Answer:
Approximately [tex]5.11 \times 10^{-19}\; {\rm J}[/tex].
Explanation:
Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.
Look up the Rydberg constant for hydrogen: [tex]R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}[/tex].
Look up the speed of light in vacuum: [tex]c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}[/tex].
Look up Planck's constant: [tex]h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}[/tex].
Apply the Rydberg formula to find the wavelength [tex]\lambda[/tex] (in vacuum) of the photon in question:
[tex]\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}[/tex].
The frequency of that photon would be:
[tex]\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}[/tex].
Combine this expression with the Rydberg formula to find the frequency of this photon:
[tex]\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}[/tex].
Apply the Einstein-Planck equation to find the energy of this photon:
[tex]\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}[/tex].
(Rounded to three significant figures.)
Which metals can be extracted from following ores (i) Argentite (ii) Haematite (iii) Chalcopyrite (iv) Bauxite
I hope it's helpful for you ☺️
1) iron
2) aluminium
3) silver
4) copper
HELP!!!!!!!!!!!!
9. Estimate the change in the thermal energy of water in a pond with a mass of
1000 kg and a specific heat of 4200 J/(kg. C) if the water cools by 1°C.
Answer:
-4,200,000 J
Explanation:
The strings in a compound bow behave approximately like a
spring. A bowstring is pulled back 0.60 m with a maximum force of
267 N (AKA a 60-pound draw weight) to shoot an 18 g arrow.
Assume energy is conserved.
a) At what speed would the arrow be launched? (Note: W = FΔd uses the average
force while F = -kx uses the instantaneous force.)
The speed at which the arrow would be launched is 133.42 m/s
The work-energy theorem asserts that the net work done applied by the forces on a particular object is equivalent to the change in its kinetic energy.
The equation for the work-energy theorem can be computed as:
[tex]\mathbf{W =\Delta K.E}[/tex]
[tex]\mathbf{F\Delta x =\dfrac{1}{2} mv^2}[/tex]
where;
Force (F) = 267 Ndistance Δx = 0.60 mmass (m) = 18 gspeed (v) = ???From the above equation, let make speed(v) the subject of the formula:
∴
[tex]\mathbf{v = \sqrt{\dfrac{2(F \Delta x)}{m}} }[/tex]
[tex]\mathbf{v = \sqrt{\dfrac{2(267 \times 0.60)}{0.018}} }[/tex]
v = 133.42 m/s
Learn more about the work-energy theorem here:
https://brainly.com/question/17081653
PLEASE HELP-I LITERALLY NEED THIS RIGHT NOW!!! I'LL GIVE BRAINLIEST AND 5 STARS!!!!!!!!!!!!!!!!
why has the number of islands in hawaii increased over the last 100 million years
Answer: oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.ANSWER HERE: This mean that volcanos are producing these new islands and it is creating a chain of different islands all over Hawaii.
Answer:
Oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.
_____________ is the study of movement in athletes. A. Sports biomechanics B. Posture C. Dynamics D. Anatomy
Answer:
I believe its A: Sports biomechanics.
you serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has how much energy
Answer:
In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.
1. A block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s.
Answer:
397 j
Explanation:
Because 5.0kg yuh
The kinetic energy of the block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s is 396.9 J.
What is kinetic energy?A moving item or particle has a certain kind of power called kinetic energy. When an item exerts a net force to perform work, which involves the transfer of energy, the object accelerates and as a result, gains kinetic energy.
The amount of kinetic energy that a moving object or particle possesses is determined by both its mass and rate of motion. Any combination of vibration, axis rotation, translation (or movement along a path from one location to another), and translation are all possible motion types.
Given:
The mass of the block, m = 5 kg,
The horizontal force, F = 80 N,
The velocity of the block, v = 12.6 m / s,
Calculate the kinetic energy by the formula given below,
[tex]KE = 1/2mv^2[/tex]
KE = 1 / 2 × 5 × 12.6²
KE = 1 / 2 × 5 × 158.6
KE = 396.9 J
Therefore, the kinetic energy of the block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s is 396.9 J.
To know more about Kinetic energy:
https://brainly.com/question/999862
#SPJ2
The complete question is A block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts from rest, and its final velocity is 12.6 m/s. Find its kinetic energy?
