What is the pH if the [H+] concentration is 3 x10^-13​

Answers

Answer 1

Answer:

pH = 12.52

Explanation:

Given that,

The [H+] concentration is [tex]3\times 10^{-13}[/tex].

We need to find its pH.

We know that, the definition of pH is as follows :

[tex]pH=-log[H^+][/tex]

Put all the values,

[tex]pH=-log[3\times 10^{-13}]\\\\pH=12.52[/tex]

So, the pH is 12.52.


Related Questions

what source of electrical energy have scientists been unable to use?

Answers

Answer:

Fusion has powered the sun for billions of years.Yet despite decades of effort, scientists and engineers have been unable to generate sustained nuclear fusion here on Earth. In fact, it's long been joked that fusion is 50 years away, and will always be.

What volume of O2 at NTP is generated from 7.84 g of
FeSO, (NH4)2SO4.6H2O?


Answers

Answer:1.12 g

Explanation:Molar mass of compound ​FeSO4(NH4)2SO4.6H2O = 392.14 g mol-1

Number of moles of compound in 7.84g sample = 7.84 g/ 392.14 g mol-1

                                                                       = 0.02 mole

1 mole of sample contain 1 mole of Fe

So, 0.02 mole of sample would contain 0.02 moles of Fe.

Mass of Fe equivalent to 0.02 mole = 0.02 mol x molar mass of Fe

                                                    = 0.02 mol x 55.84 g mol-1

                                                   = 1.12 g

Which element has the smallest mass on the periodic table? *
O
H
Pb
He
Mg

Answers

Answer:

That should be Hydrogen.

So The second option Is legit!

what is a compound ? Give five examples ?​

Answers

[tex]\huge\mathsf{\red{\underline{\underline{Compound}}}}[/tex]

[tex]{\green{\dashrightarrow}}[/tex]A chemical compound is a chemical substance that is made of two or more atoms of different elements that share a chemical bond.

[tex]{\green{\dashrightarrow}}[/tex]A chemical formula represents the ratio of atoms per element that make up the chemical compound.

[tex]\large{\pink{\sf{5~ Examples~ of~ Compound~ are:-}}}[/tex]

Example 1 :-

Water (H2O, consisting of 2 hydrogen atoms and one oxygen atom)

Example 2 :-

Carbon dioxide (CO2, consisting of one carbon atom and two oxygen atoms)

Example 3 :- Sodium Chloride (NaCl, consisting of one sodium atom and one chloride atom)

Example 4:-

Methane (CH4, consisting of one carbon atom and four hydrogen atoms)

Example 5 :-

Pure glucose is a compound made from three elements - carbon, hydrogen, and oxygen. The ratio of hydrogen to carbon and oxygen in glucose is always 2:1:1.
Here’s the answer H2O and stuff

Radium has a half-life of 1500 years. How long will it take for 250kg of Radium to decay down to less than 10kg

Answers

Answer:

6967 years

Explanation:

The radioactive substance left after a periodical t year can be expressed by using the formula:

[tex]Q(t) = Q_oe^{-kt}[/tex]

here;

[tex]Q_o[/tex] = the radioactive initial value.

We need to understand that provided that the radioactive substance will get reduced to half of the provided initial amount  after a periodic time, Then:

the half-life of the radioactive substance left is:

[tex]Q(h) = \dfrac{Q_o}{2}[/tex]

Given that:

the half-life = 1500 years

[tex]\dfrac{Q_o}{2}= Q_o e^{-k\times 1500} \\ \\ \dfrac{Q_o}{2}= Q_o e^{ -1500k}[/tex]

Divide both sides by [tex]Q_o[/tex]

[tex]\dfrac{1}{2} =e^{-1500k}[/tex]

Then, find the natural logarithm of both side;

[tex]\mathtt{In \dfrac{1}{2} = -1500 k}[/tex]

[tex]k = \dfrac{1}{-1500}\mathtt{In}\dfrac{1}{2}[/tex]

k = 0.000462

So, after a particular (t) time, a 250 kg radium sample was reduced to 10 kg;

Then:

[tex]10 = 250 e^{-0.000462t}[/tex]

[tex]0.04 = e^{-0.000462t}[/tex]

From both sides, finding the natural logarithm, we have:

In(0.04) = -0.000462t

[tex]t = \dfrac{In(0.04)}{-0.000462}[/tex]

t = 6967.26

Thus, it will take approximately 6967 years for a 250 kg radium sample to get reduced to 10 kg.

