The thermal conductivity of a product is measured in units of W/mK by the lambda value, which is also referred to as the "K-value" or "-value."
What does one lambda mean? A product's thermal conductivity is expressed in terms of W/mK by the lambda value, which is also referred to as the "K-value" or "-value."For the purpose of minimizing heat loss, effective insulation will have a lambda value as low as possible.A lambda value of 0.019 W/mK, for instance, is shared by all of our lower lambda products regardless of thickness.A non-SI measure of volume called lambda, denoted by the lowercase letter, is equivalent to 109 m3, 1 cubic millimeter (mm3), or 1 microliter (L).A variable is bound to a function using its namesake, the Greek letter lambda (), which is utilized in lambda expressions and phrases.Both typed and untyped lambda calculi are possible.Functions can only be used in typed lambda calculus if they can accept the "type" of data that is specified as an input.To learn more about lambda mean refer
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A person lifted a bag of groceries 1.75 m from the floor onto a countertop using a constant force of 57 newtons. if the force was applied for 6.0 seconds, how much power was generated by the individual, to the nearest tenth of a watt?
The person generated approximately 16.7 W of power while lifting the bag of groceries. To the nearest tenth of a watt, this would be 16.7 W.
To calculate the power generated by the person lifting the bag of groceries, you can use the equation:
Power = Work / Time
where Power is the power generated, Work is the work done, and Time is the time over which the work was done.
In this case, the work done is equal to the force applied (57 N) multiplied by the distance over which the force was applied (1.75 m), or 57 N * 1.75 m = 100.25 J. The time over which the work was done is 6.0 seconds.
Plugging these values into the equation above, we get:
Power = 100.25 J / 6.0 s
This simplifies to:
Power = 16.7 W
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A rocket, initially at rest on the ground, accelerates straight upward from rest with constant (net) acceleration 58.8 m/s^2 . The acceleration period lasts for time 6.00 s until the fuel is exhausted. After that, the rocket is in free fall.
Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant free-fall acceleration equal to 9.80 m/s^2 .
Answer:
Approximately [tex]7.41 \times 10^{3}\; {\rm m}[/tex].
Explanation:
If initial velocity, final velocity, and time taken are all found, then the change in height (displacement) can be found as:
[tex]\begin{aligned}(\text{displacement}) &= \frac{(\text{average velocity})}{(\text{time taken})} \\ &= \frac{(1/2)[(\text{initial velocity}) + (\text{final velocity})]}{(\text{time taken})}\end{aligned}[/tex].
For example, during the [tex]t = 6.00\; {\rm s}[/tex] of constant acceleration at [tex]a = 58.8\; {\rm m\cdot s^{-2}}[/tex], initial velocity was [tex]u = 0\; {\rm m\cdot s^{-1}}[/tex] and final velocity would be:
[tex]\begin{aligned}v &= (\text{initial velocity}) + (\text{acceleration}) \, (\text{time}) \\ &= (0\; {\rm m\cdot s^{-1}}) + (58.8\; {\rm m\cdot s^{-2}})\, (6.00\; {\rm s}) \\ &= 352.8\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
Displacement during this period of time would be:
[tex]\begin{aligned}(\text{displacement}) &= \frac{(\text{average velocity})}{(\text{time taken})} \\ &= \frac{(1/2)[(\text{initial velocity}) + (\text{final velocity})]}{(\text{time taken})} \\ &= \frac{(1/2)\, (0\; {\rm m\cdot s^{-1}} + 352.8\; {\rm m\cdot s^{-1}})}{(6.00\; {\rm m\cdot s^{-1}})} \\ &\approx 1.058\times 10^{3}\; {\rm m}\end{aligned}[/tex].
