What is the freezing point in degrees Celsius of a 1.33 molal solution of C 6 H 14 in benzene? The boiling point of benzene is 80.1 degrees Celsius and the boiling point elevation constant for benzene is 2.65 degrees Celsius per molal. Give your answer to the thousandths place.

Answer:

75% will have long legs and 25% will have short legs

Explanation:

Answer:

The charge will tell you if the atom is neutral, positive, or negative. "The charge of an atom is the number of protons minus the number of electrons."

Answer: i think it is Habitat but i am not 100%

Explanation:

Answer:

The answer is C

Explanation:

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✧ [tex] \large{ \red{\tt{E\:X \: O \: T \: H \: E \: R \: M \: I \: C \: \: R \: E \: A \: C \: T\: I \: O \: N}} : }[/tex]

☃ The chemical reaction in which heat is released to the surroundings is called exothermic reaction. The amount of heat energy released is written along with products. This indicates that heat is given out.

[tex] \pink{ \text{Any \: two \: balanced \: equation \: for \: Exothermic \: changes}} : [/tex]

ツ Hope I helped! ♡

☂ Have a wonderful day / night ! ☄

[tex] \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}[/tex] ✎

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Answer:

0.01 faraday

Explanation:

We'll begin by writing the balanced equation. This is illustrated below:

CaCl₂ (aq) —> Ca²⁺ (aq) + 2Cl¯ (aq)

Ca²⁺ (aq) + 2e —> Ca

Molar mass of Ca = 40 g/mol

Mass of Ca from the balanced equation = 1 × 40 = 40 g

1 mole of electron (e) = 1 faraday

2 moles of electrons (e) = 2 × 1 faraday

2 moles of electrons (e) = 2 faraday

From the balanced equation above,

40 g of Ca was deposited by 2 faraday.

Therefore, 0.2 g of Ca will be deposited by = (0.2 × 2)/40 = 0.01 faraday.

Thus, 0.01 faraday is needed for the reaction.

Answer:

1 1

5 2

6 1

8 3

10 3

6 3

9 3

13 3

Explanation:

First of you add the subscripts (the little numbers after the letters) and multiply the big numbers before the letters together to get the number of atoms

For Example:

O= 1 atom

Si{2}= 2 atoms

Mg{5}C{6}= 11 atoms

3Na{2}= 6 atoms

O(SiNa){2}= OSi{2}Na{2}= 5 atoms

Each Capital letter is a new Element

For Example:

O = 1 Element

NaSi = 2 Elements

Answer:

I'm not 100% sure but I think it would be constant

Answer:

The object is moving in the negative direction!

Explanation:The object has a negative velocity) and is speeding up.

Answer:

california

Explanation:

Answer:

pOH = 1.3, pH = 12.7

Explanation:

Since NaOH is a strong base, it will completely ionize; further, since it completely ionizes, our hydroxide concentration (a product of the ionization) will be the same as the given concentration of NaOH.

NaOH -> Na⁺ + OH⁻, [OH⁻] = 5.0 x 10^-2 M

pOH is the negative log of the hydroxide concentration, so plug our hydroxide concentration in:

pOH = -log[OH⁻] = -log[5.0 x 10^-2 M] = 1.3

Since pH + pOH = 14, we can plug in pOH and solve for pH:

pH + 1.3 = 14

pH = 14 - 1.3 = 12.7

Thus, our pOH = 1.3 and pH = 12.7.

Answer:

Venus and Mars?

Explanation:

Answer:

mass matter

Explanation:

Answer:

2.70 M.  

Explanation:

Molar mass of MgO = 24.3 + 16 = 40.3.

A molar solution will contain 40.3g in 1 Litre.

So 800 mL of 1 molar solution will contain 0.8* 40.3 g MgO.

So the molarity of the given solution

= 87 / (0.8*40.3)

= 2.699 M.

Answer:

There are 5.30*10²⁴ atoms in 8.80 moles magnesium chloride.

Explanation:

Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 1 mole of magnesium chloride contains 6.023*10²³ atoms, 8.80 moles of magnesium chloride contain how many moles of atoms?

[tex]amount of atoms=\frac{8.80 moles* 6.023*10^{23} atoms }{1 mole}[/tex]

amount of atoms= 5.30*10²⁴

There are 5.30*10²⁴ atoms in 8.80 moles magnesium chloride.

i find the answer in (Limiting Reactants and Excess ws_KEY.pdf)  

make a search for it it's the first link

According to stoichiometry and balanced chemical equation, 6.18 moles of hydrogen are formed and HBr is the limiting reactant.

Stoichiometry is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.It is used in balancing chemical equations.

In the given chemical reaction,when 3.22 moles of Al reacts with 4.96 moles of HBr₃ total of 3.22+4.96= 8.18 moles are formed.Out of which according to reaction of  which 6 moles are of hydrogen so thus,to find moles of hydrogen formed 8.18-2=6.18 moles of hydrogen are formed.

Learn more about stoichiometry,here:

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Answer:

[tex]\Delta G_{rxn}=51.0kJ/mol[/tex]

Explanation:

Hello there!

In this case, according to the definition of the Gibbs free energy of reaction in terms of the Gibbs free energy of formation of the involved reactants and products, it is possible for us to compute it as shown below:

[tex]\Delta G_{rxn}=3\Delta _f G_{NO_2}+\Delta _f G_{H_2O}-2\Delta _f G_{HNO_3}-\Delta _f G_{NO}[/tex]

Thus, by plugging in the given data, it is possible to obtain:

[tex]\Delta G_{rxn}=3(51.3)+(-237.1)-2(-110.9)-(87.6)\\\\\Delta G_{rxn}=51.0kJ/mol[/tex]

Best regards!

