What is the frequency of a wave that passes a given point 412 times in 4.0
seconds?
O A. 0.0097 s
OB. 103 Hz
O C. 408 S
O D. 1650 Hz
SUBMIT

Answer:

Its Letter C Because Gravity's characteristic is to draw objects (including us) toward its center (which in this case, Earth).

Answer:

1150J

Explanation:

Voltage = energy / charge

energy = Voltage * charge

energy = 230v * 5C = 1150J

Answer:

v = 10.09 m / s,   8.78 North of East

Explanation:

The easiest way to solve this exercise is to decompose the velocities into a coordinate system, where the x-axis coincides with the West-East direction and the y-axis coincides with the South-North direction.

athlete's velocity v₁ₓ = 3 m / s

wind speed 2 v₂ = 10 m / s with direction 65 north of east

          sin 65 = v_{2y} / v₂

          cos 65 = v₂ₓ / v₂

          v_{2y} = v₂ sin 65

          v₂ₓ = v₂ cos 65

          v_{2y} = 10 sin 65 = 9.06 m / s

          v₂ₓ = 10 cos 65 = 4.23 m / s

wind speed 3 v₃ = 8 m / s with direction 70 south of east

This angle measured from the positive side of the x-axis is

          θ = 360 - 70

          θ = 290

          sin 290 = v_{3y} / v₃

          cos 290 = v₃ₓ / v₃

          v_{3y} = v₃ sin 290

          v₃ₓ = v₃ cos 290

           v_{3y} = 8 sin 290 = -7.52 m / s

          v₃ₓ = 8 cos 290 = 2.74 m / s

now we can find each component of the velocity

X axis

        vₓ = v₁ + v₂ₓ + v₃ₓ

        vₓ = 3 + 4.23 + 2.74

        vₓ = 9.97 m / s

Y axis  

        v_y = v_{2y} + v_{3y}

        v_y = 9.06 - 7.52

         v_y = 1.54 m / s

to find the modulus let's use the Pythagorean theorem

         v = [tex]\sqrt{v_x^2 + v_y^2 }[/tex]

         v = [tex]\sqrt{9.97^2 + 1.54^2}[/tex]

         v = 10.09 m / s

let's use trigonometry for the direction

         tan θ = v_y / vₓ

        θ = tan⁻¹ v_y / vₓ

        θ = tan-1 1.54 / 9/97

         θ = 8.78

the address is 8.78 North of East

Answer:

Density = 4.84 g/cm³

Explanation:

Given the following data;

Mass = 30 g

Volume = 6.2 cm³

To find the density of the piece of iron;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

[tex]Density = \frac{mass}{volume}[/tex]

Substituting into the equation, we have;

[tex]Density = \frac{30}{6.2}[/tex]

Density = 4.84 g/cm³

Answer:

Explanation:

Since this is not parabolic motion, it is one-dimensional motion. Very simple. What we are given is

mass: 15.0 kg

initial velocity: 2.0 m/s

acceleration: .75 m/s/s

time: 6.0 seconds

Since we are looking for final velocity, the equation we need for this is

v = v0 + at that says final velocity is equal to the initial velocity plus the acceleration of the object times how long it travels. We don't have a need for the mass here at all.

[tex]v=2.0\frac{m}{s}+.75\frac{m}{s^2}(6.0s)[/tex]

Notice that one of the seconds labels to the right of the plus sign cancel out, leaving us with like units...which we HAVE to have if we want to add.

Simplifying a bit gives us

v = 2.0 m/s + 4.5 m/s so

v = 6.5 m/s

Answer:

Thermal physics

Explanation:

Because it uses temperature

Answer:

In my opinion both are easier if you'll work hard on it...

Answer:

In 1 round 62.857m

In 1.5 round 94.2855m

In 2 round 125.714m

In 2.5 round 157.1425

Answer:

Explanation:

The Law of Momentum Conservation for us has the equation

[tex][m_rv_r+m_gv_g]_b=[m_rv_r+m_gv_g]_a[/tex] and filling in:

[tex][(.50)(5.0)+(.50)(0)]=[(.50)(2.0)+(.50)v_g][/tex] and

2.5 = 1.0 + .50v and

1.5 = .50v so

v = 3 m/s

The final speed of the green ball is 3m/s. This can be calculated by the law of conservation of momentum. Thus, the correct option is D.

The principle of the law of conservation of momentum states that if any two objects undergo collision, then the total momentum of the objects before and after the collision will be the same if there is no external force acting on the colliding objects.