During the next part of the flight, initial velocity was [tex]352.8\; {\rm m\cdot s^{-1}}[/tex] (from the first part of flight) and final velocity would be [tex]0\; {\rm m\cdot s^{-1}}[/tex] when the rocket reaches maximum height. Acceleration was given to be [tex]a = (-9.80\; {\rm m\cdot s^{-2}})[/tex](negative since the rocket is accelerating downward,) but time is not known. Apply the following equation to find the change in height (displacement):
[tex]\begin{aligned}(\text{displacement}) &= \frac{[(\text{final velocity})^{2} - (\text{initial velocity})^{2}]}{2\, (\text{acceleration})} \\ &\approx \frac{(0\; {\rm m\cdot s^{-1}})^{2} - (352.8\; {\rm m\cdot s^{-1}})^{2}}{2\, (-9.80\; {\rm m\cdot s^{-2}})} \\ &\approx 6.350\times 10^{3}\; {\rm m}\end{aligned}[/tex].
The total change in height would be approximately [tex](1.058\times 10^{3}\; {\rm m}) + (6.350\times 10^{3}\; {\rm m}) \approx 7.41\times 10^{3}\; {\rm m}[/tex].
A 0.22-kg ball on a stick is whirled on a vertical circle at a constant speed. when the ball is at the three o'clock position, the stick's tension is 16 n. find the tension in the stick when the ball is (a) at the twelve o'clock and (b) at the six o'clock positions.
a) The tension in the stick when the ball is at twelve o'clock is 6N.
b) And at the six o'clock position is also 16N.
To determine the tension in the stick when the ball is at the three o'clock, twelve o'clock, and six o'clock positions, we can use the equation:
T = m × v² / r
where T is the tension in the stick, m is the mass of the ball, v is the speed of the ball, and r is the radius of the circle.
In this case, the mass of the ball is 0.22 kg, the speed of the ball is constant, and the radius of the circle is the same at all positions. Therefore, the tension in the stick will be the same at all positions.
Plugging the values for the mass and radius of the circle into the equation gives us the following:
T = 0.22 kg × v² / r = 16 N
Therefore, the tension in the stick when the ball is at the three o'clock, twelve o'clock, and six o'clock positions is 16 N.
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someone pls help me solve this problem thank you!
1. The equation of trajectory is: y = 5x²/4 +2x; it is equation of parabola.
2. The position vector = 2ti + (5t² +4t) j
3. The position of point M at t = 3 s is: ( 6,57).
4. The magnitude of velocity of point M at any time t is 2√(25t²+20t+5).
5. The magnitude of acceleration is 10m/s².
What is velocity?The term velocity has been defined as the rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is known as a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Coordinates at any instant t are:
x = 2t; y = 5t² +4t
1. equation of trajectory is:
y = 5x²/4 +2x; it is equation of parabola.
2. position vector = 2ti + (5t² +4t) j
3. the position of point M at t = 3 s is: x = 2×3 = 6; y = 5×3² +4×3 = 57; i.e., ( 6,57)
4. the velocity vector of point M at any time t is = 2i + ( 10t +4) j
magnitude of velocity = √( 2² + (10t +4)² = 2√(25t²+20t+5).
5. the acceleration vector is = 10j m/s²
Therefore, its magnitude is =10m/s².
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1. Two projectiles are thrown from the same point with the same velocity of 50 ms‐¹. The first is projected Making at an angle of θ with the horizontal and the second with an angular of (90-θ)⁰. if the second is found to rise 25m higher than the first.
A. calculate the highest to which each will rise .
B. calculate and compare their range .
C. which one reaches the ground first
The highest to which the first projectile rises will be equal to 51.25 m and the second projectile is 76.29 m.
What is Projectile Motion?A projectile can be defined as an object that will be thrown obliquely near the surface, it follows along a curved path with constant acceleration.
In a Projectile Motion, along the y-axis, there is a constant acceleration, responsible for the vertical motion of the particle while along the x-axis plotted is uniform velocity, responsible for the horizontal motion.