What is the velocity of a dropped object after it has fallen for 3.0 s?
Answer:
30 m/s.
Explanation:
Question 17 (Essay Worth 5 points)
(02.06 HC)
Choose two spheres of Earth which interact when hot springs are formed. Use complete sentences to explain how they interact during this process
X2
= 12 Source
ус
cM
В І
U S XX T
.
Styles
Format
Font
Size
A- A -
Increase Indent
Answer:
geosphere and hydrosphere
Explanation:
When an object is balanced about a pivot, the total clockwise moment must be equal to the total __________ __________. What two words complete this sentence?
Answer:
When an object is balanced, about a pivot, the total clockwise moment must be equal to the total anticlockwise moment about that pivot.
Hope that helps.
When an object is balanced about a pivot, the total clockwise moment must be equal to the total anticlockwise moment.
What is balancing?
Clockwise involves turning to the right while going in the direction of a clock's hands. The moment is referred to as a clockwise moment if the force acting on a body rotates the body clockwise with regard to the axis of rotation.
On the other hand, the moment is referred to as an anti-clockwise moment if the force rotates the body in the opposite direction. The clock face rule can be used to determine this magnet's polarity.
The face of the loop will display the North Pole if the current is flowing counterclockwise. On the other hand, if the current is moving counterclockwise, the South Pole is visible on the loop's face.
Therefore, the total clockwise and total counterclockwise moments must match when an object is balanced about a pivot.
To learn more about balancing, refer to the link:
https://brainly.com/question/21414123
#SPJ2
Which of the following is an example of physical weathering?
O calcium carbonate in limestone changes to calcium hydrogen carbonate
O flow water carves erosion channels in a hillside
Ostalactites precipitate in a cave
O acid rain corrodes a monument
Answer:
acid rain corrodes a monument. d.
Explanation:it only makes sense because its doing something to a physical object.and the other ones aren't.
A 263 g ball of clay falls onto a vertical spring.
The spring constant k = 2.52 N/cm.
The clay sticks to the spring and as the spring compresses a distance of 11.8 cm the clay momentarily comes to rest.
Determine the speed of the clay just before it hit the spring in [m/s]?
As the spring is compressed, it performs
-1/2 (252 N/m) (0.118 m)² ≈ -1.75 J
of work on the clay, while gravity does
(0.263 kg) (9.80 m/s²) (0.118 m) ≈ 0.304 J
on it. Then the total work W performed on the clay ball is approximately -1.45 J.
By the work-energy theorem, W is equal to the change in the clay ball's kinetic energy ∆K. If v is the speed with which it hits the spring, then
W = ∆K
-1.45 J = 0 - 1/2 mv²
Solve for v :
-1.45 J = -1/2 (0.263 kg) v²
v² ≈ 11.0 m²/s²
v ≈ 3.32 m/s
in what direction will the seesaw rotate and what will the sign of the angular acceleration be?
Answer:
It can rotate in any direction. The sign of the angular acceleration depends on how you set the reference system, it can be both negative or positive.
Select the correct answer. What are the directions of an object's velocity and acceleration vectors when the object moves in a circular path with a constant speed? A. The question is meaningless, since the acceleration is zero.
B. The vectors point in opposite directions.
C. Both vectors point in the same direction.
D. The vectors are perpendicular.
The centripetal acceleration which always act toward the center of the circle. The vectors are perpendicular. The correct answer for this question, is option D
The speed of an object is always constant in a circular motion while the object keeps changing direction regularly. The velocity will keep changing because of the change in direction.
Whenever there is a change in velocity, there must be acceleration.
When the object is moving in a circular path with a constant speed, the directions of an object's velocity and acceleration vectors will be perpendicular to each other
The reason is because acceleration is centripetal acceleration which always act toward the center of the circle.
Therefore, the correct answer for this question, is option D
Learn more about circular motion here: https://brainly.com/question/10493657
what is the electric field strength at a distance of .50 m from a 1.00x10^-6 c charge?
Answer:
e = k q / r² then,
e = 9×10^9 * 1×10^-6 / 50² = 3.6 N/C
hope this helps ❤.
A rocket burns fuel at a rate of 239 kg/s
and exhausts the gas at a relative speed of
6 km/s.
Find the thrust of the rocket.
Answer in units of MN.