The Law of Conservation of Momentum has the equation which is:

m₁ × u₁ + m₂ × u₂ = m₁ × v₁ + m₂ × v₂

where, m₁ = mass of object 1,

u₁ = initial velocity of object 1 before collision,

m₂ = mass of object 2,

v₁ = final velocity of object 1 after collision,

v₂ = final velocity of the object 2 after collision.

0.50 × 5 + 0.50 × 0 = 0.50 × 2 + 0.50 × v₂

2.5 + 0 = 1.0 + 0.50 × v₂

2.5 - 1.0 = 0.50 × v₂

1.5 = 0.50 × v₂

1.5/ 0.5 = v₂

v₂ = 3m/s

Therefore, the correct option is D.

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Answer:

B

A

Explanation:

please mark as brainliest :)

Answer:

The purpose of the choke is to provide a very high voltage initially between the filaments (across the two ends of the tube light). Again once the gas in the tube is ionized the choke provides a low voltage. A choke is a coil of wire. Fluorescent tubes/lamps are filled with mercury vapor

Explanation:

i hope it will help you

Answer:

YOUR answer is given below:

Explanation:

Drug B will retain the highest percentage of initial concentration.

First order degradation means that both solution will degrade by same amount in same time because first order is directly proportional relationship between given both aqueous solution.

Given that Ten (10) ml aqueous solutions of drug A (10% w/v) and drug B (25% w/v) are stored in two identical test tubes.

Since, initially concentration of Drug B is more. Therefore, at all instant concentration of Drug will be highest.

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Answer:

Quantity of charge = 1800 Coulombs

Explanation:

Given the following data;

Current = 1 A

Time = 0.5 hours

Conversion:

1 hour = 60 * 60 = 3600 seconds

0.5 hour = 0.5 * 3600 = 1800 seconds

To find the charge passing through the wire;

Mathematically, the quantity of charge passing through a conductor is given by the formula;

Quantity of charge = current * time

Substituting into the formula, we have;

Quantity of charge = 1 * 1800

Quantity of charge = 1800 Coulombs

Answer:

V = 5 m³

Explanation:

The density of air, d = 1.2 kg/m³

Mass of the dry air, m = 6 kg

We need to find the volume o the gas. We know that, the density of an object is given by mass divided by its volume. So,

[tex]d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{6}{1.2}\\\\V=5\ m^3[/tex]

So, the volume of the dry air is 5 m³.

Answer:

51.54 m/s

Explanation:

Applying,

Law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = mv+m'v'.................... Equation 1

Where m = mass of the head of the golf club, m' = mass of the gulf ball, u = initial velocity of the head of the gulf club, u' = initial velocity of the gulf ball, v = final velocity of the head of a gulf club, v' = final velocity of the gulf ball

From the question,

Given: m = 151 g = 0.151 kg, u = 43.9 m/s, m' = 46 g = 0.046 kg, u' = 0 m/s (at rest), v = 28.2 m/s

Substitute these values into equation 1

0.151(43.9)+0.046(0) = 0.151(28.2)+0.046(v')

solve for v'

6.6289+0 = 4.2582+0.046v'

0.046v' = 6.6289-4.2582

0.046v' = 2.3707

v' = 2.3707/0.046

v' = 51.54 m/s

Answer:

(I'm not 100% sure about this)

Maybe its because the soccer ball is faulty. Such troublemakers can include holes in the ball, preventing it from inflating.

Answer:

Mass = 52.63 kilograms

Explanation:

Given the following data;

Acceleration due to gravity = 3.8 m/s²

Weight = 200 N

To find mass;

Mathematically, the weight of a physical object is given by the formula;

Weight = mass * acceleration due to gravity

Substituting into the formula, we have;

200 = mass * 3.8

Mass = 200/3.8

Mass = 52.63 kg

Answer:

3,13 N

Explanation:

Del enunciado de la segunda ley del movimiento de Newton;

F = ma

Dónde;

F = Fuerza aplicada

m = masa del cuerpo

a = aceleración del cuerpo

Sustitución de valores;

F = 5,9 kg * 0,53 m / seg2 = 3,13 N

Por tanto, la fuerza aplicada es 3,13 N

Answer:

Size of an object, and the distance between the objects.

When the mass of an object increases the force of gravity increases as well.

Explanation:

The magnitude of this force depends upon the mass of each object and the distance between the centers of the two objects. Mathematically, we say the force of gravity depends directly upon the masses of the objects and inversely upon the distance between the objects squared.

Answer:

Inertia : a property of matter by which it continue in its existing state of rest or uniform motion in a straight line, unless that state is changed by external force.