25.0 g of HCl is added to 100.0 g of water. The density of the resulting solution is 1.19 g/mL. Calculate the molality of

Answers

Answer:

The molality is "6.86 m".

Explanation:

Given:

Mass of of HCL,

= 25 g

Mass of water,

= 100 g

Density,

= 1.19 g/mL

Total mass of solution,

= 125 g

Now,

The number of moles of HCl will be:

= [tex]\frac{25}{36.458}[/tex]

= [tex]0.6857[/tex]

The solution volume will be:

= [tex]\frac{125}{1.19}[/tex]

= [tex]105.04 \ mL[/tex]

hence,

The molality will be:

= [tex]\frac{No. \ of \ moles \ of \ solute}{Mass \ of \ solvent (Kg)}[/tex]

= [tex]\frac{0.6857}{0.1}[/tex]

= [tex]6.857 \ m[/tex]

or,

= [tex]6.86 \ m[/tex]

a gas tank contains 15 moles of oxygen and 20 moles helium what is apertial pressure of helium in this mixture​

Answers

Answer:

D0wnload Phot0Math......................

Explanation:

(1 point) Which compound produces the greatest number of ions when one mole of it is dissolved in water

Answers

The question is incomplete, the complete question is;

Which produces the greatest number of ions when one mole dissolves in water? a. NaCl b. NH4Cl c. NH4NO3 d. Na2SO4

Answer:

Na2SO4

Explanation:

If we consider the compounds listed in the options one after the other;

NaCl produces two moles of ions in solution

NH4Cl produces two moles of ions in solution

NH4NO3  produces two moles of ions in solution

Na2SO4 produces three moles of ions in solution

We can see that Na2SO4 produces the greatest number of ions when one mole of the substance  is dissolved in water, hence the answer above.

what colour is universal indicator when the solution is nuetral?
PLEASE ANSWER ME FAST

Answers

Answer:

Green

Explanation:

pH : < 3 = Red

pH : 3 - 6 = Orange or yellow

pH : 7 = Green

pH : 8 - 11 = Blue

Which is the same as moving the decimal point 3 places to the left in a decimal
number?
Multiplying the number by 100
Dividing the number by 1,000
Multiplying the number by 1,000
Dividing the number by 100

Answers

Answer:

B. Dividing the number by 1,000

Explanation:

Every time you move the decimal ,add a zero.Since the decimal is moved three times ,there are three zeroes. When you move left ,the number is getting smaller so it is division.

How it affects your lives or the lives of people near the area where soil erosion happened?




Please Answer! thanks! ​

Answers

Answer:

negatively

Explanation:

when soil erosion happens,by the agent of water for example,the soil will eventually lose it's valuable minerals and become infertile, people won't be able to grow crops there.

the means of X ? ⊙_⊙⊙_⊙⊙_⊙​

Answers

Answer:

x means unknown it is an unknown value.

For example if you have 2 x you have 2 u know values.

Explanation:

If you want us to explain it further please provide a picture.

Question:-

What is X

Answer:-

X mean an Unknown value in a question.

for example :- 2x = 4

Here, the value of x is not known but it can be known by solving the problem.

The solution is :-

=> 2x = 4

=> x = 4/2

=> x = 2

So, here the value of X is 2

Hence, we can say that "X is an unknown value in a question and solving that question gives the correct value of x"

-TheExtraterrestrial

Interpreting Velocity vs. Time Graphs
Velocity vs Time
Use the information presented in the graph to answer
the questions,
Which segments show acceleration?
Which segment indicates that the object is slowing
down?
What is the velocity of segment B?
What is the acceleration of segment B?|
50
B
40
30
Velocity (m/s)
20
А
10
0
8 9 10
1 2 3 4 5 6 7
Time (s)

Answers

Answer:first part is A and C, second part is C, third part is 40 m/s and the fourth part is zero

Explanation: I guessed and got them right lol

Science- I need help with a question really quick I’m ending school soon

Answers

Bar graph, and charge your phone
the answers bar graph


If ammonium phosphate reacts with sodium chloride in aqueous solution, what are the products?