The Thrust on the rocket is 1.434 MN.
To calculate the thrust of a rocket, we use the formula below
Thrust: This is the force that moves an aircraft through the air.
⇒Formula
T = M'×v.................... Equation 1⇒ Where:
T = Thrust of the rocketM' = Fuel ejection ratev = gas exhaust velocityFrom the question,
⇒ Given:
M' = 239 kg/sv = 60 km/s = 6000 m/s⇒ Substitute these values into equation 1
T = 239(6000)T = 1434000 NT = 1.434 MNHence, the Thrust on the rocket is 1.434 MN.
Learn more about Thrust here: https://brainly.com/question/13501791
A net force of 79 N causes a mass to accelerate at a rate of 3 m/s2. Determine the mass
9. How are ecological footprints useful?
Answer:
This is what the Ecological Footprint does: It measures the biologically productive area needed to provide for everything that people demand from nature: fruits and vegetables, meat, fish, wood, cotton and other fibres, as well as absorption of carbon dioxide from fossil fuel burning and space for buildings and roads.
Why it's useful:
Ecological footprint (EF), measure of the demands made by a person or group of people on global natural resources. It has become one of the most widely used measures of humanity’s effect upon the environment and has been used to highlight both the apparent unsustainability of current practices and the inequalities in resource consumption between and within countries.
A heating curve is a graph that shows the temperature change of a substance as
thermal energy is introduced.
True
False
Answer:
This statement is true, a heating curve is a graph that shows the temperature change of a substance as thermal energy is introduced.
A heating curve is a graph that represents the temperature change of a substance as thermal energy is introduced.
What is the heating curve?The heating curve can be described as the relationship between the heating supply temperature and the outside air temperature of the system. The heating curve gives what temperature the boiler is to heat the water at an outdoor temperature.
Heating curves indicate how the temperature changes as a substance are heated up. Cooling curves are generally the opposite of the heating curve. They indicate how the temperature changes as a substance are cooled down. Similar to heating curves, cooling curves have horizontal parts where the state transforms from gas to liquid/ from liquid to solid.
The heating curve represents the material in phases of solid, liquid, and gas. As this graph is a plot of T v/s q, the slope is 1/mC. As the heating continues, the solid substance melts. During this time the temperature remains constant. The length of the line can be described as the amount of heat required to melt the solid.
Learn more about the heating curve, here:
https://brainly.com/question/27018999
#SPJ2
Which type of circuit would be best to use for lights used for decorations?
Answer:
led would be the best for decorations
Explanation:
The gravitational potential energy of a cucumber-harth system changes when which factor changes?
A) the cucumber's speed
B) the cucumber's mass
c) the cucumber's temperature
D) the length
A bullet of mass 20 g has its kinetic energy equal to 400 J. Find the speed of the bullet.
Answer:
m=20g=0.02kgK.E=400J[tex]\\ \sf\longmapsto KE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}(0.02)v^2=400[/tex]
[tex]\\ \sf\longmapsto 0.01v^2=400[/tex]
[tex]\\ \sf\longmapsto v^2=40000[/tex]
[tex]\\ \sf\longmapsto v=200m/s[/tex]
what planets experience an eclipse from the sun
Answer:
Earth
Explanation:
The sun and the moon come together and they seem like one bonded.
Why doesn't the skater ever regain his potential energy?
Answer:
Friction
Explanation:
As the skateboarder goes down the ramp, potential energy is converted to kinetic energy. Because of friction, some of the energy in the system is converted to heat energy. Once the kinetic energy is converted to heat, the energy cannot be converted back to the potential or kinetic energy in the system.
hi my name is coolboy123hillok
Answer:
you should change that name
A cheetah runs at an average speed of 60mph. find the distance it runs in 30 s
Answer:60mph means it runs every minute.
Explanation: because it makes sense.
Answer:
2640 ft, or 1/2 mile
Explanation:
Recognizing that 30 s = 0.5 min, we can convert the units like this.
distance = speed × time
distance = (60 mi/h) × (1 h/(60 min)) ×(0.5 min) = 0.5 mi
In feet, that is ...
(5280 ft/mi)(0.5 mi) = 2640 ft
A cheetah runs 1/2 mile, or 2640 feet in 30 s.