The maximum height of the first projectile is given by:
[tex]\displaystyle Y_1 = \frac{u^2sin^2\theta}{2g}[/tex]
The maximum height of the second projectile is given by:
[tex]\displaystyle Y_2 = \frac{u^2sin^2(90-\theta)}{2g}[/tex]
[tex]\displaystyle Y_2 = \frac{u^2cos^2\theta}{2g}[/tex]
[tex]\displaystyle Y_2 -Y_1 = \frac{u^2(cos^2-sin^2\theta)}{2g}[/tex]
[tex]\displaystyle Y_2 -Y_1= \frac{u^2cos2\theta}{2g}[/tex]
Given, height difference Y₂ - Y₁ = 25 m, initial velocity, u = 50m/s
[tex]\displaystyle 25 = \frac{(50)^2cos2\theta}{2\times 9.8}[/tex]
cos 2θ = 0.196
θ = 39.34°
[tex]\displaystyle Y_1 = \frac{(50)^2sin^2 (39.34)}{2\times 9.8}[/tex]
Y₁ = 51.25 m
[tex]\displaystyle Y_2 = \frac{(50)^2sin^2 (50.66)}{2\times 9.8}[/tex]
Y₂ = 76.29 m
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What is the list order of accuracy for the second derivative Mcq?
The least possible order of accuracy for the second derivatives is 2.
What are derivatives?
A derivative is a security with a price that is dependent on or derived from one or more underlying assets. A derivative itself is a contract between two or more parties based on an asset or assets. Its value is determined by the fluctuations of the underlying asset. The common underlying assets include shares, bonds, commodities, currencies,. Interest rates and market indices.Derivatives can be traded (over-the-counter, OTC) or on an exchange. OTC derivatives make up a larger proportion of existing derivatives and are unregulated, while exchange-traded derivatives are standardizedTo know more about derivatives, click the link given below:
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Give an example of each of the following energy conversions/transformations:
a. Electrical to heat
b. Chemical to heat
c. Electrical to mechanical
Please respond in 1–2 complete sentences for each item using your best grammar.
The example of each of the energy electrical to heat, chemical to heat, electrical to mechanical energy is as given below.
a.) Every electric heater has a resistor as its heating element. Electric heating is the conversion of electrical energy to thermal energy. It converts electrical energy into heat energy when an electric current crosses a resistor, according to the Joule heating principle.
b.) Exothermic reactions, which commonly release chemical energy in the form of heat, are those that take place. Newly formed bonds can store some of the heat energy required for a reaction to proceed as chemical energy.
c.) An electric motor converts electrical energy into mechanical energy. A generator converts mechanical energy into electrical energy. A storage dam's mechanical energy is transformed into electrical energy via a hydroelectric powerplant.
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All of the following are examples of heat conduction except
a pressing a shirt with a hot iron.
b warming your hands over a campfire.
C warming your hands by holding a cup of hot
chocolate.
d heating soup in a pan on a stovetop.
Answer:
b
Explanation:
warming your hands over a campfire is not a example of it conduction because in heat conduction the body which transverse heat into the other bodies should be connected physically in the case of farming our hands over campfire there is no solid connectors our hands are being heated due to the radiation from the camp fire
a 200 g steel ball a hangs on a 1.0 m long string. the ball a is pulled sideways so that the string is at a 45-degree angle, then released. at the very bottom of its swing, the ball strikes a 500 g steel paperweight b that is resting on a frictionless table. to what angle does the ball rebound?
After solving the equation the ball rebound is θ2 = 18.88° is the correct answer.
What is Potential energy?
Potential energy is the energy held by an object due to its position or composition. It is the energy of an object that is stored and waiting to be released. This energy is due to the force of gravity, electric charge, and/or the force of a spring. Potential energy is also known as “stored energy”. It is measured in units of joules (J). Potential energy can be converted into kinetic energy, which is the energy of motion. Examples of potential energy include the energy stored in a stretched rubber band, the energy stored in a roller coaster car at the top of the hill, and the energy stored in a boulder at the top of a mountain. Potential energy can also be found in chemical bonds and nuclear energy.
Here Potential energy will convert to Kinetic energy,
P.E. (initial) + K.E. (initial) = P.E. (Final) + K.E. (Final)
M g L (1 – Cos 45) + 0 = 0 + ½ mv2
v2 = 2gL (1 – 1/0.414)
v = (2* 9.8* 1)0.5 * (1 – 1/0.414)0.5
v = 2.396 m/s
Thus, when ball strikes its velocity is 2.396 m/s.
