what is the domain of the function s=-4r^2 if the range is s <_ 0

Answer:

r≤0

Step-by-step explanation:

if the range is s≤0, (that means the value of s is all negative integers &0) to find the domain we have to replace that some negative integers &0.

we can replace some values of s as the following

s=‒4(0)^2 s=‒4(‒1)^2

=‒4(0) =‒4(1)

=0 =‒4

s=‒4(‒2)^2 s=‒4(‒3)^2

=‒4(4) =‒4(9)

=‒16 =‒36

so we can understand easly that the domain is negative integer&0,it can't be positive because the square of any integer is positive.

therefore the answer is r≤0

i think &i hope it is clear.

The domain is the set of values for which the given function is defined. The domain of the function s=-4r² if the range is s≤0 is r∈R. The correct option is B.

For the given function s=-4r², the domain of the function when s≤0 will be all the real numbers. This is because, for any value of r whether it is positive or negative, the value of r² will be positive, but at the same time this quantity is needed to be multiplied by -4.

Thus, the result of -4r² will be always negative, which is less than zero.

Hence, the domain of the function s=-4r² if the range is s ≤0 is r∈R.

Learn more about appropriate domain here:

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