Draw a nitrogen cycle and explain in short.
please help me
Answer: biogeochemical process
Explanation:
A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.
So acceleration of the bike which started from rest, reaches at speed of 7.10 m/s by travelling distance 35.4 m will be 0.712 m/ sec^2.
A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = â€""16t2 48t 190. Approximately when will the projectile hit the ground? 1. 5 seconds 3. 2 seconds 5. 3 seconds 6. 2 seconds.
The time for the projectile to hit the ground from the given position is 1.5 s.
The given parameters:
Initial velocity of the projectile, u = 48 ft/sHeight, h = 190 ftModel of the projectile path, h(t) = –16t² + 48t + 190.The time for the projectile to hit the ground is calculated as follows:
when the projectile hits the ground, the final velocity = 0
[tex]v_f = 0\\\\\frac{dh(t)}{dt} = v_f\\\\\frac{dh(t)}{dt} = -32t + 48\\\\-32t+48 = 0\\\\32t = 48\\\\t = \frac{48}{32} \\\\t = 1.5 \ s[/tex]
Thus, the time for the projectile to hit the ground from the given position is 1.5 s.
Learn more about time of motion of projectiles here: https://brainly.com/question/13533552
how to read a micrometer on a clark cm-100 vickers hardness tester
Answer:
Explanation:
Equipment manufactured by LECO(8 Corporation, St. Joseph, Michigan is warranted free from defect in material
and workmanship for a period of six months from the date of purchase. Equipment not manufactured by LECO is
covered to the extent of warranty provided by the original manufacturer and this warranty does not cover any
equipment, new or used, purchased from anyone other than the LECO Corporation. All replacement parts shall
be covered under warranty for a period of thirt days from date of purchase. LECO MAKES NO OTHER
REPRESENTATION OR WARRANTY OF ANY OTHER KIND, EXPRESSED OR IMPLIED, WITH RESPECT TO
THE GOODS SOLD HEREUNDER, WHETHER AS TO MERCHANTABILITY, FITNESS FOR PURPOSE, OR
OTHERWISE.
Expendable items such as crucibles, combustion tubes, chemicals and items of like nature are not covered by
this warranty.
LECO's sole obligation under this warranty shall be to repair or replace any part or parts which, to our
satisfaction, prove to be defective upon return prepaid to LECO Corporation, St. Joseph, Michigan. This
obligation does not include labor to install replacement parts, nor does it cover any failure due to accident, abuse,
neglect, or use in disregard of instructions furnished by LECO. In no event shall damages for defective goods
exceed the purchase price of the goods, and LECO SHALL NOT BE LIABLE FOR INCIDENTAL OR
CONSEQUENTIAL DAMAGES WHATSOEVER.
All claims in regard to the parts or equipment must be made within ten (10) days after Purchaser learns of the
facts upon which the claim is based. Authorization must be obtained from LECO prior to returning any other
parts. This warranty is voided by failure to comply with these notice requirements.
NOTICE
The warranty on LECO equipment remains valid only when genuine LECO replacernent parts are employed.
Since LECO has no control over the quality or purity of consumable products not manufactured by LECO, the
specifications for accuracy of results using LECO instruments are not guaranteed unless genuine LECO
consumables are employed in conjunction with LECO instruments. If purchaser defaults in making payment for
any parts or equipment, this warranty shall be void and shall not apply to such parts and equipment. No late
payment or cure of default in payment shall extend the warranty period provided herein.
LECO Corporation is not responsible for damage to any associated instruments, equipment or apparatus nor wil
LECO be held liable for loss of profit or other special damages resulting from abuse, neglect, or use in disregard
of instructions. The Buyer, their employees, agents and successors in interest assume all risks and liabilities for
the operation, use and/or misuse of the product(s) described herein and agree to indemnify, hold harmless and
defend the seller from any and all claims and actions arising from any cause whatsoever, including seller's
negligence for personal injury incurred in connection with the use of said product(s) and any and all damages
proximately resulting therefrom.
CAUTION
The instrument should be operated only by technically qualified individuals who have fully read and understand
these instructions. The instrument should be operated only in accordance with these instructions.
The operator should follow all ,of the warnings and cautions set forth in the manual and the operator should follow
and employ all applicable standard laboratory safety procedures.
LECO'" is a registered trademark of the LECO Corporatio