [f(x)]3/2

⇒ [tex]\lim_{x \to 2} (f(x))\frac{3}{2}[/tex]

= [tex]\frac{3}{2} \times (\lim_{x \to 2} f(x))[/tex]

= [tex]\frac{3}{2} \times 9[/tex]

= 27/2

Learn more about limit here:

https://brainly.com/question/1619243

#SPJ2

Answer:

Part A:

She would need $598 after 6 weeks of collecting money.

Part B:

She would have waited 17 weeks to have $411 left.

Step-by-step explanation:

Part A:

Replace w in 700 - 17w with 700 - 17(6).

This would give you $598 left until $700 has been reached.

Part B:

Replace w in 700 - 17w with 700 - 17(17).

This would give you $411 left until $700 has been reached.

Answer:

16

Step-by-step explanation:

Answer: there is your answer and how

Step-by-step explanation:

Answer:

a decimal number can be defined as a number whose whole number part and the fractional part is separated by a decimal point. The dot in a decimal number is called a decimal point. The digits following the decimal point show a value smaller than one.

Step-by-step explanation:

Answer:

y=2

Step-by-step explanation: