What is the nature of roots x2 5 0?

Answer:

I.4

ii.13

Step-by-step explanation:

....ur welcome........

Answer: look at the picture

Step-by-step explanation: Hope this help :D

Answer:

I think 26 for the quadrilateral on the 2nd page

Step-by-step explanation:

8 + 4 + 4+ 10

8 is on the top and 4 is on both sides just the right is angled differently and the bottom i think 10...IM SORRY IF YOU GET T WRONG I TRIED MY BEST!!!!!!

Rewrite the numerator as

x ² + 3x + 5 = (x - 1/2)² + 4 (x - 1/2) + 27/4

Then

(x ² + 3x + 5) / (2x - 1) = 1/2 × (x ² + 3x + 5) / (x - 1/2)

… = 1/2 × ((x - 1/2)² + 4 (x - 1/2) + 27/4) / (x - 1/2)

… = 1/2 × ((x - 1/2) + 4 + 27 / (4 (x - 1/2)))

… = 1/2 x + 7/4 + 27 / (8 (x - 1/2))

which clearly has a non-removable singularity at x = 1/2, which is to say this function has a domain including including all real numbers except 1/2.

For every number other than x = 1/2, the function takes on every possible real numbers, since 1/2 x + 7/4 alone takes on all real numbers.

So:

domain = {x ∈ ℝ | x ≠ 1/2}

range = {x ∈ ℝ}

Answer:

Rotation 180° counterclockwise about the origin

Answer:

The second one, I think.

Answer: b is your answer hope this helped

Step-by-step explanation:

pleas make brainly

Answer:

x=8

Step-by-step explanation:

3(x-5)=9

3x-15=9

3x-15+15=9+15

3x=24

x=8

Answer:

x=8

Step-by-step explanation:

3(x-5) = 9

(3(x-5))/3 = 9/3

x-5 = 3

x-5+5 = 3+5

x=8

Answer:

d=2m

Area(A)=196m

l=60m

Now,

A=d(l+b-d)

196=2(60+b-2)

196=2(58+b)

196=116+2b

2b=196-116

2b=80

b=40m

Answer:

Can't see the attached image

Step-by-step explanation:

Post another question and make sure it has the image on it :)

Answer:

[tex]\huge\purple {\boxed {m\angle FEG =23\degree}} [/tex]

[tex] \huge \orange {\boxed {m\angle FEH=113\degree}} [/tex]

Step-by-step explanation:

In the given circle, [tex] \overline{EG} [/tex] is diameter and [tex] \overline{EH} [/tex] is tangent at point E.

[tex]\therefore \widehat {EFG} [/tex] is a semicircular arc.

Since, measure of semicircular arc is 180°

[tex]\therefore m(\widehat {EFG})=180\degree... (1)[/tex]

[tex]\because m( \widehat {EF}) +m(\widehat {FG}) = m(\widehat {EFG}) [/tex] .... (2)

From equations (1) & (2)

[tex]\therefore 134\degree +m(\widehat {FG}) = 180\degree[/tex]

[tex]\therefore m(\widehat {FG}) = 180\degree-134\degree [/tex]

[tex]\therefore m(\widehat {FG}) = 46\degree [/tex]

By inscribed angle theorem:

[tex] m\angle FEG =\frac{1}{2} m(\widehat {FG} ) [/tex]

[tex] m\angle FEG =\frac{1}{2} \times 46\degree [/tex]

[tex]\huge\purple {\boxed {m\angle FEG =23\degree}} [/tex]

By tangent secant theorem:

[tex] m\angle FEH=\frac{1}{2} (46\degree +180\degree) [/tex]

[tex] m\angle FEH=\frac{1}{2} (226\degree) [/tex]

[tex] \huge \orange {\boxed {m\angle FEH=113\degree}} [/tex]

Answer:

Step-by-step explanation:

Perimeter of the rectangle = PQ + QR + RS + SP

                                      = b +l + b + l

                                      = 2b +2l

Again,  

ABCD is a rectangle. We know that the opposite sides of a rectangle are equal.