From conservation of momentum
M1v1 + m2v2 = m1V1 + m2V2
0.2*2.396 = 0.2 V1 + 0.5 V2
Here, since no information is given for collision.
I am considering it to be elastic,
U1 – U2 = V2 – V1
U1 = V2 -V1
V2 – V1 = 2.396
0.2V1 + 0.5V2 = 0.4792
V1 = -1.027 m/s ; V2 = 1.369 m/s
i.e.,
½ m1v12 = m g L (1-Cos θ2) ---- Energy Conversion
V12 = 9.8 * 2 * 1 (1- Cos θ2)
1.055 = 19.6 (1 - Cos θ2)
Cos θ2 = 0.9462
θ2 = 18.88 °
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At what value of x does f have a discontinuity due to a vertical asymptote? give a reason for your answer.
If f has a discontinuity due to a vertical asymptote at x=a, then the function has a vertical asymptote at x=a.
A vertical asymptote occurs when the function approaches infinity as x approaches a certain value from either direction. This means that the function becomes arbitrarily large as x approaches the value of the vertical asymptote, but it never actually reaches the asymptote itself.
To determine the value of x at which f has a discontinuity due to a vertical asymptote, you need to find the value of x at which the function approaches infinity. This can often be done by examining the function and looking for expressions of the form 1/0 or 0/0, which indicate that the function is becoming infinitely large as x approaches a certain value.
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If the mass of the bar is 50kg, and Shelbi exerts 550N of force, what is the acceleration of the bar?
If the mass of the bar is 50kg, and Shelbi exerts 550N of force, the acceleration of the bar is 11 N/m².
Describe force.A push, pull, or hit on any object that causes a change in its state of motion is referred to as applying force. One thing experiences a force from another. For instance, we can say that when a force was applied to the box in the form of a push, it changed its state from rest to motion because when a box is pushed, it goes forward and changes its state of motion.
Describe acceleration.Accelerations are vector quantities. According to Newton's Second Law, an object's acceleration is the result of two factors working together: the object's mass, which varies depending on the materials it is made of, and the net balance of all external forces acting on it.
Briefing:Acceleration= Force/Mass =550/50 = 11m/s²
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A bullet of mass 0.01kg is fired with velocity of [230,0]m/s in to a sack of sand of mass 9.99kg which is swinging from rope. At the moment the bullet hits, the sack has a velocity of [0,0.2]m/s. Workout the velocity of bullet of the sack.
Answer:
The velocity of the bullet and the sack after the bullet hits the sack is [0.2,0.2] m/s.
Explanation:
To calculate the velocity of the bullet and the sack after the bullet hits the sack, we can use the equation:
vf = (m1 * v1 + m2 * v2) / (m1 + m2)
Plugging in the values given in the question, we get:
vf = (0.01 kg * [230,0] m/s + 9.99 kg * [0,0.2] m/s) / (0.01 kg + 9.99 kg)
Solving for vf, we get:
vf = [0.2, 0.2] m/s
Therefore, the velocity of the bullet and the sack after the bullet hits the sack is [0.2,0.2] m/s.
The initial and final momentum of a body will be conserved during collision. From this concept, the final velocity of the bullet and sack is 2.5 m/s.
What is momentum?Momentum is the product of mass and velocity of a body. During a collision of two bodies, the sum of initial momentum of the two bodies will be equal to the sum of their final momentum.
Given that, mass of bullet = 0.01 Kg
velocity = 2300 m/s
mass of sand sack = 9.99 Kg
velocity = 0.2 m/s
Then sum of initial momentum = (0.01 kg × 2300 m/s) + (9.99 kg × 0.2 m/s) = 24.9 kg m/s.
The final momentum of the combined mass = (9.99 kg + 0.01 kg) v = 24.9 Kg m/s
Thus, final velocity v = 24.9 / ( (9.99 kg + 0.01 kg) = 2.5 m/s
Therefore, the velocity of the bullet and sack after the collision will be 2.5 m/s.
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Is waste Scope 1 or Scope 3?
Due to the fact that the reporting company purchases waste management services, treatment of waste produced during operations is designated as an originating scope 3 category.
What falls under Scope 3?Scope 3 emission are the outcome of operations on resources that the reporting company does not own or control, but which are indirectly impacted by the organization through its value chain.All sources outside of an organization's range 1 and scope 2 boundary are included in scope 3 emissions.
What targets are in scope 3?Scope 3 emissions were indirect emission of greenhouse gases that are produced in the larger economy in addition to scope 2 emissions.They result from a facility's operations but come from sources not under the ownership or control of that facility.
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What is reinforcement in Psychology?
Reinforcement can be positive, meaning that a desirable consequence is provided, or negative, meaning that an undesirable consequence is removed
Reinforcement in psychology is an important tool for motivating behavior. It works by providing a consequence after a behavior occurs that makes it more likely to happen again in similar situations. Positive reinforcement is providing a desirable consequence, such as praise or a reward, after a behavior. Negative reinforcement is the removal of an undesirable consequence, such as a punishment, after a behavior. Reinforcement can be used to shape and strengthen desirable behaviors, as well as decrease undesirable behaviors. It is an effective way of motivating people and can be used in a variety of different contexts.
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What are the 6 elements of safety?
The five pillars of safety are engineering, encouragement, enforcement, and evaluation. Your strategy to ensure that you promote a safe environment and workplace should heavily emphasize education.
What are the safety three Cs?By exercising your intellect beforehand, you may be able to save a life or at least lessen someone else's suffering. The three fundamental Cs are check, call, and care.
What number of safety components are there?
A Framework for Aligning the 14 Process Safety Management Elements. To prevent the release of extremely hazardous substances, it is essential to use related techniques to managing hazards, although it might be difficult to put Process Safety Management's operational goals into effect.
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how would you rearrange the ideal gas equation to calculate the pressure of a gas multiply p by v divide nrt by v multiply nrt by v divide v by nrt multiply pv by rt
An ideal gas equation to calculate the pressure of a gas is PV=nRT where P is pressure, V is volume, n is number of mole,R is gas constant and T is temperature.
In thermodynamics, Ideal gas equation is a clear cut guess of the way of behaving of many gases under different circumstances. Ideal Gas Condition is the blend of experimental regulations like Charle's regulation, Boyle's regulation, Gay-Lussac's regulation, and Avogadro's regulation. Ideal Gas equation is the equation characterizing the conditions of the speculative gases communicated numerically by the blends of observational and actual constants. It is likewise called the general gas condition. It very well may be characterized as:
Ideal Gas equation is the equation characterizing the equations of the speculative gases communicated numerically by the blends of exact and actual constants. It is additionally called the general gas equation. It tends to be characterized as PV=nRT.
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The wave oscillation period is 0.5 minutes. Find the length of this wave if its speed is 54 km/h
To find the length of the wave if its speed is 54 km/h, we can use the formula:
Wavelength = Speed / Frequency
where the frequency of the wave is equal to the inverse of the oscillation period. The oscillation period of the wave is 0.5 minutes, so the frequency is 1 / (0.5 minutes) = 2 oscillations/minute.
We can now plug these values into the formula to find the wavelength:
Wavelength = 54 km/h / (2 oscillations/minute)
= 27 km
Therefore, the length of the wave is 27 km
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FILL IN THE BLANK. the format specifier ________ is used to output values of type float or double.
The format specifier %f is used to output values of type float or double.
Format specifiers are used in C to accept inputs and print out the output of a type. The sign% is present in every format specifier we use. The type of data that must be submitted as input and the type of data that must be displayed on the screen are both specified by format specifiers to the compiler.
Both the input and the output use the format specifier. When a variable is taking input with scanf() or printing data with printf, there is a technique to let the compiler know what type of data is there in the variable (). Examples are %c, %d, and %f.
Format specifiers in C typically come in six different flavors.