The standard Gibbs free energy change (ΔG°rxn) for the reaction is 76.7 kJ/mol.

The balanced equation for the reaction is:

2 HNO₃(aq) + NO(g) → 3 NO₂(g) + H₂O(l)

The standard free energy change for a reaction ( ΔG0rxn) can be found out using the equation,

ΔG° = Σ ΔG°fproducts - Σ ΔGf° ​​​​​reactants

ΔG°rxn = ΔH°rxn - TΔS0rxn  

∆H°rxn = change in enthalpy of reaction

∆S° = Change in entropy of reaction

T = Temperature ( 298 K )

ΔG°rxn = (3 × ΔG°f(NO₂(g)) + ΔG°f(H₂O(l))) - (2 × ΔG°f(HNO₃)aq)) + ΔG°f(NO(g)))

Substituting the given ΔG°f values:

ΔG°rxn = (3 × 51.3 kJ/mol) + (-237.1 kJ/mol) - (2 × (-110.9 kJ/mol)) + (87.6 kJ/mol)

ΔG°rxn = 153.9 kJ/mol - 237.1 kJ/mol + 221.8 kJ/mol + 87.6 kJ/mol

ΔG°rxn = 226.2 kJ/mol - 149.5 kJ/mol

ΔG°rxn = 76.7 kJ/mol

To learn more about the Gibbs free energy, follow the link:
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Answer:

???

Explanation:

Answer: 0.0129

Explanation:

Answer:

The correct answer is - B) gaining electrons will fill their octet faster than losing them.

Explanation:

Halogens are located in the 17 th group in the periodic table and have elements like fluorine, chlorine bromine and others. All these elements are nonmetals and have similar electron numbers in their octet.

That is the reason of their high effective nuclear charge as they are electronegative and therefore readily get electrons to become anion with other elemnts in chemical reaction. These elements make anion formed when a nonmetal atom gains one or more electrons.

Answer:

I guess quantitative data is countable or measurable, relating to numbers; qualitative data is descriptive, relating to words. Quantitative data lends itself to statistical analysis; qualitative data is grouped and categorized according to themes.

Explanation:

Answer:

quantitative - actual numbers as data

Qualitative- uses senses (taste, touch, etc.)

Explanation:

Answer: FALSE

Tides and Water Levels

Gravity is one major force that creates tides. In 1687, Sir Isaac Newton explained that ocean tides result from the gravitational attraction of the sun and moon on the oceans of the earth (Sumich, J.L., 1996). ... Our sun is 27 million times larger than our moon.

HOPE THIS HELPS

Answer: a double replacement

Explanation:

Answer:

Explanation:

1) Find number of each of the type of atom that is present in the compound, using the chemical formula .

2) Then multiply number of atoms of each element that is present in the compound with the atomic weight of each of the element

3) Add everything together and add the units (grams/mole ) after the number

Let finds that of water

Chemical formula of water is (H20 )

hydogens atoms= 2

oxygen atom= 1

Atomic weight for Hydrogen= 1

Atomic weight for Oxygen= 16

Total number of atoms of Hydrogen from the formula (H2O)= 2

Total number of atoms of Oxygen from the formula (H2O)= 1

the molar mass=

Hydrogen: ( 2 x 1)= 2

Oxygen: ( 1 x 16)= 16

Add together= (16+2)

= 18

Then add the unit, we have(18 g/mol.)

Answer:

6)B.C,Ge,Pb,Si

7)A.Be,Mg,Sr

8)D.arsenic,calcium

9)B.Group 13,period 3

Answer:

i think it's c

Explanation:

Answer:

The molarity of the solution is 0.335 [tex]\frac{moles}{liter}[/tex]

Explanation:

Molar concentration is a measure of the concentration of a solute in a solution, be it some molecular, ionic, or atomic species.

Molarity is the number of moles of solute that are dissolved in a certain volume and is calculated by:

[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

Being the molar mass of BaBr2 equal to 297.14 g/mole, that is to say that 1 mole contains 297.14 grams, the mass of 198 grams are contained in:

[tex]198 grams*\frac{1 mole}{297.14 grams} = 0.67 moles[/tex]

So:

Replacing in the definition of molarity:

[tex]Molarity=\frac{0.67 moles}{2 L}[/tex]

Solving:  

Molarity= 0.335 [tex]\frac{moles}{liter}[/tex]

The molarity of the solution is 0.335 [tex]\frac{moles}{liter}[/tex]

Answer:

To calculate the pH of an aqueous solution you need to know the concentration of the hydronium ion in moles per liter (molarity). The pH is then calculated using the expression: pH = - log [H3O+].

Example: Find the pH of a 0.0025 M HCl solution.

Answer:

2KNO3 + Na --> 2KO2 + NaO2 + N2

Explanation:

on the left side there is 1 Nitrogen molecule, but on the right side there are 2.

So, by adding a coefficient of 2 on the left side the N balances out.

Then, the K's aren't balanced anymore. There are 2 K on the left and 1 K on the right.

So, if a coefficient of 2 is added to KO2 on the left, the K is then balanced.

Now check all the other molecules, and everything else is balanced!

On both sides there are 2 K's, 2 N's, 6 O's, 1 Na.