Perimeter of a Rectangle

AB = CD = 5 cm and BC = AD = 3 cm

So, the perimeter of the rectangle ABCD = AB + BC + CD + AD = 5 cm + 3 cm + 5 cm + 3 cm = 16 cm

It can be written as 5 cm + 5 cm + 3 cm + 3 cm

                       = (2 × 5) cm + (2 × 3) cm

                       = 2 (5 + 3) cm

                       = 2 × 8 cm

                       = 16 cm

We add length and breadth twice to find the perimeter of a rectangle.

Answer:

c

Step-by-step explanation:

I hope this helps you

8/4=8/4=18/9=2

Side - Side - Side

Answer:

Explanation:

All corresponding sides have the same ratio

Answer:

In my opinion No

Step-by-step explanation:

You are only given "X" SO what is "Y"?

Answer:

y = 3x + 7

Step-by-step explanation:

Rise: 3

Run: 1

Y-Intercept: 7

Answer: p=60

Step-by-step explanation: Hope this help :D

Answer: 24 inches

Step-by-step explanation:

Let the radius be represented by x

Therefore, the height will be = 2×x = 2x

Volume of a cylinder = πr²h

where, Volume = 3500

π = 3.14

r = x

h = 2x

We then slot in the values into the formula

Volume = πr²h

3500 = 3.14 × x² × 2x

3500 = 3.14 × 2x²

2x² = 3500 / 3.14

2x² = 1114.65

Divide through by 2

x² = 1114.65 / 2

x² = 557

x = ✓557

x = 23.6 = 24 approximately

The radius is 24 inches

Answer:

C

Step-by-step explanation:

27÷12=2.25

Each gallon costed 2.25$

Answer:

1 1/5 miles or 1/2 miles

Step-by-step explanation:

1/5 x 6 = 6/5 = 1 1/5 or 1/2 miles

Answer:

37.57

Step-by-step explanation:

34 + 15.45 - 19.75 + 7.87

34 + 15.45 = 49.45

49.45 - 19.75 + 7.87

49.45 + 7.87 = 57.32

57.32 - 19.75 = 37.57

official approval given by an organisation when something / somebody achieves a certain standard

hope it helps you ✌

Answer:

0.038

Step-by-step explanation:

I really hope this helps I'm sorry if its wrong

Brainliest please if its right.

Answer:

[tex]V=497.16\ cm^3[/tex]

Step-by-step explanation:

The attached figure shows a cone of radius 5 cm and height 19 cm. The formula for the volume of a cone is given by :

[tex]V=\dfrac{1}{3}\pi r^2h[/tex]

Substitute all the values,

[tex]V=\dfrac{1}{3}\times 3.14\times 5^2\times 19\\\\V=497.16\ cm^3[/tex]

So, the volume of the cone is equal to [tex]497.16\ cm^3[/tex].

Answer: d

Step-by-step explanation:

Answer:

300

Step-by-step explanation:

Answer:

2.2 inches

Step-by-step explanation:

smallest dimension = (smallest ratio / total ratio) x volume

(smallest ratio = 1

total ratio = 1 + 1.5 + 4.2 = 6.7

(1/6.7) x 14.49 = 2.2 inches

Answer:

i] 4:5

ii] 5:9

Step-by-step explanation:

i] no. of pens/ no. of notebooks

20/25

4/5

= 4:5

ii] no. of notebooks/ total no. of pens and notebooks

25/ 20+25

25/ 45

5/ 9

5:9

Answer:

use cymath.

Step-by-step explanation:

Answer:

$235

Step-by-step explanation:

3525/15 is the exchange rate which equals $235

Answer:

no solution

Step-by-step explanation:

Answer:

the answer is no solution

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

you have to rotate it 180 degrees clockwise to find the transition.