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The diagram is an illustration of global atmospheric circulation. Which of the following is the source of energy driving the circulation pattern labeled C in the diagram?
answer choices
The Coriolis effect
Solar radiation
Earth's magnetic field
The spinning core of Earth
Solar radiation is labelled as C in the diagram of global atmospheric circulation.
Winds are created by global atmospheric circulation, which results to areas of significant rainfall, such as tropical rainforests, and areas of dry air, such as deserts.
The global atmospheric circulation model is a simplified representation of the movement of air currents in the atmosphere. It is employed to aid in the explanation of weather patterns and climatic zones. Cells serve as the foundation of the global atmospheric circulation model. These cells are areas where air travels from low to high pressure.
Even though weather fronts and storms cause interruptions, there is a continuous pattern to how air travels about our planet's atmosphere. Because the Sun heats the Earth more at the equator than at the poles, this pattern is known as atmospheric circulation. It is also influenced by earth rotatory.
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heather and jerry are standing on a bridge 51 m above a river. heather throws a rock straight down with a speed of 17 m/s . jerry, at exactly the same instant of time, throws a rock straight up with the same speed. ignore air resistance. part a how much time elapses between the first splash and the second splash? express your answer to two significant figures and include the appropriate units.
Jerry launches his rock upward at a speed of 20 m/s. It will slow down until its velocity hits zero at a rate of 9.8 m/s2. At that point, it will have reached apogee and will start to plummet. Therefore, 20 m/(9.8 m/s) = 2.04 seconds. to your maximum height.
After 2.04 seconds, it will start to accelerate downward once more, this time by 9.8 m/s2. Therefore, it will arrive at the starting place after an additional 2.04 seconds while moving at 20 m/s. Then it will travel through time in a similar manner to Heather's rock.
Jerry's pebble will therefore impact the sea 4.08 seconds later than Heather's. For this issue, it is not important to know how high you are above the sea.
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What does an ammeter measure?
An ammeter is a device used to measure electric current in amperes, either in direct current (DC) or alternating current (AC).
Ammeters measure current in what ways?
A shunt resistor is used in digital ammeter systems to create a calibrated voltage proportionate to the current flowing. The analog-to-digital converter (ADC) in a digital voltmeter is then used to measure this voltage; the digital display is calibrated to show the current flowing through the shunt.
What three purposes does an ammeter serve?
1. It is utilise to gauge circuit current.
2. It is utilised in circuits to determine whether or not they are functioning properly.
3. It is also used in the electronic industry to examine the circuit and usage of the appliances.
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how many neutrinos per second should be incident on every square meter of the earth from this process? this huge number is indicative of how rarely a neutrino interacts, since large detectors observe very few per day.
The area is 4 times 1.496 times 10 to 11 meters squared, and when we divide this by the total amount of neutrinos created during the proton-proton cycle each second, we obtain 6 times 10 to 14 neutrinos per square meter every second on Earth.
At the distance from the earth, how many neutrinos flow through each square meter of a sphere's surface?Neutrinos carry away around 3% of the energy produced by nuclear fusion in the Sun. Scientists estimate about 35 million billion (3.5 1016) solar neutrinos pass through each square meter of the Earth's surface per second as a result of protons reacting and creating neutrinos inside the Sun's core.
Your thumbnail receives how many neutrinos each second?Your thumbnail receives about 100 billion solar neutrinos each second. Nuclear fusion occurs in the sun, where it results in the creation of neutrinos.
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What are the 4 types of reinforcement?
The four types of reinforcement include- positive reinforcement, negative reinforcement, punishment, extinction.
Positive reinforcement: Positive reinforcement is especially effective at establishing new behaviors, but it may not work as well in the long term if the subject becomes bored with the reward over time. This involves adding something to increase response, such as praising a child when they complete a designated task.
Negative reinforcement: Namely, negative in this theory means removing or subtracting something that either discourages negative behavior (punishment) or removes adverse stimuli to support or encourage certain behavior (reinforcement). This involves removing something to increase response, such as withholding payment until the person completes the job. The person would remain motivated till the end of the job to acquire the payment.