Answers

Answer:

[tex](NH_4)_3PO_4(aq)+3NaCl(aq)\rightarrow 3NH_4Cl(aq)+Na_3PO_4(aq)[/tex]

Explanation:

Hello there!

In this case, according to the given information, we can set up the appropriate chemical equation when ammonium phosphate reacts with sodium chloride in aqueous solution:

[tex](NH_4)_3PO_4(aq)+NaCl(aq)\rightarrow NH_4Cl(aq)+Na_3PO_4(aq)[/tex]

Which stands for a double replacement reaction, whereby ammonium changes phosphate to chloride and sodium changes chloride to phosphate on the products side. In addition, we can balance the aforementioned equation as shown below:

[tex](NH_4)_3PO_4(aq)+3NaCl(aq)\rightarrow 3NH_4Cl(aq)+Na_3PO_4(aq)[/tex]

Regards!

I need help Type th temperature (in Kelvin) in the left column and the volumes in the right column, being sure to keep pairs of data together. then click resize window to fit data.

the data appears to be
linear
quadratic
exponential
logarithmic​

Answers

Answer:

Linear

Explanation:

Why will no one help this is bogus

Answers

Answer:

D

Explanation:

Answer:

The answer is D

A science lab has copper wire coated
with rubber tubing, a plastic vial, and a
pair of cotton gloves. Which of these
materials is not an electrical insulator?

Answers

Answer:

the answer is copper wire

You have made a 2.5 molar solution (2.5 moles per liter) of a particular chemical. If the molecular weight of the chemical is 28 g (28 g/mol), how many kg of the chemical are dissolved in 1 L of this solution

Answers

Answer:

Mass of solute in Kg = 0.07 Kg

Explanation:

Given

Molecular weight of the chemical = 28 grams per mole

Solution consists of 2.5 moles of solution

Mass of solute in the solution = 2.5 *28 = 70 grams

Mass of solute in Kg =  70 grams/1000 = 0.07 Kg

g (2pts) A 10x transfer buffer solution is 250mM Tris and 1.92M glycine. Buffers are always used at 1x concentration in the lab (unless specified otherwise in the protocol), so we will have to dilute the 10x buffer to 1x before use. What is the concentration of Tris and glycine in the 1x buffer

Answers

Answer:

The explanation according to the given question is summarized below.

Explanation:

Given:

Tris,

= 250 mM

Glycine,

= 1.92 M

According to the solution,

For the dilution pf 10X to 1X buffer, we get

= [tex]1 \ ml \ of \ 10X \ buffer +9 \ ml \ of \ distilled \ water[/tex]

= [tex]10[/tex]

i.e.,

⇒ [tex]10X \ to \ 1X=1:10 \ dilution[/tex]

Now,

⇒ [tex]10X (250 \ mM\ Tris \ HCl, 1.92M\ Glycine, and\ 1 \ percent (\frac{w}{v} ) SDS) ---->1X(25 \ mM \ Tris \ HCl,0.193 M\ Glycine, and \ 0.1 \ percent(\frac{w}{v} )SDS)[/tex]

What type of reaction does this model represent?
a. Synthesis
b. Single Replacement
c. Decomposition
d. Double Replacement

Answers

Answer:

From the diagram above...

its explicitly show a compound that's dissociating or Decomposing into its Constituents.

Answer ....OPTION C.

Why does water have a high cohesion? *
Hydrogen bonding
O It is not known
O Dispersion forces

Answers

Answer:

Dispersion forces

that is the answer

What is the total mass of products formed when 64.18 grams of CH4 is burned with excess oxygen?

Answers

80 grams of product is formed when 16 grams of CH₄ is burnt in excess of Oxygen so ur answer is

80 GRAMS

Is HNO3 an acid or a base



I NEED HELP ASAP​

Answers

Answer:

HNO3 is a potent acid, a base, a nitrating agent and a heavy oxidising agent at times. In the presence of a stronger acid, it serves as a base.

Explanation:

Answer:

It is a strong acid

Explanation:

What is the entropy change in the environment when 5.0 MJ of energy is transferred thermally from a reservoir at 1000 K to one at 500 K

Answers

Answer:

The entropy change in the environment is 3.62x10²⁶.