HOPE ITS HELPS!!

[tex]\boxed{\color{red}\huge\tt\bold\purple{Answer}}[/tex]

Inertia is the tendency of an object to continue in the state of rest or of uniform motion. The object resists any change in its state of motion or rest.

Answer:

[tex] |B| = \sqrt{ {B _{x} }^{2} + {B _{y} }^{2} } \\ = \sqrt{ {7}^{2} + {5}^{2} } \\ = \sqrt{74} \\ = 8.6[/tex]

[tex]let \: the \: angle \: be \: \theta \\ \tan(\theta) = \frac{B _{y} }{B _{x} } \\ \tan( \theta) = \frac{ - 5}{7} \\ \theta = { \tan }^{ - 1} ( \frac{ - 5}{7} ) \\ = 35.5 \degree[/tex]

Resistance (R) = 9.375 ohm (Ω)

Steps:

[tex]R = \frac{V}{I} [/tex]

[tex] = \frac{12 \: volt}{1280 \: milliampere} [/tex]

[tex] = \frac{12 \: volt}{1.28 \: ampare} [/tex]

[tex] = 9.375 \: ohm (Ω)[/tex]

Explanation:

that is my answer thank me later

Answer:

oxygen difluoride a polar molecule

Answer:

the correct address is B

In Rutherford's model of the atom, the positive charge is concentrated at the center of the atom.

The model described the atom as a tiny, dense, positively charged core called a nucleus, in which nearly all the mass is concentrated, around which the light, negative constituents, called electrons, circulate at some distance, much like planets revolving around the Sun.

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Answer:

he sound waves travel to the window in the form of vibrations of air molecules. The air molecules near to the window receive the vibration and hit the window thereby passing on on the vibration.

The sound waves are transmitted to the window as air molecule vibrations. The vibration is transmitted to the window by hitting nearby air molecules that have picked up the disturbance.

Vibration is a periodic back-and-forth motion of the particles in an elastic body or medium that occurs when practically any physical system is moved out of its equilibrium condition and is left to react to forces that work to bring it back into balance.

Free and forced vibrations are the two types of vibrations. Free vibrations happen when the system is briefly perturbed and then allowed to move unrestrained. A weight suspended from a spring offers a timeless illustration. The system has the least amount of energy and the weight is at rest in an equilibrium state. The system will respond by vibrating vertically if the weight is dragged down and then let go.

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Answer:

Yes.

Explanation:

Yes, this system transmitting energy between your bodies because everybody is in thermal equilibrium with other body. Thermal equilibrium occurs when there is same amount of thermal energy is gained by the body and same amount of energy lost by the body so there is no increase or decrease occur in the thermal energy of each body so we can say that the system transmitting energy between the bodies.

Answer:

R = 4.77 ohms

Explanation:

Four resistors are given such that,

R₁ = 2 ohms

R₂ = 3 ohms

R₃ = 5 ohms

R₄ = 10 ohms

Here, R₁ and R₂ in series. The equivalent is given by :

R₁₂ = R₁ + R₂

= 2 + 5

R₁₂ = 7 ohms

Similarly, R₃ and R₄ are in series. so,

R₃₄ = R₃ + R₄

= 10+5

R₃₄ = 15 ohms

Now, R₁₂ and R₃₄ are in parallel. So,

[tex]\dfrac{1}{R}=\dfrac{1}{R_{12}}+\dfrac{1}{R_{34}}\\\\\dfrac{1}{R}=\dfrac{1}{7}+\dfrac{1}{15}\\\\R=4.77\ \Omega[/tex]

So, the equivalent resistance s 4.77 ohms.

Answer: D

Explanation: because doing a yoga desk program is physical activity, 10k steps is pysical activity, riding a bike or walking/running is also physical activity. so it should be D, all of the above.

Answer:

c they obey inverse square law

Complete question:

(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg. The initial temperature of the water is 20 ⁰C

Answer:

The energy that must be supplied to boil the given mass of the water is 672,000 J

Explanation:

Given;

mass of water, m = 2 kg

heat of vaporization of water, L =  330 kJ/kg

initial temperature of water, t = 20 ⁰C

specific heat capacity of water, c = 4200 J/kg⁰C

Assuming no mass of the water is lost through vaporization, the energy needed to boil the given water is calculated as;

Q = mc(100 - 20)

Q = 2 x 4200 x (80)  

Q = 672,000 J

Q = 672,000 J

Q = 672,000 J

Therefore, the energy that must be supplied to boil the given mass of the water is 672,000 J

Answer:

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