Punishment: Punishment is often mistakenly confused with negative reinforcement. Remember, reinforcement always increases the chances that a behavior will occur and punishment always decreases the chances that a behavior will occur. This involves adding something aversive to modify behavior. For example, yelling at a child for misbehaving. In this example, the child would associate every negative behavior with punishments. This would prevent the child from repeating such behavior.
Extinction: This involves removing or taking away something to modify a certain response. This is called negative punishment or extinction. For instance, a teenager comes home late, and the parents curb their phone usage. Next time, the teenager would think before breaking the curfew.
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study smarter a charged capacitor and an inductor are connected in series at time t 0. in terms of the period t of the resulting oscillations, determine how much later the following reach their maximum value: (a) the charge on the capacitor; (b) the voltage across the capacitor, with its original polarity; (c) the energy stored in the electric field; and (d) the current.
Alternate Approach The inductor exhibits open circuit behavior at time t=0+. At t=0+, inductive reactance is infinite, causing the inductor to initially operate as an open circuit. The inductor similarly acts like a short circuit at steady state.
At time t 0, what is an inductor?The inductor behaves as an open circuit with current reflected back at time t = 0 +. Important Information: A capacitor with a zero starting condition behaves as a short circuit at time t = 0 +, reflecting back voltage.
when an inductor and a charged capacitor are coupled?At time t = 0, an inductor is coupled to a charged capacitor. Considering the capacitor and the inductor as one, Write out the equation for the effective potential difference across the combination at any instant in time t, and then solve it to find the instantaneous current through the combination.
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g solid wooden sphere of volume 0.0100 m3 floats freely exactly one-half submerged in a liquid of density 800 kg/m3. a lightweight cord is now tied to the sphere and is used to pull the sphere under the surface and hold it completely submerged. what is the tension in the cord?
The cord has a one percent tension. When something or someone pulls on a cord or string, the tension that results is what is being described.
We are aware that T = mg + ma is the formula used to compute the force of tension.
Calculation:T = mg + ma
T = 800 × 9.8 + 800 ×9.8
How much tension is there?Tension is the force that is sent through a rope, string, or wire when two opposing forces pull on it. Along the whole length of the wire, the tension force pulls energy equally on the bodies at the ends. Every physical object that comes into contact with another one exerts force on it.
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F= 10k F2 12k F3 = 18k Problems analytical solutions using force components. check graphically 2.9 three members of a truss frame into a steel gusset plate as shown. all forces are concurrent at point o. determine the resultant of the three forces that must be carried by the gusset plate.
The resultant of the three forces that must be carried by the gusset plate is 22.14k
The resultant itself means total or amount. So, it can be said that the resultant force is the total or overall force acting on a system. The resultant force is a vector quantity.
F₁
sin 30° = x₁/10k
x₁ = 10 × sin 30° × k
x₁ = 5k
Similarly:
y₁ = 10k × cos30°
y₁ = 10k × 0.866
y₁ = 8.66k
F₂
The angle at F₂ is 0 degrees θ = 0°
So:
x₂ = -12k
y₂ = 0
F₃
cos 45° = x₃/18k
x₃ = 18 × cos 45° × k
x₃ = 12.728 k
Similarly:
y₃ = 18k × sin 45°
y₃ = 18k × 0.707
y₃ = 12.728 k
Resultant of x:
x = x₁ - x₂ + x₃
x = 5k -12 k + 12.728 k
x = 5.726 k
Resultant of y:
y = y₁ - y₂ + y₃
y = 8.66k - 0k + 12.728 k
y = 21.388k
Resultant F:
F = [tex]\sqrt{x^2 + y^2}[/tex]
F = [tex]\sqrt{ 5.726^2 + 21.388^2 }[/tex]
F = [tex]\sqrt{ 32.787+ 457.446 }[/tex]
F = [tex]\sqrt{ 490.233 }[/tex]
F = 22.14k
So, the resultant of the three forces is 22.14k
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. If five forces f₁-20N at N30°E, f₂= 40N along the west, f3=50N at N50°W, f4 = 10N on angle 270° and f5=70N on angle 200° are acting on a box find the magnitude and direction of the resultant force on the box.
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