Explanation:

The entropy change can be calculated using the following equation:

[tex]\Delta S = \frac{Q}{k_{B}}(\frac{1}{T_{f}} - \frac{1}{T_{i}})[/tex]

Where:

Q: is the energy transferred = 5.0 MJ

[tex]k_{B}[/tex]: is the Boltzmann constant = 1.38x10⁻²³ J/K  

[tex]T_{i}[/tex]: is the initial temperature = 1000 K

[tex]T_{f}[/tex]: is the final temperature = 500 K

Hence, the entropy change is:

[tex] \Delta S = \frac{5.0 \cdot 10^{6} J}{1.38 \cdot 10^{-23} J/K}(\frac{1}{500 K} - \frac{1}{1000 K}) = 3.62 \cdot 10^{26} [/tex]                                    

Therefore, the entropy change in the environment is 3.62x10²⁶.

I hope it helps you!          

What did ancient astronomers not know about eclipses?

Answers

Answer:

yes of course everyone know eclipse in ancient January 2004 eclipse was founded in other country's

Soap chemical name and chemical formula
plsss help

Answers

Answer:

the chemical name for soap is a lot, for example there is Sodium Talowate, Sodium Palmate, and even Sodium Cocoate, but there is more

Explanation:

the chemical formula for it is RCOO-Na+ it has 12 - 18 carbon atoms.

Calculate the mass of oxygen in 30 g of CH NH COOH?​

Answers

Molar mass of CH2NH2COOH - 75

Given mass of CH2NH2COOH - 30

Moles of CH2NH2COOH = Given mass/ Molar mass

moles of CH2NH2COOH = 30/75 = 0.4 mol

One mole of CH2NH2COOH contains 32 gram of oxygen

0.4 mole of CH2NH2COOH will contain = 0.4 × 32= 12.8 g of oxygen

Answer- the mass of oxygen in 30 g of CH2NH2COOH is 12.8 gram!

The mass of oxygen in 30 g of CH₂NH₂COOH is 12.8 g.

We'll begin by calculating the mass of 1 mole of CH₂NH₂COOH and the mass of oxygen in the compound.

1 mole of CH₂NH₂COOH = 12 + (2×1) + 14 + (2×1) + 12 + 16 + 16 + 1 = 75 g

Mass of oxygen in CH₂NH₂COOH = 16 + 16 = 32 g

Thus,

75 g of CH₂NH₂COOH contains 32 g of Oxygen.

With the above information, we can obtain the mass of oxygen in 30 g of CH₂NH₂COOH. This can be obtained as follow:

75 g of CH₂NH₂COOH contains 32 g of Oxygen.

Therefore,

30 g of CH₂NH₂COOH will contain = (30 × 32) / 75 = 12.8 g of Oxygen.

Thus, 12.8 g of Oxygen is present in 30 g of CH₂NH₂COOH

Complete question:

Calculate the mass of oxygen in 30 g of CH₂NH₂COOH.

Learn more about mass composition:

https://brainly.com/question/11617445

When 229 J of energy is supplied as heat at constant pressure to 3.0mol Ar(g) the temperature of the sample increases by 2.55K. Calculate the molar heat capacities at constant volume and constant pressure of the gas.

Answers

Answer:

The answer is "[tex]\bold{21.616\ \ \frac{J}{mol K}}[/tex]".

Explanation:

when it is a constant pressure:

[tex]Cp= \frac{\Delta q}{n\Delta T} \\\\[/tex]

[tex]=\frac{229}{3\times 2.55}\\\\=\frac{229}{7.65}\\\\=29.93 \frac{J}{mol\ K}\\[/tex]

and,  

[tex]Cp-Cv=R\ \ (Mayer's\ formula)[/tex]

then,

[tex]Cv=Cp-R\\\\[/tex]  

    [tex]=29.93-8.314\\\\=21.616\ \ \frac{J}{mol K}[/tex]

A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?

Answers

Answer:

571.81 mL

Explanation:

Assuming constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

V₁T₂=V₂T₁

Where in this case:

V₁ = 852 mLT₂ = 200 KV₂ = ?T₁ = 298 K

We input the data:

852 mL * 200 K = V₂ * 298 K

And solve for V₂:

V₂ = 571.81 mL

The new volume would be 571.81 mL.

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